Evaluate the expression when a=-2 and x=6. \
4x-a
Answer:
26
Step-by-step explanation:
Given
4x - a ← substitute a = - 2, x = 6 into the expression
= 4(6) - (- 2) [ note - (- ) is equivalent to + ]
= 24 + 2
= 26
Can someone explain why the answer is False. Will Mark brainliest.
Answer:
Supplementary Angles are 180 degrees. A triangle has 180 degrees. One angle is already 90 degrees, so 2 more angles with 180 degrees is impossible.
Step-by-step explanation:
please helpppp
also just click the image for it to be bigger
The matrix A has eigenvalues X₁ = 3 and X₂ = 4 with associated eigenvectors 2 V₁ = and v2 [A] Use this information to find the solution to the initial value - [³] Y' = AY where Y (0) = [ (0)] - [8] - [ 2₂ ] 1 problem = Give your answer as x(t) and y(t). y
The solution to the initial value problem is:
x(t) = [tex](1/4) * e^{(3t)} - (1/4) * e^{(4t)}[/tex] and y(t) = [tex]e^{(3t)} + (1/6) * e^{(4t)}[/tex]
To find the solution to the initial value problem Y' = AY, where A is the matrix with eigenvalues and eigenvectors given, we can use the eigenvalue-eigenvector method.
Let's denote the eigenvectors as v₁ and v₂:
v₁ = [2]
[8]
v₂ = [-3]
[2]
The general solution to the system of linear differential equations can be written as:
Y(t) = [tex]c_1 * e^{(X_1t)} * v_1 + c_2 * e^{(X_2t)} * v_2[/tex]
where c₁ and c₂ are constants.
Substituting the given eigenvalues and eigenvectors:
Y(t) = c₁ * [tex]e^{(3t)[/tex] * [2] + c₂ * [tex]e^(4t)[/tex] * [-3]
[8] [2]
Simplifying further:
Y(t) = [2c₁ * [tex]e^{(3t)[/tex] - 3c₂ * [tex]e^{(4t)[/tex]]
[8c₁ * [tex]e^{(3t)[/tex] + 2c₂ * [tex]e^{(4t)[/tex]]
To find the specific solution that satisfies the initial condition Y(0) = [0] and [8], we can substitute t = 0 into the general solution:
Y(0) = [2c₁ - 3c₂]
[8c₁ + 2c₂]
Equating this to the initial condition:
[2c₁ - 3c₂] = [0]
[8c₁ + 2c₂] [2]
Solving this system of equations will give us the values of c₁ and c₂:
2c₁ - 3c₂ = 0 ----(1)
8c₁ + 2c₂ = 2 ----(2)
Multiplying equation (1) by 4 and adding it to equation (2), we get:
16c₁ = 2
Solving for c₁, we find:
c₁ = 1/8
Substituting c₁ back into equation (1), we can solve for c₂:
2(1/8) - 3c₂ = 0
1/4 - 3c₂ = 0
3c₂ = 1/4
c₂ = 1/12
Therefore, the specific solution to the initial value problem is:
x(t) = [tex](1/8) * e^{(3t)} * 2 + (1/12) * e^{(4t) }* (-3)[/tex]
y(t) = [tex](1/8) * e^{(3t)} * 8 + (1/12) * e^{(4t)} * 2[/tex]
Simplifying further:
x(t) = [tex](1/4) * e^{(3t)} - (1/4) * e^{(4t)}[/tex]
y(t) = [tex]e^{(3t)} + (1/6) * e^{(4t)}[/tex]
Therefore, the solution to the initial value problem is x(t) = [tex](1/4) * e^{(3t)} - (1/4) * e^{(4t)}[/tex] and y(t) = [tex]e^{(3t)} + (1/6) * e^{(4t)}[/tex].
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Work out
5.2
% of
628.55
km
Give your answer rounded to 2 DP.
HELP ME PLEASEEEEEEE CIRCUMFERENCE AND AREA OF A CIRCLE
Answer:
Formula for circumference: 2 x pie(3.14 or 22/7) x radius(half of diameter or already given radius). Area of a circle: pie(3.14 or 22/7) x radius squared
Radius: 3, 6 is diameter and half of that is 3.
3 x 3.14 x 2 = 18.84 <------ circumference
3.14 x 3^2
3.14 x 9 = 28.26 <------ area of the circle
what's 13.564^4x3.59^-39?
Answer:
0
Step-by-step explanation:
hope this helps :)
Find mZN.
62°
K
N
Need help with this question?
Answer:
118degrees
Step-by-step explanation:
Assuming we are given the following and m<k and ,<N lies on the same straight line, hence;
m<K = 62 degrees
n<N = ?
Since are on the same straight line, hence;
m<N + m<K = 180
m<N + 62 = 180
m<N = 180 - 62
m<N = 118
Hence the measure of m<N is 118degrees
'
,
Factor the expression over the complex numbers. x2+20 Enter your answer in the box.
Answer:
2(x plus 20)
Step-by-step explanation:
this is the highest common factor
Consider the polynomials given below.
P(x) = 14 + 3.13 + 2x2 - + 2
Q*) = (x3 + 2x2 + 3)(x2 - 2)
Determine the operation that results in the simplified expression below.
25 + 14 - 513 - 312 + I-8
A. P+Q
B. P.Q
C. PQ
D. O-P
The operation that results in the simplified expression x⁵ + x⁴ - 5x³ - 3x² + x - 8 is; P + Q
How to Simplify Polynomials?
We are given the Polynomials as;
P(x) = x⁴ + 3x³ + 2x² - x + 2
Q(x) = (x³ + 2x² + 3)(x² - 2)
We want to find the combination of P and Q that would yield;
x⁵ + x⁴ - 5x³ - 3x² + x - 8
Let us expand Q(x) to get;
Q(x) = x⁵ + 2x⁴ + 3x² - 2x³ - 4x² - 6
Q(x) = x⁵ + 2x⁴ - 2x³ - x² - 6
Now, the combined polynomial shows us that coefficient of x⁴ is 1 and coefficient of x³ is - 5.
By inspection, we can say that the combination that would produce the required result is;
Q(x) - P(x) = x⁵ + 2x⁴ - 2x³ - x² - 6 - x⁴ - 3x³ - 2x² + x - 2
Q(x) - P(x) = x⁵ + x⁴ - 5x³ - 3x² + x - 8
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Karlyn had an online business selling earrings. The materials to make a pair of earrings cost $15.00. Since it took her an hour to make each pair of earrings, she wanted to markup the price by $35 for her time and sell them for $50.00. What is the % markup for that pair of earrings?
The markup would be 133.33%
30is 200% of 15
5 is 33.33333333% of 15
33.33333333%+100+=133.33333333%
The markup is 133.33% or 133.33333333%
Now, the Group of Good would like to decide how they should infiltrate the gallery. The group wants to vote on different plans to sneak into the gallery; the plans are labelled a - e. While the group puts all of the plans together so everyone can see them, a tragedy occurs. Kenny gets a paper cut by Plan a! The cut is too deep! Saddened by their colleague’s sudden paper death, they decide that the leader should have more say in which plan is picked (in hopes to avoid more unnecessary death). Suppose the leader’s vote (from the last question) counts as 5 votes. The following preference schedule is produced:
Total Votes = 2 2 1 1
Choice 1 e c a b b
Choice 2 d a b d a
Choice 3 c d e c d
Choice 4 a b d e c
Choice 5 b e c a e
(a) If plurality voting is used, what plan should the group use? Does this plan have a majority
Total Votes = 2 2 1 1
Choice 1 e c a b b
Choice 2 d a b d a
Choice 3 c d e c d
Choice 4 a b d e c
Choice 5 b e c a e
(b) If Instant Runoff Voting is used, what plan should the group use? Show how you discovered your answer.
Total Votes = 2 2 1 1
Choice 1 e c a b b
Choice 2 d a b d a
Choice 3 c d e c d
Choice 4 a b d e c
Choice 5 b e c a e
(c)If the Borda Count method is used, what plan should the group use? Show how the winner is computed
What was the best part of this project? What was the worst part?
(a) If plurality voting is used, Plan E will be chosen.
b It has the most first-place votes, with 2 each from voters 1 and 5. No other plan has more than 1 first-place vote.
c If the Borda Count method is used, Plan C will be chosen.
How to explain the informationa The best part of this project was learning about different voting methods and how they can be used to choose a winner. The worst part of the project was the difficulty of calculating the Borda Count.
b If Instant Runoff Voting is used, Plan C will be chosen. In the first round of counting, Plan E is eliminated, as it has the fewest first-place votes. In the second round, Plan C is eliminated, as it has the fewest second-place votes. In the third round, Plan B is eliminated, as it has the fewest third-place votes. In the fourth round, Plan D is eliminated, as it has the fewest fourth-place votes. This leaves Plan A as the winner, as it has the most votes remaining.
c If the Borda Count method is used, Plan C will be chosen. Each voter's ballot is assigned a number of points equal to the number of candidates ranked lower than that candidate. For example, voter 1's ballot gives Plan E 5 points, Plan C 4 points, Plan A 3 points, Plan B 2 points, and Plan D 1 point. The total number of points for each candidate is then calculated. Plan C has the most points, with 16, so it is the winner.
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Let f(x) E Z[x] with deg (f(x)) ≥ 1, and let f(x) be the polynomial in Z, [x], where p is prime integer, obtained from f(x) by reducing all the coefficients of f(x) modulo p. Assume that deg (F(x)) = deg(f(x)), then: If f(x) is reducible over Q. then f(x) is irreducible over Z O This option If f(x) is reducible over Zp, then f(x) is reducible over Q If f(x) is reducible over Zp, then f(x) is reducible over Q O This option None of choices
If f(x) is reducible over Zp, then f(x) is reducible over Q.
What is the probability of selecting a respondent who prefers public transportation or cycling from a survey of 500 commuters?If a polynomial f(x) with integer coefficients is reducible over Zp (the integers modulo p), where p is a prime number, then it is also reducible over Q (the rational numbers).
This result follows from the fact that if a polynomial is reducible over a smaller field (Zp), it must also be reducible over a larger field (Q).
Since Zp is a subset of Q, any factorization of the polynomial in Zp can also be used in Q. Therefore, if f(x) is reducible over Zp, it is also reducible over Q.
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A steam power plant operates on the ideal reheat-pipe steam Rankine cycle and generates 90 MW of net power. Steam enters the high pressure turbine at a pressure of 10 MPa and a temperature of 520° and exits at a pressure of 1 MPa. Some steam leaving the turbine at this pressure is used to heat the boiler feedwater in an open feedwater heater. After the remaining steam is heated to 480°, it is expanded in the low pressure turbine to a condenser pressure of 14 kPa. Calculate the mass flow rate of the steam passing through the boiler and the thermal efficiency of the cycle by showing the cycle in a T-s diagram with saturated liquid and saturated steam curves.
The mass flow rate is 0.56 kg/s
How to determine the mass flow rateThe formula for calculating the mass flow rate is expressed as;
m = W / (hf - hg)
Such that the parameters are expressed as;
m is the mass flow rate (kg/s)W is the net power output (W)hf is the enthalpy of the feedwater (kJ/kg)hg is the enthalpy of the steam at the turbine exit (kJ/kg)Substitute the values, we get;
m = 90 MW / (2418 - 2257)
Subtract the values, we have;
m = 90/161
Divide the values, we get;
m= 0.56 kg/s
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what's the ratio of 0.9?
Answer:
[tex] \frac{9}{10} = 0.9[/tex]
40 students where has their favorite shoe color
how many chose blue?
Answer:
8 students
Step-by-step explanation:
There are 20 boxes and there are a total of 40 students interviewed. So, each box is worth 2 students. Since blue has 4 boxes, 4*2 = 8 students chose blue as their favorite shoe color.
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⚡✨
A payment of $970 scheduled to be paid today and a second payment of $1,260 to be paid in seven months from today are to be replaced by a single equivalent payment. What total payment made today would place the payee in the same financial position as the scheduled payments if money can earn 6.25%? (Do not round intermediate calculations and round your final answer to 2 decimal places.)
Therefore, the total payment made today by the payee is $2,149.01
Payment calculation.
To total payment made today would place the payee in the same financial position as the scheduled payments if money can earn 6.25% we will use the formula below.
PV = FV /(1 + Rr)^n
r =6.25%
FV = $1,260
PV = $ 1,260 / (1+ 0.0625) ^(7/12)
PV = $ 1,179.01
The value of the second payment is $ 1,179.01.
Lets find the total payment. We can represent the total payment by X.
X - $ 970 = $ 1,179.01.
To isolate X, we will add $ 970 to both sides.
X = $ 970 + $ 1,179.01.
X = $2,149.01
Therefore, the total payment made today by the payee is $2,149.01
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please someone help me out, please don't put the incorrect answer
What is the distance between the points (-1, 2) and (2, 6)?
Answer:
5
Step-by-step explanation:
Distance Equation Solution:
[tex]d=\sqrt{(2-(-1)^2+(6-2)^2}\\d=\sqrt{(3)^2+(4)^2} \\d= \sqrt{9+6}\\d= \sqrt{25}\\d=5[/tex]
Question Two
The concept of sets underlies every branch of modern mathematics for economics. Suppose the universal set is a set of positive integers, Z + , and let
X={ x € Z + :x<=20 and x^ 2 € Z +}
Y={ x € Z + :x<=24 and sqrt x € Z +}
a) Determine X U Y and X n Y in enumeration and functional form.
b) Determine sets X n Z +, X U Z + ,Y n Z +, Y U Z + .
The sets X and Y are defined based on specific conditions on positive integers. In functional form, X n Y can be represented as X n Y = {x € Z + : x ≤ 20, x ≤ 24, and x^2 € Z +, sqrt(x) € Z +}.
a) To find X U Y (the union of X and Y), we need to identify all the positive integers that satisfy either the condition for X or the condition for Y. In enumeration form, X U Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 24}. In functional form, X U Y can be represented as X U Y = {x € Z + : (x ≤ 20 and x^2 € Z +) or (x ≤ 24 and sqrt(x) € Z +)}.
To find X n Y (the intersection of X and Y), we need to identify the positive integers that satisfy both the condition for X and the condition for Y. In enumeration form, X n Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16}. In functional form, X n Y can be represented as X n Y = {x € Z + : x ≤ 20, x ≤ 24, and x^2 € Z +, sqrt(x) € Z +}.
b) To determine the sets X n Z + and Y n Z +, we need to identify the positive integers that satisfy the conditions for X and Y, respectively, and also belong to the universal set of positive integers, Z +. Since X and Y are subsets of Z +, X n Z + = X and Y n Z + = Y.
To find X U Z +, we need to identify all the positive integers that satisfy either the condition for X or belong to Z +. In this case, X U Z + = Z + since all positive integers are included in X. Similarly, Y U Z + = Z + since all positive integers are included in Y.
In summary, X U Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 24} and X n Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16}. The sets X n Z + and Y n Z + are equal to X and Y, respectively, while X U Z + and Y U Z + are both equal to Z +.
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Given the points P(0,0,-2), Q(2,3,4), R(4, 6, 5), and S(6, 11, 10), find the following: (a) The area of triangle PQR. (b) An equation of the form ax + by + cz = d for the plane containing points P, Q, and R. (c) The volume of the parallelepiped with edges PO.PR, and Ps. (d) A point on the line through P and Q which is two units away from P.
(a) The area of triangle PQR is 9.165 units².
(b) The formula for a plane given three points is: 10x - 7y - 2z = 0
(c) The volume of the parallelepiped with edges PO, PR, and PS is 148 units³.
(d) A point on the line through P and Q which is two units away from P is (4/5, 6/5, 2/5).
(a) The area of triangle PQR is 9.165 units².
The formula for the area of a triangle given three points is:
Area = 1/2 | ((x2 − x1) × (y3 − y1)) − ((y2 − y1) × (x3 − x1)) |
The coordinates for P, Q, and R are: P (0, 0, -2)Q (2, 3, 4)R (4, 6, 5)
Substituting into the formula gives us:
Area = 1/2 | ((2 - 0) × (5 + 2)) − ((3 - 0) × (4 - 0)) |
Area = 9.165 units² (rounded to three decimal places)
(b) An equation of the form ax + by + cz = d for the plane containing points P, Q, and R is:
10x - 7y - 2z = 0
The formula for a plane given three points is: ax + by + cz = d
To find a, b, c, and d, we first need to find two vectors on the plane.
We can use PQ and PR.
PQ = Q - P = (2 - 0)i + (3 - 0)j + (4 + 2)k = 2i + 3j + 6k
PR = R - P = (4 - 0)i + (6 - 0)j + (5 + 2)k = 4i + 6j + 7k
Now we can find the normal vector by taking the cross product of PQ and PR:
PQ x PR = <3i - 26j - 12k>
So the equation of the plane is:3x - 26y - 12z = 0
We can simplify this by multiplying all terms by -2, which gives:10x - 7y - 2z = 0
(c) The volume of the parallelepiped with edges PO, PR, and PS is 148 units³.
The volume of a parallelepiped is given by the scalar triple product of three vectors.
We can use OP, PR, and PS.
OP = P - O = -i - j - 2k = < -1, -1, -2 >
PR = R - P = 4i + 6j + 7k = < 4, 6, 7 >
PS = S - P = 6i + 11j + 12k = < 6, 11, 12 >
The scalar triple product is:
OP ⋅ (PR x PS)OP ⋅ (PR x PS) = < -1, -1, -2 > ⋅ (< 54, -20, -10 >)OP ⋅ (PR x PS) = -148
The volume of the parallelepiped is 148 units³.
(d) A point on the line through P and Q which is two units away from P is (4/5, 6/5, 2/5).
The equation of the line through P and Q is:x = 2t, y = 3t, z = 4 + 6t
A point on the line that is two units away from P is given by:
t = 2/5
Substituting into the equations for x, y, and z gives:(4/5, 6/5, 2/5)
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plz help me please please
Answer:
5%
Step-by-step explanation:
Answer:
5% increase
Step-by-step explanation:
30/600 equals .05 or 5%
b) A shopping center consists of two stores and two parking lots. In the diagram, w represents the width of Store B in meters. 25 13.5 Which expression for the area of the shopping center is written as the area of the stores plus the area of the parking lots? 38.5(w + 10) 10 Store A Parking Lot A 38.5w + 385 Store B Parking Lot B 25(w + 10) + 13.5(w + 10) (25 + 13.5)(10) + (25 + 13.5)w
Answer:
Step-by-step explanation:
25(w+10) + 13.5(w +10)
Answer:
25(w+10)+13.5(w+10)
Step-by-step explanation:
hope it helps
Please help!!! I’ll mark you as brainliest!!!!!!
0.138613961 as a percent rounded to the nearest tenth
Answer:
13.9% Approximately
Suppose that 8% of the patients tested in a clinic are infected with HIV. Furthermore, suppose that when a blood test for HIV is given, 92% of the patients infected with HIV test positive and that 9% of the patients not infected with HIV test positive. What is the probability that a patient testing positive for HIV with this test is not infected with HIV?
The problem involves calculating the probability that a patient who tests positive for HIV is not actually infected with HIV. Given that 8% of the patients tested are infected and that the test has a 92% true positive rate for infected patients and a 9% false positive rate for non-infected patients, we need to determine the probability of a false positive result.
Let's denote the events as follows:
A: Patient is infected with HIV
B: Patient tests positive for HIV
We are interested in finding P(A'|B), which represents the probability that a patient is not infected (A') given that they test positive (B).
According to Bayes' theorem, we can express this probability as:
P(A'|B) = (P(B|A') * P(A')) / P(B)
First, let's calculate P(B|A'), which represents the probability of testing positive given that the patient is not infected. Since the false positive rate is given as 9%, we have P(B|A') = 0.09.
Next, we need to calculate P(A'), which is the probability of not being infected. Since 8% of the patients are infected, the complement event (not being infected) has a probability of 1 - 0.08 = 0.92.
To calculate P(B), the probability of testing positive, we need to consider the total probability of testing positive, which includes both infected and non-infected patients. Therefore, we have:
P(B) = P(B|A) * P(A) + P(B|A') * P(A') = 0.92 * 0.08 + 0.09 * 0.92.
Finally, substituting these values into Bayes' theorem, we can calculate P(A'|B), the probability that a patient testing positive is not infected with HIV.
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I've done everything I can, please help
Answer:
D
Step-by-step explanation:
Answer:
4 is choice C. THis is because the y intercept is 1 and when you go up 2 units, and go right once, you go to another point (rise over run)
Step-by-step explanation:
Which of the graphs below represents the soltuion set for d - 4 > -3?
Answer:
The answer is d
Step-by-step explanation:
Algebra pls help
Really
Answer: n=-14
Step-by-step explanation:
CONCEPT:
When the same-base exponents MULTIPLY= adding the exponents When the same-base exponents DIVIDE= subtracting the exponentsSOLVE:
The expression in the questions is [tex](x^{3} )(x^{-17})[/tex] which is MULTIPLYING, which means we should add the exponents together
[tex](x^{3} )(x^{-17})[/tex]=[tex]x^n[/tex] ⇔ Given
[tex]x^{3+(-17)}[/tex]=[tex]x^n[/tex] ⇔ Adding Exponents Together
[tex]x^{3-17}[/tex]=[tex]x^n[/tex] ⇔ Simplify
[tex]x^{-14}[/tex]=[tex]x^n[/tex] ⇔ Simplify
[tex]n[/tex]=[tex]-14[/tex] ⇔ Correspondingly
Hope this helps!! :)
Please let me know if you have any questions
pythagorean theorem
Answer:
The pythagorean theorem is a theorem which states that the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
Pythagorean theorem
in the right angle triangles there is a relationship that governs the length of the three sides. if we knows the length of any two sides, the third side may be calculated by the use of the Pythagorean theorem.
This theorem states that the square on the hypotenuse of a right angled triangle is equal to the sum of the squares on the remaining two sides.
we only use Pythagorean theorem to find the length of the missing side of a right angled triangle only.
Last year the records of a convenience store chain showed the mean amount spent by a customer was $52. A sample of 36 transactions made this month revealed the mean amount spent was $50 with a standard deviation of $11. At the 0.10 significance level, test the claim that the mean amount spent by a customer has significantly decreased since last year.
There insufficient evidence to support the claim that the mean amount spent by a customer has significantly decreased since last year.
Step 1: State the hypotheses:
- Null hypothesis (H0): The mean amount spent by a customer is equal to or greater than last year's mean ($52).
- Alternative hypothesis (H1): The mean amount spent by a customer is significantly less than last year's mean ($52).
Step 2: Set the significance level:
The significance level (α) is given as 0.10. This represents a 10% chance of rejecting the null hypothesis when it is true.
Step 3: Formulate the decision rule:
Since the alternative hypothesis is stating a decrease in the mean amount spent, we will conduct a one-tailed t-test and reject the null hypothesis if the test statistic falls in the critical region corresponding to the left tail of the t-distribution.
Step 4: Calculate the test statistic:
We need to calculate the t-statistic using the formula:
t = (sample mean - population mean) / (sample standard deviation / √(sample size))
Given data:
Population mean (μ) = $52
Sample mean (X) = $50
Sample standard deviation (s) = $11
Sample size (n) = 36
Plugging in the values:
t = ($50 - $52) / ($11 / √(36))
t = -2 / ($11 / 6)
t ≈ -1.0909
Step 5: Determine the critical value and make a decision:
Since the significance level is 0.10 and the test is one-tailed to the left, we need to find the critical t-value at a 0.10 significance level with degrees of freedom equal to (n - 1) = (36 - 1) = 35.
so, the critical t-value is -1.3104.
Since the calculated t-statistic (-1.0909) does not fall in the critical region (t < -1.3104), we do not have enough evidence to reject the null hypothesis.
Step 6: State the conclusion:
Based on the data and the hypothesis test, at the 0.10 significance level, there is insufficient evidence to support the claim that the mean amount spent by a customer has significantly decreased since last year.
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Translate each equation into slope-intercept form. Then, state the slope and y-intercept . 4y=2x+20
Answer:
The slope-intercept form of the equation: y = 0.5x + 5
The slope: m = 0.5
The y-intercept: b = 5
Step-by-step explanation:
Slope-intercept form is y = mx + b, where m is the slope and b is y-intecept
4y = 2x + 20 {divide both sides by 4}
y = 0.5x + 5 ⇒ m = 0.5 and b = 5