Determine the range of the following graph:

Answer:

16

Step-by-step explanation:

(|7 − 3 x 5| ÷ 4)³ + √64

(|7 − 3 x 5| ÷ 4)³ + √64

(|7 − 15| ÷ 4)³ + √64

(|7 − 15| ÷ 4)³ + √64

(8 ÷ 4)³ + √64

(8 ÷ 4)³ + √64

2³ + √64

8 + 8

16

Answer:

16

Step-by-step explanation:

To solve, use PEMDAS as it applies to the expression.

First, you must carry out what is in the parenthesis.

Multiply (3*5 = 15), then subtract (7 - 15 = -8). The two little vertical lines surrounding (7 - 3 x 5) mean absolute value. This means that you will write -8 as +8.

Continuing on in the parenthesis, carry out (8 ÷ 4 = 2).

Next, we must do exponents.

We see that everything in the parenthesis is being raised to the power of three (cubed). Since we've solved what was in the parenthesis, we simply need to carry out ([tex]2^{3}[/tex] = 8).

Now, we need to quickly carry out [tex]\sqrt{64}[/tex]. Square roots are just whatever number can be multiplied by itself to get, in this case, 64.

[tex]\sqrt{64} = 8[/tex].

Finally, we must add what remains.

8 + 8 = 16.

So, (|7 - 3 x 5) | ÷ [tex]4)^{3}[/tex] + [tex]\sqrt{64}[/tex] = 16.

Both Roger and Jeff will have run a distance of 1/3 mile when Jeff catches up to Roger after 2 minutes.

To solve this problem, we can determine the relative speeds of Roger and Jeff.

Since Roger runs one mile in 9 minutes, his speed is 1/9 miles per minute.

Similarly, Jeff runs one mile in 6 minutes, so his speed is 1/6 miles per minutes.

Let's assume that Jeff catches up to Roger after t minutes.

In that time, Roger would have run (1/9) [tex]\times[/tex] t miles, and Jeff would have run (1/6) [tex]\times[/tex] t miles.

Since Jeff gives Roger a 1-minute head start, we can express their distances covered as:

Distance covered by Roger = (1/9) [tex]\times[/tex] (t+1) miles

Distance covered by Jeff = (1/6) [tex]\times[/tex] t miles

For Jeff to catch up to Roger, their distances covered must be equal. So we can set up the equation:

(1/9) [tex]\times[/tex] (t+1) = (1/6) [tex]\times[/tex] t

To solve for t, we can cross-multiply and simplify:

6(t+1) = 9t

6t + 6 = 9t

6 = 9t - 6t

6 = 3t

t = 2

Therefore, it will take 2 minutes for Jeff to catch up to Roger.

Substituting t = 2 back into the equations, we can find the distances covered by each:

Distance covered by Roger = (1/9) [tex]\times[/tex] (2+1) = 1/3 mile

Distance covered by Jeff = (1/6) [tex]\times[/tex] 2 = 1/3 mile

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It will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.

Let's calculate the time it takes for Jeff to catch up to Roger and the distance each will have run.

First, we need to determine how much distance Roger covers during the 1-minute head start. Since Roger runs one mile in 9 minutes, in 1 minute, he would cover 1/9 of a mile.

Now, let's set up an equation to represent the time it takes for Jeff to catch up to Roger:

Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start

Let's denote the time it takes for Jeff to catch up as t minutes. During this time, Jeff runs a distance of 1 mile, while Roger runs a distance of 1/9 of a mile (from the head start).

Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start

1 mile = (1/9) mile + (6 minutes) × t × (1 mile/6 minutes)

Now, let's solve this equation to find the time it takes for Jeff to catch up:

1 = (1/9) + (1/6)t

Multiplying the equation by the least common multiple (LCM) of 9 and 6, which is 18, to clear the fractions:

18 = 2 + 3t

Subtracting 2 from both sides:

16 = 3t

Dividing by 3:

t = 16/3 = 5.33 minutes (rounded to two decimal places)

Therefore, it will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.

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The table of values for the equation y = 3/x can be completed as follows:

x | y

1 | 3/1 = 3

2 | 3/2 = 1.5

3 | 3/3 = 1

4 | 3/4 = 0.75

5 | 3/5 = 0.6

To complete the table of values for the equation y = 3/x, we substitute different values of x into the equation and calculate the corresponding values of y.

When x = 1:

Substitute x = 1 into the equation: y = 3/1 = 3

So, when x = 1, y = 3.

When x = 2:

Substitute x = 2 into the equation: y = 3/2 = 1.5

So, when x = 2, y = 1.5.

When x = 3:

Substitute x = 3 into the equation: y = 3/3 = 1

So, when x = 3, y = 1.

When x = 4:

Substitute x = 4 into the equation: y = 3/4 = 0.75

So, when x = 4, y = 0.75.

When x = 5:

Substitute x = 5 into the equation: y = 3/5 = 0.6

So, when x = 5, y = 0.6.

By substituting different values of x into the equation y = 3/x, we can complete the table of values as shown above.

Hence, the completed table of values for y = 3/x is:

x | y

1 | 3

2 | 1.5

3 | 1

4 | 0.75

5 | 0.6

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Answer:

a

Step-by-step explanation:

The correct solutions to the quadratic equation are:

c. -8

e. 2

To determine the solutions to the quadratic equation 2x^2 + 6x - 10 = x^2 + 6, we need to solve for x.

First, let's simplify the equation by combining like terms:

2x^2 + 6x - 10 - x^2 - 6 = 0

x^2 + 6x - 16 = 0

Now, we can solve this quadratic equation by factoring or by using the quadratic formula.

By factoring:

(x + 8)(x - 2) = 0

Setting each factor equal to zero, we get:

x + 8 = 0 --> x = -8

x - 2 = 0 --> x = 2

So, the solutions to the quadratic equation are x = -8 and x = 2.

Now, let's check the given options:

a. -2: This value is not a solution to the equation.

b. 1/3: This value is not a solution to the equation.

c. -8: This value is a solution to the equation.

d. -1/2: This value is not a solution to the equation.

e. 2: This value is a solution to the equation.

f. 8: This value is not a solution to the equation.

The following are the proper answers to the quadratic equation: c. -8 e.2

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Answer:

f(2.5) = 100

Step-by-step explanation:

to evaluate f(2.5) substitute x = 2.5 into f(x)

f(2.5) = 16(2.5)² = 16 × 6.25 = 100

The calculated value o x in the circle is 7

From the question, we have the following parameters that can be used in our computation:

The circle

The value of x can be calculated using teh equation of the intersection of chords

So, we have

122 = 1/2(6x + 8 + 194)

Evaluate

244 = 6x + 202

So, we have

6x = 42

Divide by 6

x = 7

Hence, the solution for x is 7

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Answer:

A

Step-by-step explanation:

For a table of values to be a function, all inputs must have one unique output. The only table that doesn't violate this is table A.

Notice that while two different inputs (-4 and 1) have the same output of 7, it is still a function because both outputs of 7 are associated with two different inputs.

Answer:

Step-by-step explanation:

To find the density of the wooden board, we need to divide the mass of the board by its volume. The volume of a rectangular prism is calculated by multiplying its length, width, and height.

Given:

Length (l) = 0.3 m

Width (w) = 2.1 m

Height (h) = 0.1 m

Mass (m) = 0.17 kg

Volume (V) = l × w × h

V = 0.3 m × 2.1 m × 0.1 m

V = 0.063 m³

Density (ρ) = mass / volume

ρ = 0.17 kg / 0.063 m³

ρ ≈ 2.7 kg/m³

The density of the wooden board is approximately 2.7 kg/m³.

The calculated vertex of the function y = 2(x + 4)(x - 2) is (-1, -18)

From the question, we have the following parameters that can be used in our computation:

y = 2(x + 4)(x - 2)

Expand the equation

So, we have

y = 2x² + 4x - 16

Differentiate the function and set to 0

So, we have

4x + 4 = 0

So, we have

4x = -4

Evaluate

x = -1

Next, we have

y = 2(-1 + 4)(-1 - 2)

Evaluate

y = -18

This means that the vertex is (-1, -18)

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The length of the shortest path ABCD is 7 units.

To find the length of the shortest path ABCD, we need to determine the coordinates of points B and C and then calculate the distances between these points.

Given that B has a y-coordinate of 2, it lies on a horizontal line. Therefore, the y-coordinate of B is 2, and the x-coordinate is the same as the x-coordinate of point A, which is 7. So, B is the point (7, 2).

Similarly, C lies on a vertical line, and its x-coordinate is the same as the x-coordinate of point D, which is -5. So, C is the point (-5, 0).

Now, we can calculate the distances between the points. The distance between A and B can be found using the distance formula:

AB = √[tex]((x2 - x1)^2 + (y2 - y1)^2[/tex])

Substituting the coordinates of A and B, we have:

AB = √[tex]((7 - 7)^2 + (2 - 4)^2) = √(0^2 + (-2)^2[/tex]) = √4 = 2

The distance between B and C is simply the difference in their y-coordinates:

BC = |y2 - y1| = |2 - 0| = 2

Finally, the distance between C and D can be calculated using the distance formula:

CD = √[tex]((-5 - (-5))^2 + (0 - (-3))^2)[/tex] = √[tex](0^2 + 3^2)[/tex] = √9 = 3

Therefore, the length of the shortest path ABCD is the sum of the distances AB, BC, and CD:

Shortest path ABCD = AB + BC + CD = 2 + 2 + 3 = 7

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Answer:

Step-by-step explanation:

0

Answer:

0

Step-by-step explanation:

25 ÷ 5+7-(4 x 3)

25 ÷ 5+7-(4 x 3)

5+7-(4 x 3)

5+7-(4 x 3)

5+7-12

12-12

0

I wrote in bold the steps you need to follow using PEMDAS (Parentheses, Exponents, Multiplication and Divison left to right, and Addition and Subtraction left to right).

The probability that the dial stops on yellow is 2/5 or 0.4 (or 40%).

Therefore, there is a 40% chance that the spinner will stop on yellow.

To find the probability that the spinner stops on yellow, we need to determine the number of favorable outcomes (yellow) and the total number of possible outcomes.

The spinner has 10 equally sized slices, with 4 yellow, 4 red, and 2 blue.

The number of favorable outcomes (yellow) is 4 because there are 4 yellow slices.

The total number of possible outcomes is 10 because there are 10 slices in total.

Therefore, the probability of the spinner stopping on yellow can be calculated as:

Probability = Number of favorable outcomes / Total number of possible outcomes

Probability = 4 / 10

Simplifying this fraction, we get:

Probability = 2 / 5

So, the probability that the dial stops on yellow is 2/5 or 0.4 (or 40%).

Therefore, there is a 40% chance that the spinner will stop on yellow.

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The given statement proposition is a that suggests that if x is an inductive element, defined in terms of the set X as described, then it follows that every non-zero natural number can be expressed as the successor of some other natural number.

The given statement is a logical proposition involving the concept of induction. Let's break it down and analyze its components.

"If x is inductive..."

This implies that x is a concept or object that possesses the property of being inductive. In mathematics, the term "inductive" typically refers to the property of being a natural number or belonging to the set of natural numbers.

"...then so is (x ∈ X : x = Ф or x = y ∪ {y} for some y)"

Here, we have a set X that consists of elements satisfying a certain condition. The condition states that an element x in X can either be equal to the empty set (Ф) or the union of a set y with itself ({y}). This construction represents a recursive definition, where each element in X is defined in terms of a base case (Ф) and a recursive step ({y}).

"...hence each n ≠ 0 is m + 1 for some m."

This conclusion states that for every natural number n that is not equal to 0, there exists another natural number m such that n can be expressed as m + 1. In other words, any non-zero natural number is the successor of some other natural number.

Overall, the given statement is a proposition that suggests that if x is an inductive element, defined in terms of the set X as described, then it follows that every non-zero natural number can be expressed as the successor of some other natural number.

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The speed of Jake's initial trip is x = 24 kilometers per hour, and the speed of the return trip is x + 6 = 30 kilometers per hour.

Let's assume that Jake's speed during the initial trip is represented by "x" kilometers per hour.

On the return trip, he drives 6 kilometers per hour faster, so his speed can be represented as "x + 6" kilometers per hour.

To find the time taken for each trip, we can use the formula Time = Distance / Speed.

For the initial trip, the time taken is 120 kilometers divided by x kilometers per hour, which gives us 120/x hours.

On the return trip, the time taken is 120 kilometers divided by (x + 6) kilometers per hour, which gives us 120/(x + 6) hours.

According to the problem, the return trip takes 1 hour less than the initial trip. So we can set up the equation:

120/x - 1 = 120/(x + 6)

To solve this equation, we can multiply both sides by x(x + 6) to eliminate the denominators:

120(x + 6) - x(x + 6) = 120x

Simplifying this equation:

120x + 720 - x² - 6x = 120x

Combining like terms:

x² + 6x - 720 = 0

Now we can solve this quadratic equation by factoring or using the quadratic formula. By factoring, we find:

(x + 30)(x - 24) = 0

This gives us two potential solutions: x = -30 or x = 24.

Since speed cannot be negative, we discard the solution x = -30.

Therefore, the speed of Jake's initial trip is x = 24 kilometers per hour, and the speed of the return trip is x + 6 = 30 kilometers per hour.

So, Jake drives at a speed of 24 kilometers per hour on the initial trip and 30 kilometers per hour on the return trip.

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By using the change of base formula: The solution to the equation log(base y) (X-2) = 5 is [tex]X = y^5 + 2.[/tex]

To solve the equation log(base y) (X-2) = 5 using the change of base formula, we can rewrite the equation as log(base b) (X-2) / log(base b) y = 5.

Using the change of base formula, we can choose any base for b.

Let's choose base 10 for simplicity.

So the equation becomes log(base 10) (X-2) / log(base 10) y = 5.

We know that log(base 10) (X-2) represents the logarithm of (X-2) to the base 10, and log(base 10) y represents the logarithm of y to the base 10.

Now, to solve for X, we can isolate it by multiplying both sides of the equation by log(base 10) y:

log(base 10) (X-2) = 5 [tex]\times[/tex] log(base 10) y.

This simplifies to:

log(base 10) (X-2) [tex]= log(base 10) y^5.[/tex]

Since the logarithms on both sides have the same base, we can remove the logarithm and equate the arguments:

[tex]X - 2 = y^5.[/tex]

Now we can solve for X by adding 2 to both sides:

[tex]X = y^5 + 2.[/tex]

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The solutions associated with the final matrices representing a system of linear equations are listed below:

First case: x = 3, y = 1, z = 8

Second case: No solution

Third case: No solution

In this problem we find three of final matrices, each of them representing a system of linear equations. There are two rules to be considered:

Now we proceed to determine the solution associated with each matrix:

First matrix:

x = 3, y = 1, z = 8

Second matrix:

No solution

Third matrix:

No solution

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Step-by-step explanation:

For the left matrix, since the matrix is already in reduced row form,

The solutions to the matrix is (3,-1,8)

For the middle matrix, we need to convert the -6 to a zero,

notice how in the third row, every entry except the last one is 0, this implies that

0=-2, which is not the case thus the middle matrix has no solution.

For the last one, notice that we have 3 colums but only two non zero rows, this means that this matrix has infinite solutions.

Answer:

A= 220.5ft

B= $2425.5

Step-by-step explanation:

A= 220.5ft

B= $2425.5

Answer:

52500

Step-by-step explanation:

Let there be x employees in the previous year

Now, the company has 32% more employees whis is 69300

i.e.

[tex]x + \frac{32}{100} x = 69300\\\\ \implies\frac{132x}{100} = 69300 \\\\\implies 132x = 6930000\\\\\implies x = \frac{6930000}{132}\\[/tex]

⇒ x = 52500

There were 52500 employees in the previous year

The row operation on the matrix [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex] is [tex]\left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

From the question, we have the following parameters that can be used in our computation:

[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

The row operation is given as

1/2R₁

This means that we divide the entries on the first row by 2

Using the above as a guide, we have the following:

[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

Hence, the row operation on the matrix is [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

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The solution to the system is (a) a = 4/5, b = 5, c = -4 and d =-4

From the question, we have the following parameters that can be used in our computation:

The augmented matrix

Where, we have

[tex]\left[\begin{array}{cccc|c}1&0&0&0&4/5\\0&1&0&0&5\\0&0&1&0&-4\\0&0&0&1&-4\end{array}\right][/tex]

From the above, we have the diagonals to be 1

And other elements to be 0

This means that the equation has been solved

So, we have

a = 4/5, b = 5, c = -4 and d =-4

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The correct answer is:  A. Yes; each input pairs with only one output.

To determine whether the given mapping diagram represents a function, we need to analyze the relationship between the input values (x) and the corresponding output values (y).

Looking at the mapping diagram, we can see that the input value -5 is paired with the output value 8. This implies that when x = -5, the corresponding y value is 8. Similarly, when x = 9, the corresponding y value is -8.

Since each input value has a unique and specific output value, we can conclude that the mapping diagram represents a function. In other words, for every input value, there is only one output value associated with it.

This is consistent with the definition of a function, where each input has a single and distinct output. Therefore, the mapping diagram satisfies the criteria for a function, and the correct answer is:

A. Yes; each input pairs with only one output.

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The mapping diagram does not represent a function that reflects this is: No; each output value pairs with two input values. D.

To determine whether the mapping diagram represents a function, we need to assess whether each input value pairs with only one output value.

Looking at the given mapping diagram:

-5 -> 8

9 -> y

-8 -> y

We can see that the input value -5 maps to the output value 8.

There are two different input values, 9 and -8, that map to the same output value, y.

In a function, each input should correspond to exactly one output, but in this case, the output value y is associated with two different input values.

In this case, y, the output value, pairs with both 9 and -8, indicating that the diagram does not meet the criteria for a function.

We must examine if each input value couples with only one output value in order to evaluate whether the mapping diagram reflects a function.

Observing the provided mapping diagram:

-5 -> 8 9 -> y -8 -> y

As can be seen, the input value of -5 corresponds to the output value of 8.

The identical output value, y, is mapped to two distinct input values, 9 and -8.

A function should have only one output for each input, however in this situation, the output value y is connected to two separate input values.

This figure does not fit the definition of a function because the output value, y, couples with both 9 and -8.

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Answer:

a) x² - x - 12 = 0

Step-by-step explanation:

We have equation A = equation B

⇒ x² - 9 = x + 3

⇒ x² - 9 - x - 3 = 0

⇒ x² - x - 12 = 0

Answer:

[tex]y = |x - 2| + 3[/tex]

The correct answer is C.

Answer:

$3.3

Step-by-step explanation:

4x = 1.32

x = 0.33$ / ft

10x = 10 * 0.33 = 3.3$

Answer:

9

Step-by-step explanation:

To find the volume of the given cylinder, we need to use the formula of volume of a cylinder which is given by V = πr²h, where V is the volume of the cylinder, r is the radius of the cylinder and h is the height of the cylinder. So, the volume is 1078.1 cubic units.

Given, Length = 14 units, Height = 11 units. Now, we know that the formula for the volume of a cylinder is given as; V = πr²h.

Here, the radius of the cylinder is half the length of the cylinder, which is; Radius = Length/2

Radius = 14/2

Radius = 7 units

Substituting the value of the radius and height, we have; V = π(7)²(11)

V = 1078.1 cubic units. Therefore, the volume of the cylinder is 1078.1 cubic units. Rounded off to one decimal place, the volume is 1078.1 cubic units.

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