By the distributive law, 49 * 17 + 49 * 3 =

Answer:

The hypotenuse is twice the length of the shortest side so;

A could be the answer as when 5 is shortest and 10 is hypotenuse we get 5√3 for the other side which = 8.6

It cannot be B, C or D as the numbers cannot be 2 values same as hypotenuse (the longer length) as 5 + 5 = 10 and we cant use 4 lengths in one triangle and either of 3 out of 4 values do not show ratio of lowest side any value middle value = LV +√3 and hyp LV(2)

so A is the answer.

Step-by-step explanation:

Answer:

[tex]\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{-3}{8}[/tex]

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Constant]:                                                                                             [tex]\displaystyle \lim_{x \to c} b = b[/tex]

Limit Rule [Variable Direct Substitution]:                                                             [tex]\displaystyle \lim_{x \to c} x = c[/tex]

Limit Property [Addition/Subtraction]:                                                                   [tex]\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)[/tex]

L'Hopital's Rule

Differentiation

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Step-by-step explanation:

We are given the following limit:

[tex]\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16}[/tex]

Let's substitute in x = -2 using the limit rule:

[tex]\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{(-2)^3 + 8}{(-2)^4 - 16}[/tex]

Evaluating this, we arrive at an indeterminate form:

[tex]\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{0}{0}[/tex]

Since we have an indeterminate form, let's use L'Hopital's Rule. Differentiate both the numerator and denominator respectively:

[tex]\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \lim_{x \to -2} \frac{3x^2}{4x^3}[/tex]

Substitute in x = -2 using the limit rule:

[tex]\displaystyle \lim_{x \to -2} \frac{3x^2}{4x^3} = \frac{3(-2)^2}{4(-2)^3}[/tex]

Evaluating this, we get:

[tex]\displaystyle \lim_{x \to -2} \frac{3x^2}{4x^3} = \frac{-3}{8}[/tex]

And we have our answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Limits

Answer:

-99

Step-by-step explanation:

Answer:

- 99

Step-by-step explanation:

11 - 11 × 11 + 11

➛ 0 × 11 + 11

➛ - 110 + 11

➛ - 99

Answer:

Step-by-step explanation:

From the given information:

ΔG° = -30.5 kJ/mol

By applying the following equation to calculate the value of K.

ΔG° =-RT㏑K

making ㏑ K  the subject of the formula:

[tex]\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}[/tex]

where;

Temperature at 25° C = (25 + 273)K

= 298K

R = 8.3145 J/mol.K (gas cosntant)

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}[/tex]

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }[/tex]

㏑K = 12.309

[tex]K = e^{12.309}[/tex]

K = 221682.17

K = 2.22 × 10⁵

b) The reaction for the metabolism of glucose is given as:

[tex]C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}[/tex]

From the above expression, let calculate the Gibbs free energy by using the formula:

[tex]\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}[/tex]

[tex]\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)][/tex]

At standard conditions;

The values of corresponding compounds are substituted into the equation above:

Thus,

[tex]\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -3786 +911 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875000 \ J/mol[/tex]

Now, the no of ATP molecules generated = [tex]\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}[/tex]

= (-2875000 J/mol ) / -30500 J/mol

= 94.26

≅ 94 ATP molecules generated

Answer:

n = √108 or 6√3

Step-by-step explanation:

n is the altitude of the right triangle

Based on the right triangle altitude theorem, we would have:

h = √(xy)

Where,

h = n

x = 18

y = 6

Substitute

n = √(18*6)

n = √108

Or

n = 6√3

No.

Since w = 8, you must replace the variable with the number associated to it.

So, it would be 5 + 8 = 58

5 + 8 is not equal to 58, it is equal to 13.

If you wanted to find out what w was, simply subtract 5 on both sides.

w = 58 - 5

Answer:

Trapezoid

Step-by-step explanation:

It has two opposite parallel lines and the other two are not parallel

Answer: choice D

Step-by-step explanation:

In order for something to be a function for every x input there must be exactly 1 y output. This means that if x is a number then y must always be 1 number and that 1 number only.

The volume of the prism is (B) 864 mm3

Answer: yes yes no yes yes no

Step-by-step explanation:

Answer:

20 degrees

Step-by-step explanation:

Angles on a line equal 180 degrees.

180–140=40

40=2x

x=20

20 degrees

Answer:

The answer is A 1 4/5

Work:

7 1/5- 6 2/5

turn 7 1/5 into 6 6/5 and now subtract the two fractions

6/5-2/5= 4/5

now subtract the whole numbers:

6-6=1

So, your answer should be 4/5 (A)

Given:

The graph of function.

To find:

The correct statement for the domain and range of the given graph.

Solution:

Domain: The set of input values.

Range: The set of output value.

From the given graph it is clear that the graph represents a polynomial function.

The given graph of a polynomial function is defined for all real values of x. So, the domain is the set of all real numbers.

The graph of the function approaches from negative infinite to positive infinite. So, the output the given graph is set of all real numbers. It means the range is the set of all real numbers.

Therefore, the correct options are B and D.

The true statements are:

B. The range is the set of all real numbers.

D. The domain is the set of all real numbers.

From the figure, we can see that the graph extends in all directions without any end.

This means that, the graph of the function can take any real value as its input, and output

Hence, the domain and the range of the graph are set of all real numbers

Read more about domain and range at:

https://brainly.com/question/10197594

Answer:

The number of men needed to perform a piece of work twice as great in tenth part of the time  working 8 hours a day supposing that three of the second set can do as much  work as four of the first set is:

Step-by-step explanation:

To find the answer, first, we're gonna find how many hours take to make the piece of work in 16 days, taking into account each day just has 10 hours:

Now, we divide the total hours among the number of persons:

This equivalence isn't the real work of each person, we only need this value to make the next calculations. Now, we have a piece of work twice as great as the first, then, we can calculate the hours the piece of work needs to perform it (twice!):

We need to make this work in tenth part of the time working 8 hours a day, it means:

Now, we know three of the second set can do as much  work as four of the first set, taking into account the calculated equivalence, we have:

So, three persons of the second set can make a equivalence of 8 hours. At last, we calculate all the number of workers we need in a regular time:

Remember we need to perform the job not in a regular time, we need to perform it in tenth part of the time, by this reason, we need 10 times the number of people:

With this calculations, you can find the number of men needed to perform a piece of work twice as great in tenth part of the time  working 8 hours a day supposing that three of the second set can do as much  work as four of the first set is 1200 persons.

Answer:

32

Step-by-step explanation:

14+6(9-6)

[9-6=3]

14+6x3

[6x3=18]

14+18

32

---

hope it helps

Answer:

14+6×(9-6)=32

Answer:

254.47 mm

Step-by-step explanation:

Answer: 4) 8

Step-by-step explanation:

-80/10=-8

-8 = - 8. - No

80/-10= - 8. - 8=-8 - No

-(80/10)=-(8)=-8. - 8=-8 - No

8 - Yes.

Answer:

Step-by-step explanation:

Answer:

260

Step-by-step explanation:

Answer:

C-15.12. That is the most suitable answer

Answer:

CI 98 %  =  ( 3.332  ;  5.668 )

t(c)  =  2.9979

Step-by-step explanation:

Confidence Interval  CI  98 %   then  α  =  2 %   α  =  0,02    α/2  =  0.01

Sample information:

Sample size    n  =  8

sample mean     x  =  4.5

standard deviation of sample    s  =  1.1 kg

degree of freedom     df  =  n  -  1     df  =  8  -  1    df  =  7

With    α/2  0.01  and  df  =  7 from t-studente table we find   t(c)

t(c)  =  2.9979

CI 98 %  =  (   x  ±  t(c) * s/√n )

CI 98 %  =  (  4.5  ±  2.9979 *  1.1/ √8 )

CI 98 %  =  (  4.5  ±  3.2976/2.8228 )

CI 98 %  =  (  4.5  ± 1.168 )

CI 98 %  =  ( 3.332  ;  5.668 )

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Compare the equation to that of an ellipse with center (h, k) and axes of lengths 2a and 2b.

  ((x -h)/a)^2 +((y -k)/b)^2 = 1

We see that (h, k) = (4, 0) and a=2, b=3.

This tells us the center of the ellipse is (4, 0), the major axis is parallel to the y-axis, and the minor axis is parallel to the x-axis. The ellipse extends ±2 units from its center in the x-direction and ±3 units from its center in the y-direction.

Answer:

It is graph C on edge.

Step-by-step explanation:

Answer:

Step-by-step explanation:

To prove that the sum of the first n even +ve integers is:

[tex]\mathsf{2+4+6+8+ . . . +2n = n^2+ n }[/tex]

By using mathematical induction;

For n = 1, we get:

2n = 2 × 1 = 2

2 = 1² + 1 ----- (1)

∴ the outcome is true if n = 1

However, let assume that the result is also true for n = k

Now, [tex]\mathsf{2+4+6+8+. . .+2k = k^2 + k --- (2)}[/tex]

[tex]\mathsf{2+4+6+8+. . .+2k+2(k+1)}[/tex]

we can now say:

[tex]\mathsf{= (k^2 + k) + 2(k + 1)} \\ \\ \mathsf{= k^2 + k + 2k + 1}[/tex]

[tex]\mathsf{= (k^2 + 2k + 1) + (k + 1)}[/tex]

[tex]\mathsf{= (k + 1)^2 + (k + 1)}[/tex]

∴

[tex]\mathsf{2 + 4 + 6 + 8 + . . . + 2k + 2(k + 1) = (k + 1)^2 + (k + 1)}[/tex]

Thus, the result is true for n = m+1, hence we can posit that the result is also true for each value of n.

As such [tex]\mathsf{2+4+6+8+. . .+2n = n^2 + n }[/tex]

Answer:

this is a linear equation. whatever value you set for x, you substitute and make a table that would probably look like this.

      x      |     y

-------------|-----------

5            | 17/3       <------- what would y be if x is 5?

3             | 5                     lets substitute x with 5

               |                          y=1/3*5+4

               |                         y=5/3+4

               |                        y=17/3

Answer:

Amount paid by insurance company = $6,200

Step-by-step explanation:

Given:

Total cost of car damage = $7,200

Amount deductible = $1,000

Find:

Amount paid by insurance company for total damage

Computation:

Amount paid by insurance company = Total cost of car damage - Amount deductible

Amount paid by insurance company = $7,200 - $1,000

Amount paid by insurance company for total damage = $6,200

9514 1404 393

Answer:

  x = 10·cos(θ) -4·cot(θ)

Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

If the junction point in the middle of AB is labeled X, then we have ...

  sin(θ) = 4/BX   ⇒   BX = 4/sin(θ)

  cos(θ) = x/XA   ⇒   XA = x/cos(θ)

Then ...

  BX +XA = AB = 10

Substituting for BX and XA using the above relations, we get

  4/sin(θ) +x/cos(θ) = 10

Solving for x gives ...

  x = (10 -4/sin(θ))·cos(θ)

  x = 10·cos(θ) -4·cot(θ) . . . . . simplify

_____

We used the identity ...

   cot(θ) = cos(θ)/sin(θ)

Answer:

We think about ourselves way less than we think 8% of the time.

Step-by-step explanation:

In a self-awareness: introspection research study conducted by Mihaly Csikszentmihalyi and Thomas Figurski in 1982, to determine the degree to which people find out about themselves through the process of introspection (thinking about themselves).

The research involved an arrangement where participants were given beepers and asked to write down what they were thinking about when the beepers went off randomly throughout the day. The results indicated that "We think about ourselves way less than we think 8% of the time."

Answer:

(121.576 ; 273.424)

Step-by-step explanation:

Given the data:

175, 125, 180, 220, 240, 245

We can calculate the mean and standard deviation

Mean = Σx/ n = 1185 / 6 = 197.5

Standard deviation = 46.125 (calculator)

The confidence interval :

Mean ± margin of error

Margin of Error = Tcritical * s/sqrt(n)

Tcritical at 99%, df = n - 1 ; 6 - 1 = 5

Tcritical = 4.032

Margin of Error = 4.032 * 46.125/√6

Margin of error = 75.924

Confidence interval :

197.5 ± 75.924

Lower boundary = 197.5 - 75.924 = 121.576

Upper boundary = 197.5 + 75.924 = 273.424

(121.576 ; 273.424)