Can someone double check my work? (Ideal Gas Law Equation)
I am solving for the amount of moles in two gases.
For one, it was 4.75mL at 0.5C (273.65K) and 1.2atm.
n=(1.2*4.75)/(0.0821/273.65)=(5.7/22.456)=0.25361653 moles
For the other gas, it was 4.6mL at 0.5C and 1.2atm.
n=(1.2*4.6)/(0.0821/273.65)=(5.52/22.456)=0.24581403 moles
Please double check these for any errors in math or whatever. Thank you.

Answers

Answer 1

I did not see any errors, i may be wrong but what i can see is that it is correct


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Answer:

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Explanation:

The molarity of the hydrochloric acid solution is 1 M

Molarity is simply defined as the mole of solute per unit litre of water. Mathematically, it can be expressed as:

[tex]Molarity = \frac{mole}{volume}[/tex]

With the above information in mind, we can obtain the molarity of the hydrochloric acid solution as follow:

Mole of HCl = 3 moles

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[tex]Molarity = \frac{mole}{volume}\\Molarity = \frac{3}{3}\\Molarity = 1 M[/tex]

Therefore, the molarity of the hydrochloric acid solution is 1 M.

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Answer:

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Answer:

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Answer:

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Nitrogen and hydrogen react to form ammonia and is a combination reaction. The grams of hydrogen used in the reaction with nitrogen to form ammonia is 2.0 grams.

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Mass is the weight or the product of the volume and density of the substance. It can be calculated as, [tex]\rm volume \times density.[/tex]

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Answer:

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Answer:

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Answers

Answer:

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If I have an unknown quantity of gas held at a temperature of 1195 K in a container with a volume of 25 liters and a pressure of 1,000 atm, how many moles of gas do I have?

Answers

I think you use PV= nRt.

So P=1000
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We are trying to find the moles so n is blank.
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This means that your equation is:

(1000)(25) = (n)(0.08206)(1195)

So you are gonna divide each side by (0.08206)(1195) because you are trying to get the moles by itself.

(0.08206)(1195) is gonna cancel each other out, so your new equation is going to be:

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Answer:

4.67 moles of Li2SO3 dissolved to make 2.04 liters of solution. 4.67 mol ... water. In the second solution, I use 1.0 mole of salt to make a 1.0 L solution. Do the two ... How many milliliters are needed to make. 100.0 mL of ... 4. If I add 25 mL of water to 125 mL of a 0.15 M Naoh solution, what will the molarity of the diluted ...

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How much stock solution is needed to make 250 mL of a 6.0 M solution. The stock solution has a molarity of 18 M.

Answers

Answer:

83 mL

Explanation:

Use the dilution equation M1V1 = M2V2

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Answers

Answer:

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Explanation:

For this question you can use the ideal gas law,

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Because of the units given, R will equal .08026[tex]P=4046 atm[/tex]

Rearrange the equation to solve for pressure:

[tex]P=\frac{nRT}{V}[/tex]

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