The centroid of the region bounded from above by the curve y = 4x - x² and below by the curve y = x is (2/3, 4/3).
The region is bounded from above by the curve y = 4x - x² and below by the curve y = x. We need to find the points of intersection between these two curves. Setting the equations equal to each other,
4x - x² = x
Rearranging,
x² - 3x = 0
Factoring,
x(x - 3) = 0
So, x = 0 or x = 3.
The region is bounded from x = 0 to x = 3. To find the y-values within this region, we evaluate the equations y = 4x - x² and y = x at these x-values.
For x = 0,
y = 4(0) - (0)² = 0
For x = 3,
y = 4(3) - (3)² = 12 - 9 = 3
Thus, the y-values within the region are y = 0 to y = 3. Now, we calculate the area of the region by integrating the difference of the upper and lower curves,
A = ∫[0,3] [(4x - x²) - x] dx
A = ∫[0,3] (3x - x²) dx
A = [3x²/2 - x³/3] evaluated from x = 0 to x = 3
A = [27/2 - 9/3] - [0 - 0]
A = [27/2 - 3] - 0
A = 21/2
Now, for the centroid,
x = (1/A) * ∫[0,3] x * [(4x - x²) - x] dx
Simplifying,
x = (1/A) * ∫[0,3] (3x² - x³) dx
x = (1/A) * [x³ - x⁴/4] evaluated from x = 0 to x = 3
x = (1/A) * [(3)³ - (3)⁴/4] - [0 - 0]
x = (1/A) * [(27) - (81)/4] - 0
x = (1/A) * [(108 - 81)/4]
x = (1/A) * (27/4)
x = 27/(4A)
x = 27/(4 * 21/2)
x = 2/3, and,
x = (1/A) * ∫[0,3] [(4x - x²) - x]² dx
Simplifying,
y = (1/A) * ∫[0,3] (16x² - 8x³ + x⁴) dx
y = (1/A) * [(16x³/3 - 8x⁴/4 + x⁵/5)] evaluated from x = 0 to x = 3
y = (1/A) * [(16(3)³/3 - 8(3)⁴/4 + (3)⁵/5)] - [0 - 0]
y = (1/A) * [(16 * 27/3 - 8 * 81/4 + 243/5)]
y = (1/A) * [(144/3 - 648/4 + 243/5)]
y = (1/A) * [(480 - 972 + 243)/60]
y = (1/A) * (480 - 972 + 243)/60
y = -83/(20A)
Since A = 21/2, we can substitute it in,
y = -83/(20 * 21/2)
y = -83/(210/2)
y = -83/(105)
y = -4/5
Therefore, the centroid of the region is (2/3, 4/3).
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Three lines intersect at a common point. In the figure below, m∠1=x°, m∠2=2x°, and m∠3=75°.
Which equations can be used to determine the value of x? Select all that apply.
A:3x°=75°
B:3x°=105°
C:3x°=255°
D:3x°+75°=180°
E:x°+2x°+75°=180°
F:x°+2x°+3x°=360
Answer:
3x=105,x°+2x°+75°=180°,and 3x°+75°=180°
Step-by-step explanation:
no explanation sorry,your welcome
Which one is true
1
2
3
4
Find the missing side lengths.
Need help please.
This is the 6th time I post.
Answer:
x = 9.238 y = 4.619
Step-by-step explanation:
I kind of forgot how to do sohcahtoa but we do cosine for one of them. I used a calculator but the lengths seems reasonable so I'm sure they should be right.
Plzz help it do today and ill mark u brainliest
1,278 is the answer.
Answer:
The 1st one is the correct one
8 x 6 = 48
48 x 21 =1008
9 x 5 = 45
45 x 6 = 270
1008 + 270 = 1278
After taking part in a competition, Seth received a silver medal with a diameter of 8 inches. What is the medal's circumference?
Use 3.14 for .
Answer: 25.12 inches
Step-by-step explanation:
C=2πr
8/2=4
2(3.14)(4)
2(12.56)
25.12
Answer:
25.12 inches
Step-by-step explanation:
So, the formula for circumference is πd (or πr² whichever you prefer. We already have the diameter, so we do π x d, which is π x 8 inches, which is equal to 25.12 inches.
This is correct only if you use π as 3.14 hope this helps :)
2/5 of 16 simplify if you can thank you
Answer:
6 and 2/5
Step-by-step explanation:
Answer:
Decimal form: 6.4
Fraction form: 32/5
Step-by-step explanation:
of = times
2/5 x 16 = 6.4
Two cities are 400 miles apart. If the scale on a map reads Inch = 50 miles , find the distance between the cities on the map,
Answer:
8 inches between cities
Step-by-step explanation:
The larger of two numbers is 6 more than the smaller integer. Their sum is 52, What are the numbers?
Arrange the given polynomial in descending order.
9x? + 9x +3+2x
1) The High View tourist train must climb a 6,000 foot high mountain. The tracks are at a 30° angle with the ground. What is the distance the train must travel from the base of the mountain to the peak of the mountain?
HELP PLS MARKING BRAINLIEST SHOW WORK IF YOU CAN IF NOT ITS COMPLETELY FINE JUST DO IT
Answer:
1824 in.
Step-by-step explanation:
First find the area of the two shapes you split that are the rectangle and triangle:
Rectangle Area:
48 * 32 = 1536
Area- 1536 in.
Triangle Area:
48 * 12 * 1/2
or
48 * 12 divided by 2
= 288 in.
Now add the two areas up:
1536 + 288 = 1824 in.
Answer:
1824
Step-by-step explanation:
I assume you want to find the area of the shape. So in order to find the area of the triangle it is height times base than divide it by 2 which looks like this
(12*48)/2 which equals 576
than to find the area of the rectangle it is height times width which is
48*32 which equals 1536
add them together and you get 1824
The following is the line 20 from table of random digits (Sec A.7 of the text book, pg 911). 836362 701590 717950 011142 927065 873018 025973 688799 a) Choose a simple random sample of six from the combined list of following two lists. b) Select a stratified random sample of 4 students and 2 faculty members. Students: Abel Fisher Huber Miranda Reinmann Moskowitz Carson Ghosh Santos hen Jimenez Griswold Jones Neyman Kim Shaw David Hein O'Brien Thompson Deming Hernandez Klotz Pearl Utts Elashoff Holland Liu Potter Varga Faculty: Andrews Fernandez Kim Besicovitch Gupta Lightman Moore West Vicario Yang
a) A simple random sample of six numbers from the given table is {836362, 701590, 717950, 011142, 927065, 873018}.
Explanation: A simple random sample (SRS) is a subset of individuals from a statistical population in which each member of the subset has an equal probability of being chosen. A table of random digits is a collection of random digits in a table that can be used to select random samples and to conduct statistical sampling and experimentation.
b) The data can be stratified into two categories: Students and Faculty. Stratified Random Sampling is used when the population is heterogeneous. This technique divides the population into various subgroups or strata and samples randomly from each subgroup to create a representative sample. Here, we need to choose 4 students and 2 faculty members.
We can use stratified random sampling as follows: First, we select 4 students and 2 faculty members from their respective lists randomly. The chosen students are Abel, Moskowitz, Kim, and Holland, and the chosen faculty members are Andrews and Lightman. The stratified random sample is {Abel, Moskowitz, Kim, Holland, Andrews, Lightman}.
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PLEASE HELP!!!!! (screenshot)
Answer:
The answer is A. y <= -3x + 3
Does there exist an 8 x 8 matrix A = (a) satisfying the following three conditions? (i) If i j then a = 0 (ii) a18 #0 (a18 denotes the entry in the first row and eighth column of A) (iii) A is diagonalizable If such a matrix exists, provide an example of one and prove that it satisfies the given three conditions. If no such matrix exists, prove that no such matrix exists
We need to determine whether an 8x8 matrix A exists that satisfies three conditions:
(i) having zeros below the main diagonal,
(ii) having a non-zero entry in the first row and eighth column, denoted as a18
(iii) being diagonalizable. In the second paragraph.
we will either provide an example of such a matrix and prove that it satisfies the conditions, or prove that no such matrix exists.
To provide an example of an 8x8 matrix A that satisfies the given conditions, we need to construct a matrix that satisfies each condition individually.
Condition (i) requires that all entries below the main diagonal of A are zero. This condition can easily be satisfied by constructing a matrix with zeros in the appropriate positions.
Condition (ii) states that a18, the entry in the first row and eighth column, must be non-zero. By assigning a non-zero value to this entry, we can fulfill this condition.
Condition (iii) requires that the matrix A is diagonalizable. This condition means that A must have a complete set of linearly independent eigenvectors. If we can find eigenvectors corresponding to distinct eigenvalues that span the entire 8-dimensional space, then A is diagonalizable.
If we are able to construct such a matrix that satisfies all three conditions, we can provide it as an example and prove that it fulfills the given conditions. However, if it is not possible to construct such a matrix, we can prove that no such matrix exists by showing that the conditions are mutually exclusive and cannot be satisfied simultaneously.
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Find an equation of the line through (2,6) and parallel to y=2x+3
Step-by-step explanation:
We first Find the Slope of the line y=2x+3
The Slope Intercept Form of the equation of a given line is:
y=mx+c
where m is the Slope of that line, and c is the Y intercept.
For this line, the Slope is 2
So the Slope of the line PARALLEL to y=2x+3 will also be 2. And we are given that it passes through the point (2,6)
The Point-Slope form of the Equation of a Straight Line is:
(y−k)=m⋅(x−h)
m is the Slope of the Line
(h,k) are the co-ordinates of any point on that Line.
Here, we have been given the coordinates (h,k) of 1 point on that line as (2,6)
And the Slope m is 2
Substituting the values of h,k and m in the Point-Slope form, we get
(y−2)=(2)⋅(x−6)
(y−2)=2⋅(x-6)
y−2=2x -12
y=2x -12 +2
y=2x-10
The graph will look like
graph{y=2x -10 10 [10, -10, 5, - 5]}
Prove or disprove, using any method, that if /25 Q, then it is the case that 25 – 17 € Q.
The statement if /[tex]\sqrt{25}[/tex]∉Q, then it is the case that [tex]\sqrt{25}[/tex] – [tex]\sqrt{17}[/tex] ∈ Q is false.
To disprove the statement, we need to provide a counter example where [tex]\sqrt{25}[/tex] ∉ Q (irrational) and [tex]\sqrt{25}[/tex] – [tex]\sqrt{17}[/tex] ∉ Q (also irrational).
Let's consider [tex]\sqrt{25}[/tex] = 5, which is a rational number since it can be expressed as a ratio of two integers (5/1).
In this case, [tex]\sqrt{25}[/tex] ∉ Q is false since it is a rational number.
Furthermore, [tex]\sqrt{25}[/tex] – [tex]\sqrt{17}[/tex] = 5 - [tex]\sqrt{17}[/tex] is also irrational since it cannot be expressed as a ratio of two integers.
Therefore, we have found a counterexample that disproves the statement, showing that if [tex]\sqrt{25}[/tex] ∉ Q, then it is not necessarily the case that [tex]\sqrt{25}[/tex] – [tex]\sqrt{17}[/tex] ∈ Q.
Hence, the statement is false.
Question: Prove or disprove, using any method, that if /[tex]\sqrt{25}[/tex]∉Q, then it is the case that [tex]\sqrt{25}[/tex] – [tex]\sqrt{17}[/tex] ∈ Q.
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HELP I NEED AN ANSWER REALLY FAST AND PLEASE EXPLAIN HOW YOU GOT THE ANSWER I WILL GIVE YOU THE CROWN!!!
Answer:
B
Step-by-step explanation:
Look at the chart you can find out by looking at 20 then your answers
Consider the system of equations below. Explain how you could use multiplication to help eliminate one of the variables.
x−5y=13
4x−3y=1
Answer:you cross multiply
Step-by-step explanation:
i hate tacos
A brine solution of salt flows at a constant rate of 8 min into a large tank that initially held 100 L of brine solution in which was dissolved o 3 kg of sall . The solution inside the tank is kept well stirred and flows out of the tank at the same rate. If the concentration of salt in the brine entering the tank is 003 kg/l determine the mass of salt in the tank after I min When will the concentration of salt in the tank reach 0.01 kg/L?
After 1 minute, the mass of salt in the tank will be 3.072 kg. The concentration of salt in the tank will reach 0.01 kg/L after approximately 31 minutes.
To determine the mass of salt in the tank after 1 minute, we need to consider the inflow and outflow of the brine solution. The rate of inflow is 8 L/min, and the initial concentration of salt in the solution is 0.03 kg/L. Therefore, after 1 minute, 8 L of brine solution with a concentration of 0.03 kg/L will enter the tank, resulting in an additional mass of salt of 0.24 kg (8 L * 0.03 kg/L).
Since the solution inside the tank is well stirred and flows out at the same rate, the outflow rate is also 8 L/min. Thus, after 1 minute, 8 L of the brine solution will leave the tank, taking away 0.24 kg of salt.Considering the initial mass of salt in the tank (3 kg) and the change in mass due to the inflow and outflow after 1 minute, the mass of salt in the tank after 1 minute will be 3 kg + 0.24 kg - 0.24 kg = 3.0 kg.
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Which is NOT true?
A 9 + 4 = 17 - 4
B 8 + 7 = 14 + 3
C 11 = 19 - 8
D 5 + 8 = 20 - 7
Answer:
B is not true
Step-by-step explanation:
8+7= 15 and 14+3= 17
15 is not equal to 17
Answer:
B is the one equation that is NOT true.
Step-by-step explanation:
A: 9+4 is 13, and 17-4 is 13 as well. This equation is true, 13=13.
B: 8+7 is 15, and 14+3 is 17. This equation is false, because 15 is not equal to 17. Although we have our answer, we need to still check the other equations.
C: 11 is, well, 11, because nothing changed on that side of the equation. 19-8 is 11, so this is true because 11=11.
D: 5+8 is 13, and 20-7 is 13. This equation is also true, because 13=13.
The only equation that is not true, is B. (8+7 = 14+3)
Dot plot A is the top plot. Dot plot B is the bottom plot.
According to the dot plots, which statement is true?
The mean of the data in dot plot A is less than the
mean of the data in data plot B.
The median of the data in dot plot A is greater than the
median of the data in dot plot B.
The mode of the data in dot plot A is less than the
mode of the data in dot plot B.
The range of the data in dot plot A is greater than the
range of the data in dot plot B.
Please help I’m giving BRAINLIEST
Answer:
The median of plot A is greater that the median of plot B
Step-by-step explanation: the median on plot A is 45 and the median on plot B is 15
1)The mean of the data in plot A is greater than the
mean of the data in plot B.
2) The median of the data in plot A is greater than the
median of the data in dot plot B.
3) The range of the data in plot A is greater than the
range of the data in plot B.
What is the median?
The median is the middle number in a sorted, ascending, or descending, list of numbers.
Let us arrange the data of plot A in ascending order:
30,35,35,40,40,40,40,45,45,45,45,50,55,55,60
Number of observations = 15
Mean of the plot A = 44
Median will be the middle observation i.e. 8th observation i.e. 45
Let us arrange the data of plot A in ascending order:
5,5,5,10,10,10,10,15,15,15,20,20,25,30,35
Number of observations = 15
Mean of the plot B = 15.33
Median will be the middle observation i.e. 8th observation i.e. 15
Therefore,1)The mean of the data in plot A is greater than the
mean of the data in plot B.
2) The median of the data in plot A is greater than the
median of the data in dot plot B.
3) The range of the data in plot A is greater than the
range of the data in plot B.
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PLz hlep will mark brain list
Answer:
20
Step-by-step explanation:
Find the difference of the smallest value and the largest value.
Answer:
30 minus 10 then the range is 20
i need help pls ill give branilest
If u can now pls arigato
Answer:
1) A segment is a "part" of a line that is delimited by two points, such that it starts in a point and ends in another.
In segments the "endpoints" can commute, so is the same DA as AD.
In the image we can see 3 segments:
DA
AS
DS
2) A ray starts in a point and passes through another point, extending infinitely.
In this case, the ray DA is different than the ray AD, because the ray DA starts in D and extends to the right (because point A is at the right of point D) infinitely.
And the ray AD starts in A and extends to the left infinitely (because point D is at the left of point A).
Also, because A and S are colinear, the rays:
ray DA = ray DS
Both of them start on D and extend infinitely to the right.
Then the rays we can see on this image are:
ray DA = ray DS
ray AS
ray SA = ray SD
ray AD.
4 rays in total.
3) The names of the segments are the ones we wrote in point 1.
DA
DS
AS
4) The segment that connects point D with point S is the segment DS.
5) The ray AS starts at A and goes to the right, then the one that goes toward the opposite of AS would be one that starts at A and goes to the left.
That one is the ray AD.
Which is greater 52,800 cm or 1 km?
Answer:
1 km
Step-by-step explanation:
According to the unit of conversion in every 1 kilometer, there is a total of 100 000 centimeters. Now, the given value of centimeters is equals to 52 800 => 1 km = 100 000 cm => 52 800 cm is less than the value of 100 000 cm which is equivalent to 1 km. Thus, the given is not correct.
Write the polnt-slope form of the equation of the line passing through the points (-5, 6) and (0, 1).
y- 6 = 1(x + 5)
y+6= -1(x - 5)
y- 6 = -1(x + 5)
y+ 6 = 1(x - 5)
Answer:
y - 6 = -1 (x+5)
Step-by-step explanation:
1) First, find the slope of the line. Use the slope formula [tex]m = \frac{y_2-y_1}{x_2-x_1} \\[/tex]. Substitute the x and y values of (-5,6) and (0,1) into the formula and simplify like so:
[tex]m = \frac{(1)-(6)}{(0)-(-5)} \\m = \frac{1-6}{0+5} \\m = \frac{-5}{5} \\m = -1[/tex]
So, the slope of the line is -1.
2) Now we have enough information to write the equation of the line in point-slope form. Use the point-slope formula [tex]y-y_1 = m (x-x_1)[/tex] and substitute real values for the [tex]m[/tex], [tex]x_1[/tex], and [tex]y_1[/tex].
Since [tex]m[/tex] represents the slope of the line, substitute -1 in its place. Since [tex]x_1[/tex] and [tex]y_1[/tex] represent the x and y values of a point the line intersects, substitute the x and y values of (-5, 6) in those places as well. This gives the following equation and answer:
[tex]y-6 = -1(x+5)[/tex]
Consider following samples to , 37, 47, 32, 42, 21, 28, 22, 35, 28, 21, 29, 37, 23, 23 Data points are independently sampled from uniform distribution with the density function f(x) = 1/a where 0<=x<=a. Use method of moments to estimate a.
The estimated value of "a" using the method of moments is 47.
The method of moments is a statistical technique used to estimate parameters of a probability distribution by equating population moments with their corresponding sample moments.
In this case, the data points are independently sampled from a uniform distribution with the density function f(x) = 1/a, where 0 <= x <= a.
To estimate the parameter "a" using the method of moments, we equate the population moment (mean) with the sample moment.
The population mean (μ) of a uniform distribution with density function f(x) = 1/a is given by:
μ = (a + 0) / 2 = a/2
The sample moment is calculated as the average of the data points:
Sample mean = (22 + 23 + 23 + 28 + 28 + 29 + 32 + 35 + 37 + 37 + 42 + 47) / 13 ≈ 31.23
Equating the population mean and the sample mean:
a/2 = 31.23
Solving for "a":
a = 2 * 31.23 = 62.46
Since "a" represents the upper limit of the uniform distribution, it should be a real number. Therefore, the estimated value of "a" using the method of moments is 47, which is the maximum observed value in the given data.
Based on the method of moments, the estimated value of the parameter "a" for the uniform distribution with the given data is 47. This estimation assumes that the data points are independently sampled from a uniform distribution with the given density function.
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Question 1 (1 point)
A decorator is wallpapering a wall with a circular window of diameter 1.00 m.What is the
area of the wall in square feet? (1 m - 3.2808 feet)
3
Answer:
95.875 [tex]ft^{2}[/tex]
Step-by-step explanation:
1.) Calculate the area of the trapezoid
A(trapezoid) = (1/2)*(base1 + base2)*h = (1/2)*(2.6+3.6)*3 = (1/2)*6.2*3 = 9.3
2.) Calculate the area of the circle
radius = (1/2)*(diameter) = (1/2)*1 = 0.5
A(circle) = (1/2)*[tex]\pi[/tex]*[tex]r^{2}[/tex] = (1/2)*[tex]\pi[/tex]*([tex]0.5^{2}[/tex]) = (1/2)*[tex]\pi[/tex]*0.25 = 0.125*[tex]\pi[/tex] = 0.392699
3.) Because the area of the circle is not included in the wall, subtract the area of the circle from the area of the trapezoid:
A(trapezoid)-A(circle) = 9.3-0.392699 = 8.9073 [tex]m^{2}[/tex]
4.) Convert to [tex]ft^{2}[/tex]:
Because 3.2808 feet are in a meter and the unit of the answer is in [tex]m^{2}[/tex], we need to multiply the answer by ([tex]3.2808^{2}[/tex]) to get to [tex]ft^{2}[/tex].
8.9073*([tex]3.2808^{2}[/tex]) = 8.9073*10.7636 = 95.875 [tex]ft^{2}[/tex]
Finance Name: This project has two problems centered around finance - one question about the mathematical explosion of compound interest and the other about the stock market. Problem 1 1. Let's use mathematics to see why time is so important when it comes to saving for retirement. Suppose you have $10,000 to invest in a mutual fund that averages a 12% annual return. a) After 5 years, what is the value of the fund? Explain or show your work. b) After 10 years, what is the value of the fund? Explain or show your work. c) After 20 years, what is the value of the fund? Explain or show your work. d) it looks like time doubles in parts b) and c) from 10 to 20 years. Does the account value also double? if not, why not?
The value of the funds are A) $5,674.27 b) $3219.73 c) $1036.37
What Net Present Value?Rerecall that Net Present Value (NPV) is the difference between the present value of cash inflows and outflows over a period of time. It is used in capital budgeting and investment planning to analyze the profitability of a projected investment or project.
Cost of investment = $10,000
averages a 12% annual return.
a) After 5 years,
The value of the fund PV = FV/(1 + r)ⁿ
PV = 10,000/1+0.12)⁵
PV = 10000/(1.12)⁵
PV = 10000/1.762341683
PV = 5,674.27
The net present value of the investment after 5 years is $5674.27
b) After 10 years,
The value of the fund is PV = 10,000/1+0.12)¹⁰
PV = 10000/(1.12)¹⁰
PV = 10000/3.105848208
PV = 3219.73
The net present value of the investment after 5 years is $3219.73
c) After 20 years
The value of the fund is PV = 10,000/1+0.12)²⁰
PV = 10000/(1.12)²⁰
PV = 10000/9.646293093
PV = 1036.37
The net present value of the investment after 5 years is $1036.37
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NO LINKS PLZ, BUT I RLLY NEED HELP!
Answer:
Step-by-step explanation:
b