Determine the surface area and volume. Note: The base is a square.

1a.) The amount that the eldest son received would be =GHç 1,360

b .) The amount received by the daughter would be =G Hç 2176

c.) The difference between the amount the two sons received would be =GHç1,904

For 1a.)

The amount that the land is worth= $8,600

The amount received for various purposes= $1,800

The remaining amount shared to the sons= 8,600-1800= $6,800

The percentage amount received by the eldest son= 20% of 6800

That is;

= 20/100×6800/1

= 136000/100

= $1,360

The remaining amount= 6800-1360= $5,440

For 1b.)

The ratio that the remaining amount was shared between the other son and the daughter = 3 : 2 respectively.

The total ratio= 3+2=5

For daughter= 2/5× 5440

= 10880/5 = 2176

The other son= 5440-2176 = 3264

For 1c.)

The difference between the amount the two sons received would be =3264-1,360 = GHç1,904.

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a) The summation (Ex) of the given data set, we add up all the values

Ex = 77

b) n = 5

c) x = 15.4

a) To compute the summation (Ex) of the given data set, we add up all the values:

19 + 10 + 15 + 17 + 16 = 77

b) The sample size (n) is the total number of data points in the set. In this case, there are 5 data points, so:

n = 5

c) To calculate the sample mean (x), we divide the summation (Ex) by the sample size (n):

x = Ex / n

x = 77 / 5

x = 15.4

Therefore, the answers are:

a) Ex = 77

b) n = 5

c) x = 15.4

The summation is 77, the sample size is 5, and the sample mean is 15.4.

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The number of membership passes that will contribute to deferred revenue in 2016 is: 1,000 (total passes sold) x 20% (passes utilized in 2017) = 200 passes.

To calculate the deferred revenue in 2016 for LuluYoga, we need to consider the membership passes that were sold but not yet utilized.

In 2016, LuluYoga sold 1,000 membership passes for $2,000 each. We know that 80% of the classes purchased were used in 2016, which means 20% of the classes will be utilized in 2017.

Therefore, the number of membership passes that will contribute to deferred revenue in 2016 is:

1,000 (total passes sold) x 20% (passes utilized in 2017) = 200 passes

The revenue generated from these 200 passes will be realized in 2017 when the classes are utilized. Therefore, the revenue from these passes should be deferred to the following year.

To calculate the deferred revenue, we need to multiply the number of passes by the price per pass:

200 (passes) x $2,000 (price per pass) = $400,000

Hence, the deferred revenue in 2016 for LuluYoga is $400,000.

Deferred revenue represents the amount of revenue that has been received but has not yet been earned. In this case, LuluYoga has received payment for the membership passes, but the revenue associated with the unused classes will be recognized in the subsequent year when the classes are actually utilized.

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Answer:c

Step-by-step explanation:

Answer:

A) The y-intercept(s) is/are 2

Step-by-step explanation:

Y-intercepts are where the graph of a function cross over the y-axis. In this case, the line passes through y=2, which is the y-intercept.

Answer:

Step-by-step explanation:

We must simplify and rearrange the variables to divide x in order to determine the comparable inequality to the supplied inequality, -4(x + 7) 3(x - 2).

Below are the steps to solve the problem:

-4(x + 7) < 3(x - 2)

Expanding the equation:

-4x-28<3x-6

Gather the variable term on one side and constants on the other:

Adding -4x and 28 on both sides:

-4x + 4x - 28 + 28 < 3x + 4x - 6 + 28

=>0 < 7x + 22

To make the coefficient of x positive, we divide the entire inequality by 7:

0/7 < (7x + 22)/7

=> 0 < x + 22/7

Answer:

Henrich has to pay $154,672.50 (32%) in taxes on his $484,500 income

Explanation:

The question is: What is Henrich's income tax liability in each of the following alternative scenarios?

Here are the scenarios:

1. All of his income is salary from his employer. Assume his modified AGI is $520,000.

2. His $484,500 of taxable income includes $2,000 of long-term capital gain that is taxed at preferential rates. Assume his modified AGI is $520,000.

3. His $484,500 of taxable income includes $48,000 of long-term capital gain that is taxed at preferential rates. Assume his modified AGI is $520,000.

4. Henrich has $197,250 of taxable income, which includes $50,900 of long-term capital gain that is taxed at preferential rates. Assume his modified AGI is $214,500.

Here are the answers:

1. Henrich's income tax liability is $133,476.25.

2. Henrich's income tax liability is $133,476.25 and his net investment income tax liability is $0.

3. Henrich's income tax liability is $133,476.25 and his net investment income tax liability is $1,344.

4. Henrich's income tax liability is $54,175.00 and his net investment income tax liability is $745.00.

1. Henrich has a total income of $484,500.

2. He has to pay $133,476.25 in income tax.

3. He also has to pay $21,196.25 in net investment income tax.

4. If he has $2,000 or less in long-term capital gains, he doesn't have to pay any net investment income tax.

5. If he has more than $2,000 in long-term capital gains, he has to pay a net investment income tax of 3.8% on the amount over $2,000.

Tax on his investment income:

1. Henrich's income tax liability is $133,476.25.

2. His net investment income tax liability is $21,196.25.

3. His net investment income tax liability is $0.

4. His net investment income tax liability is $1,344.00.

5. His net investment income tax liability is $745.00.

1. Henrich has to pay $133,476.25 in taxes.

2. If he has some long-term capital gains, he only has to pay taxes on $2,000 of it.

3. If he has more than $48,000 in long-term capital gains, he has to pay taxes on the amount over $48,000.

4. If he has less than $197,250 in taxable income, he only has to pay taxes on $50,900 of it.

1. Henrich's income tax liability is $133,476.25.

2. If he has long-term capital gains, his net investment income tax liability is $0 if it is less than $2,000.

3. If he has long-term capital gains, his net investment income tax liability is $1,344 if it is more than $48,000.

4. Henrich's income tax liability is $54,175 if his taxable income is less than $197,250.

**Scenario 1: All of his income is salary from his employer. Assume his modified AGI is $520,000.**

Henrich's income tax liability is $133,476.25. This is calculated by first finding his tax bracket, which is the 24% bracket. Then, he multiplies his taxable income by the tax rate for that bracket, which is 24%. This gives him an income tax liability of $112,280.00. He also has a net investment income tax liability of $21,196.25. This is calculated by first finding his net investment income, which is $40,000. Then, he multiplies his net investment income by the net investment income tax rate, which is 3.8%. This gives him a net investment income tax liability of $1,520.00.

**Scenario 2: His $484,500 of taxable income includes $2,000 of long-term capital gain that is taxed at preferential rates. Assume his modified AGI is $520,000.**

Henrich's income tax liability is $133,476.25. This is calculated in the same way as in Scenario 1. His net investment income tax liability is $0. This is because his net investment income is only $2,000, which is below the threshold for the net investment income tax.

**Scenario 3: His $484,500 of taxable income includes $48,000 of long-term capital gain that is taxed at preferential rates. Assume his modified AGI is $520,000.**

Henrich's income tax liability is $133,476.25. This is calculated in the same way as in Scenario 1. His net investment income tax liability is $1,344.00. This is calculated by first finding his net investment income, which is $48,000. Then, he subtracts the preferential rate amount, which is $2,000. This gives him a net investment income of $46,000. Then, he multiplies his net investment income by the net investment income tax rate, which is 3.8%. This gives him a net investment income tax liability of $1,728.00.

**Scenario 4: Henrich has $197,250 of taxable income, which includes $50,900 of long-term capital gain that is taxed at preferential rates. Assume his modified AGI is $214,500.**

Henrich's income tax liability is $54,175.00. This is calculated by first finding his tax bracket, which is the 22% bracket. Then, he multiplies his taxable income by the tax rate for that bracket, which is 22%. This gives him an income tax liability of $43,395.00. He also has a net investment income tax liability of $745.00. This is calculated in the same way as in Scenario 3.

chatgpt

bardAI

On Day 10, Kelly will have a total of 20 pennies in her penny jar.

To determine how many pennies Kelly will have on Day 10, we need to consider the progression of pennies added to her jar each day.

On Day 1, Kelly starts with 2 pennies. On Day 2, she adds 2 more pennies, resulting in a total of 2 + 2 = 4 pennies. This pattern continues, with 2 more pennies being added each day.

To find the number of pennies on Day 10, we can observe that the number of pennies on any given day can be calculated using the formula:

Number of pennies = Initial number of pennies + (Number of days - 1) * Number of pennies added per day

Using the provided information, we can substitute the values into the formula:

Number of pennies on Day 10 = 2 + (10 - 1) * 2

= 2 + 9 * 2

= 2 + 18

= 20

Therefore, on Day 10, Kelly will have a total of 20 pennies in her penny jar.

To summarize, starting with 2 pennies and adding 2 more pennies each day, Kelly will have a total of 20 pennies in her penny jar on Day 10.

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Answer:

D

Step-by-step explanation:

the area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

here b = 16 and h = 8 , then

A = [tex]\frac{1}{2}[/tex] × 16 × 8 = 8 × 8 = 64 ft²

Step-by-step explanation:

b. To determine the coordinates of the points on the graph, we need to consider the information given.

At the beginning of the second lap, one minute and three seconds had passed. Since each lap is 4.7 kilometers long, we can calculate the distance traveled at the beginning of the lap using the formula:

Distance = (Number of laps - 1) × Length of each lap

For the beginning of the second lap:

Distance = (2 - 1) × 4.7 km = 4.7 km

At the beginning of the third lap, one minute and three seconds had passed. Therefore, the distance traveled at the beginning of the third lap is:

Distance = (3 - 1) × 4.7 km = 9.4 km

The coordinates of the points on the graph would be:

Point A: (4.7 km, 4.7 km)

Point B: (9.4 km, 9.4 km)

On the graph, the x-axis would represent the distance traveled at the beginning of the lap, and the y-axis would represent the distance traveled at the end of the lap.

c. To find the equation of the line between the two points, we can use the slope-intercept form of a linear equation:

y = mx + b

where m is the slope and b is the y-intercept.

Using the coordinates of the two points (4.7 km, 4.7 km) and (9.4 km, 9.4 km), we can calculate the slope:

m = (y2 - y1) / (x2 - x1)

= (9.4 km - 4.7 km) / (9.4 km - 4.7 km)

= 4.7 km / 4.7 km

= 1

The slope of the line is 1.

Since the line passes through the origin (0, 0), the y-intercept (b) is 0.

Therefore, the equation of the line is:

y = 1x + 0

y = x

This line represents a one-to-one relationship between the distance traveled at the beginning of the lap and the distance traveled at the end of the lap.

d. To estimate how long it would take Fernando to finish the entire race if he continues to average the same speed, we need to find the time it takes for one lap.

In the given scenario, Brandon timed Fernando's lap for one minute and three seconds. Since there are 3 laps in total, we can divide the total time by the number of laps to find the average time per lap:

Average time per lap = Total time / Number of laps

= 1 minute and 3 seconds / 3

= 21 seconds

Since each lap is 4.7 kilometers long, we can calculate the speed:

Speed = Distance / Time

= 4.7 km / (1 minute + 21 seconds)

To estimate the time it would take Fernando to finish the entire race, we divide the total race distance by the speed:

Total race time = Total race distance / Speed

= 500 km / (4.7 km / (1 minute + 21 seconds))

To calculate the time, we need to convert 1 minute and 21 seconds to a decimal form:

1 minute + 21 seconds = 1 minute + (21 seconds / 60 seconds)

= 1 minute + 0.35 minutes

= 1.35 minutes

Substituting the values:

Total race time = 500 km / (4.7 km / 1.35 minutes)

= 500 km × (

1.35 minutes / 4.7 km)

= 500 km × 0.28723...

≈ 143.615 minutes

Therefore, it would take approximately 143.615 minutes for Fernando to finish the entire race if he continues to average the same speed.

According to slope intersept form : y = mx+b

m is slope and b is y intersept

so y = -6x+5

slope(m) = -6

y intersept = 5

HOPE IT HELPS

PLEASE GIVE BRAINLIEST

The probability of drawing blue, red, and white balls consecutively is 120/3375 with replacement and 120/2730 without replacement.

To calculate the probability of drawing three balls from a box containing six white balls, five red balls, and four blue balls, we need to consider two scenarios: with replacement and without replacement.

(i) With replacement:

When each ball is replaced after it is drawn, the total number of balls remains the same for each draw. Therefore, the probability of drawing a specific color on each draw remains constant.

The probability of drawing a blue ball on each draw is 4/15, the probability of drawing a red ball is 5/15, and the probability of drawing a white ball is 6/15 (assuming all colors are equally likely to be drawn).

To find the probability of drawing a blue, red, and white ball consecutively, we multiply the probabilities together since the events are independent:

P(Blue, Red, White) = (4/15) * (5/15) * (6/15) = 120/3375

(ii) Without replacement:

When the balls are not replaced after being drawn, the total number of balls decreases for each subsequent draw. This affects the probability of each color being drawn on subsequent draws.

For the first draw, the probability of drawing a blue ball is 4/15, a red ball is 5/15, and a white ball is 6/15.

For the second draw, the probability of drawing a blue ball is 3/14, a red ball is 5/14 (as one blue ball is already drawn), and a white ball is 6/14.

For the third draw, the probability of drawing a blue ball is 2/13, a red ball is 4/13 (as two blue balls and one red ball are already drawn), and a white ball is 6/13.

To find the probability of drawing a blue, red, and white ball consecutively without replacement, we multiply the probabilities together:

P(Blue, Red, White) = (4/15) * (5/14) * (6/13) = 120/2730

Therefore, the probability of drawing blue, red, and white balls consecutively is 120/3375 with replacement and 120/2730 without replacement.

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Answer:

[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] + 2x - 4

Step-by-step explanation:

(8x + 2[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex]) - (4 + [tex]x^{3}[/tex] + 6x)

= 8x + 2[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] - 4 - [tex]x^{3}[/tex] - 6x

= 2x + [tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] - 4

= [tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] + 2x - 4

Point B: Electric field strength due to sphere X = 2073.6 NC⁻¹ and Electric field strength due to sphere Y = -2073.6 NC⁻¹.

data: Spheres X and Y are 4.0 m apart. The charge on sphere

X = + 72 mC = 72 × 10⁻³ C.

The charge on sphere

Y = -72 mC = -72 × 10⁻³ C.

The constant of proportionality = 9 × 10⁹ Nm²/C².

The formula to calculate the electric field strength due to a point charge is

E = k q / r²

where E is the electric field strength, k is the Coulomb's constant (= 9 × 10⁹ Nm²/C²), q is the magnitude of the charge, and r is the distance from the charge.The electric field due to sphere X at point A is

EaX = [tex]k q / r²where r = 4.0 m, q = + 72 × 10⁻³ CSo, EaX = 9 × 10⁹ × 72 × 10⁻³ / (4.0)²EaX = 9 × 9 × 2 × 2 × 2 × 2 / 10[/tex]EaX = 2592 / 10EaX = 259.2

NC⁻¹The electric field due to sphere Y at point A is

[tex]EaY = k q / r²where r = 4.0 m, q = -72 × 10⁻³ CSo, EaY = 9 × 10⁹ × 72 × 10⁻³ / (4.0)²EaY = -9 × 9 × 2 × 2 × 2 × 2 / 10EaY = -2592 / 10EaY = -259.2[/tex]

NC⁻¹The electric field due to sphere X at point B is

[tex]EbX = k q / r²where r = 4.0 m, q = + 72 × 10⁻³ C + 72 × 10⁻³ C = 144 × 10⁻³ C.So, EbX = 9 × 10⁹ × 144 × 10⁻³ / (4.0)²EbX = 9 × 9 × 4 × 4 × 4 × 4 / 10EbX = 20736 / 10EbX = 2073.6[/tex]

NC⁻¹The electric field due to sphere Y at point B is

[tex]EbY = k q / r²where r = 4.0 m, q = -72 × 10⁻³ C - 72 × 10⁻³ C = -144 × 10⁻³ C. So, EbY = 9 × 10⁹ × -144 × 10⁻³ / (4.0)²EbY = -9 × 9 × 4 × 4 × 4 × 4 / 10EbY = -20736 / 10EbY = -2073.6 NC⁻¹[/tex]

Therefore, the electric field strength at points A and B due to each sphere's presence are: Point A: Electric field strength due to sphere X = 259.2 NC⁻¹ and Electric field strength due to sphere Y = -259.2 NC⁻¹.

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The correct statement is D. Hannah's unit rate is 1 fewer word per minute than Becky's unit rate.

To compare the unit rates, we need to determine the rate at which each person types words per minute.

For Hannah, the equation y = 11x represents her typing speed, where y is the number of words and x is the number of minutes. This means that Hannah types 11 words per minute (11 words/minute).

Looking at Becky's graph, we can determine her unit rate by calculating the change in the number of words divided by the change in time.

The change in words is 48 - 2 = 46, and the change in time is 3 - 2 = 1. So, Becky's unit rate is 46 words per minute (46 words/minute).

Comparing the unit rates:

Hannah's unit rate: 11 words/minute

Becky's unit rate: 46 words/minute

Therefore, Hannah's unit rate is 35 words per minute less than Becky's unit rate.

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Answer:

A. 6

Step-by-step explanation:

You have 3 molecules of H2SO4, each molecule has two atoms of H and you have 3 molecules, so 3*2=6 atoms of H

This flexibility of a money market account makes it an ideal option for people who need to save money without risking their inheritance.

After inheriting $25,000 from a distant uncle, you would like to save it for ten years before doing anything with it. Since you want to save the money, there are several options for keeping it safe and earning interest, including a savings account, a certificate of deposit (CD), and a money market account.

Money market accounts, in my opinion, would be the best place to keep the inheritance. The money market account is a low-risk account with high-interest rates, making it an attractive option for someone who wants to save their money. As a result, it would be reasonable to place the inheritance into a money market account that pays a daily compounded rate of 3%.There are several reasons for choosing this option.

Firstly, the daily compounded interest will generate a higher return over the ten-year period than the simple interest or monthly compounded interest offered by other accounts. Second, the account is FDIC-insured, which means that the account holder is guaranteed to receive their money in the event of a bank failure.

Furthermore, the money market account provides easy access to the account holder's money while still earning interest. Most money market accounts have a limit on the number of withdrawals a person can make per month. Still, the account holder can easily transfer funds into a checking account or withdraw money from an ATM if needed.

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The midpoint of the line segment joining the pair of points (8, -8) and (-5, -1) is (1.5, -4.5).

To find the midpoint, we need to take the average of the x-coordinates and the average of the y-coordinates of the two given points.

For the x-coordinate: (8 + (-5))/2 = 3/2 = 1.5

For the y-coordinate: (-8 + (-1))/2 = -9/2 = -4.5

Thus, the midpoint of the line segment is (1.5, -4.5).

In more detail, the midpoint formula is derived by averaging the x-coordinates and y-coordinates separately. For a line segment with endpoints (x1, y1) and (x2, y2), the midpoint (xm, ym) is given by:

xm = (x1 + x2)/2

ym = (y1 + y2)/2

In this case, the x-coordinates are 8 and -5, and their average is (8 + (-5))/2 = 1.5. The y-coordinates are -8 and -1, and their average is (-8 + (-1))/2 = -9/2 = -4.5.  

Therefore, the midpoint of the line segment joining the two given points is (1.5, -4.5).

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To solve these problems, we can use Coulomb's Law, which states that the magnitude of the electric field produced by a charged particle is directly proportional to the charge and inversely proportional to the square of the distance from the particle.

a) Without finding the charge of the particle, we can use the inverse square relationship. If the electric field magnitude is 2.0 N/C at a distance of 50 cm, then at half the distance (25 cm), the electric field would be four times stronger. Therefore, the electric field at 25 cm would be 4 * 2.0 N/C = 8.0 N/C.

b) Doubling the charge would result in doubling the electric field magnitude. So, if the electric field at a distance of 50 cm was initially 2.0 N/C, it would become 4.0 N/C after doubling the charge.

c) To determine the magnitude of the particle's charge, we need to use the equation for the electric field:

E = k * (|q| / r^2)

where E is the electric field magnitude, k is the electrostatic constant, |q| is the magnitude of the charge, and r is the distance from the particle.

Using the known values of E = 2.0 N/C and r = 50 cm (or 0.5 m), we can rearrange the equation to solve for |q|:

|q| = E * r^2 / k

Substituting the values and the known value of k, we can calculate the magnitude of the charge.

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The length of the arc in terms of π and the actual length is as follows;

8.17π m²

25.68 m²

Let's find the length of the arc of the circle as follows:

Therefore,

length of an arc = ∅ / 360 × 2πr

where

Hence,

∅ = 180 - 88 = 92 degrees

r = 16 m

length of an arc MA = 92 / 360 × 2 × π × 16

length of an arc MA = 2944π / 360

length of an arc MA = 8.17π

Therefore,

length of an arc MA = 25.68 m²

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The number of votes needed in an election can vary depending on various factors such as the type of election, voting rules, and specific requirements.

Without additional context or information about the specific election, it is challenging to provide an exact number of votes needed.The number of votes needed in an election is typically determined by factors such as the majority threshold, minimum vote requirement, or any specific criteria outlined in the election rules.

For example, in some elections, a candidate may need a simple majority (more than half) of the votes cast to win, while in others, a candidate may need a specific number or percentage of votes to secure victory.To determine the number of votes needed, it is essential to refer to the specific guidelines or rules established for that particular election.

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Answer:

(f + g)(1) = 5

Step-by-step explanation:

(f + g) means we are going to add f(x) and g(x). But also, the (1) part means we are going to let x be equal to 1. We're going to fill in 1 in place of x. You can do this in either order.

Generally speaking its "easier" to fill in the 1 for x first and then do the adding part.

f(x) = x + 6

f(1) = 1 + 6 = 7

and,

g(x) = x - 3

g(1) = 1 - 3 = -2

add the 7 and -2 together:

7 + - 2

= 5

It works out the same if you add first:

f(x) + g(x)

= x + 6 + x - 3

= 2x + 3

then put the 1 in:

= 2×1 + 3

= 2 + 3

= 5

Hope this helps!

The inequality representing the situation is "y ≥ 0.75x," where y is the total number of hours Lionel spends practicing and x is the number of days he practices.

To represent the situation where Lionel practices for a minimum of 45 minutes on the days he practices, we can use the variables x and y, where x represents the number of days Lionel practices and y represents the total number of hours he spends practicing.

We know that Lionel practices for a minimum of 45 minutes on each day. Since there are 60 minutes in an hour, this is equivalent to 0.75 hours. Therefore, for each day Lionel practices, he spends at least 0.75 hours.

To find the total number of hours Lionel spends practicing (y), we can multiply the number of days he practices (x) by the minimum number of hours he spends on each day (0.75). This gives us the equation:

y ≥ 0.75x

This inequality states that the total number of hours Lionel spends practicing (y) must be greater than or equal to 0.75 times the number of days he practices (x). It ensures that Lionel practices for a minimum of 45 minutes (0.75 hours) on each day he practices.

By using this inequality, we can track Lionel's practice time and ensure that he meets the minimum requirement of 45 minutes per day.

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The estimated standard deviation of the bear weights, based on the given graph and using the 69-95-99.7% rule, is approximately 63.

The 69-95-99.7% (empirical) rule, also known as the 3-sigma rule, is a rule of thumb that applies to data that follows a normal distribution. According to this rule:

- Approximately 68% of the data falls within one standard deviation of the mean.

- Approximately 95% of the data falls within two standard deviations of the mean.

- Approximately 99.7% of the data falls within three standard deviations of the mean.

In the given graph, if we assume the bear weights follow a normal distribution, we can estimate the standard deviation using the 69-95-99.7% rule.

Based on the graph, we know that the midpoint of the distribution (mean) is 200. Assuming the graph is symmetric, we can estimate one standard deviation as half the distance between the mean (200) and either end (74 or 326).

To calculate this, we subtract the mean from one of the endpoints and divide by 2:

Standard Deviation ≈ (326 - 200) / 2 ≈ 126 / 2 ≈ 63

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The reason why Figure A is congruent to Figure C is that they undergo the same sequence of transformations: a translation followed by a reflection.

The statement "Figure A is translated 3 units right and 2 units up. The translated figure is labeled Figure B. Figure B is reflected over the x-axis. The reflected figure is labeled Figure C" describes a sequence of transformations applied to Figure A to obtain Figure C.

When Figure A is translated 3 units right and 2 units up, it undergoes a rigid transformation known as a translation. This transformation preserves the shape and size of the figure. The translated figure, Figure B, will have the same dimensions and orientation as Figure A but will be shifted to the right and up.

When Figure B is reflected over the x-axis, it undergoes a reflection. This transformation flips the figure vertically, changing the sign of the y-coordinates of its vertices while keeping the x-coordinates the same. The reflected figure, Figure C, will have the same shape and size as Figure B, but it will be oriented in the opposite direction.

Since translations and reflections are both rigid transformations, they preserve congruence. Therefore, Figure A and Figure C are congruent because they undergo the same sequence of transformations (translation followed by reflection) from Figure A.

In conclusion, Figures A and C go through the same set of transformations, a translation and a reflection, which explains why they are congruent.

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