Conservation efforts have been effective in _______.
a.
increasing the number of endangered species
b.
reducing all the negative impacts of human activity
c.
preserving wildlife habitats
d.
all of the above

We will take it Cm

Scale factor

So

#Mercury

Ven us

Earth

Mars

Jupiter

Saturn

#Uranus

Neptune

The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m toward + x.

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

The following are the x and y axes for the supplied vector:

Vector V in x direction;

[tex]\rm V_x = Vcos \theta \\\\ V_x = 448cos(224^0)\\\\ Vx = -322.26[/tex]

Vector V in y direction;

[tex]\rm V_y = Vsin \theta\\\\ V_y = 448 \times sin224^0\\\\ V_y = -311.2[/tex]

Vector W in x direction;

[tex]\rm W_x = 336 \times cos(75.9^0)\\\\ W_x = 81.86[/tex]

Vector W in y direction;

[tex]\rm W_y = 336 \times sin75.9\\\\\ W_y = 325.88[/tex]

The resultant vector in the x direction is;

∑X = -322.26 + 81.86

∑X == -240.4

The resultant vector in the y direction is;

∑Y = -311.2 + 325.88

∑Y  = 14.68

The resultant vector is found as;

[tex]\rm R =\sqrt{(-240.4)^2+(14.68)^2} \\\\R = 240.84 \ m[/tex]

Hence,  the direction of their vector sum is 240.84 toward +x-axis.

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This question involves the concept of Newton's Law of Gravitation.

The force of attraction will be changed to "D. 20 Newtons".

According to Newton's Law of Gravitation, the gravitational force of attraction between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically,

[tex]F=\frac{Gm_1m_2}{r^2}[/tex]

where,

Now, reducing the distance by half, we get:

[tex]F'=\frac{Gm_1m_2}{(\frac{r}{2})^2}\\\\F'=4\frac{Gm_1m_2}{r^2}\\\\F'=4F\\F'=4(5\ N)[/tex]

F' = 20 N

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Answer:

See image

Explanation:

Plato

Answer:

Animals follow the seasons very closely. Changes in the length of the day or temperature affect the animals' hormone production and cause them to behave according to the season. For that reason, animals instinctively know when it's time for them to mate, build a nest, fly south or stock up on food for the winter.

Answer:

One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2). The pascal is also used to measure stress, specifically tectonic stress in the Earth's plates.

Explanation:

Answer:

10.75 m/s

Explanation:

let  velocity of Dodgems b  be y

law of conservation of momentum

120 x 10 + 160 x 7=120x5+ 160 x y

1200+1120 = 600 + 160 x y

160y = 1720

y = 10.75 m/s

Answer:

0.315C

Explanation:

Force/Electric field

7520N/23900C

sine's law

h/sin 30 = 50/sin 60

h/0.5 = 50/(0.5√3)

h=28.9 m

Answer:

the units of work and energy is joule and unit of power is Watt

The acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is  8.933 m/s².

It is the acceleration caused by any object when placed on the surface on the Earth due to its weight.

The acceleration due to gravity is related to the distance as

g =GM/R²

where G is the gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

Given is the height R = 7 x 6.4 x 10⁶ m and mass of  Earth M = 6 x 10²⁴ kg

Substitute the values into the expression to find the acceleration due to gravity.

g = ( 6.67 x 10⁻¹¹ x 6 x 10²⁴)/ ( 7 x 6.4 x 10⁶)²

g = 8.933 m/s²

Thus,  the acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is  8.933 m/s².

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Answer:

3 m/s

Explanation:

Average velocity = Initial velocity + Final velocity / 2

Solving :

⇒ Average velocity = 2 + 4 / 2

⇒ Average velocity = 6/2

⇒ Average velocity = 3 m/s

if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity

So the average velocity is 3ms.

That states that the blackhole ends are working like bridges between one space to another.

This may be possible

Answer:

A

Explanation:

d = 1/2 a t^2 = 1/2 (4)(28^2) = 1568 m  ~ 1.6 x 10^3

[tex]speed_{avg} = \frac{Σ\:distance}{ total\: time}[/tex]

So, according to the question:

distance = 90 miles

time = 1h 45min + 15 min + 1h = 3h

[tex]Therefore:\\ speed_{avg} = \frac{90}{3} mph \\ = \boxed {30 \: mph}[/tex]

Answer:

0.5 m

Explanation:

To find wavelength (λ) : apply the formula

Solving :

In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.

In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.

The science lab is a place where the experiments related to the science background are performed with the use of apparatus.

The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.

Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.

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Answer:

[tex]\huge\boxed{\sf T = 0.67\ seconds}[/tex]

Explanation:

Given Data:

Cycles = c = 3 cycles

Time = t = 2 seconds

Required:

Time period = T = ?

Formula:

1) f = c/t

2) T = 1/f

Solution:

Finding frequency first:

f = c / t

f = 3/2

f = 1.5 Hz

Now, finding period:

T = 1/f

T = 1 / 1.5

T = 0.67 seconds

[tex]\rule[225]{225}{2}[/tex]

F=m.a

a = F/m

a = 90/65

a = 1.385 m/s²

Answer:

solution

here,

Explanation:

weight = 90N

mass=65kg

acceleration due to gravity (g)=??

Now,

w=m×g

90=65×g

90/65=g

:g=1.38m/s^2

The distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

Given that data in the question;

Note that;

1 miles = 1.609 kilometers

Now, the distance in kilometers will be;

distance = 25 miles

distance = ( 25 × 1.609 )kilometers

distance = 40.23km

Therefore, the distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

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a)A spherical convex mirror form the image at image distance is 8.57cm.

b) Mirror forms the image of height is 12.855 cm.

c)The magnification of the spherical convex lens is 0.4285.

The mirror which is a part of sphere with radius R is painted from inside forms the convex mirror.

The focal length of convex lens,  f = R/2

Given , the radius of mirror is R =30cm, the focal length will be

f =30cm/2 = 15cm

a) Object distance u =20 cm, object height =0.30m, then the image distance will be 1/f = 1/u + 1/v where v is the image distance from the lens.

1/15 = 1/20 + 1/v

v= 8.57 cm

Thus, the image distance is 8.57cm.

b) Ratio of image distance to the object distance is equal to the ratio of image height to the object height.

Substitute the values into the expression, we get the image height as

h(image) = 8.57/20 x 30

h(image) = 12.855 cm

Thus, the image height is 12.855 cm.

c) The magnification is the ratio of image height to the object height.

Putting the values, we have

= 12.855/30

= 0.4285

Thus, the magnification is 0.4285.

d) Size of object is large as compared to the size of image. Object distance is small as compared to the image distance. The image formed is virtual.

e)  The setup drawing is attached.

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Answer:

1.48kg

Explanation:

Here,

potential energy (P.E) = 29j

height (h) = 2m

acceleration due to gravity(g) =

[tex]9.8m {s}^{ - 2} [/tex]

mass(m) = ?

we know,

P.E = mgh

or, 29 = m×9.8×2

or, 29/19.6 = m

or,m = 1.48kg

The angle will the first diffraction minimum be found will be 0.034895°.

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The equation of diffraction grating is given as

[tex]\rm d= \frac{m \lambda}{sin \theta }[/tex]

The angle between the incident ray and the point of the occurrence of the diffraction is found as;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \lambda= (2.0))(\frac{1.00 \times 10^{-12}}{1\ pm} )\\\\\ \lambda=2.00 \times 10^{-12}[/tex]

The angle will the first diffraction minimum be found is;

[tex]\theta = sin^{-1}(\frac{m\lambda}{d} )\\\\\ \theta = sin^{-1}(\frac{1 \times 2.000 \times 10^{-12}}{1\times 10^{-12}} )\\\\\ \theta= 0.0348995^0[/tex]

Hence,the angle will the first diffraction minimum be found will be 0.034895°.

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Let's see

We need distance between them?

[tex]\\ \rm\Rrightarrow F=\dfrac{GMm}{r^2}[/tex]

[tex]\\ \rm\Rrightarrow r^2=\dfrac{GMm}{F}[/tex]

[tex]\\ \rm\Rrightarrow r^2=\dfrac{6.673\times 10^{-11}\times 8.1\times 10^2\times 4.5\times 10^8kg}{1.9\times 10^{-3}}[/tex]

[tex]\\ \rm\Rrightarrow r^2=128.02\times 10^{2}[/tex]

[tex]\\ \rm\Rrightarrow r^2=12802[/tex]

[tex]\\ \rm\Rrightarrow r=\sqrt{12802}[/tex]

[tex]\\ \rm\Rrightarrow r=113.14m[/tex]

The upward force F exerted by the biceps on the forearm will be 583 N.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The torque balancing equation is found as;

[tex]\rm \tau_i=\tau_R+\tau_F+\tau_{BB}=0\\\\ R(0)+F(0.0300)-(50.0)(0.350)\\\\ F=583 \ N[/tex]

Hence,the upward force F exerted by the biceps on the forearm will be 583 N.

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Answer:

A

Explanation:

Applying the First Equation of Motion :

⇒ v = u + at

⇒ v = 30 + (-6)(4)

⇒ v = 30 - 24

⇒ v = 6 m/s

Answer:

Resistors connected in series

The best estimate for the ratio of Power radiated per unit Area on Earth and Power radiated per unit Area on Venus is 1/16. The correct option is D.

Power radiated is directly proportional to the fourth power of Temperature at the surface and also to the cross-section area.

P = σ A T⁴

For 600 K at Venus, σ A T⁴ = σ A (600)⁴

For 300 K at Earth , σ A T⁴ = σ A (300)⁴

Comparing, we get

[σ A (300)⁴/ σ A (600)⁴ ] = 1/16

Thus, the the best estimate for the ratio is 1/16. The correct option is D.

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Explanation:

The pinna collects the sound waves and conducts them to the auditory canal. Sound waves struck at the ear drum and set it into vibration. Eustachian tube equalizes the pressure on either side of the ear drum and thus allows it to vibrate freely. Ear drum transmits the vibrations to ear ossicles.

Answer:

acts as a one-way switch for current