Can someone help me please

Applying the Corresponding Angles Theorem, the measure of ∠MLK = 84°

Recall:

Corresponding angles are congruent, that is, their angle measures are equal based on the corresponding angles theorem.

The diagram given, showing triangle KLM is in the image attached below.

m∠MLK and m∠MON are corresponding angles, therefore:

m∠MLK =m∠MON

3 x + 75 = 93 − 3 x

3x + 3x = 93 - 75

6x = 18

x = 3

m∠MLK = 3 x + 75

m∠MLK = 3(3) + 75

m∠MLK = 84°

Therefore, applying the Corresponding Angles Theorem, the measure of ∠MLK = 84°

Learn more about the Corresponding Angles Theorem on:

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Answer:

Last answer, height is 150 ft

Step-by-step explanation:

from the graph, you can clearly see, when T=3, H=150

Which means The firework is at a height of 150 feet

Answer:

D

Step-by-step explanation:

At 3 seconds, the firework is at a height of 150 feet

Answer is D. third option

The firework is at a height of 150 feet

Answer:

1:4

Step-by-step explanation:

(1/4 in : 6 ft)

1/4 in : 6 (12 in)

1/4 in : 72 in

divide each side by 1/4

288/72 simplified is ...

1 : 4

Answer:

Exponents

Step-by-step explanation:

Parentheses

Exponents and roots

Multiplication

Division

Addition

Subtraction

Answer:

1) 1584.72

2) 4811.2

3) 2381.721

4) 1672.376

5) 3901.59

Step-by-step explanation:

Answer:

55 degrees

Step-by-step explanation:

a line is 180 degrees. also, all angles in any triangle add up to 180 degrees. so, find the missing angle in the triangle by 180-30-25=125 degrees. Then to find angle 4, 180-125=55 degrees.

Answer:

The one you clicked on in the picture is correct

Step-by-step explanation:

By elimination you can tell that it is the bottom two answers (+3 is inverse of -3). And it is the answer you selected because it cube roots whats in parentheses. So you are correct with the answer you have selected right now

Answer:

Decreasing (2, 6); increasing on (-∞, 2) U (6, ∞)

Step-by-step explanation:

To determine where [tex]f(x)[/tex] is increasing or decreasing, we set [tex]f'(x)=0[/tex] and check for the intervals.

We see that [tex]f'(x)=0[/tex] when either [tex]x=2[/tex] or [tex]x=6[/tex]. Therefore, we'll need to check the intervals [tex](-\infty,2)[/tex], [tex](2,6)[/tex], and [tex](6,\infty)[/tex]

For the interval [tex](\infty,2)[/tex], we can pick [tex]x=0[/tex] . This means that[tex]f'(0)=(2-0)(6-0)=(2)(6)=12>0[/tex], showing that [tex]f(x)[/tex] increases on the interval [tex](-\infty,2)[/tex]

For the interval [tex](2,6)[/tex], we can pick [tex]x=4[/tex]. This means that [tex]f'(4)=(2-4)(6-4)=(-2)(2)=-4<0[/tex], showing that [tex]f(x)[/tex] decreases on the interval [tex](2,6)[/tex]

For the interval [tex](6,\infty)[/tex], we can pick [tex]x=7[/tex]. This means that [tex]f'(7)=(2-7)(6-7)=(-5)(-1)=5>0[/tex], showing that [tex]f(x)[/tex] increases on the interval [tex](6,\infty)[/tex]

Therefore, [tex]f(x)[/tex] is increasing on [tex](-\infty,2)\cup(6,\infty)[/tex] and is decreasing on [tex](2,6)[/tex].

Answer:

[tex]a. \ (x-2)(x+i)(x-i)[/tex]

Step-by-step explanation:

First of all let's notice that [tex](x-i)(x-i)=(x-i)^2 = x^2+2xi-1 \in \mathbb{C}[/tex] while our original polynomial is real. So we can rule out the even options B and D. At this point, if the polynomial has a factor of [tex](x-\alpha)[/tex] it means tha [tex]\alpha[/tex] is a zero of the polynomial. Let's check both 2 (for option a) and -2 (for option c)

[tex]p(2)=2^3-2(2)^2+2-2= 8-8+2-2=0[/tex]

[tex]p(-2)= (-2)^3-2(-2)^2+(-2)-2=-8-8-2-2=-20[/tex]

At this point 2 is a zero, and our final factoring is a[tex](x-2)(x+i)(x-i)[/tex]

Answer:

1.64×10⁷ km

Step-by-step explanation:

We know this is a triangle rectangle, so we apply the Pythagorean Theorem

QR=sqrt(PR²+PQ²)

Solving it, we will encounter in

sqrt(2.56×10¹⁴+1.296×10¹³)

to solve it, we need to bring the two numbers at the same power of ten, so we move 1.296 of one place to the left:

sqrt(2.56×10¹⁴+0.1296×10¹⁴)

we can now add the two numbers:

sqrt(2.6896×10¹⁴)

to solve this, we do the square root of 2.6896 and divide 14 by two (the index of the root is 2, so for roots' properties we can divide 14 by 2 - the index)

which gives us

1.64×10⁷

Answer:

She will go to 729 games in 162 days.

Step-by-step explanation:

27÷6 = 4.5

4.5 · 162 = 729

Answer:

729 games in 162 days

Step-by-step explanation:

If she goes to 6 games in 27 days, then you divide 27 by 6, to get the unit rate.

27/6=4.5

Now that you have the unit rate, you multiply 162 by the unite rate, or 4.5, in this case.

162x4.5=729

-hope it helps

Answer:

y=5/4x -7

Step-by-step explanation:

Hope this helps!

= 3x+y=-2

= Linear equations with two variables have multiple infinite solutions.

= Assuming x=0

then y=-2

= Assuming x=1

then y=-2-3

= y=-5

= Assuming x=2

then y=-2-6

= y=-8

Writing them as coordinate points -

(0,-2),(1,-5),(2,-8)...and so on.

__________________________.

= y=2x+3

Assuming x=0

then y=3

Assuming x=1

then y=2+3

= y=5

Assuming x=2

then y=4+3

= y=7

Writing them as coordinate points -

(0,3),(1,5),(2,7)...and so on.

Answer:

Point Form:

( − 1 , 1 )

Equation Form:

x = − 1 , y = 1

Step-by-step explanation: there you go

Answer:

D

Step-by-step explanation:

BH is perpendicular to AC since an orthocenter is a point at which the three altitudes of a triangle intersect. The altitude of a triangle is that line that passes through its vertex and is perpendicular to the opposite side. Since you know that BH is an altitude due to Point H being an orthocenter, you know that BH is perpedendicular to AC.

Answer:

6

Step-by-step explanation:

66

The student made $100 in week 8.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Amount earned from the first week to 6 weeks.

110, 100, 90, 110, 100, 90

We see that,

Every 3 weeks the amount gets repeated.

So,

7th week = 110

8th week = 100

Thus,

The amount earned in week 8 is $100.

Learn more about expressions here:

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#SPJ2

Recall that for two vector x and y making an angle θ with each,

x • y = ||x|| ||y|| cos(θ)

If we replace y with x, we see that

x • x = ||x|| ||x|| cos(0) = ||x||²   ⇒   ||x|| = √(x • x)

Using the last identity, the magnitude of w is

||w|| = √(w • w)

but since w = u + v, we have

w • w = (u + v) • (u + v)

The dot product distributes over sums and is commutative, so

w • w = (u • u) + (u • v) + (v • u) + (v • v)

… = ||u||² + 2 (u • v) + ||v||²

… = ||u||² + 2 ||u|| ||v|| cos(θ) + ||v||²

If u has a direction of 45° with the positive x-axis, v has a direction of 150°, then the angle between u and v is |45° - 150°| = 105°. So,

||w|| = √(||u||² + 2 ||u|| ||v|| cos(150°) + ||v||²)

… = √(10² + 2 • 10 • 13 cos(150°) + 13²)

… ≈ 14.2

Using the parallelogram rule for vector addition (see attached sketch), the sum of the angle between w and u and 45° is equal to the direction of w.

If φ is the angle between w and u, then

w • u = ||w|| ||u|| cos(φ)

… = 14.2 • 10 • cos(φ)

but we also have

w • u = (u + v) • u

… = (u • u) + (v • u)

… = ||u||² + ||u|| ||v|| cos(105°)

… = 10² + 10 • 13 • cos(105°)

… ≈ 66.4

Then

14.2 • 10 • cos(φ) ≈ 66.4

cos(φ) ≈ 0.467

φ ≈ 62.1°

and so the direction of w is 62.1° + 45° ≈ 107.1°.

I think its C sorry if its wrong

Answer:

29

hope this helps

Answer: A

It is a function and no x values repeat .  If the x values repeat more than then it's not a function.

Answer:

[tex]y = -x - 7[/tex].

Step-by-step explanation:

Slope of the given line segment:

[tex]\begin{aligned} m_{1} = \frac{(-5) - (-1)}{(-6) - (-2)} = 1\end{aligned}[/tex].

The slope of any line perpendicular to this line segment would be:

[tex]\begin{aligned}m_{2} &= \frac{-1}{m_{1}} = -1\end{aligned}[/tex].

Midpoint of the given line segment:

[tex]\displaystyle \left(\frac{(-2) + (-6)}{2},\, \frac{(-1) + (-5)}{2}\right)[/tex].

Simplifies to get:

[tex](-4,\, -3)[/tex].

Find the equation of the perpendicular bisector in point-slope form and simplify.

[tex]y - (-3) = (-1)\, (x - (-4))[/tex].

[tex]y + 3 = -x - 4[/tex].

[tex]y = -x - 7[/tex].

Answer:

$151.2

Step-by-step explanation:

To find the price after the tax is implemented,

set a relationship x/140=8/100 (8/100) basically means 8%.

cross multiply (140)(8)=1120. Then divide it by 100x, you get $11.2.

But that's just 8 percent of the total amount. So you need to add onto the original price, 140+11.2=$151.2.

Answer:

[tex]8\sqrt{2}[/tex]

Step-by-step explanation:

To find the length of an isosceles triangle, you know that the angles of the triangle are 45-45-90, so let's use that triangle theorem.

Therefore, the length of the hypotenuse (BD) is [tex]x\sqrt{2}[/tex], and x is equal to 8 (length of BC).

[tex]x\sqrt{2}[/tex]

x=8

Therefore, [tex]8\sqrt{2}[/tex] would be the length of side BD.

Answer:

oh snap i have this question too sorry cant help :(

Step-by-step explanation:

but i can provide with advice bc is the side down and bd is across us this to your advantage

Answer:

84

Step-by-step explanation:

TPS + SPR = RPT and TPS = RPT - SPR

The measure of RPT and SPR are given so we just need to place them and do the calculation

TPS = 137 - 53

TPS = 84

[tex] \large \bigstar \frak{ } \large\underline{\sf{Solution-}}[/tex]

Consider, LHS

[tex]\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}[/tex]

We know,

[tex]\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} 

\\ \\ \text{So, using this identity, we get}

\\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}[/tex]

We know,

[tex]\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\ [/tex]

So, using this identity, we get

[tex]\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}[/tex]

can be rewritten as

[tex]\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}[/tex]

[tex]\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}[/tex]

[tex]\rule{190pt}{2pt}[/tex]

Answer:

[tex]\sqrt{18a}[/tex]

Step-by-step explanation:

To insert the factor, you must first find its squared value, in this case, 3's squared number is 9 so.....[tex]3=\sqrt{9}[/tex]

Now with square roots, they multiply like any other number

so you end up with[tex]\sqrt{9}*\sqrt{2a} \\\sqrt{9*2a}\\\\\sqrt{18a} <------ ANSWER[/tex]

Please leave a thanks!!!

Answer:

Makes the lungs able to fill more