Answers
Answer:
For 9 is 2,4,1 and 3.For 10 b-c moves 15 from each other and e-f moves 15 also from each other.
Related Questions
a car ends up at x = -245 m after a displacement of -103 m. what was its initial position?
Answers
Answer:
-142m
Explanation:
To find the initial position of the car, we can add the displacement.
-245 + 103 = -142
Best of Luck!
Light is produced by which fundamental force?
strong nuclear
electromagnetic
weak nuclear
gravitational
Answers
Answer:
ans: Electromagnetic
Answer:
B on edg.
Explanation:
Ben has two carts with masses of 0.1 kg and 0.2 kg. He pushes the smaller cart toward the larger cart and they collide. The smaller cart rebounds back in the direction it came from. He measures the force on the smaller cart from the larger cart to be 5 N. What was the magnitude of the acceleration of the smaller cart?
Answers
Answer:
The acceleration of the smaller cart is 50 m/s²
Explanation:
The given masses of the carts are 0.1 kg and 0.2 kg
The direction in which the small cart bounces = In the revers to its initial direction
The force exerted by the larger cart on the small cart = 5 N
Therefore, we have;
Force acting on smaller cart = Mass of smaller cart × Acceleration of the smaller cart
∴ The acceleration of the smaller cart = Force acting on smaller cart/(Mass of smaller cart)
The acceleration of the smaller cart = 5 N/(0.1 kg) = 50 m/s²
The acceleration of the smaller cart = 50 m/s².
What distance is required for a train to stop if its initial velocity is 23 m/s and its
deceleration is 0.25 m/s²? (Assume the train decelerates at a constant rate.)
Answers
-- The train starts at 23 m/s and slows down by 0.25 m/s every second.
So it'll take (23/0.25) = 92 seconds to stop.
-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s
-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover
(11.5 m/s) x (92 sec) = 1,058 meters .
The distance required for the train to travel before stopping is 1,058 m.
The given parameters;
initial velocity of the train, u = 23 m/s
deceleration of the train, a = 0.25 m/s
The distance traveled by the train is calculated as follows;
[tex]v^2 = u^2 -2as[/tex]
where;
v is the final velocity of the train
The final velocity of the train is zero when the train stops
[tex]v^2 = u^2 -2as\\\\0 = 23^2 - 2(0.25)s\\\\0.5s = 529\\\\s = \frac{529}{0.5} \\\\s = 1,058 \ m[/tex]
Thus, the distance required for the train to travel before stopping is 1,058 m.
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please can i have help with this question
Answers
4. Why do chemists use relative masses of atoms compared to a reference isotope rather than the
actual masses of the atoms?
a. The actual mass of an electron is very large compared to the actual mass of a proton.
b. The actual masses of atoms are very small and difficult to work with.
c. The number of subatomic particles in atoms of different elements varies.
d. The actual masses of protons, electrons, and neutrons are not known.
Answers
Answer:
B
Explanation:
Answer:
answer is B
Explanation:
took the test
You're driving your car at a constant speed in a straight line which of the following can be used to cause your car to experience a centripetal acceleration
A)brake pedal
B) steering wheel
C)gas pedal
D)All of the above
Answers
HELLO! Please Help me.
I can't do it! it's Science
Answers
Answer:
9V
Explanation:
V=IR
V=2.5*3.6
V=9
Answer:
9V
Explanation:
V =IR
V =2.5 * 3.6
V = 9V
Dos pilotos suicidas, que están inicialmente a una distancia de 500 m entre sí, deciden chocar directamente de frente arrancando ambos desde el reposo. Ambos autos pueden desarrollar una aceleración máxima constante de 15 m/s2 . Si el piloto A arranca un segundo antes que el piloto B, encuentra: a) la posición donde los autos chocan, medida a partir de la posición donde arranca el piloto A, y b) la rapidez relativa de la colisión (la rapidez de B con respecto a A justo antes de la colisión, ó viceversa).
Answers
Answer:
a) El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A es de aproximadamente 293,14 metros.
b) La velocidad del automóvil A, en relación con la velocidad del automóvil B, es de 15 m / s
Explanation:
Los parámetros del movimiento son;
La distancia entre ambos coches = 500 m
La aceleración de ambos coches = 15 m / s²
La dirección de movimiento de ambos coches = uno hacia el otro
La hora de inicio del conductor A = Un segundo antes de la hora de inicio del conductor B
Por lo tanto, de la ecuación de movimiento, tenemos;
s = u · t + 1/2 · a · t²
v² = u² + 2 · a · s
Dónde;
u = La velocidad inicial de los autos = 0 (los autos parten del reposo)
t = El tiempo de movimiento de una aceleración dada
a = La aceleración = 15 m / s²
s = La distancia recorrida en el tiempo t
Por lo tanto, para el controlador A, tenemos;
s₁ = 0 × (t + 1) + 1/2 × 15 × (t + 1) ² = 7.5 × (t + 1) ²
s₁ = 7.5 × (t + 1) ²
Para el conductor B, tenemos;
s₂ = 0 × t + 1/2 × 15 × t² = 7.5 × t²
s₂ = 7,5 × t²
Dado que ambos chocan a lo largo del camino de 500 m, tenemos;
s₁ + s₂ = 500 metros
∴ 7.5 × (t + 1) ² + 7.5 × t² = 500
∵ s₁ + s₂ = 7.5 × (t + 1) ² + 7.5 × t²
Lo que da;
15 · t² + 15 · t + 7.5 = 500
15 · t² + 15 · t - 492,5 = 0
Resolver usando la aplicación en línea da; t = -6,25181 o t = 5,25181
Dado que t es un número natural, tenemos el valor correcto para t = 5.25181 segundos
a) Por tanto, el punto de colisión de los dos coches desde donde parte el conductor del coche A es;
s₁ = 7.5 × (t + 1) ² = 7.5 × (5.25181 + 1) ² ≈ 293.14 metros
El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A ≈ 293,14 metros
b) La semilla de A en el punto de colisión se da de la siguiente manera
Velocidad, v₁ = u + a × (t + 1) = 0 + 15 × (5.25181 + 1) ≈ 93.78
v₁ ≈ 93,78 m / s
La semilla de B en el punto de colisión también se da de la siguiente manera
Velocidad, v = u + a × (t) = 0 + 15 × 5.25181 ≈ 78.78
v₁ ≈ 78,78 m / s
Por lo tanto, la velocidad del automóvil A, en relación con la velocidad del automóvil B, [tex]v_{relative}[/tex] se da como sigue;
= v₁ - v₂ = 93,78 m / s - 78,78 m / s = 15 m / s
la velocidad del automóvil A, relativa a la velocidad del automóvil B = 15 m/s.
A. 2kg
B. 6kg
C. 8kg
D. 14kg
Answers
Answer:
A
Explanation:
We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.
Cody’s car accelerates from 0M/S 245 in/at Northwoods and 15 seconds what is the acceleration of the car
Answers
Answer:
3m/s^2
Explanation:
Acceleration is change in velocity / time = 45/15 = 3m/s^2
please help
Which equipment is best to hold and to measure liquids?
A). flask and graduated cylinder
B). scale and ruler
C). caliper and thermometer
D). stopwatch and beaker
Answers
Answer:
I'm pretty sure that the answer is A
Why do oil tankers sit lower in water
Answers
When a lower tank is damaged, the incoming sea water pushes the oil in the damaged tank up into the ballast tank. Because of the hydrostatic pressure, there is an automatic transfer out of the damaged tank. The double-hull design is aimed at the probability of zero outflow.
if two objects are repelled from each other which force most likely caused this?
A. gravitational
B. weak nuclear
C. electromagnetic
D. strong nuclear
Answers
Answer:
it's C! electromagnetic
Explanation:
explain how the air balloon moves up and down.
Explain in terms of density
Answers
Answer:
hope it helps ....
Explanation:
The inside air that has been heated rises due to the difference of density between the hot and cold air particles. The heated air, the air that is inside the balloon, is less dense than the cool air, the air outside of the balloon. ... You can see that the bigger the volume gets, the smaller the density is.
What is the weight of a body at a centre of Earth
Answers
is isopropyl alcohol a element compound or mixture
Answers
Answer:
Isopropyl is an element compound.
Explanation:
Which has more inertia, a car with a mass of 900kg or a car with a mass of 1,500kg. Explain your answer.
Answers
Answer:
Which has more inertia - a car with a mass of 900kg or a car with a mass of 1500kg - explain. The bigger the mass - the larger the inertia but you need to exert more force to start the movement.
Explanation:
a pulling force carried by a rope is called what
Answers
Answer:
The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.
Explanation:
Carlos gets tired of pushing and instead begins to pull with force Fpull at an angle to the horizontal.
The block slides along the rough horizontal surface at a constant speed. A free-body diagram for the
situation is shown below. Blake makes the following claim about the free-body diagram:
Blake: “The velocity of the block is constant, so the net force exerted on the block must be zero.
Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied
force Fpull.”
What, if anything, is wrong with this statement? If something is
wrong, identify it and explain how to correct it. If this statement is
correct, explain why.
Answers
Answer:
The wrong items are;
1) The normal for FN equals the weight Fmg
2) The force of friction, Ff, equals the applied force Fpull
The corrected statements are;
1) The normal force is weight less the vertical component of the applied force Fpull
FN = Fmg - Fpull × sin(θ)
2) The force of friction equals the horizontal component of the applied force Fpull
Ff = Fpull × cos(θ)
Explanation:
The given statement was;
The velocity of the block is constant, so the net force exerted on the block must be zero. Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied force Fpull
By the equilibrium of forces actin on the system, given that the applied force acts at an angle, θ, with the horizontal, we have;
The normal force is equal to the weight less the vertical component of the applied force;
That is we have, FN = Fmg - Fpull × sin(θ)
The friction force similarly, is equal to the horizontal component of the applied force;
Ff = Fpull × cos(θ)
The wrong items are therefore as follows;
1) The normal for FN equals the weight Fmg
1 i) The normal force is weight less the vertical component of the applied force Fpull
FN = Fmg - Fpull × sin(θ)
2) The force of friction, Ff, equals the applied force Fpull
2 i) The force of friction equals the horizontal component of the applied force Fpull
Ff = Fpull × cos(θ).
The amount of matter in a substance or object is called:
??? What the answer
Answers
Answer:
mass!!
Explanation:
match the letter with the layer
Answers
Answer:
Thermosphere A,B
Mesosphere B,C,D
Stratosphere D,E,F
Troposphere G
Hope this helps please give me brainliest!
God bless :)
What is the name of the kind of stretch that involves stretching as far as you can and then holding for 10-30 seconds
Question 2 options:
PNF
ballistic
dynamic
static
Answers
Answer:
Static stretching.
Explanation:
It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.
Which force is involved in kicking a ball?
1. Frictional force
2. Pushing force
Answers
Answer:
Pushing force
Explanation:
You technically push a ball when kicking it.
3. Mount Everest, an eastern Himalayan peak on the Tibet-Nepal border, was discovered to be the world's highest mountain in March 1856. The Survey Department of the Government of India computed its height to be 29,002 ft. Express this height in scientific notation.
Answers
Answer:
h = 2,9002 10⁴ ft
Explanation:
Scientific notation is a method to write very large and small numbers clearly, the figure is written with an integer and the other figures in decimals, with an exponent so that the number does not change.
If it is necessary to approximate a figure, the criterion is if the next figure is greater than or equal to five, the figure rises by one unit.
Mount Everest height
h = 29002 ft
h = 2,9002 10⁴ ft
if we approximate three significant figures that
h = 2.90 10⁴ ft
Answer:
[tex]2.9002 \cdot 10^{4} ft[/tex]
Explanation:
To express the height 29,002 in scientific notation we need to move the decimal point four places to the left and express the answer into a base-ten power, as follows:
[tex]29,002 = 2.9002 \cdot 10^{4}[/tex]
The answer expressed in scientific notation results in 2.9002 times a ten to the fourth power, as a result of the four movements of the decimal point.
I hope it helps you!
That
Vhy do people engage in various
e long answer to the following questions.
Which tradition of our society needs to be reform
and write the ways to reform them
of Nepal
Answers
Why does sonar use ultrasound rather than sound?
Answers
Answer; Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances.
Answer:
Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances
Explanation:
Mass refers to the gravitational force on the matter in contact with the surface of a planet. true or false
Answers
Answer:
False
Explanation:
The mass of something does not depend on gravity. A planet has a constant gravitational force. Earth's is 9,80 N/kg. The moon, on the other hand, is 1,6 N/kg. the number of kilograms of something doesn't change if you go from one planet to another and since mass is measured in kilograms, mass doesn't change, therefore it does not refer to gravity. Mass refers to the quantity of matter in an object. It is weight that refers to the gravitational force on an object, since it is measured in newtons, and the amount of newtons per kilogram changes from planet to planet due to different gravity constants
16. True/False: Protons are exchanged between objects by induction
Answers
What disagreement did Sigmund Freud have with both Josef Breuer and Jean Martin Charcot?
A. whether hypnosis was a neurological or psychological phenomenon
B. whether hypnosis should be conducted with pregnant women
C. whether hypnosis had any value as a curative remedy for patients
D. whether hypnosis was an effect of a "hidden observer" or the id
Answers
Answer:
The correct answer is 'A'
Explanation:
I guessed and was correct.
Freud backed Bernheim's efforts to establish hypnosis and suggestion as acceptable fields of study for science and to advance them as therapeutic tools. Thus, option A is correct.
What is the neurological or psychological phenomenon?Both neurologists and psychiatrists treat illnesses and ailments that affect the brain and the psyche. However, while psychiatrists focus on psychological issues, neurologists are experts in physiological illnesses.
According to medical terminology, neurological disorders are conditions that impact the spinal cord, brain, and body's nerves.
A variety of symptoms can be caused by structural, metabolic, or electrical abnormalities in the brain, spinal cord, or other nerves.
Therefore, whether hypnosis was a neurological or psychological phenomenon.
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