(d) Explain the trend in the boiling points in the table above.

The detection time when an industrial process wastewater contains a mixture of metal fragments and sand is 1392.8 seconds.

From the information regarding the industrial process wastewater, the settling velocity for the sand particles will be:

= 9.81/[18(1.002 × 10^-6] × (2.65 - 1) × (0.04 × 10^-³)²

= 0.001435

Therefore, the detection time will be:

t = 2/0.001435

t = 1392.8 seconds.

The detection time is 1392.8 seconds.

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[tex]\large \sf\underline{Question:}[/tex]

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[tex]\large \sf\underline{Answer:}[/tex]

[tex] \qquad \qquad \huge \bold{Option \: B}[/tex]

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[tex]\large \sf\underline{Explanation:}[/tex]

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Answer: 2.749 x 10^-14

Explanation:

Given:

The concentration of Ce(IO3)4 in the solution = 1.5 x 10-2 g/100 mL= 0.15 g/1000 mL​​​​​​​= 0.15 g/L

Molar mass of Ce(IO3)4 = 839.7267 g/mol

Therefore, the molarity of Ce(IO3)4 in the solution is given by:

[tex]$$\begin{gathered}M=\frac{0.15 \mathrm{~g} / L}{839.7267 \mathrm{~g} / \mathrm{mol}} \\M=1.7863 \times 10^{-\mathbf{4}} \mathrm{mol} / {L}=\mathbf{1 . 7 8 6 3 \times 1 0 ^ { - \mathbf { 4 } } \boldsymbol { M }}\end{gathered}$$[/tex]

The solubility equilibrium is given by:

[tex]$$\mathrm{Ce}\left(\mathrm{IO}_{3}\right)_{4(s)} \rightleftharpoons \mathrm{Ce}_{(a q)}^{3+}+3 \mathrm{IO}_{3}^{-}(a q)$$[/tex]

Therefore, the solubility product is given by:

[tex]\begin{gathered}K_{s p}=\left[C e^{3+}\right] \cdot\left[I O_{3}^{-}\right]^{3} \\\therefore K_{s p}=\left(1.7863 \times 10^{-4}\right) \times\left(3 \times 1.7863 \times 10^{-4}\right)^{3}\end{gathered}[/tex]

[tex]\therefore {K_{s p}=2.749 \times 10^{-14}[/tex]

The change in vapor pressure when 74.10 g fructose, C6H12O6, are added to 181.5 g water is 0.146.

Vapor pressure is the  measure or tendency of  a substance to change into a vapor or gaseous state.

[tex]\rm Mole\; fraction\; of\; water = \dfrac{nH_2O}{nH_2O+npent.}[/tex]

Calculate the moles of water and fructose

[tex]\rm Number\;of \;moles= \dfrac{181.5 g}{18.02}= 10.072\\\\\rm Number\;of \;moles= \dfrac{74.10 g }{180.156 g/mol}=0.4113[/tex]

The total number of moles are

[tex]\dfrac{10.072}{10.072 + 0.486} = \dfrac{10.072}{10.558} = 0.953[/tex]

Calculating the vapor pressure

0.953 x 3.1690 kPa = 3.023

Change in vapor pressure

3.1690 kPa - 3.023 = 0.146

Thus, the  change in vapor pressure is 0.146.

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Moles of oxygen

2 mol reactants required for 3mol O_2

So our answer is 2

Answer:1950-200

Explanation:

During 1950-2000​ of the following 50-year intervals has the world's population increased the most. Hence, option D is correct.

The whole number of people or inhabitants in a country or region.

The world's population increased from 2.5 billion in 1950 to around 7.3 billion in 2015 and is expected to continue to rise until 2050/2100 under most UN.

During 1950-2000​ of the following 50-year intervals has the world's population increased the most. Hence, option D is correct.

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According to the research, levers are used to modify or generate a force and transmit displacement.

It is a simple machine composed of a rigid bar of some moderately resistant material, which rotates freely on a support point.

It can be used to maximize the mechanical force applied to an object, increasing its speed or the distance it travels, by applying a proportionally smaller amount of force.

Therefore, we can conclude that according to the research, levers are used to modify or generate a force and transmit displacement.

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Answer:

stroke

Explanation:

Answer:

Diamond.

Graphite.

Fullerene

Explanation:

these are three crystalline forms of carbon.

Answer: RATIOS IN TERMS OF MOLES

Solution: Solution According to the balanced equation, 2 moles of NH3 are produced when 3 moles of H2 react.

Answer:

H3PO4 + H2O (Phosphoric acid + Water)

Explanation:hope its help

Answer:

I think the answer might be yes..

Answer:

= 1.35M

Explanation:

data:

volume = 437ml

               = 437 /1000

                 = 0.437dm^3

no. of moles = 0.590 moles

solution:

        molarity = [tex]\frac{no. of moles}{volume in dm^3}[/tex]

                       = 0.590 / 0.437

        molarity = 1.35M

Answer:

5.4 moles CaO   1 mole CaCl₂   5.4 mole CaCl₂

                           1 mole CaO

Explanation:

Answer:

85.4

Explanation:

Answer:

that is your answer hope this helps u

The number of moles in 72 gram H₂O is 3.942 MOL.

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

First, know the molar mass of water.

The given mass is 71 gram

[tex]\rm Number\;of \;moles= \dfrac{mass}{molar\;mass}\\\\\rm Number\;of \;moles= \dfrac{71}{18.01}= 3.942 mol[/tex]

Thus, the number of moles in 72 gram H₂O is 3.942 MOL.

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See

NaOH was in solid state

Both the solute and solvent turns to aqueous i.e liquid form .

So

So

Answer:

B. Spectator ions

Explanation:

Spectator ions are described as spectators literally because they "spectate", or, in other words, do not participate in the overall reaction. They may show up in the reaction equation, but they don't react themselves.

Thus, spectator ions stay unchanged throughout a reaction. We see many spectator ions in precipitation reactions. Remember that ionic compounds disassociate in solution.

For example, the reaction between silver nitrate [tex]AgNO_{3}[/tex] and sodium chloride [tex]NaCl[/tex] produces a solid precipitate of silver chloride [tex]AgCl[/tex] as represented by the equation below:

[tex]Ag^+_{(aq)} + NO^-_{3(aq)}+Na^+_{(aq)}+Cl^-_{(aq)}[/tex] -------> [tex]AgCl_{(s)}+Na^+_{(aq)}+NO_{3(aq)}^-[/tex]

However, the sodium and nitrate ions remained aqueous, like before, so they did not react. Thus, they are spectator ions.

Answer:

5.09 moles of Fe is required to react with 3.82 moles of O₂.

0.326 moles of O₂ are needed to produce 34.7 grams of Fe₂O₃.

Reaction stoichiometry

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Fe: 4 moles

O₂: 3 moles

Fe₂O₃: 2 moles

The molar mass of the compounds is:

Fe: 55.85 g/mole

O₂: 32 g/mole

Fe₂O₃: 159.7 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Fe: 4 moles ×55.85 g/mole= 223.4 grams

O₂: 3 moles ×32 g/mole= 96 grams

Fe₂O₃: 2 moles ×159.7 g/mole= 319.3 grams

Moles of Fe needed

The following rule of three can be applied: If by stoichiometry of the reaction 3 moles of O₂ react with 4 moles of Fe, 3.82 moles of O₂ react with how many moles of Fe?

moles of Fe= 5.09 moles

Finally, 5.09 moles of Fe is required to react with 3.82 moles of O₂.

Moles of O₂ needed

The following rules of three can be applied: If by reaction stoichiometry 319.3 grams of Fe₂O₃ are formed from 3 moles of O₂, 34.7 grams of Fe₂O₃ are formed from how many moles of O₂?

moles of O₂= 0.326 moles

Finally, 0.326 moles of O₂ are needed to produce 34.7 grams of Fe₂O₃.

Explanation:

Answer:

3.40⋅1022 helium atoms weigh 0.226 gram.

Explanation:

Answer:

b

Explanation:

That is the defintion of pH

At STP one mol weighs 22.4L

Moles of O_2

1 mol.O_2 can create 2mol water

moles of water

Volume of water

Answer:

The given equation is:

N2H4(l) + O2(g) → N2(g) + 2H2O(g)

From the periodic table:

Therefore:

molar mass of N2H4 = 2(14) + 4(1) = 32 grams

mass of water = 2(1) + 16 = 18 grams

From the balanced equation:

1 moles of N2H4 produces 2 moles of H2O.

32 grams of N2H4 produce 18*2=36 grams of water

To know the mass of N2H4 needed to produce 96 grams of water, all you need to do is cross multiplication as follows:

Answer:

2.35 atm

Explanation:

According to the Ideal Gas Equation,

Here :

Solving :

They have no definite shape and no definite volume because they are gases.

Gases have no definite shape and no definite volume because they are present in free state. Those substances that are close together and held tightly have definite shape and volume.

So we can conclude that they have no definite shape and no definite volume because they are gases.

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The pressure of the N₂ collected if the temperature was 22°C celcius is 98.6823 kPa.

What is atmospheric pressure?

The air around you has weight, and it presses against everything it touches. That pressure is called atmospheric pressure, or air pressure.

Atmospheric pressure = 101.325 kPa

Vapor pressure of water at 22°C = 2.6427 kPa

Pressure of N₂ = (Atmospheric pressure) - (vapour pressure of water at 22°C)

Pressure of N₂ = (101.325 kPa) - ( 2.6427 kPa)

Pressure of N₂ = 98.6823 kPa

Therefore, the pressure of the N₂ collected if the temperature was 22°C celcius is 98.6823 kPa.

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56.5

Explanation:

the degradation would be 28.25 times 2