Determine how many molecules are in 86L of carbon dioxide at STP?

Answer:

Explanation:

The answer is true.

Answer:

true

Explanation:

acids have ph which is less than 7 and base have ph greater than 7

Answer:

i think its the gibbous phase

Explanation:

Answer: C.

Explanation:

two H nuclei fused into one He nucleus

Answer: A!

Explanation: just did it

Explanation:

Sonic is my bf forever, back off

Answer:

oof I always lose on video games so I just quit

Answer:

A heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture

Answer:

m = 176.04 g .

Explanation:

Hello there!

In this case, according to the mole-mass relationships, which are based off the mass of one mole of any compound via the molar mass, it is possible to realize that the molar mass of carbon dioxide is 44.01 (12.01+16*2) g/mol, and therefore, the mass in grams of 4.00 moles of this compound are calculated as shown below:

[tex]m=4.00molCO_2*\frac{44.01gCO_2}{1molCO_2}\\\\m=176.04g[/tex]

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Answer:

b

Explanation:

i know

Answer:

Question 16: I'm not sure but most likely #3

Question 17: #4

Explanation: Hope this Helps

Answer:

A for first one and second one is A

Answer:

What do you need help with

Explanation:

Explanation:

okay I'll help but whats the question

Answer:

[tex]53.55gNO[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to calculate the produced grams of nitrogen monoxide by starting with 25.0 g of nitrogen via their 1:2 mole ratio and the molar masses of 30.1 g/mol and 28.02 g/mol, respectively and by some stoichiometry:

[tex]=25.0gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNO}{1molN_2}*\frac{30.01 gNO}{1molNO}\\\\=53.55gNO[/tex]

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Answer:

Distance cover by Paul's sister by swim = 38.125 miles

Explanation:

Given:

Distance cover by Paul by swim = [tex]7\frac{5}{8}[/tex] = 61/8 miles

Distance cover by Paul's sister by swim = 5 times Distance cover by Paul

Find:

Distance cover by Paul's sister by swim

Computation:

Distance cover by Paul's sister by swim = 5 times Distance cover by Paul

Distance cover by Paul's sister by swim = 5 x [61 / 8 miles]

Distance cover by Paul's sister by swim = 305 / 8 miles

Distance cover by Paul's sister by swim = 38.125 miles

Answer:

a.

[tex]rate_{NH_3}=\frac{2d[NH_3]}{dt}[/tex]

b.

[tex]rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}[/tex]

Explanation:

Hello there!

In this case, according to the law of rate proportions, it is possible to write the the rates of reaction for the formation of NH3 and the disappearance of the N2 and H2, by considering that the coefficient in the reaction for NH3 is +2 and those of N2 and H2, -1 and -3 respectively. Moreover, we set up these equations as derivatives as shown below:

a.

[tex]rate_{NH_3}=\frac{2d[NH_3]}{dt}[/tex]

b.

[tex]rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}[/tex]

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Answer:

Explanation:

From the information given:

Mass of BiPO₄ = 0.3451 g

Number of moles of BiPO₄ = [tex]0.3451 \ g \ BiPO_4 \times \dfrac{1 \ mol \ BiPO_4}{303.95 \ g \ BiPO_4}[/tex]

[tex]= 0.001135 \ mol[/tex]

The number of moles of Bi³⁺ in 20.00 mL is:[tex]= 0.001135 \ mol \ BiPO_4 \times \dfrac{1 \ mol \ of \ Bi^{3+}}{1 \ mol \ BiPO_4}[/tex]

=  0.001135 mol of Bi³⁺

The number of moles of Bi³⁺ in 100 mL stock solution

[tex]= 0.001135 \ mol \ Bi^{3+} \times \dfrac{100 \ mL}{20.0 \ mL}[/tex]

[tex]= 0.005675 \ mol[/tex]

Mass of BSS in 4.9993 g tablets

[tex]m = 0.005675 \ mol \ Bi^{3+} \times \dfrac{1 \ mol \ BSS}{1 \ mol \Bi^{3+}} \times \dfrac{362.1 \ g \ BSS}{1 \ mol \ BSS}[/tex]

m = 2.055 g BSS

Mass of BSS in 5.0103 g (5 tables)

[tex]m = 2.055 g \ BSS \times \dfrac{5.0103 \ g}{4.9993 \ g}[/tex]

= 2.06 g

∴

The mass of BSS per tablet is [tex]=\dfrac{2.06 \ g}{5 \ tablet}[/tex]

= 0.412 g BSS/ tablet

Answer:

71.6 g of Ru(CO)₅ is the maximum mass that can be formed.

The limiting reactant is Ag

Explanation:

The reaction is:

RuI₃ (s) + 5CO (g) + 3Ag (s) → Ru(CO)₅ (s) + 3AgI (s)

Firstly we determine the moles of each reactant:

169 g . 1mol /481.77g = 0.351 moles of RuI₃

58g . 1mol /28g = 2.07 moles of CO

96.2g . 1mol/ 107.87g = 0.892 moles

Certainly, the excess reactant is CO, therefore, the limiting would be Ag or RuI₃.

3 moles of Ag react to 1 mol of RuI₃

Then 0.892 moles of Ag may react to (0.892 . 1) /3 = 0.297 moles

We have 0.351 moles of iodide and we need 0.297 moles, so this is an excess. In conclussion, Silver (Ag) is the limiting.

1 mol of RuI₃ react to 3 moles of Ag

Then, 0.351 moles of RuI₃ may react to (0.351 . 3) /1 = 1.053 moles

It's ok, because we do not have enough Ag. We only have 0.892 moles and we need 1.053.

5 moles of CO react to 3 moles of Ag

Then, 2.07 moles of CO may react to (2.07 . 3) /5 = 1.242 moles of Ag.

This calculate confirms the theory.

Now, we determine the maximum mass of Ru(CO)₅

3 moles of of Ag can produce 1 mol of Ru(CO)₅

Then 0.892 moles may produce (0.892 . 1) /3 = 0.297 moles

We convert moles to mass → 0.297 mol . 241.07g /mol = 71.6 g

Answer:

all of the above

Explanation

Answer:

Calculate the pH of 0.010 M HNO2 solution. The K, for HNO2 is 4.6 x 104

Answer: pH = 2.72

Answer:

yayyy! proud of u

Explanation:

Answer:

We can Observe that the Compound does not have the Positive or the negative Charge thus it is Neutral. Hence, the Oxidation Number of the Compound Will be 0. Thus, the Highest Oxidation Number of the X is 6.

The oxidation state/number for X in XO3 is determined as +6.

The oxidation state/number for X in XO3 is determined from the overal charge of the compound and the charge of oxygen atom.

The oxidation state of "X" is calculated as;

X + (3 x -2) = 0

X - 6 = 0

X = +6

Thus, the oxidation state/number for X in XO3 is determined as +6.

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Ozone gas can be smelled in the air after a thunderstorm as a result of  reactions between oxides of nitrogen and volatile organic compounds.

Ozone gas can be produced due to chemical reactions between oxides of nitrogen and volatile organic compounds. This reaction occurs when pollututed gas is emitted from vehicles react and other activities with each other in the presence of sunlight.

So we can canclude that Ozone gas can be smelled in the air after a thunderstorm as a result of  reactions between oxides of nitrogen and volatile organic co

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Answer:

c substance

Explanation:

Matter is never destroyed or created in chemical reactions. The particles of one substance are rearranged to form a new substance. The same number of particles that exist before the reaction exist after the reaction.

Answer:

The agricultural revolution increased agricultural production and technological advancements. I think this led to population growth because the increase in labor and the increase in technologies increased human deveolpment. The revolution also allowed farmers to grow and produce more food and transport it to where it was needed.

Explanation:

Answer:

iodous acid

Explanation:

iodous acid would also be known as HIO2

Answer:

0.875

...............

Answer:

c. 10–14[H3O+]

Explanation:

On a calculator, calculate 10-8.34, or "inverse" log ( - 8.34). Example: What is the pOH of a solution that has a hydroxide ion concentration of 4.82 x 10-5 M? The hydroxide ion concentration can be found from the pOH by the reverse mathematical operation employed to find the pOH.

Answer:

4. KCl(s)

Explanation:

KCl is an ionic salt that dissolves in water to form a KCl aqueous solution.

A solution is defined as the homogeneous mixture of one or more solutes dissolved in a solvent. Here in the saturated solution of potassium chloride, the solute is KCl. The correct option is 4.

A solute is defined as the substance which is dissolved in a solution. In a solution the amount of the solute present is always smaller than the amount of the solvent. For example in a salt solution, salt dissolves in water and therefore salt is the solute.

The particles of the solute present in a solution cannot be seen by our eye. The solute from a solution is not possible to separate by filtration. In an unsaturated solution, the concentration of the solute is much lower than that of the concentration of the solvent.

A solution is a combination of the solute and the solvent.

Thus the correct option is 4 - KCl.

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Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll use the molar mass of hydrogen peroxide (H₂O₂), as follows:

There are 8 moles in 272 grams of hydrogen peroxide.

Answer:

NaCl and water: Ion - Dipolo forces

NaCl and Hexane: Ion-ion force between Na+ and Cl− ions and London dispersion force between two hexane molecules

Explanation:

NaCl and water:

The ion-dipole force is established between an ion and a polar molecule.  Polar molecules are dipoles, they have a positive end and a negative end.

H2O has an important charge separation in its atoms (the H has a positive partial charge and the O has a negative partial charge) and this causes permanent electrical dipoles in the water molecules.

Sodium chloride is an ionic compound formed of positive and negative charge ions, Na + and Cl-. Depending on their charge, these ions will be attracted to opposite charges in the water molecules (H attracts chloride ions and O attracts sodium ions), causing the salt to dissolve in water.

Explanation:

Answer:

A. PbI2(s) ===> Pb2+(aq) + 2I-(aq)

B. Ksp = [Pb2+][I-]^2

C. 1.52 x 10^-3 M. It is equal to the moles/L of PbI2 that go into solution.

D. 2 x 1.52 x 10^-3 = 3.04 x 10^-3 M

E. Ksp = (1.52x10^-3)(2.31x10^-6) = 3.51 x 10^-9

Explanation:

In the given question, [tex]\rm PbI_2(s) \rightleftharpoons Pb^{2+}(aq) + 2I^-(aq)[/tex] is the dissolution reaction of [tex]\rm PbI_2[/tex] in water,   [tex]\rm Ksp = [Pb^{2+}][I^-]^2[/tex] is expression for Ksp for [tex]\rm PbI_2[/tex],  [tex]1.52\times 10^{-3 }[/tex] mol/L is the concentration of [tex]\rm Pb^{2+ }[/tex] in the equilibrium solution,  [tex]3.04\times 10^{-3}[/tex] mol/L is the concentration of I- in the equilibrium solution and

[tex]1.40\times 10^{-8}[/tex] is the solubility product of  [tex]\rm PbI_2[/tex], respectively.

A reaction is a process that involves the transformation of one or more substances into one or more different substances.

1. The dissolution reaction of [tex]\rm PbI_2[/tex] in water is:

[tex]\rm PbI_2(s) \rightleftharpoons Pb^{2+}(aq) + 2I^-(aq)[/tex]

2. The expression for Ksp for [tex]\rm PbI_2[/tex] is:

 [tex]\rm Ksp = [Pb^{2+}][I^-]^2[/tex]

Where, [tex]\rm [Pb^{2+}][/tex] is the concentration of [tex]\rm Pb^{2+ }[/tex] ions in solution and [tex]\rm [I^-][/tex] is the concentration of [tex]\rm I^-[/tex] ions in solution.

3. The solubility of  [tex]\rm PbI_2[/tex] is [tex]1.52\times 10^{-3 }[/tex] mol/L. Since [tex]\rm PbI_2[/tex] dissociates into one  [tex]\rm Pb^{2+ }[/tex] ion and two [tex]\rm I^-[/tex] ions, the concentration of  [tex]\rm Pb^{2+ }[/tex] in solution is equal to the solubility of  [tex]\rm PbI_2[/tex], which is [tex]1.52\times 10^{-3 }[/tex] mol/L.

[tex]\rm [Pb^{2+}] = 1.52\times 10^{-3}\ mol/L[/tex]

4. Since  [tex]\rm PbI_2[/tex] dissociates into one [tex]\rm Pb^{2+ }[/tex] ion and two  [tex]\rm I^-[/tex] ions, the concentration of  [tex]\rm I^-[/tex] ions in solution is twice the solubility of  [tex]\rm PbI_2[/tex] .

[tex]\rm [I^-] = 2 \times 1.52\times 10^{-3 }\ mol/L[/tex]

= [tex]3.04\times 10^{-3}[/tex] mol/L

5. The solubility product of  [tex]\rm PbI_2[/tex] can be calculated using the expression for Ksp and the concentrations of [tex]\rm Pb^{2+ }[/tex] and  [tex]\rm I^-[/tex] ions in solution.

[tex]\rm Ksp = [Pb^{2+}][I^-]^2[/tex]

=  [tex]1.52\times 10^{-3 }[/tex]  [tex]\times[/tex] [tex]\rm (3.04\times 10^{-3} mol/L)^2[/tex]

= [tex]1.40\times 10^{-8}[/tex]

Therefore, the dissolution reaction of [tex]\rm PbI_2[/tex] in water, expression for Ksp for [tex]\rm PbI_2[/tex], the concentration of Pb2+ in the equilibrium solution, the concentration of I- in the equilibrium solution and solubility product of  [tex]\rm PbI_2[/tex] is mentioned above.

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