if a big person and a small person run up the stairs at the same time who has more force
Answer:
a big person
Explanation:
because the big person exerts more force over the same distance
Answer:
the big person exerts the largest force on the stairs because he weighs more
Explanation:
this question answer is ☝️☝️
Can someone please give me the (Answers) to this? ... please ...
Answers:
1. Newton's second law states that the force on an object is equal to its mass times its acceleration. Equation: F = ma, or force is equal to mass times acceleration.
2.
a=F/ma= 120N/68kga=(120 kg x m/s^2)/ (68kg)a = 1.8 m/s^23. a = 0.25 m/s^2
4. a = 0.4 m/s^2
is orange orange because its orange or is orange orange because its orange
Answer:
orange it is lol
Explanation:
Answer:
HELP ORANGE DOESNT LOOK LIKE A WORD ANYMORE
Explanation:
Two gravitational forces act on a
given object. How do you determine the total gravita-
tional force acting on the object?
Answer:
Explanation:
Depends on the location of the two forces. If they are aligned on the same side of the object, you would simply add.
X -----------F1 -------F2
X is the object. F1 and F2 are both masses which create a gravitational force. They both are the form of Fx = G * m1 * m2 / r^2. The total force is F1 + F2
If they are are on either side of the object, you subtract.
F1 ---------X ---------F2
Fx = F1 - F2
Any other location of F1 and F2 is much more complicated by the use of trigonometry.
Help me as soon as possible <3
Answer: ??? what the
Explanation:
The magnetic field 0. 02 m from a wire is 0. 1 T. What is the magnitude of the magnetic field 0. 01 m from the same wire? 0. 01 T 0. 05 T 0. 1 T 0. 2 T.
The magnitude of the magnetic field 0.01 m from the same wire is 0.2 T.
Given to us:
Magnetic field, [tex]B_1 = 0.1\ T[/tex]
Radius of wire, [tex]R_1 = 0.02\ m[/tex]
To find out the magnitude of the magnetic field 0. 01 m from the same wire, we need to find out current first. we will use the formula,
[tex]B = \dfrac{\mu_oI }{2\pi R},\\\rn\\where,\\B= magnetic\ field\\\mu_o = 4\pi\times 10^{-7} m\cdot kg\cdot s^{-2} A^{-2}\ is\ the\ magnetic\ constant\\I= current\\R= radius\ of\ the\ wire[/tex]
Putting the values,
[tex]B_1 = \dfrac{\mu_oI }{2\pi R_1},\\\rn\\\\0.1= \dfrac{4\times \pi \times 10^{-7}\times I}{2\times \pi\times0.02}\\\\I=10,000\ A[/tex]
Now, for [tex]B_2[/tex]
[tex]B_2 = \dfrac{\mu_oI }{2\pi R_2},\\\rn\\\\B_2= \dfrac{4\times \pi \times 10^{-7}\times 10,000}{2\times \pi\times0.01}\\\\B_2= 0.2\ T[/tex]
Hence, the magnitude of the magnetic field 0. 01 m from the same wire is 0.2 T.
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plssss helppppppppppp i need it
Answer:
D
Explanation:
I don't know how to explain it I just did it
By the way thxs for help on one of my problems
the system shown above is released from rest. if friction is negligible, the acceleration of the 4.0 kg block sliding on the table shown above is most nearly
The acceleration of the first block (4 kg) is -9.8 m/s².
The given parameters:
Mass of the first block, m₁ = 4.0 kgMass of the second block, m₂ = 2.0 kgThe net force on the system of the two blocks is calculated as follows;
[tex]m_2 g - T = m_1 a[/tex]
where;
T is the tension in the connecting string due weight of the first block[tex]m_2 g - m_1 g = m_1 a\\\\a = \frac{m_2 g - m_1g}{m_1} \\\\a = \frac{g(m_2 - m_1)}{m_1} \\\\a = \frac{9.8(2-4)}{2} \\\\a = -9.8 \ m/s^2[/tex]
Thus, the acceleration of the first block (4 kg) is -9.8 m/s².
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Pleaseeeee HELPPPP THIS IS TIMED ALSO,
A book slides along a table and comes to a stop. Explain, in detail, all the forces acting on the book.
Answer:
Friction, normal force, and weight
Explanation:
If the book slows down, it means that there must be friction acting in the opposite direction of the direction the book is moving in.
Weight is caused by the gravitational pull of the Earth on the book, and normal force is the table pushing the book up because the book is pushing down on the table (3rd law.)
Note that weight and normal force is not the 3rd law action-reaction pair. The pair is the force of the book on the table and the force of the table on the book.
Which of the balls will exert the greatest force on object A?Why?
F = mass × Acceleration ( give Acceleration is 9.8 )
So force of 5 kg mass on A is
F = 5 × 9.8 = 49N
Force of mass 1 kg on A
F = 1 × 9.8 = 9.8 N
Force of mass 10 kg on A is
F = 10 × 9.8 = 98N
Clearly the 10 kg ball experts the most force cause it has more mass
A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0. 8 seconds when caught. If the softball has a mass of 0. 2 kilograms, what’s the force of the impact? Use F = ma, where. The force of the impact is newtons.
The force of impact of the softball at the given conditions is 8 N.
The given parameters:
Horizontal velocity of the ball, v = 32 m/sChange in time of motion of the ball, Δt = 0.8 sMass of the ball, m = 0.2 kgThe force of impact of the softball is calculated by applying Newton's second law of motion as follows;
[tex]F = ma\\\\F = m \times \frac{\Delta v}{\Delta t} \\\\F = 0.2 \times \frac{32 - 0}{0.8 - 0} \\\\F = \frac{0.2 \times 32}{0.8} \\\\F = 8 \ N[/tex]
Thus, the force of impact of the softball at the given conditions is 8 N.
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how to determine my slope in physics graph
Answer:
Determine the coordinates of two points on the line. Calculate the difference between these two locations' y-coordinates (rise). Calculate the x-coordinate difference between these two places (run). Divide the y-coordinate difference by the x-coordinate difference (rise/run or slope).
A textbook is sitting at rest on a desk. Compared to the magnitude of the force of the textbook on the desk, how
would you describe the magnitude of the force of the desk on the book?
o less
O zero
O more
O equal
what equation do you use to calculate force from work to distance
Answer:
Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. The mass of the eight ball, m2, is 6 g with a velocity of 1 m/s. After the balls collide, they bounce off each other. The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball? 8. 6 m/s 5. 7 m/s â€"5. 7 m/s â€"8. 6 m/s.
This question involves the concepts of the law of conservation of momentum and velocity.
The velocity of the eight ball is "5.7 m/s".
According to the law of conservation of momentum:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
m₁ = mass of number three ball = 5 g
m₂ = mass of the eight ball = 6 g
u₁ = velocity of the number three ball = 3 m/s
u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)
v₁ = final velocity of the three number ball = - 5 m/s
v₂ = final velocity of the eight ball = ?
Therefore,
(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)
[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]
v₂ = 5.7 m/s
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HELPPP PLEASE
1) if the distance between two masses are 15 meters and the masses are 350kg and 492 kg
respectively; what is the magnitude of gravitational force?
Answer:
-8
5.092×10
Explanation:
given,
distance (d) =15m
mass (M1) =350kg
mass(M2) = 492kg
Gravitational constant (G)=6.67×10^-11
we know,
gravitational force=(Gm1m2)÷d^2
=(6.67×10^-11×350×492)÷15^2
= (1.14857×10^-5)÷225
= 5.092×10^-8
Mars is 7.83x10^10m [^10 is an exponent] from planet earth. The planet Earth is 5.98x10^24kg [^24 is an exponent] while Mars has a mass of 6.42x10^23kg [^23 is an exponent]. What is the gravitational attraction between the two planets? G=6.67×10^-11 (-11 is an exponent)
Answer:
Approximately [tex]4.18 \times 10^{16}\; \rm N[/tex].
Explanation:
Consider two objects of mass [tex]m_{1}[/tex] and [tex]m_{2}[/tex]. Let [tex]r[/tex] denote the distance between the center of mass of each object. Let [tex]G[/tex] denote the gravitational constant. ([tex]G \approx 6.67 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}}[/tex].)
By Newton's Law of Universal Gravitation, the size of gravitational attraction between these two objects would be:
[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}}\end{aligned}[/tex].
In this question, [tex]m_{1} = 5.98\times 10^{24}\; {\rm kg}[/tex] and [tex]m_{2} = 6.24 \times 10^{23}\; {\rm kg}[/tex] are the mass of the two planets. The distance between the two planets is [tex]r = 7.83 \times 10^{10}\; \rm m[/tex] (approximately the same as the distance between the center of mass of planet Earth and the center of mass of Mars.)
Apply Newton's Law of Universal Gravitation to find the size of gravitational attraction between the two planets:
[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}} \\ &= \frac{1}{(7.83 \times 10^{10}\; {\rm m})^{2}} \\ &\quad \times (6.67 \times 10^{11}\; {\rm m^{3} \cdot kg^{-1} \cdot s^{-2}}) \\ &\quad \times (5.98 \times 10^{24}\; {\rm kg}) \\ &\quad \times (6.42 \times 10^{23}\; {\rm kg}) \\ &\approx 4.18 \times 10^{16}\; {\rm kg \cdot m \cdot s^{-2}} \end{aligned}[/tex].
Since [tex]1\; {\rm kg \cdot m \cdot s^{-2}} = 1\; {\rm N}[/tex], the size of gravitational attraction between the two planets would be approximately [tex]4.18 \times 10^{16}\; {\rm N}[/tex].
HELP ME IM NOT GOOD THAT THIS :))))
Someone plz give me some boy advice I really need it.
Read the excerpt from The Building of Manhattan.
A temporary, small narrow-gauge track system was installed on each floor as it was needed. This enabled the material to be moved from the truck at ground level onto dump carts, raised by elevator to the designated floor, wheeled onto the track, and moved quickly to the exact spot needed. Turntables built into the track allowed the carts to be shifted about in any direction.
Which question can be answered only if an illustration accompanies the text?
What did turntables built into the track allow?
How were dump carts raised to designated floors?
When was a track system installed on a floor?
What does a turntable built into a track loo
Answer: this would be D.) What does a turntable built into a track look like
Explanation:
If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?
PLEASE ANSWER
CORRECTLY PLS
Answer:
The reaction force is the water pushing the swimmer in the rightward direction.
Hope you could get an idea from here.
Doubt clarification - use comment section.
What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.
The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
HOW TO CALCULATE KINETIC ENERGY:
The kinetic energy of a moving body can be calculated by using the following formula:
K.E = ½mv²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:
K.E = ½ × 0.75 × 4²
K.E = 8 × 0.75
K.E = 6J
Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
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HELP!!!!
Which statement describes earthquakes?
They release energy.
They are caused by reduced stress in rocks.
They begin at the epicenter.
They result from movement on Earth’s surface.
Answer:
A
Explanation:
earthquakes release energy
Answer:
i think it begins at the epicenter
Explanation:
i can remember
pls give brainleist
John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s
The horizontal component of the velocity is equal to: D. 15 m/s.
Given the following data:
Velocity = 30 m/sAngle = 60°To determine the horizontal component of the velocity:
The horizontal component of the velocity represents the influence of velocity in displacing an object or projectile in the horizontal direction.
Mathematically, the horizontal component of velocity is given by the formula:
[tex]V_x = Vcos(\theta)[/tex]
Substituting the given parameters into the formula, we have;
[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]
Horizontal component, Vx = 15 m/s
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Exert a force on the object, what happens to their state of motion
The force might make the object move or bring the object to rest or change in direction of motion
Rafiq has heard that continued exposure to light for 10 days can change the colour of some blue dyes used to colour cotton clothing. He decides to test this. He takes a piece of clothing dyed with a blue dye which is suspected to lose colour on such exposure. He cuts the cloth into two pieces.
Which experiment is likely to help him conclude if the dye indeed can change colour?
He should expose, for 10 days-
A. Both pieces under 2 identical lamps.
B. One piece under a lamp; keep the other in darkness.
C. One piece for 5 days and one for 10 days under identical lamps
D. One piece folded and one piece spread out under 2 identical lamps.
PLZ HELP ME FAST A relationship between two variables is called:
A.
observable
.B.
correlation
.C.
causation
D.
finite.
Answer:
B- Correlation
Explanation:
Answer:
correlation
Explanation:
I have two questions. I hope anyone can help me <3 Question 8 & Question 9.
Answer:
i have not study it till now
Explanation:
sorry i don't know
In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s
Answer: 0.22
Explanation: Subtract 0.01kg from 0.23kg
how are mass, distance and gpe related
Answer:
It is direct proportionality. The greater the mass, the greater is the gravitational potential energy. The equation for GPE is : GPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height above the ground. As you can see GPE is directly proportional to mass, and height. KT.
Explanation:
Gravitational potential energy is a function of both the mass of your system and the mass of the thing generating the gravity field around your system.
The relationship is linear, which means that if you multiply or divide one of the masses by some number but leave everything else the same, you multiply or divide the potential energy by the same number. A 3kg mass has three times the gravitation potential energy of a 1kg mass, if placed in the same location.