Consider the following declaration for a two-dimensional array.
int[][] grid new int [7] [4];
int c = 0;
for (int i = 0; i < grid.length; i++)
(
}
for (int j = 0; j < grid[i].length; j++)
(
grid[i][j] = c;
C++;
}
What element is displayed when the following line of code is
executed?
System.out.println(grid[3][2]);

Answers

Answer 1

The output of the line System.out.println(grid[3][2]) will be: 11.

In the given code snippet, a two-dimensional array named grid is declared with dimensions 7 rows and 4 columns. The code then initializes the elements of the array using a nested loop.

The loop iterates over each row (i) and then each column (j) within that row.

The variable c is used to assign a value to each element of the array in a sequential manner, starting from 0 and incrementing by 1 with each iteration of the inner loop.

When the line of code System.out.println(grid[3][2]); is executed, it accesses the element at row 3 and column 2 of the grid array.

Since arrays in Java are zero-indexed, the row and column indices start from 0. In this case, grid[3][2] refers to the element in the fourth row (index 3) and the third column (index 2) of the array.

Considering the given loop logic, the elements of the grid array are assigned values in a sequential manner.

Therefore, when System.out.println(grid[3][2]) is executed, it will display the value that corresponds to the element at the intersection of the fourth row and the third column of the grid array.

Given that the elements are assigned values starting from 0 and incrementing sequentially, the value displayed will be the third value in the fourth row of the array, which is 11.

Therefore, the output of the line System.out.println(grid[3][2]) will be: 11.

This assumes that no modifications are made to the array between its initialization and the execution of the System.out.println statement.

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