Answer:
On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.
Step-by-step explanation:
Mr. Ali cut a wooden plank into three parts in the ratio 2:3:8. The longest part was 72 centimeters
Answer:
117 centimeters
Step-by-step explanation:
Since the longest pieces is 72 centimeters and it’s ratio is 8, that means the individual unit of the ratio is 9 (72/8=9). You can multiply each part of the ratio by 9
2x9=18
3x9=27
We already know the third part of the ratio is 72. Add all of it together to get the original length.
18+27+72=117 cm
Simplify. the square root of 3 times the square root of 5
Answer:
[tex]\sqrt{15}[/tex]
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then
[tex]\sqrt{3}[/tex] × [tex]\sqrt{5}[/tex] = [tex]\sqrt{3(5)}[/tex] = [tex]\sqrt{15}[/tex]
SOMEBODY PLEASE HELP ME!
Answer:
[tex]43.7[/tex]
Step-by-step explanation:
Since the triangles are similar, the ratio of their corresponding sides is maintained. Therefore, we can up the following proportion to solve for [tex]OP[/tex]:
[tex]\frac{9}{7}=\frac{OP}{34},\\OP=\frac{34\cdot 9}{7}=43.7142857143\approx \boxed{43.7}[/tex]
43.7
Step-by-step explanation:
Since the two are similar triangles, the ratio of the legs of one triangle is equal to the ratio of the legs of the other triangle.
OP/ON = LM/LK
OP/34 = 9/7
Solving for OP,
OP = 34(9/7)
= 43.7
The trampoline park charges a $8 for kids and $4 for adults. Your extended family is going there to celebrate your birthday. Your family has at most $190 dollars to spend on entrance fees. You can invite at most 35 people. What are some possible combinations of adults and kids who could go to your party? Write a system of equations for this situation.
Answer:
a+k ≤ 35
8a+4k ≤ 190
Some possible combinations are 10 adults and 20 kids
5 adults and 29 kids
Step-by-step explanation:
Let k= number of kids
a = number of adults
a+k ≤ 35 since you can have at most 35
8a + 4k ≤ 190 since the most you can spend is 190
Some possible combinations are 10 adults and 20 kids
(10+30 < 35 and 8*10+4*20 = 80+80 =160< 190)
Another possible combination
5 adults and 29 kids
(5+29 < 35 and 5*10 + 4*29 =50+116=166)
Find three consecutive even integers such that the product of the second and
third integers is equal to 35.
Step-by-step explanation:
first number=x
second number=x+2
third number=x+4
(x+2)(x+4)=35
x(x+4)+2(x+4)=35
x²+4x+2x+8=35
x²+6x+8=35
x²+6x=35-8
x²+6x=33
x²+6x-33=0
using that, you can find the first number,
then use the data to find the other two.
This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the triangle is 15.7 centimeters. The equation 2a + b = 15.7 models this information.
If one of the longer si
des is 6.3 centimeters, which equation can be used to find the length of the base
Answer:
2(6.3) + b = 15.7
12.6 + b = 15.7
b = 3.1
(15 points!!) please help!! If you can answer the other questions on my page I will Venmo u!
Answer:
y = (x - 3)² - 4 Vertex form
(3, -4) Vertex
Step-by-step explanation:
f(x) = x² - 6x + 5
Complete the square
y = (x - 3)² + 5 - (-3)²
y = (x - 3)² + 5 - 9
y = (x - 3)² - 4 Vertex form
(3, -4) Vertex
PLEASE HELP!! this is due soon and i rlly need help
explanation = brainliest
The radius of a circle is 3 kilometers. What is the area of a sector bounded by a 90° arc?
give the exact answer in simplest form.
Answer:
Step-by-step explanation:
r = 3 km
Ф = 90°
Area of a sector = [tex]\frac{theta}{360}*\pi *r^{2}[/tex]
[tex]= \frac{90}{360}* 3.14 * 3 * 3\\\\= \frac{3.14*3*3}{4}\\[/tex]
= 7.065 sq.km
Answer:
Solution given:
r=3km
area of sector bounded by a 90° arc=90°/360°*πr²
=¼*π*3²
=9/4 π or 7.068km²
is a required answer
how do i find the circumference of a circle when the given radius is 3 1\2 cm, answers in terms of π
Answer:
Circumference of circle is 9.42cm.
Step-by-step explanation:
Here we have given that A circle with having radius 3 and 1 / 2 cm. And We need to find circumference of circle.
Formula using
Circumference of circle = π × 2 × radius
substitute the value
Circumference of circle = π × 2 × 3 and 1/2 cm.
cancle the 2
Circumference of circle = π × 3 cm
Using π = 22 / 7
[tex] \small \sf \ Circumference \: of \: \: circle = \frac{ 22}{7 }×3 cm \\ [/tex]
[tex] \small \sf \ Circumference \: of \:circle = 9.42 cm[/tex]
Hence, Circumference of circle is 9.42cm.
In a right triangle, one angle measures x°, where sin xº 4/5
What is cos(90° - xº)?
==========================================================
Rule:
if A+B = 90, then cos(A) = sin(B) and sin(A) = cos(B)
This can be rephrased into cos(A) = sin(90-A) and sin(A) = cos(90-A)
We'll focus on the second case sin(A) = cos(90-A)
Simply replace A with x and we have the same idea.
---------
So,
sin(x) = cos(90-x)
cos(90-x) = sin(x)
cos(90-x) = 4/5
You can prove this by drawing out a right triangle as shown below.
What is the force on the surface of a square of side 5 m if the pressure acting on it is 25 pascal ?
Answer:
625 N
Step-by-step explanation:
First, find the area of the square.
Area = side x side
= 5 x 5
= 25 m²
Force = pressure x area
= 25 x 25
= 625 N
Hope this helps!
What is the area of this triangle ?
A polynomial consisting of only one term is called a
Answer:
answer
maybe monomial ...
Answer:
That would be a monomial.
Step-by-step explanation:
Hope this helped!
What index of y makes value1/ y^2?
Answer:
the index of y is -2
Step-by-step explanation:
[tex]y^{-2}[/tex]
=[tex]\frac{1}{y^2}[/tex]
PLEASE HELP! THANKS
EXPLANATION = BRAINLIEST
the straight line distance between points is ___ units
24. A car costs $21,435. Each year the car depreciates (decreases in value) by 8%. How much will
the car be worth after 10 years?
Answer:
Step-by-step explanation:
vtrtv
Ambwene cut 3 lawns in his neighborhood on Friday and more on Saturday,
He earns $22.50 for each lawn cut. His total earning for both days is $135.
How many lawes did he cut on Saturday?
Pls help will mark brainliest
Answer:
1/ 4^2
Step-by-step explanation:
4^4 * 4^-6
We know that a^b * a^c = a^(b+c)
4^(4-6)
4^-2
We also know that a^-b = 1/a^b
1/4^2
Use the sum of cubes identity to write this polynomial expression in factored form:
8x3 + 27.
Answer:
[tex] {8x}^{3} + 27 \\ = {8x}^{3} + {3}^{3} \\ let : 8x \: be \: a \\ : 3 \: be \: b \\ = > {a}^{3} + {b}^{3} : \\ {(a + b)}^{3} = (a + b)( {a}^{2} + 2ab + {b}^{2} ) \\ {(a + b)}^{3} = ( {a}^{3} + 3{a}^{2} b + 3a {b}^{2} + {b}^{3} ) \\ ( {a}^{3} + {b}^{3} ) = {(a + b)}^{3} - 3ab(a + b) \\ \therefore( {8x}^{3} + 27) = {(8x + 3)}^{3} - 72(8x + 3)[/tex]
Please help me with this question...
Answer:
my answer is in this picture. sorry about my presentation and English
Bab needs help with mafs
Answer:
Step-by-step explanation:
line HI
What is the solution to the inequality |X-4 <3?
Answer:
x<7
therefore {x:x<7}
Step-by-step explanation:
x-4<3
x<3+4
x<7
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out the maximum amount of profit the company can make, to the nearest dollar.
y=−9x^2+571x−3884
if a person gives you their card number and they say you can spend a certain amount of money and u spend more is it considered stealing? or is it not because they gave u their card willingly and all u did was go over the limit.
Answer:
It would be considered stealing.
Step-by-step explanation:
They did willingly give you their card BUT, they trusted you to only spend a certain amount and not go over that certain limit. You went over the limit even though they specifically told you not to go over it so yes, it would be classified as stealing.
Find the aw tire area and show work
Answer the question pleaseeeee
explain why 7x+3 cannot be factorised
Answer:
There is no common factor
Step-by-step explanation:
PLEASE HELP ME 50 PTS and i'll give brainliest please help me this is the video they game me to do this hw but I still don't understand it https://youtu.be/7Uos1ED3KHI
1.) 70x/100x^2 = 7/10x
2.) 16x^3/24x = 2x^2/3
3.) 7x(2x+1)/21(2x+1) = x/3
4.) 35x - 35/x^2 - 1 = 35/x + 1
5.) x + 7/x^2 + 4x - 21 = 1/x - 3
6.) x^2 - 6x + 5 = x - 5/5
7.) x^2 - 36/x^2 - 3x - 18 = x + 6/x + 3
8.) x^2 - 3x - 10/x^2 + x - 2 = x - 5/x - 1
Mathssssssssssssssssssssssssss
Answer:
The value of x is 5
The interior angle of a regular polygon is 120. Work out the number of sides of the polygon.
Answer:
6 sides
Step-by-step explanation:
The interior angle and the exterior angle sum to 180° , then
exterior angle = 180° - 120° = 60°
The sum of the exterior angles of a polygon is 360° , so
number of sides = 360° ÷ 60 = 6
Answer:
6 sides
Step-by-step explanation:
180 - 120 =60°
sum of exterior angles is 360°
therefore , 360°/60°
ans = 6 sides
Good luck :-)