Consider the function g(x) shown below over a domain of [1,∞).
g(x) = 2(x – 1)2 – 3
Part A
Determine g–1(x).
Part B
Identify the domain and range of g(x) and g–1(x). Represent the domains and ranges in inequality, interval, and set notation. Describe the relationship between the domains and ranges of g(x) and g–1(x).
Part C
Graph g(x) and g–1(x). Describe the relationship between the graphs of g(x) and g–1(x).
Answers
The inverse of a function may or may not be a function
The function g(x) is given as:
[tex]g(x) = 2(x - 1)^2 - 3[/tex]
(a) Inverse function g^-1(x)
We have:
[tex]g(x) = 2(x - 1)^2 - 3[/tex]
Replace g(x) with y
[tex]y = 2(x - 1)^2 - 3[/tex]
Swap the positions of x and y
[tex]x = 2(y - 1)^2 - 3[/tex]
Add 3 to both sides
[tex]x + 3 = 2(y - 1)^2[/tex]
Divide both sides by 2
[tex]\frac{x + 3}2 = (y - 1)^2[/tex]
Take square roots of both sides
[tex]\sqrt{\frac{x + 3}2} = y - 1[/tex]
Add 1 to both sides
[tex]1 + \sqrt{\frac{x + 3}2} = y[/tex]
Rewrite as:
[tex]y = 1 + \sqrt{\frac{x + 3}2}[/tex]
Express as inverse function of g
[tex]g^{-1}(x) = 1 + \sqrt{\frac{x + 3}2}[/tex]
Hence, the inverse function of g is [tex]g^{-1}(x) = 1 + \sqrt{\frac{x + 3}2}[/tex]
(b) The domain, and the range of g(x) and g^-1(x)
Function g(x)
The function g(x) is a quadratic function.
So, the domain is:
Inequality: [tex]-\infty < x < \infty[/tex]Interval: [tex](-\infty ,\infty)[/tex]Set: {R}The range is:
Inequality: [tex]f(x) \ge -3[/tex]Interval: [tex][-3 ,\infty)[/tex]Set: [tex]\{y|y\ge -3\}[/tex]Function g^-1(x)
The function g^-1(x) is a square root function.
So, the domain is:
Inequality: [tex]x \ge -3[/tex]Interval: [tex][-3 ,\infty)[/tex]Set: [tex]\{x|x\ge -3\}[/tex]The range is:
Inequality: [tex]-\infty < y < \infty[/tex]Interval: [tex](-\infty ,\infty)[/tex]Set: {R}The domain of g(x) is the range of g^-1(x), while the range of g(x) is the domain of g^-1(x).
(c) The graph
See attachment for the graph
Read more about inverse functions at:
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Answers
Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Explainations
he first step that Sarah performed to simplify the expression StartFraction 4(6.8 minus 4.2) plus 8.2 over 2 EndFraction before entering it into the calculator is shown.
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Which statement is true?
Sarah performed the first step correctly.
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Sarah performed the first step correctly.
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[tex]\dfrac{4(6.8-4.2)+8.2}{2}[/tex]
To simplify the function, the first step Sarah carries out is to divide the numerator by 2:
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
Slope-intercept form: y = mx + b
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To divide fractions you keep (the first equation), change (the division sign to multiplication), and flip (the second fraction).
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Step 2: Plug slope and a point into y=mx+b to solve for b.[tex]\frac{11}{12}[/tex] = ([tex]\frac{1}{2}[/tex])*([tex]\frac{1}{3}[/tex])+b
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Answer:
The slope of this parallel line is 3.
Step-by-step explanation:
Parallel lines have the same slope. The given line y = 3x - 2 has the slope 3. Therefore the desired parallel line also has the slope 3. This is all that is necessary to answer this question.
The slope of this parallel line is 3.