Answers
oh ok where is it bring it
Related Questions
A wheel rolls 5 revolutions on a horizontal surface without slipping. If the center of the wheel moves 3.2 m, what is the radius of the wheel
Answers
The radius of the wheel is 0.102 m.
What is radius of a circle?The radius of a circle is a straight line that comes from the center of a circle to any point of the circumference of the circle.
To calculate the radius of 5 revolutions of the wheel, we use the formula below.
Formula:
d = 10πr.............. Equation 1Where:
d = Total distance moved by the wheelr = radius of the wheel.π = pieMake r the subject of the equation
r = d/(10π)........... Equation 2From the question,
Given:
d = 3.2 mπ = 3.14Substitute these values into equation 2
r = 3.2/(10×3.14)r = 3.2/31.4r = 0.102 m.Hence, the radius of the wheel is 0.102 m.
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Answer this simple question and explain it briefly
Answers
Answer:
Explanation:
Here,
P=Pressure
V=Volume
Subscript meanings: 1 is before, 2 is after. So P1 is starting pressure, P2 is ending pressure.
In the P1V1 = P2V2 equation, P and V are inversely proportional.
It means that when a quantity will increase then another will decrease.
The pressure of a gas is directly proportional to the. The temperature when volume and amount of substance are constant. P1/T1 = P2/T2. Combined gas law: P1V1/T1 = P2V2/T2 Use the gas laws for pressure, volume, and temperature calculations. Avagadro's law and the Ideal gas law.
A single Oreo cookie provides 53 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without acceleration) a 100-pound weight two-feet above the ground with an energy efficiency of 25%. How many repetitions can she do with the energy supplied from a single Oreo cookie? What happens to the number of repetitions that can be done if the efficiency increases?
Answers
The number of times the athlete can lift the weight with single energy supplied by the Oreo cookie is 204 times and this number of times will increase if the efficiency increases.
Energy used by the athleteThe energy used by the athlete is calculated as follows;
E = Fd
where;
F is the applied force = 100 lb weight = 444.82 Nd is the distance = 2 ft = 0.61 mE = 444.82 x 0.61 = 271.34 J
Input energyThe Input energy of the athlete = 53 kcal = 221752 J
Number of times the athlete can lift the weight[tex]E = \frac{0utput \ energy}{1nput \ energy} \\\\0.25 = \frac{n(271.34)}{221752} \\\\271.34n = 55483\\\\n = \frac{55483}{271.34} \\\\n = 204[/tex]
Thus, the number of times the athlete can lift the weight with single energy supplied by the Oreo cookie is 204 times and this number of times will increase if the efficiency increases.
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According to newton second law of motion what is force equal to
Answers
Answer:
According to Newton, "Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration."
Force = mass x acceleration
Answer: According to Newton’s Second Law of physics, the force is equal to the mass of the object times the acceleration. The force acting on an object would be equal to the mass of an object times its acceleration... This means the more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration
What is that force that simply pushes bodies through the planet's gravitational field
Answers
Answer:
Actually, it is not a force. It is a velocity attained by the bodies hence escaping through the gravitational field.
This velocity is called escape velocity.
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Answer:
Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun. Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity, which is 9.8 m/s2 on Earth. The gravitational force between two bodies is directly proportional to the product of the masses of those bodies and is inversely proportional to the square of the distance between them.
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What is the effect of clouds on the "output" of a Solar PV module?
Answers
Answer:
What is the effect of clouds on the "output" of a Solar PV module?
Clouds do impact photovoltaic panels. The quantity of power your photovoltaic panels can produce is directly dependent on the level of light they receive. ... They will see complete direct sunlight “plus” reflected light from the clouds! They will drink in more energy than they could on a cloudless day!
Explanation:
I hope it will help you...
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The lightbulb of a flashlight creates light and heat, both of which are forms of
energy. What is the source of the energy?
A. Elastic potential energy stored in the molecules of the flashlight
B. Chemical potential energy stored in the ions of the battery
C. Kinetic energy of the electrons flowing through the lightbulb
O D. Gravitational potential energy stored in Earth's gravitational field
Answers
Answer:
B
Explanation:
What does it mean to discover
the truth in the context of
detective work? What kinds of
truth can be discovered?
Answers
Answer:
When the machine indicates a lie, what is the probability that the suspect is really lying? If the machine does not indicate a lie, what is the probability that the suspect is really telling the truth?
My solution if the probability that a test subject is chosen at random from the 200 in fact lie = 80/(80+5)=0.94
Then when 15% of people arrested lie, the probability that the suspect is really lying is 0.15*0.94=0.141
A 10 N force is applied to a 2 kg mass, how fast will it be going in 10 sec?
Answers
Answer:
v = 50 ms^1
Explanation:
We know:
F = 10N
m = 2kg
t = 10 sec
F=ma
10 = 2*a
5=a
a = 5 ms^2
Now,
a=v/t
5 = v/10
50 = v
v = 50 ms^1
A 10 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 5 N opposing the motion.
Calculate the acceleration of the object.
Answers
Newton second's law
∑F = m.a
40 - 5 = 10.a
35 = 10.a
a = 3.5 m/s²
Answer:
The acceleration of the object was 3.5 m/s².
Explanation:
Let the direction of the horizontal force be positive.
By Newton's second law, the sum of the horizontal forces is as follows:
[tex]\displaystyle \sum F_x = F_A - F_k = ma[/tex]
Where Fk is the frictional force and FA is the horizontal force.
Substitute in known values and solve for acceleration a:
[tex]\displaystyle \begin{aligned} (40\text{ N}) - (5\text{ N}) & = (10\text{ kg})a \\ \\ a &= 3.5\text{ m/s$^2$}\end{aligned}[/tex]
Hence, the acceleration of the object was 3.5 m/s².
Question 3
Which of the following is an example of positive acceleration?
A car increases its speed from 5 m/s to 10 m/s.
A car is traveling at 25 m/s for 5 minutes.
A car is traveling at 25 m/s and begins to slow down as it approaches a stop sign.
A car is in park.
Answers
Answer: 1ST OPTION A car increases its speed from 5 m/s to 10 m/s
Explanation:IN 1ST OPTION : because the vel and force are in the same direction therefore acceleration is positive
IN 2ND & 3RD OPTION : the force and velocity in opposite direction so its velocity decreases therefore acceleration is negitive
A car engine burns gas at 495 K and exhausts to the air at 293 K if it ran at the highest possible efficiency and use 10,000 J of input heat how much he would it be rejected into the air? WILL GIVE BRAINLIEST
Answers
Answer:
5,920 J
Explanation:
Lowest temperature T₂ = 293 K
Highest temperature T₁ = 495 K
Highest possible efficiency e = 1 - T₂/T₁ = 1 - 293/495 = 0.408
Input heat Q₁ = 10,000 J
Find output heat Q₂
e = 1 - Q₂/Q₁
0.408 = 1 - Q₂/10,000
Q₂/10,000 = 1 - 0.408 = 0.592
so
Q₂ = 10,000 x 0.592 = 5,920 J
One mole of a monatomic gas is subjected to the following sequence of steps.
a. Starting at 300 K and 10 atm, the gas expands freely into a vacuum to double its volume.
b. The gas is next heated reversibly to 500 K at constant volume.
c. The gas is then reversibly expanded at constant temperature until its volume is doubled
d. The gas is finally reversibly cooled to 300 K at constant pressure
Required:
Calculate the values of q and w and the changes in U, H, and S.
Answers
Answer:
c
Explanation:
the gas is the reversible expanded and constant temperature until it's volume is doubled
Which example is a simple machine?
1. ramp
2. bicycle
3. car
4. steering wheel system of a boat
Answers
Answer:
Ramp
Explanation:
All of the other things are fairly complex, bikes have to be made with multiple parts so do cars and steering wheels are another part of a boat, a ramp usually consists of two or fewer parts making it the simplest.
Physics Unit 5 CA - Conservation of
1. A student is pushing a car toward a gas station. They exert a constant force of 100 N
on the car for 40 m bring the car from rest to 5 m/s. What is the mass of the car?
Answers
Answer:
160 kg
Explanation:
f = ma
100 = m * a
a = v/t
v = distanc/time
dist = 40m
time = 8 sec
v = 40/8
a = 40/(64)= 5/8
m = 100*8/5= 160 kg
Calculate change in height of a 2kg ball moving a speed of 10m/s up a frictionless ramp until it stops
Answers
The change in the height of the object is 5.1 m.
Conservation of mechanical energyThe principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.
The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;
P.E = K.E
[tex]mg \Delta h = \frac{1}{2} mv^2\\\\g \Delta h = \frac{1}{2}v^2\\\\\Delta h = \frac{v^2}{2g} \\\\\Delta h = \frac{(10)^2}{2(9.8)} \\\\\Delta h = 5.1 \ m[/tex]
Thus, the change in the height of the object is 5.1 m.
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If a yellow ball is rolled with an average speed of 5 m/s, how far will it travel
in 5 seconds? (just type the number, no need for units).
*
Answers
Explanation:
5m/s if 5 seconds pass then 5 • 5, you get 25m
Hope this helps!
For the purpose of calculating the electric field strength by means of Gauss’s law, determine whether approximate cylindrical symmetry holds in each of the following situations.
Part (a) We have a 3.6-m long copper rod of radius 1 cm, carrying a charge of 1.5 nC distributed uniformly along the rod’s length. We want to calculate the electric field strength at a point 4.9 cm from the rod near its center.
TRUE FALSE
Part (b) We have a 8.9-cm long copper rod of radius 1 cm, carrying a charge of 1.5 nC distributed uniformly along the rod’s length. We want to calculate the electric field strength at a point 4.9 cm from rod near its center.
TRUE FALSE
Part (c) A 1.9-m long wooden rod is glued end-to-end to a 1.9-m long plastic rod, both of radius 1 cm. The combined rod is then painted with an electrically charged paint so that it is covered with a uniform charge density, giving it total charge of 1.5 nC. We want to calculate the electric field strength at a point 4.9 cm from the rod near its center.
TRUE FALSE
Part (d) For the same charged rod as in part (c) we want to calculate the electric field strength at a point 8.9 m from each end of the rod.
TRUE FALSE
Answers
Answer:
1. True
2. False
3. True
4. False
Explanation:
a) In this case, length of the copper rod is 3.6 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.
b) In this case, length of the copper rod is 8.9 cm which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.
c) In this case, length of the copper rod is 3.8 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.
d) In this case, length of the copper rod is 3.6 m which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.
this is the question on the attachment
Answers
Explanation:
a) to allow for the metal tracks to expand on hot days.
reason:- as you have seen in summer the sunlight fall on these tracks and make the metal expand and fill that gaps.
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Two spheres carry a charge of 1x10^-7 C. Their centers are separated by 0.7m. Calculate the magnitude of the force between the two charged objects.
Write your answer in scientific notation using one significant figure
PLEASE HELP ME
Answers
We have that the force between the two charged objects is mathematically given as
F=2.349N
Magnitude of the force between two charged objects.Question Parameters:
Two spheres carry a charge of 1x10^-7 C.
Their centers are separated by 0.7m.
Generally the equation for the Force is mathematically given as
[tex]F=\frac{q1q2}{4*\pi e*r}[/tex]
Therefore
[tex]F=\frac{(1e-7)^2}{9e9*0.7}[/tex]
F=2.349N
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Calculate the speed of a 5 kg object that possesses 20 J of kinetic energy KE=1/2
mv2
2.83 m/s/s
2.83 m/s
2 m/s
4 m/s
Answers
Answer:
2.83 m/s
Explanation:
m = 5 kg,
KE = 20 J
KE = mv^2/2
20 = 5*v^2/2
5*v^2 = 40
v^2 = 8
v = [tex]\sqrt{8}[/tex] = 2.83 m/s
using my friend account again
HELP ME PLIS
Answers
Using the angle addition postulate, you can see that 55 + 63 is equivalent to 118
1. A strobe pattern is made of marks on a piece of paper recorded every 0.1 s. Two adjacent marks near the middle of the pattern are 3.4 cm apart. Use this information to estimate the instantaneous speed at that point.
Answers
3.4cm / 0.1s = 34 cm/sec
I need help algebra in physics
Answers
Answer:
A: 0.26
Explanation:
If a driver brings a car traveling at 22m/s to a full stop in 2.0 s with an acceleration of -8 m/s2 then how far did the car travel while braking?
Answers
Answer:
v=u + at
0= 22 + a*2
a = -22/2 = -11 m/s^2
The car's acceleration is -11 m/s^2
V^2 = u^2 + 2as
022^2 + 2*(-11)s
s = 22^2/22 = 22m
The car will travel 22 m before stopping.
Explanation:
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A ball with a weight of 15 N is thrown striaght up into the air with an initial speed of 14 m/s. What is the maximum height it will achieve above its starting position
Answers
Answer:
10m above initial height
Explanation:
let acceleration due to gravity = 9.8 m/s/s
v final = v initial - time • gravity
0 = 14m/s - t • 9.8m/s/s
t = 1.43 seconds to reach max height
distance = 1/2 • acceleration • time^2
distance = 1/2 • 9.8 • 1.43^2
distance = 10 meters above initial height
A car moving 12.2 m/s starts to coast up a frictionless 14.0 degree hill. what is its acceleration?
Answers
Answer:
−2.373
Explanation:
Theta=14
ma=-mgsin(theta)
a= -gsin(theta)
a= -9.81sin(14)
a=−2.373
A car moving 12.2 m/s starts to coast up a frictionless 14.0 degree hill. -2.37 m/s² is its acceleration.
What is acceleration ?Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force applied on the item determines the object's acceleration.
An object has positive acceleration if it is accelerating and travelling in the right direction. Positive acceleration was demonstrated in the first example by the speeding car. The acceleration is occurring in the same direction as the car's motion, which is forward and speeding up.
The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). Using this, you may gauge the speed of velocity changes in meters.
θ = 14
Acceleration = -gsinθ
= - 9.8 × sin 14°
= -2.37 m/s²
Thus, A car moving 12.2 m/s starts to coast up a frictionless 14.0 degree hill. -2.37 m/s² is its acceleration.
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A new company is making security cameras. These security cameras will be different than other security cameras because instead of detecting motion, they will detect body heat.
What type of electromagnetic wave will the camera detect?
A
gamma ray
B
infrared
C
microwave
D
radio wave
Answers
Answer:
b
Explanation:
Car 1 brakes to a stop on a dry road. Car 2 does the same thing, at the same speed, on a road where it has been raining. Explain how the following will be different for car 2: a) braking distance, b) thinking distance and c) stopping distance.
Answers
Answer: car 1 is going how fast
Explanation: no need to answer without speed I won't know distance.
how do you work this out
Answers
Answer:
A= v-u/t
= 8m/s - 18m/s ÷ 100s
= - 0.1m/s^2
Hope this helps!