Calculate the average time it took the car to reach each checkpoint. Record the average times in Table B of your Student Guide.
The average time to the first quarter checkpoint is
seconds.
The average time to the second quarter checkpoint is
seconds.
The average time to the third quarter checkpoint is
seconds.
The average time to the finish line is
seconds.
Answers
Answer:
The average time to the first quarter checkpoint is 2.07 seconds.The average time to the second quarter checkpoint is 3.16 seconds.The average time to the third quarter check point is 4.11 seconds.The average time to the finish line is 4.92 seconds.Explanation: I got it right on edge2021 :)
s
average we find the average times for each checkpoint
point 1 [tex]t_{avg}[/tex] = 2.07 s
point 2 t_{avg} = 3.16 s
point 3 t_{avg} = 4.11 s
point 4 t_{avg} = 4.92 s
given parameters
* Graph with time for each interval
to calculate
* average time for each interval (checkpoint)
The average of a magnitude is
[tex]t_{avg} = \sum \frac{t_i}{n}[/tex]
where [tex]t_{avg}[/tex] in the average time, t_i each time the magnitude is measured and n the number of times the measurement is repeated for the same point.
The table shows the times measured for each interval
measurement time (s) in interval,
1 2 3 4
1 2.02 3.17 4.12 4.93
2 2.05 3.07 3.98 4.81
3 2.15 3.25 4.23 5.01
we look for the average time to get married check point
point 1
t_{avg} = (2.02 + 2.05 + 2.15) / 3
t_{avg} = 2.07 s
Point 2
t_{avg} = (3.17 +3.07 + 3.25) / 3
t_{avg} = 3.16 s
point 3
t_{avg} = (4.12 + 3.98 + 4.23) / 3
t_{avg} = 4.11 s
checkpoint 4
t_{avg} = (4.93 + 4.81 + 5.01) / 3
t_{avg} = 4.917 s
We use the criterion of significant figures for the sum, which is stable that the result must be given with the number of decimal places of the figure that I have the least.
t_{avg} = 4.92 s
the average allows to find the average times for each check point
point 1 tavg = 2.07 s
point 2 tavg = 3.16 s
point 3 tavg = 4.11 s
point 4 tavg = 4.92 s
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Answer:
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Answer:
490000J
Explanation:
Given parameters:
Mass of boulder = 1000kg
Height of cliff = 50m
Acceleration due to gravity = 9.8m/s²
Unknown:
Potential energy = ?
Solution:
Potential energy is due to the position of a body. It is expressed as;
P.E = mgH
m is the mass
g is the acceleration due gravity
H is the height
Now insert the parameters and solve;
P.E = 1000 x 9.8 x 50 = 490000J
Data:
m = 1000 kg
h = 50 m
g = 9.8 m/s^2
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P.E = ?
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Answer:
Explanation:
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plz dont be mad that i coppied it sounded so good so i wanted veryone to see it when they look bc i am dumb
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Answer:
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Explanation:
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Answer:
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Explanation:
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Answer:
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Answer:
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