Answer:
Explanation:
We shall represent vector B and C in terms of i and j .
B = 5 cos115 i + 5 sin115 j
= -2.11 i + 4.53j
Similarly
C = 4 cos255 i + 4 sin225 j
= -1.04 i -3.86 j
R = B + C
= -2.11 i + 4.53j -1.04 i -3.86 j
= -3.15 i + .67 j
magnitude of R
= √( 3.15² + .67² )
= √( 9.92 +.45 )
= 3.22
Angle Ф
TanФ = - .67 / 3.15
= - .21
Ф = - 12⁰
= 180 - 12
= 168 degree counterclockwise from positive x axis.
Joyce pushes Efua, whose mass is 40.0 kg, with the force of 5.0 N. What is Efua's resulting acceleration?
Answer:
[tex]a=0.125\ m/s^2[/tex]
Explanation:
Given that,
Mass of Efua, m = 40 kg
Force, F = 5 N
We need to find Efua's resulting acceleration. We know that the force acting on an object is given by :
F = ma
where a is acceleration
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{5\ N}{40\ kg}\\\\a=0.125\ m/s^2[/tex]
So, the resulting acceleration is [tex]0.125\ m/s^2[/tex].
The suns in the binary star system would be very far away, how does this
impact the size they would be in the sky?
When learning a new exercise what is the first thing you should focus on?
A
how much weight you can lift
B
if your form is correct
Dc
how many sets you can complete
D
if you can get done first
Answer:
If your form is correct (b)
Answer:
The answer is B if your form is correct
Power describes the
a. rate
b. scale
of the work that is being done.
C. amount
d. direction
Please select the best answer from the choices provided
Ο Α
О В
Ос
OD
Power describes the rate of the work that is being done. The correct option is A.
What is power?
Power is defined as the rate at which work is done or the amount of work done per unit time. In other words, power describes how quickly work is being done or how fast energy is being transferred.
The unit of power is the watt (W), which is equal to one joule of work per second.
Power can be calculated by dividing the amount of work done by the time it takes to do that work, or by multiplying the force applied by the distance traveled and dividing by the time it takes to travel that distance.
For example, if a machine does 100 joules of work in 10 seconds, then the power of the machine is 10 watts, calculated as:
Power = Work / Time
Power = 100 J / 10 s
Power = 10 W
Therefore, power describes the rate or speed at which work is being done, and it is measured in watts.
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HELP ASAP
This diagram shows Earth orbiting the Sun?
At position B in the Northern Hemisphere it would be which season?
A. winter
B. fall
C. summer
D. spring
Answer:
B
Explanation:
A is summer, C is winter, B should be fall in-between those 2
Florida is a peninsula bound by the Atlantic Ocean on the east and the Gulf of Mexico on the west. The sea affects temperatures along Florida’s coast. How do coastal temperatures compare to those inland?
Which statement BEST describes scientific theories? A. Scientific theories attempt to explain an entire group of related phenomena. B. Scientific theories are based on facts that describe natural events. C. Scientific theories describe natural events but do not explain them. D. Scientific theories are facts based on observations of events in the natural world.
I NEED ANSWERS FAST!!
Answer:
C
Explanation:
A theory does not have any proven facts about it, it is just a theory, so this would likely be the best option.
Answer:
A. Scientific theories attempt to explain an entire group of related phenomena.
Explanation:
PLEASE HELP!!!!
One cereal bar has a mass of 37g. what is the mass of 6 cereal bars? is that more than or less than 1kg. explain your answer
Answer:
6 cereal bars = 222g, which is much less than 1kg
Explanation:
Example 1: Two physics students, Ben and Bonnie, are in the weightlifting room. Bonnie lifts the 50kg barbell
over her head (approximately .60 m) 10 times in one minute; Ben lifts the 50 kg barbell the same distance over his
head 10 times in 10 seconds.
o Which student does the most work?
O
Which student delivers the most power?
Answer:
Same
Ben.
Explanation:
m = Mass Bonnie and Ben lift = 50 kg
s = Displacement of mass by both the students = 0.6 m
Work done by both the student is
[tex]W=Fs\\\Rightarrow W=10\times 50\times 0.6\\\Rightarrow W=300\ \text{J}[/tex]
The amount of work done by both the students will be equal to 300 J.
[tex]t_1[/tex] = Time taken by Bonnie = 1 minute = 60 seconds
[tex]t_2[/tex] = Time taken by Ben = 10 seconds.
Power delivered by Bonnie
[tex]P=\dfrac{W}{t_1}\\\Rightarrow P=\dfrac{300}{60}\\\Rightarrow P=5\ \text{W}[/tex]
Power delivered by Ben
[tex]P=\dfrac{W}{t_2}\\\Rightarrow P=\dfrac{300}{10}\\\Rightarrow P=30\ \text{W}[/tex]
So, power delivered by Ben is more.
A stunt driver drives a car at 15 m/s off a cliff and into a lake. The surface of the water is 25 m below the cliff.
a) How long did it take to reach the water?
b) What was the horizontal distance from the cliff where the car entered the water?
c) At what velocity did the car hit the water?
Answer:
Explanation:
Given
initial velocity u = 15m/s
Height below the water = 25m
a) Using the equation of motion S = (v+u)/2 * t
25 = 0+15/2 * t
25 = 7.5t
t = 25/7.5
t = 3.33s
Hence it will take 3.33secs to reach the water
b) The horizontal distance is expressed as;
S = Uxt
S = 15(3.33)
S = 50m
Hence the horizontal distance from the cliff where the car entered the water is 50m
c) The velocity of the car v.
Using the equation of motion;
v² = u²+2gS
v² = 15²+2(9.8)(25)
v² = 225+490
v = √715
v = 26.74m/s
Hence the car hit the water at the velocity of 26.74m.s
Is a stone in the ground example of newtons first law of motion?
Answer:
yes, a stone in the ground is a example of newtons first law of motion because it does change it position until an external force is applied.
(Newton’s first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. )
Explanation:
Write down the characteristics of images formed
when an object is kept at the center of curvature of
concave mirror.
Explanation:
When the object is placed at centre of curvature (C) of a concave mirror, a real and inverted image is formed at the same position. Properties of image: Same size of object.
Describe the situation that would call for baboons to vote on what to do next
Answer:
baboons??
Explanation:
Answer:trumps downfall
Explanation:Baboons harrases monkeys
ILL ADD BRAINLIEST
Match the biomes with the corresponding animals, vegetation, or geographic location.
forest at highest latitudes:
prairies/ temperate climate:
high humidity and rainfall/ near equator:
no trees/ polar bears/ mosses:
<25cm rain/ few animals:
mostly small mammals/ many scrubs/ steppes:
abundant thick vegetation/ many species:
hardwood trees/ deer, squirrel, foxes:
This is kinda confusing. I wish u just to a screenshot of the problem but here goes...
Forest at highest latitudes- Hardwood trees/deer, squirrel, foxes
Praries/temperate climate- Mostly small mammals/scrubs/steppes
High humidity/rainfall near equator- Abundant thick vegatation/manny species
No trees/ polar bears/ mosses- 25cm rain/few animals
A ball of 12 kg is attached to a string of 0.8 meter spun at 4
m/s. What is the centripetal force?
Answer:
240 N
Explanation:
The Centripetal force of the spun ball is 240 N.
The Centripetal force can be calculated using the formula below.
Formula:
F = mv²/r........................ Equation 1Where:
F = centripetal force m = mass of the ballr = radiusv = velocity.From the question,
Given:
m = 12 kgv = 4 m/sr = 0.8 mSubstitute these values into equation 1
F = 12(4²)/0.8F = 240 NHence, The Centripetal force of the spun ball is 240 N.
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PLEASE HELPPP Count the number of atoms of each element in this molecule: 2H2K(OH2)2
Answer:
H = 6 atoms
K= 2 atoms
O = 2 atoms
Answer:
H is 6 atoms K is2 atoms and O is 2 atoms
Explanation:
What is the primary difference between static and ballistic stretching? Do you see this as being beneficial or potentially harmful? Why?
what is the dimension of permeance
Answer:
metric dimensions, i think
Explanation:
What is the velocity of an object that travels south 6.9m in 3 seconds?
Answer:
oke
Explanation:
v=d\t
=6.9\3
=2.3m\s
A 49 N coconut is in a 15 m tree. What is te potential energy of the coconut?
PE= mgh-wh
g9.8 m/s
Answer:
735 J
Explanation:
From the question given above, the following data were obtained:
Weight (W) = 49 N
Height (h) = 15 m
Potential energy =?
Potential energy is simply defined as the product of weight of the object and height to which the object is raised. Mathematically, it is expressed as:
Potential energy = weight × height
With the above formula, we can obtain the potential energy of the coconut as follow:
Weight (W) = 49 N
Height (h) = 15 m
Potential energy =?
Potential energy = weight × height
Potential energy = 49 × 15
Potential energy = 735 J
Thus, the potential energy of the coconut is 735 J
A rural mail carrier leaves the post office and drives 22.0 km in a direction 35 degrees to the next town. She then drives in a direction 60.0 degrees for 47 km. What is her magnitude and displacement from the post office?
Answer:
D = 72.96 km, θ = 36.43º
Explanation:
This is a vector addition exercise, we are going to solve it by decomposing the displacements.
First displacement
cos 35 = x₁ / L
x₁ = L cos 35
cos 35 = y₁ / L
y₁ = L sin 35
x₁ = 22.0 cos 35 = 18.0 km
y₁ = 22 sin 35 = 12,619 km
Second displacement
cos 60 = x₂ / L
x₂ = L cos 60
x₂ = 47 cos 60 = 23.5 km
sin 60 = y₂ / L
y₂ = L sin 60
y₂ = 47 sin 60 = 40.70 m
In total displacement it is
x_total = x₁ + x₂
x_total = 18 + 40.7 = 58.7 km
y_total = y₁ + y₂
y_total = 12.629 +40.70
y_total = 53,329 km
Let's use the Pythagorean theorem
D = √(x_total² + y_total² )
D = √ (58.7² + 43,329²)
D = 72.96 km
For the direction we use trigonometry
tan θ = y_total / x_total
θ= tan-1 (43,329 / 58.7)
θ = 36.43º
Whom do you feel empathy for ? Why ?
After soccer practice, Coach Miller goes to the roof of the school to retrieve the errant soccer balls. The height of the school is 3.5 m 3.5 m. He kicks a soccer ball which leaves the roof with a horizontal velocity, but no vertical velocity. Ignoring air resistance, which of the following values indicates how much horizontal velocity is needed for the ball to reach the soccer field located 22 m 22 m from the school?
To reach the soccer field located 22 m from the school, required horizontal velocity is 25.88 meter/second.
What is velocity?The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time is the definition of velocity.
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
The time of falling of the ball = √(2h/g)
= √( 2 × 3.5/9.8) second.
= 0.85 second.
hence, to reach the soccer field located 22 m from the school, required horizontal velocity = distance/time
= 22 meters/0.85 seconds
= 25.88 meter/second.
Hence, the required horizontal velocity is 25.88 meter/second.
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Find the direction of the sum of
these two vectors:
3.14 m,
30.0°
60.0°
2.71 m
The magnitude of the resultant vector is 4.14m and the direction is 50°.
What is the magnitude of the forces?The resultant magnitude of the vector is the sum of the algebraic forces acting at the point.
The magnitude of the resultant vector, F is calculated below:
[tex]F = \sqrt{3.14^{2} + 2.71^{2}} = 4.14m[/tex]
The direction is given below as follows:
[tex]x = tan^{-1} × \frac{3.14}{2.71} = 50[/tex]
Therefore, the magnitude of the resultant vector is 4.14m and the direction is 50°.
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In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2
Calculate the amount of force at which the wrecking ball strikes the building.
The wrecking ball strikes the building with a force of
1,324
N.
Answer:
4
Explanation:
TRUST ME AND I AM SORRY IF RONG
Answer:
The real answer should be 1391. Considering the mass x acceleration
A golf ball with a mass of 45 g is rolling down a hill. At the bottom of the hill, its speed is 6 m/s. What is its GPE?
Answer:
GPE = 0 (when the golf is downhill)
GPE = 0.81 [J](when the golf is at the highest point of the hill)
Explanation:
In order to solve this problem, we must use the principle of energy conservation, which tells us that energy is transformed from kinetic energy to potential energy or vice versa.
We must define a reference energy point, where at this point the potential energy is zero. Let's take this point at the bottom of the hill.
At this point where the potential energy is zero, all the potential energy will have been transformed into kinetic energy, at this point the velocity will be maximum.
[tex]E_k=E_p\\where:\\E_{p}=m*g*h\\E_{k}=\frac{1}{2} *m*v^{2}[/tex]
where:
m = mass = 45 [g] = 0.045 [kg]
g = gravity acceleration = 9.81 {m/s²]
h = elevation [m]
v = velocity = 6 [m/s]
[tex]E_{k}=\frac{1}{2}*0.045*(6)^{2} \\E_{k}=E_{p}=0.81 [J][/tex]
GPE = 0 (when the golf is downhill)
GPE = 0.81 [J](when the golf is at the highest point of the hill)
1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the minimum coefficient of static friction between tires and track needed to keep the car on circular path.
Answer:
μ = 0.1
Explanation:
In order to keep the car on circular track, the centripetal force must be equal to the frictional force between tires and track:
Frictional Force = Centripetal Force
μmg = mv²/r
μ = v²/gr
where,
μ = coefficient of friction = ?
v = speed of car = 10 m/s
g = 9.8 m/s²
r = radius of track = 100 m
Therefore,
μ = (10 m/s)²/(9.8 m/s²)(100 m)
μ = 0.1
What is the current in a circuit if 3.50 C of charge passes any given point in a circuit in 1.80 s?
Answer:
I = 1.944 A
Explanation:
Given the following data;
Charge, Q = 3.5C
Time, t = 1.8 secs
Charge of a substance is given by the formula;
[tex] Q = It[/tex]
Where;
Q is the amount of charge measured in Colombs.
I is the current measured in Amperes.
t is the time measured in seconds.
Making I the subject of formula, we have
[tex] I = \frac {Q}{t} [/tex]
[tex] I = \frac {3.5}{1.8} [/tex]
I = 1.944 A
Therefore, the current in the circuit is 1.944 Amperes.
Alcohol consumption slows people's reaction times.In a controlled government test,it takes a certain driver 0.320 s to hit the brakes in a crisis when unimpaired and 1.00 s when drunk.When the car is initially traveling at 90km/h,how far does the car travel before coming to a stop when the person is drunk compared to sober?
Answer:
When the person is drunk the car travels 20.1 meters more than when the person is sober. The distance traveled by car is:
Person drunk: 28.1 m
Person sober: 8 m
Explanation:
The distance traveled can be found using the following equation:
[tex] v = \frac{x}{t} \rightarrow x = v*t [/tex]
Where:
v: is the speed = 90 km/h
t: is the time
When the person is sober, the time that takes to hit the brakes is 0.320 s, so we have:
[tex] x = v*t = 90 \frac{km}{h}*\frac{1 h}{3200 s}*0.320 s = 8 \cdot 10^{-3} km = 8 m [/tex]
And when the person is drunk, the time is 1.00 s, hence the distance is:
[tex] x = v*t = 90 \frac{km}{h}*\frac{1 h}{3200 s}*1 s = 0.0281 km = 28.1 m [/tex]
The distance traveled by the car when the person is drunk compared when the person is sober is:
[tex] d = 28.1 m - 8 m = 20.1 m [/tex]
Therefore, when the person is drunk the car travels 20.1 meters more than when the person is sober.
I hope it helps you!
A light with a second-order dark band forms a diffraction angle of 20.0 degrees. The diffraction grating has 200.0 lines per mm. The wavelength of the light, to the nearest whole number, is _____ nm.
Answer:
The value is [tex]\lambda = 684 \ nm[/tex]
Explanation:
From the question we are told that
The order of the dark fringe is m = 2
The diffraction angle is [tex]\theta = 20^o[/tex]
The diffraction grating is [tex]l = 200\ lines\ per\ mm \ = \ 200000\ lines\ per\ m[/tex]
Generally separation between the slits is mathematically represented as
[tex]d = \frac{1}{ 200000}[/tex]
=> [tex]d = 5 *10^{ -6} \ m[/tex]
Generally the condition for destructive interference is mathematically represented as
[tex]dsin(\theta ) = (m - \frac{1}{2} ) \lambda[/tex]
=> [tex]5 *10^{-6} sin(20) = [2 + \frac{1}{2}] * \lambda[/tex]
=> [tex]\lambda = 684 *10^{-9} \ m[/tex]
=> [tex]\lambda = 684 \ nm[/tex]