Consider the growth function f(x)=200(1.08). Describe the characteristics of the functions by using the drag and drop feature

Consider The Growth Function F(x)=200(1.08). Describe The Characteristics Of The Functions By Using The

Answers

Answer 1

Answer:

1) Domain: -∞ < x < +∞

2) Range: y > 0

3) y intercept: (0, 200)

4) Asymptote: y = 0

5) The growth rate; r = 0.08

6) The growth factor = 1.08

7) End Behavior: As x → -∞, f(x) → 0

8) End Behavior: As x → +∞, f(x) → +∞

Step-by-step explanation:

1) The domain of the function is given as the x values for which the function is valid which includes from -∞ < x  to +∞

2) The range of the function, are the range of the output values of the function for the given range of the input values

For the function, f(x) = 200·(1.08)ˣ, we have, f(x) = y > 0, for all values of x

3) The y-intercept is the value of y, when x = 0, given as follows;

y intercept = f(0) = 200·(1.08)⁰ = 200 × 1 = 200

4) The asymptote is the line that the function approaches but never reaches

In the question, as x tends to -∞, the function f(x) approaches 0. Therefore, f(x) = y = 0 is the asymptote of the function

5) The growth rate of an exponential function, y = a(1 + r)ˣ is r

Therefore, for the function, 200·(1.08)ˣ, which is equivalent to 200·(1 + 0.08) ˣ, the growth rate = 0.08

6) The growth factor of an exponential function, y = a(1 + r)ˣ is (1 + r)

Therefore, for the function, 200·(1.08)ˣ, which is equivalent to 200·(1 + 0.08) ˣ, the growth factor = (1 + 0.08) = 1.08

7) The end behavior as x tends to -∞, [tex]f(x) = y= 200 \cdot (1.08) ^{-\infty} \rightarrow 0[/tex]

8) The end behavior as x tends to +∞, [tex]f(x) = y= 200 \cdot (1.08) ^{-#+\infty} \rightarrow + \infty[/tex]

Answer 2

The texts that complete the blanks are:

Domain: -∞ < x < +∞Range: y > 0y intercept: (0, 200)Asymptote: y = 0The growth rate; r = 0.08The growth factor = 1.08End Behavior: As x → -∞, f(x) → 0End Behavior: As x → +∞, f(x) → +∞

The domain

The domain of an exponential function is all set of real numbers.

So, the domain is: -∞ < x < +∞

The range

The range of an exponential function is always greater than 0.

So, the range is y > 0

The y-intercept

This is when x = 0.

So, we have:

[tex]f(x) = 200(1.08)^x[/tex]

This gives

[tex]f(0) = 200(1.08)^0[/tex]

[tex]f(0) = 200[/tex]

So, the y-intercept is (0,200)

The asymptote

This is the line that is close to the function but is not on the function.

The range is:

y > 0.

So, the asymptote is y = 0

The growth rate and the growth factor

The function is given as:

[tex]f(x) = 200(1.08)^x[/tex]

The growth factor is 1.08, while the growth rate (r) is calculated as:

[tex]r = 1.08 - 1[/tex]

[tex]r = 0.08[/tex]

Hence, the growth rate is 0.08, and the growth factor is 1.08

The end behavior

The end behavior of an exponential growth function is:

a x → -∞, f(x) → 0 and as x → +∞, f(x) → +∞

Read more about exponential function at:

https://brainly.com/question/11464095


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Answer:

3

Step-by-step explanation:

Step-by-step explanation:

First, subtract  

7

from each side of the equation to put the equation in standard form:

x

2

+

4

x

+

4

7

=

7

7

x

2

+

4

x

3

=

0

We can now use the quadratic formula to find the solutions for  

x

. The quadratic formula states:

For  

a

x

2

+

b

x

+

c

=

0

, the values of  

x

which are the solutions to the equation are given by:

x

=

b

±

b

2

(

4

a

c

)

2

a

Substituting:

1

for  

a

4

for  

b

3

for  

c

gives:

x

=

4

±

4

2

(

4

1

3

)

2

1

x

=

4

±

16

(

12

)

2

x

=

4

±

16

+

12

2

x

=

4

±

28

2

x

=

4

±

4

7

2

x

=

4

±

4

7

2

x

=

4

±

2

7

2

x

=

4

2

±

2

7

2

x

=

2

±

7

Or

x

=

2

+

7

and  

x

=

2

7

The number of students, SSS, serviced by the school system in the town of Emor, ttt years from 2000 can be modeled by the function S(t)=10{,}000(1.1)^t. The number of classrooms, C, in the town of Emor, t years from 2000 can be modeled by the function C(t)=450+40t. Let D be the average number of students per classroom in Emor's school system t years from 2000.

Answers

Answer:

The formula of D (t) is .1000.(1.1)/45+4t

Step-by-step explanation:

The expression representing the number of students serviced by the school system in the town of Emor, t years from 2000 is:

And the expression representing the number of classrooms in the town of Emor, t years from 2000 is: s(t)=10,000.(1.1)^t

The expression D (t) represents the average number of students per classroom in Emor's school system t years from 2000.

Then the average number of students per classroom can be computed by:

C(t)=450+40t.

Average number of students/classroom = Number of students/Number of classrooms so the answer is D (t) .1000.(1.1)/45+4t

                                                         

                                                                 

Thus,the formula of D (t) is .

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The answer is 3.48 because 0.87 multiplied by 4 is 3.48

Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

If they are perpendicular it means they cross at a 90 degree angle so since both L and M are perpendicular to N both the answers would be 90

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Answers

Answer:

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Step-by-step explanation:

Given that:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Answer:

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