Check the picture below.
5. John is now three times as old as Bill.
In four years, John will be only twice
as old as Bill. Find John's age.
6
A. 4
B.
C.
8
D. 10
E. 12
Answer:
12 is johns age
Step-by-step explanation:
all you have to do is multiply johns age times 3 then you get your anser
what is he inverse of the function f(x) = 1/2x+10?
What is the distance between point C (-4,-6)and point D(1,6)
Answer:
the distance between the CD points is 5
Step-by-step explanation:
(-4,-6) (1,6)
it takes 4 to get from -4 to 0 plus 1 to get to 1
so 4+1=5
Find the sum and express it in simplest form. (3a2+2a)+(5a2-a-7)
Done
[tex] \pink{\underline{\boxed{8a²+a-7}}}[/tex]
Solution :-
[tex]\Longrightarrow\sf{(3a ^2 + 2a) + (5a^2 -a-7)}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\Longrightarrow\sf{3a^2+ 2a + 5a^2-a-7}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\Longrightarrow\sf{8a^2+2a-a-7}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex] \Longrightarrow\sf{8a^2+1a-7}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\Longrightarrow\sf{8a^2+a-7}[/tex]
[tex]\red{━━━━━━━━━━━━━━━━━━━━━━}[/tex]
The price of a jacket was increased from $110 to $126.5. What was the percent increase in the price of the jacket?
Answer:
15%
Step-by-step explanation:
percent increase is actual increase divided by starting value16.5/110 = 0.1515%Percent increase in the original price of jacket = 15%
What is percentage?Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".
Given,
Original price of jacket = $110
Increased price of jacket = $126.5
Increased amount = $126.5 - $110
= $16.5
Increased amount in percentage = ($16.5/$110) × 100
= 0.15 × 100
= 15%
Hence, 15% is increase in the original price of jacket.
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Solve ABC given A= 74 , a= 126, b=84
IF the sum of four times a number and four less than three times a number is seventeen what is the number
Answer: 3
Step-by-step explanation: This equation can be written as 4x+3x-4=17
We can now solve.
Moving the 4 to the other side (adding) and we get 21.
Now we have 4x+3x. Adding like terms, we get 7x = 21. Now we divide by 7.
X = 3.
Ammaar put 4/7 of the money he earned raking leaves in the bank. He spent 1/3 of the money on a book.
Create an expression with common denominators that can be used to find the difference between the fraction of money Ammaar put in the bank and the fraction he spent on the book
Answer for grade 6 pls
The expression that can be use to find the difference between the fraction of money Amar put in the bank and the fraction he spent on the book is 4 / 7 x - 1 / 3 x
How to create an expression?Amar put 4/7 of the money he earned raking leaves in the bank. Therefore,
let the money she earned = x
Hence,
amount put in bank = 4 / 7 x
She spent 1 / 3 of the money on books. Therefore,
money spent on books = 1 / 3 x
Therefore, the expression that can be use to find the difference between the fraction of money Amar put in the bank and the fraction he spent on the book is as follow:
4 / 7 x - 1 / 3 x
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PLEASE HELP ME OR I WILL GET IN TROUBLE PLEASE
kevin and anita are writing poems. kevin has no poems to start and writes three new poems each day anita has four poems to start and writes two new poems each day. After how many days will they have the same number of poems in their collections?
ANSWER
A) 1day
B) 2days
C) 3days
D) 4days
Answer:
4 days
Step-by-step explanation:
Answer:
D)
Step-by-step explanation:
Kevin starts with 0 poems but increases 3 each day
Let kevin = x
y = 3x
Anita has 4 poems to start with but increases 2 each day
Let anita = y
y = 2x + 4
As seen on this graph:
The point of intersection is (4,12)
The x axis being the number of days.
Thus the answer is D)
simplify (-1 1/2) ÷ 3/4 x -2/3
Answer:
Step-by-step explanation:
1[tex]\frac{1}{2}[/tex]=1×[tex]\frac{2}{2}[/tex], +[tex]\frac{1}{2}[/tex]
(-[tex]\frac{3}{2}[/tex])÷[tex]\frac{3}{4}[/tex]×(-[tex]\frac{2}{3}[/tex])
[tex]\frac{3}{2}[/tex]×[tex]\frac{4}{3}[/tex]×[tex]\frac{2}{3}[/tex]
[tex]\frac{1}{2}[/tex]×4×[tex]\frac{1}{3}[/tex]
4×[tex]\frac{1}{3}[/tex]=[tex]\frac{1}{3}[/tex]+[tex]\frac{1}{3}[/tex]+[tex]\frac{1}{3}[/tex]+[tex]\frac{1}{3}[/tex]
=[tex]\frac{4}{3}[/tex]
Which is the graph of -2x + y < 5?
Answer:
Graph D
Step-by-step explanation:
Graph D is the graph of -2x + y < 5
A cylinder has a base diameter of 12 inches and a height of 13 inches. What is its volume in cubic inches, to the nearest tenths place?
The volume of the given cylinder.
Solution:First, we'll have to find the raduis.
[tex]d = 2r [/tex]
[tex]r = \frac{12}{2} [/tex]
[tex]r = 6 \: in [/tex]
Now, we can work out the volume.
[tex]V = \pi {r}^{2} h[/tex]
[tex]V = \pi \times {6}^{2} \times 13[/tex]
[tex]V = 1470.26536 \: {in}^{3} [/tex]
[tex]\large\boxed{\sf{V = 1470.3 \: {in}^{3}}}[/tex]
Hence, the volume of the given cylinder is 1470.3 cubic inches.
Other question! 5th grade! help asap
The names of this polygon include:
Acute triangle. Scalene triangle. Which polygon is described?The polygon given has three sides which means that it is a triangle. It is an acute triangle because the angles are all less than 90°.
It is also a scalene triangle because all the sides have different lengths from each other.
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Answer:
Step-by-step explanation:
I: acute triangle
L: Isosceles triange
(sorry if im wrong i have not done this in a good few years lol)
10. The following measurements from yaw marks left at the scene of an accident were taken by law
enforcement officers. Using a 31-ft-long chord, the middle ordinate measured approximately 3
ft. The drag factor for the road surface is 1.02.
a. Determine the radius of the yaw mark to the nearest tenth of a foot.
1
Determine the minimum snood that it
The radius of the yaw mark to the nearest tenth of a foot is 11.2 ft
The minimum speed 11.1634 miles per hour.
What is Yaw mark?Yaw marks are always curved. They are, initiated by a steering input. They're what's left from a tire that is still rolling but is simultaneously sliding laterally.
The formula for determining radius from a chord and middle ordinate is
[tex]r^{2}= \frac{c^{2}}{8m}+\frac{m}{2}[/tex]
To find the radius of the yaw mark, we have to use the formula
[tex]r^{2}= \frac{c^{2}}{8m}+\frac{m}{2}[/tex]
where c is the length of the chord and m is the middle ordinate
As the tires leave a yaw mark with a 31 foot chord and a middle ordinate of 3 feet.
So,
[tex]r^{2}= \frac{31^{2}}{8*3}+\frac{3}{2}[/tex]
[tex]r^{2}= 40.041 +1.5\\r^{2}=41.541[/tex]
Now to find the minimum speed, we are going to use the formula: [tex]s=\sqrt{15fr}[/tex]
where 'f' is drag factor and 'r' is the radius
drag factor is 0.2, f=0.2
and r= 41.541 ft
So, [tex]s=\sqrt{15* 0.2*41.541}\\s=\sqrt{124.623}\\s= 11.1634 mph[/tex]
The minimum speed before the brakes are applied was 11.1634 miles per hour.
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Two quantities, Pand Q, are connected by
the relationship P= kQ+ c, where k and c
are constants. Q= 60 when P= 10 and
Q= 240 when P= 100.
Find the equation connecting P and Q.
Answer:
P = 0.5Q - 20
Step-by-step explanation:
P = kQ + c
substitute Q = 60 , P = 10 into the equation
10 = 60k + c → (1)
substitute Q = 240, P = 100 into the equation
100 = 240k + c → (2)
subtract (1) from (2) term by term to eliminate c
90 = 180k ( divide both sides by 180 )
[tex]\frac{90}{180}[/tex] = [tex]\frac{1}{2}[/tex] = 0.5 = k
substitute k = 0.5 into (1) and solve for c
10 = 60(0.5) + c
10 = 30 + c ( subtract 30 from both sides )
- 20 = c
then
P = 0.5Q - 20
Ariana is opening a new restaurant. She has six entrees. How many different orders can she list them on her menu?
Answer:
if each was used only once, the answer would be 52080
Step-by-step explanation:
plssssss helppppp i give 98 points
To write 28 + 24 as a product of two factors, we need to determine the HCF of the addends (28 and 24). This can be done by listing the factors of the addends. The greatest factor that is common in 28 and 24 is the HCF.
If the number is in bolded text, the number is a common factor.
Factors of 28: 1, 2, 4, 7, 14, 28Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24Since 4 > 2 > 1, the HCF is 4.
2) Writing 28 and 24 as a product of two factorsNow, let us put the provided expression between parentheses.
⇒ (28 + 24)Finally, factor four out of the expression, as it is the GCF of 28 and 24.
⇒ (28 + 24)⇒ [(4 × 7) + (4 × 6)]⇒ 4(7 + 6)Therefore, 28 + 24 as a product of two factors is 4(7 + 6).
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Miguel is designing shipping boxes that are rectangular prisms. The shape of one box, with height h in feet, has a volume defined by the function V(h) = h(h - 7)(h - 11). Graph the function. What is the maximum volume for the domain 0 < h < 11? Round to the nearest cubic foot.
Answer:
96 ft³
Step-by-step explanation:
A graphing calculator conveniently graphs this function. It shows the maximum volume is about 96 ft³.
Challenge. The mean of two numbers is
28. Find the numbers if 3 times one of the
numbers equals half the other number.
Hint. The mean of x and y is (x + y)/2 =
1/2(x + y).
Answer:
8 and 48
Step-by-step explanation:
Here is how to find it mathematically
x = one number 6x = other number ( because 3x is 1/2 of x)
(x + 6x) /2 = 28
7x = 56
x = 8 then 6x = 48
How tall is Merapi in Indonesia?
A. 2,698 meters
B. 3,000 meters
C. 5,201 meters
D. 26.2 miles
what was the price per ounce of a 24-ounce bag of chocolate chips that cost $5.40?
Answer:
22.5¢ per oz
Step-by-step explanation:
24 oz cost = $5.30
1 oz cost = $5.40/24 = 22.5¢ per oz
Answer:
0.22.5
Step-by-step explanation:
ANSWER THIS CORRECTLY FOR BRAINLIEST!!!!
Answer:
3052.08
Step-by-step explanation:
How is the step by step of this problem
Answer:
I would edit this answer and tell you what I hope would be the correct answer if you give me the problem you are confused with
Step-by-step explanation:
I can't help you otherwise
Sorry
The legs of a right triangle are 8 and 9 units long. What is the area of the triangle in square units?
Answer:
Step-by-step explanation:
Area of a triangle is a*b divided by 2
Lets assume a = 8 and b= 9
8 *
9=72
72/2=36
What is the equation of the that contains the point (3,-2) and has a slope of 5?
Answer:
y = 5x-17
Step-by-step explanation:
point slope form would be
y- -2 = 5(x-3) or re-arrange to: y = 5x -17
The function h(x) is a translation of the exponential function g(x) = 2(3)x − 4. What's h(x) if the translation is a vertical stretch by a factor of 2, a vertical shift upward 9 units, and a horizontal shift to the right 7 units? Question 11 options: A) h(x) = 4(3)x − 7 + 9 B) h(x) = 4(3)x − 9 + 7 C) h(x) = 4(3)x – 7 + 7 D) h(x) = 4(3)x + 7 − 9
The function h(x) is a translation of the exponential function [tex]g(x) = 2(3)^{x - 4}[/tex] , is [tex]h(x) = 4(3)^{x + 7} - 9[/tex]
What are exponential functions?When the expression of function is such that it involves the input to be present as an exponent (power) of some constant, then such function is called exponential function.
There usual form is specified below. They are written in several such equivalent forms.
The function h(x) is a translation of the exponential function given as
[tex]g(x) = 2(3)^{x - 4}[/tex]
We have to determine, the h(x) if the translation is a vertical stretch by a factor of 2, a vertical shift upward of 9 units, and a horizontal shift to the right 7 units.
The function h(x) is vertically stretched by 2.
[tex]h(x) = 2 (2(3)^{x - 4})\\\\h(x) = 4((3)^{x - 4})[/tex]
Vertically shift upward by 9,
[tex]h(x) = 4((3)^{x - 4})\\\\h(x) = 4((3)^{x - 4})- 9[/tex]
And a horizontal shift to the right 7 units,
[tex]h(x) = 4((3)^{x - 7})- 9[/tex]
The function h(x) is a translation of the exponential function [tex]g(x) = 2(3)^{x - 4}[/tex] , is [tex]h(x) = 4(3)^{x + 7} - 9[/tex]
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For the graph, what is a reasonable constraint so that the function is at least 600?
I took the test and got this question wrong, as you can see from the image below. Anyone else want to try?
Answer:
[tex]0 \leqslant x \leqslant 20[/tex]
100 POINTS!!! VERY URGENT
Answer:
D) (f o g)(x) = 10x² - 60x + 93
Step-by-step explanation:
f(x) = 10x² + 3
g(x) = x - 3
⇒ (f o g)(x)
⇒ f(x - 3)
⇒ f(x - 3) = 10(x - 3)² + 3
⇒ f(x - 3) = 10(x² - 6x + 9) + 3
⇒ f(x - 3) = 10x² - 60x + 90 + 3
⇒ (f o g)(x) = 10x² - 60x + 93
Answer:
[tex]\textsf{D)} \quad (f \circ g)(x)=10x^2-60x+93[/tex]
Step-by-step explanation:
[tex]\textsf{If }\:f(x)=10x^2+3\:\textsf{ and }\:g(x)=x-3\:\textsf{ then}:[/tex]
[tex]\begin{aligned}(f \circ g)(x) & = f[g(x)]\\ & = f(x-3)\\& = 10(x-3)^2+3\\& = 10(x^2-6x+9)+3\\& = 10x^2-60x+90+3\\& = 10x^2-60x+93\\\end{aligned}[/tex]
solving system of equations by graphing.
Answer:
see attached image
Step-by-step explanation:
i need this answer quickly