The concentration of HBr used in the titration is found to be 0.0978M.
Volume of NaOH used is 27.50ml and it’s molarity used is 0.200M.
Volume of HBr used is 56.20ml.
On comparing molarity of both the solutions, we get the relation
HBr × VHbr = MNaOH × VNaOH
MHBr = 0.200M × 27.50ml /56.20ml
MHBr = 0.0978M.
A colorless, stifling gas called hydrogen bromide is highly dissociated in water and exceedingly soluble in water. In the presence of damp air, it rapidly fumes. Hydrogen bromide gas is a very caustic chemical that, when contacted, can result in serious burns.
To determine the concentration of an identified analyte, titration is a typical laboratory technique for quantitative chemical analysis. A standard solution with a defined concentration and volume is prepared as a reagent, also known as the titrant.
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Which of the following are SI units? Select all that apply.gLs
INFORMATION:
We have the following options
g
L
s
And we must select the options that are SI units.
STEP BY STEP EXPLANATION:
The SI units are:
- For mass: Kg
- For volume: cm^3
- For time: s
- For length: m
Finally, we can see that from given options, s is the unique that belongs to the SI units.
ANSWER:
s
b) Given the following standard enthalpy changes at 298 K, calculate the standard enthalpy change for the reaction given below. S(s) + O2(g) → SO2 (g) AH = -296.8 kJ mol-1 SO2(g) + 3/2 O2(g) → SO3 (g)AH = -98.9 kJ mol-¹ S(s) + 3/2 O2(g) → SO3 (g) AHr = ?
−791.4 kJ is the standard enthalpy change for the reaction.
Given,
SO2(g) → S(s) + O2(g)
ΔH° = +296.8 kJ
2SO2(g) + O2(g) → 2SO3(g)
ΔH° = −197.8 kJ
Modified equation:
S(s) + 2O2(g) → 2SO2(g)
ΔH° = −593.6 kJ, multiply by 2 and flip
2SO2(g) + O2(g) → 2SO3(g)
ΔH° = −197.8 kJ here no change
The 2SO2 will balance out by canceling it when the equations are added. Add the enthalpies for the final answer:
−593.6 + (−197.8) = −791.4 kJ
The change in enthalpy of a compound when one mole of the compound is generated from all components of the same constituent is known as the standard enthalpy of formation, also known as the standard heat of formation.
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Help please 30 POINTS!!!!
Where is visible light located on the EM spectrum?A. Right in the middleB. It isn’t on the EM spectrumC. All the way to the rightD. All the way to the left
explanation - Visible light sits in the region with ultraviolet (UV) to the left of the spectrum.
see picture below :
• The picture shows exactly where the visible light is located in the electromagnetic spectrum .
• That is to the left of the ultraviolet radiation, and to the right of infrared (IR).
How many valence electrons are in the outermost shell of all noble gases except helium?
Answer:
8
Explanation:
All noble gases have 8 electrons in their outermost shell and are in an octet state.
What Mass of Lithium nitrate would have to be dissolved in 30.0g of water in order to make an 18%. Solution?
The mass of lithium nitrate that needs to de dissolved in 30.0g of water in order to make 18% solution is 6.58 grams.
The Percentage Concentration of a solution is the calculation of concentration of an element in a solution using the masses of solute/solvent and solution. It can be defined by the formula:
=> Percentage = (Mass of solute/Mass of solution)*100
The density of water is 1 gm/cm³, so the mass of 30.0g of water is 30ml. 18% concentration is given. The formula for percentage of concentration is given as
Percentage = (Mass of solute/Mass of solution) × 100
Here, Mass of solute is m, Mass of solution is m+30, and percentage is 18, So we get
=> 18 = (mass of solute/Mass of solution) × 100
=> 18 = (m/m+30)*100
=> 18(m+30) = m
=> 18m + 540 = 100m
=> 82m = 540
=> m = 6.58
Hence, the mass of lithium nitrate dissolved in 30g water to make 18% solution is 6.58g.
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Of the molecules SiCl4 and SiI4 , which has bonds that are more polar?
The SiCl4 molecules' bonds will be more polar.
In a molecule, the difference in electronegativity between the atoms engaged in a bond determines its polarity. Iodine is not as electronegative as chlorine. As a result, the electrons in the Si-Cl bond will be localized more close to the Cl, giving the bond its polarity. Iodine is less electronegative than chlorine, hence it won't produce a Si-I bond that is highly polarized.
Tetrachlorosilane, often known as silicon tetrachloride, is an inorganic chemical having the formula SiCl4. It is an air-fuming, colorless volatile liquid. High purity silicon and silica are made using it for industrial applications.
The chemical compound with the formula SiI4 is called silicon tetraiodide. It is a tetrahedral molecule with 2.432 Si-I bonds. The silicon amides with the formula Si(NR2)4 are precursors to SiI4. Additionally, it has attracted attention in the production and etching of silicon for microelectronics.
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Please I need answer to this question
Answer:
What??
I dont understand the questii
When radium-226 experiences alpha decay, the relative mass of the particle released in amu is
Energy of a photon is equal to 4.655 (4.44 + 0.08).
=0.135MeV=135KeV
Nature contains the radioactive element Ra-226. In 1898, Pierre and Marie Curie were working with uranium ore when they made the discovery of radium.
Uranium-238 undergoes radioactive decay, resulting in Ra-226.
A light paint was also created by combining radium-226 with fluorescent zinc sulfide. During and after World War I, this luminescent paint was employed to decorate watches, compasses, and other equipment.
High radium levels can result in cancer (particularly bone cancer), anemia, a blood issue, shattered teeth and cavities, and cataracts, growths in the eyes.
Some of these medical issues take years to manifest. The majority are brought on by gamma radiation, which can spread widely through the atmosphere.
The mineral uraninite contains the highest concentrations of radium 226 in nature, while it can be found in different proportions in almost all types of rocks and soils that contain naturally occurring uranium.
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Determine whether the bond between each of the following pairs of atoms is purely covalent, polar covalent, or ionic.
- I and Cl
-C and O
- Ca and F
- P and P
The kind of bonds that can be formed between each of the atoms is;
I and Cl - ionic bondC and O - polar covalent bond Ca and F - ionic bond P and P - covalent bondWhat is the Ionic bond?The ionic bond is the kind of bond that is formed between two atoms in a compound when there is a complete transfer of electrons between the atoms in the compound.
A covalent bond is said to be formed between two atoms when there is a sharing of the electrons that can be found between two atoms. We know that a bond is ionic when the difference in the electronegativity of the atoms is high.
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Use the reaction below to determine how many liters of H2O(g) result when 2.7 grams of CH4 are combusted in excess oxygen. The temperature after combustion is 380K and the pressure is 1.5 atm.CH4(g) + 2O2(g) > CO2(g) + 2H2O(g)
1) Write the chemical equation.
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]2) List the known and unknown quantities.
Sample: 2.7 g CH4.
Temperature: 380 K.
Pressure: 1.5 atm.
3) Convert grams of CH4 to moles of CH4.
The molar mass of CH4 is 16.0425 g/mol.
[tex]mol\text{ }CH_4=2.7\text{ }g\text{ }CH_4*\frac{1\text{ }mol\text{ }CH_4}{16.0425\text{ }g\text{ }CH_4}=0.17\text{ }mol\text{ }CH_4[/tex]4) Moles of H2O produced from 0.17 mol CH4.
The molar ratio between CH4 and H2O is 1 mol CH4: 2 mol H2O.
[tex]mol\text{ }H_2O=0.17\text{ }CH_4*\frac{2\text{ }mol\text{ }H_2O}{1\text{ }mol\text{ }CH_4}=0.34\text{ }H_2O[/tex]5) Volume of H2O produced in the reaction.
5.1- List the known and unknown quantities.
Moles: 0.34 mol H2O.
Temperature: 380 K.
Pressure: 1.5 atm.
Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)
5.2- Set the equation.
[tex]PV=nRT[/tex]5.3- Plug in the known values and solve for V (liters).
[tex](1.5\text{ }atm)*(V)=(0.34\text{ }mol\text{ }H_2O)*(0.082057\text{ }L*atm*K^{-1}*mol^{-1})*(380\text{ }K)[/tex][tex]V=\frac{(0.34\text{ }mol\text{ }H_2O)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(380\text{ }K)}{1.5\text{ }atm}[/tex][tex]V=7.1\text{ }L[/tex]7.1 L H2O was produced from 2.7 g CH4 in the reaction.
Calculate the molar mass of Na2CO3(in g/mol)
105.987. First we have to find the atomic mass of each atom of the molecule Na = 22.98977, C = 12.011 and O = 15.999. Since we have two atoms of Na the atomic mass of Na need be multiplied by 2, in case of carbon is 1 and 3 for oxigen and add them all together. 2x(22.98977) +1x(12.011) + 3x(15.999) = 105.987
I need help with solving this problem
2.04 x 10^23 atoms of carbon to grams
Answer
Mass of carbon = 4.069 g
Explanation
Given:
Number of atoms = 2.04x10^23 atoms
Required: Mass of carbon
Solution
Step 1: Find the number of moles of carbon
1 mole = 6.022x10^23 atoms
x moles = 2.04x10^23 atoms
Solve for x
x = (2.04x10^23 atoms x 1 mole)/6.022x10^23 atoms
x = 0.339 mol
Step 2: From the moles, calculate the mass of carbon
m = n x M where m is the mass, n is the moles and M is the molar mass of carbon
m = 0.339 mol x 12,011 g/mol
m = 4.069 g
if you have 4.0 moles of nitrogen and 5.0 moles of hydrogen, what is the maximum amount of ammonia that you can produce?
Answer:
Explanation:
Here, we want to get the maximum amount of ammonia that can be produced
From the question, we have it that:
1 mole nitrogen gave 2 moles ammonia
Thus:
4 mole nitrogen will give 8 moles ammonia
Furthermore:
3 moles of hydrogen gave 2 moles of ammonia
5 moles of hydrogen will give:
[tex]\frac{5\times2}{3}\text{ = }\frac{10}{3}[/tex]The maximum amount of ammonia that can be produced is thus 8.0 moles
Please HELP!!!?! Describe competitive and noncompetitive in inhibitors describe how mutations can lead to resistance with non-competitive inhibitors
A competitive inhibitor physically mimics the substrate for a specific enzyme and engages in binding competition with the substrate at the enzyme's active site.
A noncompetitive inhibitor can bind to either the free enzyme or the enzyme-substrate complex and binds at a location different from the active site.
What are inhibitors that are competitive and noncompetitive? How do they function?The substrate cannot attach to the active site because the competitive inhibitor is bound there. The noncompetitive inhibitor attaches to a different spot on the enzyme.
The inhibitor binds at an allosteric location apart from the active site of substrate binding in noncompetitive inhibition. Therefore, in noncompetitive inhibition, the inhibitor can attach to its target enzyme even if a bound substrate is present.
Inhibitors that are non-competitive can bind to both the enzyme and the enzyme-substrate complex. Uncompetitive inhibitors only bind to the complex of the enzyme and substrate.
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i need help on question 2For each of the reactions below, write the (i)equilibrium constant expression, (ii) find its value,and (iii) determine if it’s reactant-favored, product-favored, or neither.(a) N 2 (g) + 3 H 2 (g) -----> 2 NH 3 (g)[N 2 ]eq = 1.50 M [H 2 ]eq = 2.00 M[NH 3 ]eq = 0.01 M(b)HF(aq) -----> H + (aq) + F – (aq)[HF] eq = 0.55 M [H + ] eq = 0.001 M[F – ] eq = 0.001 M(c) Fe 3+ (aq) + SCN – (aq) -----> FeSCN 2+ (aq)[Fe 3+ ] eq = 0.55 M [SCN – ] eq = 0.001M[FeSCN 2+ ] eq = 0.001 M
Answer
Explanation
Part A
Given:
a) N₂ (g) + 3H₂ (g) -----> 2NH₃ (g)
[N₂ ]eq = 1.50 M, [H₂ ]eq = 2.00 M, [NH 3 ]eq = 0.01 M
Solution:
i. The equilibrium constant expression for the reaction is
[tex]Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}[/tex]What is the minimum temperature at which 59 g of NH4Cl would completely dissolve in 100 grams of water?
1) Identify the curve of the solute.
2) Look for the grams of solute in the vertical axis.
3) Go down looking for the temperature
The minimum temperature at which 59 g of NH4Cl would completely dissolve in 100 g H2O is 70ºC.
Given the system at equilibrium: N2O4(g) + 58.1 kJ <----> 2 NO2(g) What will be the result of an increase in temperature at constant pressure?D) The equilibrium will shift to the right, and the concentration of NO2(g) will increaseA) The equilibrium will shift to the left, and the concentration of NO2(g) will decrease. B) The equilibrium will shift to the left, and the concentration of NO2(g) will increase. C) The equilibrium will shift to the right, and the concentration of NO2(g) will decrease.
STEP-BY-STEP EXPLANATION:
Given information
[tex]N_2O_{4(g)}\text{ + 58.1KJ }\rightleftarrows2NO_{2(g)}[/tex]From the given reaction, you will see that energy is added to the reactant side. This implies that the reaction is an endothermic reaction.
An endothermic reaction is a type of reaction in which heat is absorbed from the surroundings.
Recall, Le Chatelier's principle states that when external constraints such as (temperature, pressure, and concentration) are imposed in a chemical equilibrium system, the equilibrium shift so as to annul or neutralize the effect of the constraints
When temperature is
1. Which of the following elements are metals, nonmetals and metalloids?
As, Xe, Fe, Li, B, Cl, Ba, P, I, Si.
Answer:
Aluminium, Thorium, Barium and Strontium. Nonmetals will be : Fluorine, Phosphorus and Krypton. Metalloids will be : Gallium and Tellurium.
Density
Which of the following do you think is more dense?
Water
Ping Pong Ball
Which is more dense a drop of water or ping pong ball
A drop of water is denser than a ping-pong ball.
Usually, water is made of particles that are firmly pressed together. In differentiation, plastic (the material ping pong balls are made of) may be a lightweight fabric and the particles are not as firmly stuffed together.
The thickness of a ping pong ball is 0.0840 g/cm³, though water’s thickness is 997 kg/m³. Subsequently, ping pong balls aren’t about as thick as water and will continuously coast and surface greatly quickly.
The ping pong ball appears to oppose gravity and coast within the air.
Ping-pong balls drift within the water since they are amazingly lightweight, empty, and filled with air. Too, the water’s surface pressure makes it simple for the ping pong ball to drift.
In expansion, water is denser than ping pong balls, making them look for the most noteworthy point of water.
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Please I need answer to my question
Calcium carbonate (CaCO3) is not an organic substance since it only contains one of the two elements—carbon or hydrogen.
To identify whether a compound is organic, it is important to check:
if the compound contains carbon, hydrogen, and other non-metals altogetherthere should be no metal in the compoundIf a compound contains one of two elements, that is Carbon or Hydrogen, then it is not an organic compound.
Carbohydrates are a common type of organic compound. Carbohydrates contain the chemical formula (CH2O)n.
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Which of the following is an example of only a physical change? (1 point)Odry ice becoming vaporthe green color of the Statue of Libertythe creation of table saltO the smell of rotten eggs
Answer:
Dry ice becoming vapor.
Explanation:
In a physical change, the substance is the same, but in this case, it changes state from solid to vapor.
calculate the percentage oxygen in aluminum phosphate
To determine the percentage of oxygen in the molecule we must first know its structure and how many oxygen atoms are contained in it. The structure of aluminum phosphate is AlPO4.
It means that there are 4 oxygen atoms, 1 Aluminum atom, and 1 phosphate atom.
Now we will determine the weight of the molecule AlPO4 by adding the atomic weights of the elements as follows:
Element Atomic mass # of atoms Mass
Al 26.9815 1 26.9815
P 30.9738 1 30.9738
O 15.999 4 63.996
Total mass of AlPO4 = 26.9815+30.9738+63.996 = 121.9513 g/mol
Now we will determine the mass percentage with the following equation:
[tex]\text{Mass percentage = }\frac{Oxygen\text{ mass}}{\text{Total mass of the molecule }}\times100[/tex]We replace the known terms:
[tex]\begin{gathered} \text{Mass percentage = }\frac{63.996}{\text{121.9513 }}\times100 \\ \text{Mass percentage = }52.477 \end{gathered}[/tex]So, the percentage of oxygen in aluminum phosphate is 52.477%
.A voltaic cell consists of a Ni electrode in 1.0M Ni(NO3
)2
and an Fe electrode
in 1.0M Fe(NO3
)2
.
Calculate E°
cell for the spontaneous cell reaction at 25°C
The standard electrode potential value of a cell can be calculated from the reduction potentials of the electrodes. The standard electrode potential E⁰ of the voltaic cell with Ni electrode and iron electrode is 0.19 V.
What is standard electrode potential?The reduction potential of an electrode at standard conditions that is at 298 K and 1 bar pressure is called standard electrode potential.
There are two types of electrodes in a cell called cathode and anode. Cathode is the electrode at which reduction occur where as the electrode which undergo oxidation is called anode.
The standard electrode potential of a cell can be measured as follows.
[tex]E^{0} _{cell} = E^{0} _{cathode} - E^{0} _{anode}[/tex]
Here, the anode is Fe electrode with a standard electrode potential of -0.44 V and the anode is Ni electrode having -0.25 V reduction potential.
Thus the standard electrode potential of the voltaic cell can be calculated as follows:
[tex]E^{0} _{cell} = E^{0} _{Ni^{2+}/Ni} = E^{0} _{Fe/Fe^ {2+}}[/tex]
= (-0.25 v) - (-0.44 v)
= 0.19 V.
Hence, the standard electrode potential of the cell E⁰ containing Ni electrode and Fe electrode is 0.19 V.
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Consider the reaction below Which species is/are) the Bronsnsted-Lowry base(s)?HCO₃⁻ (aq) + F⁻ (aq) = CO₃²⁻ (aq) + HF (aq)A) F-,HFB) HCO3-, F-C) CO32-, HFD) CO32-, F-
Answer
D) CO₃²⁻, F⁻
Explanation
A Brønsted-Lowry acid is a compound that supplies a hydrogen ion in a reaction. A Brønsted-Lowry base, conversely, is a compound that accepts a hydrogen ion in a reaction. Thus, the Brønsted-Lowry definitions of an acid and a base focus on the movement of hydrogen ions in a reaction, rather than on the production of hydrogen ions and hydroxide ions in an aqueous solution.
HCO₃⁻ (aq) + F⁻ (aq) = CO₃²⁻ (aq) + HF (aq)
Therefore, in the reaction above, the species that is/are Bronsnsted-Lowry base(s) are CO₃²⁻ and F⁻
Thus, the correct answer is: D) CO₃²⁻, F⁻
What ions are present in Fe(NO3)3 (aq) solutions?
Explanation:
Iron (III) nitrate is a soluble salt. When dissolved in water it will dissociate into its ions: Iron (III) and nitrate.
Fe(NO₃)₃ (aq) ----> Fe³⁺ (aq) + 3 NO₃⁻ (aq)
Answer: Fe³⁺ and NO₃⁻.
Samples of two metals of equal mass but with different heat capacities are originally at the same temperature. Il the same amounto1'heat is added to both samples, for which metal will the final temperature be lower (assume that no phase change, such as meltng, occurs).
The heat capacity corresponds to the energy needed to raise one degree of temperature for one gram of substance. That is, the greater the heat capacity, for the same mass, the greater the energy required to raise the temperature of the material.
Therefore, between the two metals with the same mass, the same initial temperature, and the same heat added, we can say that the one with the higher heat capacity will present a lower final temperature.
How many molecules of n2o4 are in 76.3 g n2o4 ? The molecular mass of n2o4 is 92.02g/mol
CS₂(l) + 3O₂(g) → CO₂(g) + 2SO₂(g) 13. What volume of O₂(g) is required to react with excess CS₂(l) to produce 4.0 L of CO₂(g)? (Assume all gases are measured at 0°C and 1 atm.)
The volume of a substance at STP for one mole is 22.4 L. The volume of oxygen required to react with excess of carbon sulphide to produce 4 L of carbon dioxide 4.0 L is 12 L.
What is volume?Volume of a substance is the space occupied by the particles of the substance. As the temperature increase, volume also increases. The volume of one mole of every substance at standard temperature and pressure is 22.41 L
According the balanced reaction given, 3 moles of O₂ is required to produce one mole carbon dioxide. One mole of O₂ is 22.4 L. Thus volume of 3 moles of oxygen is calculated as follows:
Volume of O₂= 3×22.41 =67.2 L.
Thus, 67.2 L of O₂ produces one mole or 22.4 L of carbon dioxide.
The volume O₂ required to produce 4 L of carbon dioxide is calculated as follows:
Volume of O₂ = (67.2 L × 4 L) / 22.41 L
= 12 L.
Therefore, the volume of oxygen molecule required to produce 4 L of carbon dioxide on the reaction with excess of carbon sulphide is 12 L.
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