First solution
(x-3)=11
x=11+3
x=14Second solution
-(x-3)-11
multiply by -1 both sides
x-3=-11
x=-11+3
x=-8therefore
answer is
-8,14
You are about to enter an elevator with a weight capacity of 500 pounds. There are three people already in the elevator. The weights of the passengers are 107 pounds, 172 pounds and 129 pounds. Assuming that you weigh 136 pounds, is it safe for you to enter the elevator?
Given
capacity of 500 pounds.
weights of the passengers are 107 pounds, 172 pounds and 129 pounds.
you weigh 136 pounds
Find
is it safe for you to enter the elevator?
Explanation
as total pounds in the elevator = 107 + 172 + 129 = 408 pounds
total pounds included my weight = 408 + 136 = 544 pounds
capacity = 500 pounds
so , extra pounds = 544 - 500 = 44 pounds
so , no it is not safe for you to enter the elevator.
Final Answer
Therefore , No the weigh capacity would be exceeded by 44 pounds
it takes 126 cubes that have edge lengths of 1/3feet to completely fill this plastic bin what is the area of the base of bin
Answer: 1) Each of the 126 cubes has a volume = (1/3)3 = 1/3 × 1/3 × 1/3 = 1/27 cubic feet.
2) It takes 126 cubes to fill the bin, so the bin has a volume of 126 × 1/27 = 126/27 cubic feet. (Don't do this division yet - leave it as an improper fraction)
3) The volume of the bin is also given by the formula Volume = Area of Base × Height. Plus we know the volume is 126/27 cubic feet and the height is 2 1/3 = 7/3 of a foot, so:
Step-by-step explanation: Volume = Area of Base × Height
126/27 = Area of Base × 7/3
126/27 × 3/7 = Area of Base
The area of the base of bin is 2 feet².
What is Volume of Cube?The formula of volume of the cube is given by: Volume = a³, where a is the length of its sides or edges.
Given:
Edge = 1/3 feet
Volume of 1 cube= l³= (1/3)³ = 1/27
Totals cubes= 126
So, Volume of 126 cube= 126 x 1/27 = 126/ 27
Then, Volume of Plastic Bin= Area of base x height
126 / 27 = Area of base x 7/3
Area of base = 126 /27 x 3 /7
Area of base = 2 ft²
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6.4 The ratio of length and breadth of a rectagular field is 4:3. If perimeter of the field is 700m, find (i) length and breadth of the field (ii) area of the field.
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Does the graph represent a function? 4 5 6 7 -3+ no O yes
To prove:
The given graph is a function.
The given graph is a function if and only if no x value has more than one value of y, or we can say that a graph is a function iff no vertical line intersects the graph in more than one point.
Thus, by the given graph it is clear that for x = 7 their are two values for y that is y = -6 , -7
So, the given graph is not a function
Use the formula h = 16t2, where t is time in seconds and h is the distance in feet traveled by a free-falling body or object to solve the following problem.
A diver dives from a cliff that has a height of 125 feet. Determine the time of the dive.
The dive lasted approximately
seconds.
(Type an integer or decimal rounded to the nearest tenth as needed.)
If a diver dives from a cliff that has a height of 125 feet, The dive lasted approximately 2.80 seconds
A diver dives from a cliff that has a height of 125 feet
The formula h = 16t², where t is time in seconds and h is the distance in feet traveled by a free-falling body or object
125 = 16t²
125/16 = t²
t = √(125/16)
t = √125/√16
t = 5√5 /4
t = 1.25 x 2.23
t = 2.795
t = 2.80
Therefore, if a diver dives from a cliff that has a height of 125 feet, The dive lasted approximately 2.80 seconds
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2. A new car dealership invites 500 people to a promotional event. Only 330 people attend the event. What percentage of the people attend the event?
since
[tex]550X=330[/tex]then
[tex]X=\frac{330}{500}=0.66[/tex]then it is the 100x0.66= 66%
how many cubic blocks with a side length of 1/6 cm are needed to fill the volume of this prism?The answer choices are 4,8,9,32.
Given the figure, we can deduce the following information:
Height=1/2 cm
Length=1/2 cm
Width= 1/6 cm
To determine the number of cubic blocks with a side length of 1/6 cm needed to fill the volume of the given prism, we first note that a cube has equal sides. So, the dimensions of the cube must be:
Height= 1/6 cm
Length=1/6 cm
Width=1/6 cm
Next, we get the volume of the cube by using the formula:
[tex]\begin{gathered} Volume\text{ of the cube}=(Height)(Length)(Width) \\ =(\frac{1}{6})(\frac{1}{6})(\frac{1}{6}) \\ Simplify \\ =\frac{1}{216}\text{ }cm^3\text{ } \end{gathered}[/tex]Then, we get the volume of the given prism using the same formula:
[tex]\begin{gathered} Volume\text{ of the given prism}=(He\imaginaryI ght)(Length)(W\imaginaryI dth) \\ =(\frac{1}{2})(\frac{1}{2})(\frac{1}{6}) \\ =\frac{1}{24}\text{ }cm^3\text{ } \end{gathered}[/tex]Now, we find the number cubic blocks by using the formula:
[tex]\begin{gathered} Number\text{ }of\text{ cubic blocks}=\frac{Volume\text{ of the given prism}}{Volume\text{ of the cube}} \\ =\frac{\frac{1}{24}}{\frac{1}{216}} \\ Simplify \\ =9 \end{gathered}[/tex]Therefore, the answer is 9.
22. A 250W carrier is to be modulated at an 85% modulation level. What is the total transmitted power? a. 340.3 W b. 25.32 dB c. 0.340 kW d. 55.32 dBm e. All of the above.
The total transmitted power is a. 340.3 W.
The transmitted and carrier power is related with modulation through the formula -
[tex] P_{t} = P_{c}(1 + \frac{ {m}^{2} }{2} )[/tex]
where [tex]P_{t}[/tex] is transmitted power, [tex]P_{t}[/tex] is carrier power and m is modulation.
Keep the values in formula to find the value of total transmitted power.
[tex]P_{t}[/tex] = 250 (1 + 85%²/2)
Taking square of percentage
[tex]P_{t}[/tex] = 250 (1 + 0.7225/2)
Performing division in the bracket
[tex]P_{t}[/tex] = 250 (1 + 0.36125)
Performing addition in the bracket
[tex]P_{t}[/tex] = 250×1.36125
Performing multiplication
[tex]P_{t}[/tex] = 340.3125
Thus, the total transmitted power when carrier power is 250 W and modulation is 85% is a. 340.3 W.
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find the value of x and y that make the quadrilateral
The quadrilateral have equal opposite sides, for example:
Then, (4x + 6) must be equal to (7x - 3), and (4y - 3) is equal to (3y + 1), therefore
[tex]4x+6=7x-3[/tex]We can solve that equation for x
[tex]\begin{gathered} 4x+6=7x-3 \\ \\ 3x=9 \\ \\ x=\frac{9}{3}=3 \end{gathered}[/tex]Hence, x = 3. Now let's solve the other equation
[tex]\begin{gathered} 4y-3=3y+1 \\ \\ y=4 \end{gathered}[/tex]Then the value of y is 4.
Final answers:
x = 3
y = 4
A trendline is given to depict the enrollment at a local college where x is the year and y represents enrollment. y=178.09x−353194Use the trendline to estimate the enrollment for 2009. Round to the nearest whole number.
To determine the enrollment in 2009 we need to plug x=2009 in the equation given to determine the value of y:
[tex]\begin{gathered} y=178.09(2009)-353194 \\ y=357782.81-353194 \\ y=4588.81 \end{gathered}[/tex]Therefore, in the year 2009, there were 4589 students enrolled
In a square box problem, the:Top number is the product of those left and rightBottom number is the sum of those at left and rightComplete this square box problem
Answer
Draw the box to complete the table.
Next,
To get the top, multiply both the left and the right = 11 x (-3)
= -33
To get the top, add both the left and the right = 11 + (-3) = 11 - 3 = 8
f(x)=4x+6 and g(x)=1/2 * f(x)
What is the function rule for function g?
g(x)=
Answer: 2x + 3
Step-by-step explanation:
f(x) = 4x + 6
g(x) = 1/2 * f(x)
Plug f(x) into the g(x) equation.
g(x) = 1/2 * (4x + 6)
Now simplify,
g(x) = 2x + 3
Which of the following equations represents a line that is perpendicular toy=-3x+6 and passes through the point, (3, 2)?A. y=-3x+1B. y=(1/3x)+3C. y=(-1/3x)+1OD. y=(1/3x)+1
Step 1
For perpendicular lines
[tex]m_1=-\frac{1}{m_2}[/tex][tex]m_1=-3[/tex][tex]\begin{gathered} -3=-\frac{1}{m_2} \\ m_2=-\frac{1}{-3} \\ m_2=\frac{1}{3} \end{gathered}[/tex]Step 2
[tex]\begin{gathered} Given\text{ points \lparen3,2\rparen} \\ y=mx+b---\text{ Standard equation of a line} \\ y=\frac{1}{3}x+b \end{gathered}[/tex][tex]2=\frac{1}{3}(3)+b[/tex]Find b, the y-intercept
[tex]\begin{gathered} 2=1+b \\ b=2-1=1 \end{gathered}[/tex]Answer; Option D
[tex]y=\frac{1}{3}x+1[/tex]Find the standard form for the equation of a circle ( x − h )^2 + ( y − k )^2 = r^2 with a diameter that has endpoints ( − 4 , − 8 ) and ( 6 , − 4 ) .h=k=r=
Answer:
[tex](x-1)^2+(y+6)^2=29[/tex][tex]\begin{gathered} h=1 \\ k=-6 \\ r=\sqrt{29} \end{gathered}[/tex]Explanation:
Given:
Endpoints of the diameter of a circle as (-4, -8) and (6, -4)
To find:
Equation of a circle in standard form
The equation of a circle in standard form is generally given as;
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h, k) is the coordinate of the center of the circle and r is the radius of the circle.
We'll go ahead and determine the coordinates of the midpoint of the endpoints of the diameter which will be the coordinates of the center of the circle as seen below wi;
[tex]h=\frac{x_1+x_2}{2}=\frac{-4+6}{2}=\frac{2}{2}=1[/tex][tex]k=\frac{-8+(-4)}{2}=\frac{-12}{2}=-6[/tex]So the center of the circle has coordinates (1, -6)
Since h = 1, and k = -6 and we have that x1 = -4 and y1 = -8, we can go ahead and solve for r as seen below;
[tex]\begin{gathered} (-4-1)^2+(-8-(-6))^2=r^2 \\ (-5)^2+(-2)^2=r^2 \\ 25+4=r^2 \\ 29=r^2 \\ \therefore r=\sqrt{29} \end{gathered}[/tex]We can now write the equation of the circle in standard form as;
[tex]\begin{gathered} (x-1)^2+(y-(-6))^2=29 \\ (x-1)^2+(y+6))^2=29 \end{gathered}[/tex]Melissa brought 6 apples for $1.20 .if each apple cost the same amount, how much would 20 apples cost
The cost of 20 apples is such that the ratio of apples to cost maintained or each apple costs the same amount is $4.
What are the ratio and proportion?The ratio is the division of the two numbers.
For example, a/b, where a will be the numerator and b will be the denominator.
As per the given,
Melissa brought 6 apples for $1.20.
The ratio of cost to apple ⇒
1.20/6
Now let's suppose the cost of 20 apples is x dollars.
The ratio of cost to apple ⇒
x/20
Since the cost of each apple is the same, therefore, both ratios must be the same.
x/20 = 1.20/6
x = 20(1.20/6)
x = 4
Hence "The cost of 20 apples is such that the ratio of apples to cost maintained or each apple costs the same amount is $4".
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Gravel is being dumped from a conveyor belt at a rate of 30 ft^3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 10 ft high?
The height of the pile increasing at the rate of 4.56 inches per minute when the pile is 10 ft high.
In given situation, the rate of change of height is equal to the rate of change of volume, divided by the base area.
First we find the base area.
base area = (π/4)d²
base area = (π/4)10²
base area = 25π ft²
base area ≈ 78.5 ft²
Then the rate of change of height would be,
(30 ft³/min)/(78.5 ft²)
≈ 0.38 ft/min
= 4.56 inches / minute
Therefore, the height of the pile increasing at the rate of 4.56 inches per minute when the pile is 10 ft high.
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For j(x) = 3x − 1, find j of the quantity x plus h end quantity minus j of x all over h period a 3 to the power of the quantity x minus 1 end quantity times the quantity 3 to the power of h end quantity all over h b 3 to the power of the quantity x minus 1 end quantity times the quantity 3 to the power of h minus 1 end quantity all over h c 3 to the power of the quantity x minus 1 end quantity times the quantity 3 to the power of h plus 1 end quantity all over h d the quantity x minus 1 end quantity times the quantity 3 to the power of h plus 1 end quantity all over h
The resulting value of the function [j(x+h)-j(x)/h] is 3⁽ˣ⁻¹⁾ ([tex]3^{h}[/tex]-1)/h
What is an exponential function?An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.
It is a relation of the form y = aˣ in mathematics, where x is the independent variable
Given the function expressed as;
j(x) = 3⁽ˣ⁻¹⁾
Required value of the function [j(x+h)-j(x)]/h
We have to determine the function j(x+h) and j(x)
j(x+h) = [tex]3^{(x+h) -1}[/tex]
Substitute the values,
[j(x+h)-j(x)]/h = [ [tex]3^{(x+h) -1}[/tex] - 3⁽ˣ⁻¹⁾ ]/h
⇒ [ [tex]3^{(x-1) +h}[/tex] - 3⁽ˣ⁻¹⁾ ]/h
⇒ [ [tex]3^{(x-1)} \times3^{h}[/tex] - 3⁽ˣ⁻¹⁾ ]/h
⇒ 3⁽ˣ⁻¹⁾ ([tex]3^{h}[/tex]-1)/h
Hence, the equivalent value of the function is 3⁽ˣ⁻¹⁾ ([tex]3^{h}[/tex]-1)/h
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Can someone answer this question for me please, I really need the help:
Answer:
4x² +28x +49
Step-by-step explanation:
You want a polynomial equivalent to the area of the figure shown.
PolynomialThe polynomial can represent the sum of three areas:
blue area + green area + yellow area
= 4x² +4(7x) +7²
= 4x² +28x +49
Evaluate (You can use which ever first step you
selected above)
[tex] \frac{3 \times 3 \times 2^{ - 4} \times 2^{0} }{(3 \times 2 ^{ - 3}) ^{2} } \\ = \frac{3^{ 1+1 } \times 2^{ - 4 + 0} }{3 \times 2 ^{ - 3 \times 2} } \\ = \frac{ {3}^{2} \times {2}^{ - 4} }{3 \times {2}^{ - 6} } \\ = 3^{2 - 1} \times 2^{ - 4 - ( - 6)} \\ = 3 \times {2}^{ - 4 + 6} \\ = 3 \times {2}^{2} \\ = 3 \times 4 \\ = 12[/tex]
I USED THE LAWS OF EXPONENTS.
IF YOU DO NOT KNOW THEM PLEASE TELL ME AS SOON AS POSSIBLE TO ARRANGE FOR YOU.
Given that f(x) = x sqaured - 10x + 16 and g(x) = x - 8, find f (x) · g(x) andexpress the result in standard form.
Given the functions
[tex]f(x)=x^2-10x+16[/tex][tex]g(x)=x-8[/tex]You have to calculate
[tex]f(x)\cdot g(x)[/tex][tex](x^2-10x+16)\cdot(x-8)[/tex]To solve this you have to apply the distributive property of multiplications, that is, you have to multiply each term of the first parenthesis with each term of the second parenthesis.
As follows:
[tex]\begin{gathered} (x^2-10x+16)\cdot(x-8) \\ (x^2\cdot x)+(x^2)\cdot(-8)+(-10x\cdot x)+(-10x)\cdot(-8)+(16\cdot x)+(16\cdot(-8)) \\ x^3-8x^2-10x^2+80x+16x-128 \end{gathered}[/tex]Now simplify the like terms
[tex]\begin{gathered} x^3+(-8x^2-10x^2)+(80x+16x)-128 \\ x^3-18x^2+96x-128 \end{gathered}[/tex]The result in standard form is
[tex]f(x)\cdot g(x)=x^3-18x^2+96x-128[/tex]14. Write a quadratic equation that cannot be factored.
Given:
Quadratic equation
To write a quadratic equation that cannot be factored or cannot be solved by factoring, we note first that factoring is the easiest method to solve a quadratic equation as long as the equation is easily factorable. If not, we'll need alternative approaches like employing the quadratic formula.
We also note that factoring cannot always be used to solve quadratic equations.
Below is an example of an equation that can be solve by factoring:
[tex]\begin{gathered} x^2-3x-10=0 \\ (x-5)(x+2)=0 \end{gathered}[/tex]Now, the equation that cannot be factored or cannot be solved by factoring is:
[tex]x^2+x-1=0[/tex]We cannot apply factoring to the above equation. Therefore, the answer is:
[tex]x^2+x-1=0[/tex]If P is the centroid of the triangle JKL, JK = 22, KN = 13, and OL = 18, find each measure.
Given
JK = 22
KN = 13
OL = 18
Procedure
Centroid formulation
KM = JK/2 = 22/2 = 11
KM = 11
NL = KN
NL = 13
KL = 2KN = 2(13) = 26
KL = 26
JO = OL = 18
JO = 18
JL = 2OL = 2(18)
JL = 36
what is seven times negative three / 7(-3)
-21
1) Let's calculate this product:
7 (-3) Multiply 7 by -3
-21
2) So, seven times negative three is equal to -21 that is the same as adding seven times the number -3. Remember different signs in a product turns to out to a negative result.
find the lateral area and surface area the lateral area of the prism is __in squared. the surface area of the prism is __ in squared
Answer
The lateral area of the prism is 900 in squared
The surface area of the prism is 960 in squared
Explanation
Given:
The first side of the triangular base, a = 12 in
The second side of the triangular base, b = 13 in
The height of the prism, h = 30 in
What to find:
The lateral area and surface area of the prism.
Step-by-step solution:
The first step is to find the third side, c of the triangular base using Pythagoras rule.
[tex]\begin{gathered} b^2=c^2+a^2 \\ \\ 13^2=c^2+12^2 \\ \\ c^2=13^2-12^2 \\ \\ c^2=169-144 \\ \\ c^2=25 \\ \\ c=\sqrt{25} \\ \\ c=5\text{ }in \end{gathered}[/tex]Now, the next step is to calculate the lateral area of the prism using the formula below.
[tex]\begin{gathered} L.A=ha+hb+hc \\ \\ L.A=30\times12+30\times13+30\times5 \\ \\ L.A=360+390+150 \\ \\ L.A=900\text{ }in^2 \end{gathered}[/tex]The lateral area of the prism is 900 in squared
The final step is to calculate the surface area of the prism using the formula below.
[tex]S.A=Lateral\text{ }Area+Base\text{ }Area[/tex]The base area is
[tex]=2(\frac{1}{2}cb)=2(\frac{1}{2}\times5\times12)=2(\frac{60}{2})=60\text{ }in^2[/tex]Therefore, the Surface Area = (900 + 60) = 960 in squared
i just want the answers, i dont want an explanation.
Given:
Required: Evaluation
Explanation:
Use BODMAS rule to evaluate all
71.
[tex]\begin{gathered} 16+4(-3)-7=16-12-7 \\ =-3 \end{gathered}[/tex]72.
[tex]\begin{gathered} (-24)\div(4)+16(2)=-6+32 \\ =26 \end{gathered}[/tex]73.
[tex]\begin{gathered} -5-8+6(-3)=-13-18 \\ =-31 \end{gathered}[/tex]74.
[tex]\begin{gathered} 30-6\div3+4=30-2+4 \\ =32 \end{gathered}[/tex]75.
[tex]\begin{gathered} 21-45+8\div2=21-45+4 \\ =25-45=-20 \end{gathered}[/tex]Final Answer:
71 - E
72 - AE
73 - A
74 - BE
75 - B
Which of the following statements best describe the branches of the hyperbola?Select one:a.It is not possible to determine how the branches of the hyperbola open.b.The branches of the hyperbola are positioned at a 30⁰ angle.c.The branches of the hyperbola open up and down.d.The branches of the hyperbola open side to side.
Answer:
Explanation:
The first step is to plot the graph of the parabola. It is shown below
Looking at the graph, the branches open up and down. Thus, the correct option is
c. The branches of the hyperbola open up and down.
As part of a charity drive, 50 fourth grade students each donated an equal number of dimes and 30 third grade students each donated the same number of nickels. Let d represent the number of dimes and n represent the number of nickels. Determine which of the expressions shows the total amount (in cents) donated by the 3rd and 4th grade students. A.) 10(50d)+5(30n)B.) 80cC.) 10d+5nD.) 50d+30n
IXL Transversals of parallel lines: prove angle relationships 6QF for geometry, please help
4) [tex]m\angle XWY=m\angle HGY[/tex] (definition of congruent angles)
5) [tex]\angle HGY \cong \angle GTU[/tex] (corresponding angles theorem)
6) [tex]m\angle HGY=m\angle GTU[/tex] (definition of congruent angles)
7) [tex]\angle GTU[/tex] and [tex]\angle UTR[/tex] are supplementary (linear pair)
8) [tex]m\angle GTU+m\angle UTR=180^{\circ}[/tex] (definition of supplementary angles)
9) [tex]m\angle HGY+m\angle UTR=180^{\circ}[/tex] (substitution)
10) [tex]m\angle RTU+m\angle XWY=180^{\circ}[/tex] (substitution)
A manufacturer of ski clothing makes ski pants and ski jackets. The profit on a pair of ski pants is $3 and on a jacket is $2. Both pants and jackets require the work of sewing operators and cutters. There are 60 minutes of sewing operator time and 48 minutes of cutter time available. It takes 8 minutes to sew one pair of ski pants and 4 minutes to sew one jacket. Cutters take 4 minutes on pants and 8 minutes on a jacket. The manufacturer wants to make a minimum of 4 ski pants and 2 ski jackets, Let x represent the number of ski pants. Let y represent the number of ski jackets.
For the sewing operator:
[tex]8x\text{ + 4y }\leq\text{ 60}[/tex]For cutter:
[tex]4x\text{ + 8y }\leq48[/tex]The two above equation is solve to obtain the graph
The solution of the graph is where the two lines meet
The coordinate is (10, 4), at the this point the maximum profit is made
So 10 ski pants and 4 ski jackets is made to get maximum profit
The profit made is given by
P = 3x + 2y
x =10 , y = 4
P = 3(10) + 2(4)
P = 30 + 8 = $38
Find a_10 5, 12, 19, 26, 33...
Given,
The progression is 5, 12, 19, 26, 33...
The first term of the series is, a = 5.
The common difference of the series is,
d = 12 - 5 = 7
The 10th term of the series is,
[tex]\begin{gathered} a_{10}=a+(10-1)\times d \\ =5+9\times7 \\ =5+63 \\ =68 \end{gathered}[/tex]Hence, the 10th term of the series is 68.