Using the image above, set up the equation that would help to determine the value
of angle x.

Answer:

2.  Not enough information

4. Congruent SAS

4. Similar, not enough information to determine congruency.

Step-by-step explanation:

2.  We only know one side and one angle are congruent,  Not enough to determine congruency

4.  We know two sides and the angle between are vertical angles and vertical angles are congruent.  SAS is how the triangles are congruent.

6.  The three angles are congruent which makes the triangles similar.  We need to know a side if they are to be congruent

Answer:

A. 25 < (x – 1)² + y² and 16 > x² + (y + 4)²

Step-by-step explanation:

the solutions are in the outside of the bigger circle, but inside of the smaller circle

The inequality is 25 < (x – 1)² + y² and 16 > x² + (y + 4)². Option A is correct.

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to, > ‘greater than, or < ‘less than.

The solutions are on the outside of the bigger circle, but inside of the smaller circle.

The radius of the bigger circle is 5 and the radius of the smaller circle is 4. The graph of the inequality is attached with the answer below.

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Answer:

it is 50%

Step-by-step explanation:

>:( im doing ixl and im in paine but here is the answer ok

Answer:

Step-by-step explanation:

the pidgeon is flying east

Answer:

D

Step-by-step explanation:

Answer:

D....................

coz 100 has 0 so the number should at least have 0 in it

Answer:

if I'm not mistaking (please correct if I'm wrong) but I think he would have 16 left.

Step-by-step explanation:

you have to divide one-fifth of 30 which would get you 6, then divide one-third of 24 ( because 30 - 6 is 24) then total both fractions to get 14. then finally subtract 14 from 30 to get 16.

Answer:

MN = 50

Step-by-step explanation:

Given:

PQ = 49 – 8x

MN = 41 + 3x

Required:

Measure of MN

Solution:

PQ = ½(MN) => Mid-segment theorem of a triangle

Substitute

49 - 8x = ½(41 + 3x)

Multiply both sides by 2

2(49 - 8x) = 41 + 3x

98 - 16x = 41 + 3x

Collect like terms

98 - 41 = 16x + 3x

57 = 19x

57/19 = 19x/19

3 = x

x = 3

Find MN:

MN = 41 + 3x

Plug in the value of x

MN = 41 + 3(3) = 41 + 9

MN = 50

Answer: With that assumption, we have a square, whose area is given by the formula Asquare=a2, and two semicircles. The distance D is simply the square's diagonal. The area of each semicircle is given by the formula Asemicircle=π*r2/2. then you will get your answer!

Answer:

I think the answer is option B

Answer:

I think it is (b

Step-by-step explanation:

Answer:

Arc GH = 78°

Step-by-step explanation:

Inscribed angle = m<GIH = 39°

Measure of arc related to inscribed angle = arc GH = ?

Thus:

m<GIH = ½(arc GH) => Inscribed angles theorem

Substitute

39° = ½(arc GH)

Multiply both sides by 2

2*39° = arc GH

78° = arc GH

Arc GH = 78°

Answer:

616

Step-by-step explanation:

A fraction that is equivalent to 38 is 616

Answer:

1496 cubic inches

Step-by-step explanation:

Answer:

A plane figure with 4 sides is called a quadrilateral.

Step-by-step explanation:

A plane figure bounded by more than four straight lines is generally referred to as a polygon. A polygon is a closed two-dimensional shape formed by connecting multiple line segments. The line segments, also known as sides, should intersect only at their endpoints, forming vertices of the polygon.

Polygons can have various numbers of sides, and their names are typically based on the number of sides they possess. Some common examples include triangles (3 sides), quadrilaterals (4 sides), pentagons (5 sides), hexagons (6 sides), and so on.

However, when the statement specifies that the plane figure is bounded by "more than four" straight lines, it suggests that the figure in question is a polygon with more than four sides. The exact name or classification of the polygon would depend on the specific number of sides it possesses.

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Step-by-step explanation:

pool = 1600 sq.cm

1600 sq.sm = 50cm × 32cm

AB = 50cm

the area of the park of A'B' :

50cm×4=200 sq.cm

Write a general formula to describe each variation.

The square of T varies directly with the cube of a and inversely with the square of d; T = 4 when a = 2 and d = 3

T² =  [tex]\frac{18a^3}{d^2}[/tex]

Few things to note:

i. direct variation: When a variable x varies directly with another variable y, we write it in this form;

x ∝ y.

This can then be written as;

x = ky

Where;

k = constant of proportionality variation.

ii. inverse variation: When a variable x varies inversely with another variable y, we write it in this form;

x ∝ [tex]\frac{1}{y}[/tex]

This can then be written as;

x = k([tex]\frac{1}{y}[/tex])

Where;

k = constant of proportionality or variation

iii. combined variation: When a variable x varies directly with variable y and inversely with variable z, we write it in this form;

x ∝ ([tex]\frac{y}{z}[/tex])

This can then be written as;

x = k ([tex]\frac{y}{z}[/tex])

Where;

k = constant of proportionality or variation

From the question;

The square of T varies directly with the cube of a and inversely with the square of d.

Note that

square of T = T²

cube of a = a³

square of d = d²

Therefore, we can write;

T² ∝ [tex]\frac{a^3}{d^2}[/tex]

=> T² =  k ([tex]\frac{a^3}{d^2}[/tex])        -------------------(i)

Since;

T = 4 when a = 2 and d = 3

We can find the constant of proportionality k, by substituting the values of T=4, a = 2 and d = 3 into equation (i) and solve as follows;

(4)² =  k ([tex]\frac{2^3}{3^2}[/tex])

16 =  k ([tex]\frac{8}{9}[/tex])

8k = 16 x 9

8k = 144

k = [tex]\frac{144}{8}[/tex]

k = 18

Now substitute the value of k back into equation (i);

T² =  18 ([tex]\frac{a^3}{d^2}[/tex])

T² =  [tex]\frac{18a^3}{d^2}[/tex]

Therefore, the general formula that describes the variation is;

T² =  [tex]\frac{18a^3}{d^2}[/tex]

Answer:

Step-by-step explanation:

============================================================

Explanation:

Ignoring the slashes, there are 8 digits here. If we could tell those '1's and '2's apart, then we'd have 8! = 40,320 different codes. The exclamation mark indicates a factorial.

However, the '1's and '2's are indistinguishable. We have to divide by a!*b! = 3!*3! = 6*6 = 36 to account for this.

The a! = 3! = 6 is from the fact we have 3 copies of '1'.

The b! = 3! = 6 is from the fact we have 3 copies of '2'

Dividing by 36 gets us (40,320)/36 = 1120

Answer:

a) The probability distribution is [tex]f(x) = \frac{1}{8}[/tex]

b) 0.5 = 50% probability that X will take on a value between 21 and 25.

c) 0.25 = 25% probability that X will take on a value of at least 26.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{a - x}{b - a}[/tex]

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

Uniform distribution over the interval from 20 to 28.

This means that [tex]a = 20, b = 28[/tex]

a. What’s the probability density function?

The probability density function of the uniform distribution is:

[tex]f(x) = \frac{1}{b - a}[/tex]

In this question:

[tex]f(x) = \frac{1}{28 - 20} = \frac{1}{8}[/tex]

b. What’s the probability that X will take on a value between 21 and 25?

[tex]P(21 \leq X \leq 25) = \frac{25 - 21}{28 - 20} = \frac{4}{8} = 0.5[/tex]

0.5 = 50% probability that X will take on a value between 21 and 25.

c. What’s the probability that X will take on a value of at least 26?

[tex]P(X > 26) = \frac{28 - 26}{28 - 20} = \frac{2}{8} = 0.25[/tex]

0.25 = 25% probability that X will take on a value of at least 26.

Answer:

A) 0.7696

B) 0.0474

C) Yes it's unusual

D) 0.05746

E) No, it is not unusual

F) No, it is not unusual

Step-by-step explanation:

This is a binomial probability distribution question.

We are told that 92.4% of those admitted graduated.

Thus; p = 92.4% = 0.924

From binomial probability distribution, q = 1 - p

Thus;

q = 1 - 0.924

q = 0.076

Formula for binomial probability distribution is;

P(x) = nCx × p^(x) × q^(n - x)

A) At least 11 graduated out of 12.

P(x ≥ 11) = P(11) + P(12)

P(11) = 12C11 × 0.924^(11) × 0.076^(12 - 11)

P(11) = 0.3823

P(12) = 12C12 × 0.924^(12) × 0.076^(12 - 12)

P(12) = 0.3873

P(x ≥ 11) = 0.3823 + 0.3873

P(x ≥ 11) = 0.7696

B) that exactly 9 of them graduated out of 12. This is;

P(9) = 12C9 × 0.924^(9) × 0.076^(12 - 9)

P(9) = 0.0474

C) We are not given significance level here but generally when not given we adopt a significance level of α = 0.05.

Now, exactly 9 out of 12 that graduated which is P(9) = 0.0474.

We see that 0.0474 is less than the significance level of 0.05. Thus, we can say that it is unusual to randomly select 12 students from the special programs and get exactly 9 that graduate

D) that at most 9 of them out of 12 graduated.

P(x ≤ 9) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)

This is going to be very long so I will make use of an online probability calculator to get the values of P(0) to P(8) since I already have P(9) as 0.0474.

Thus, we have;

P(0) = 0

P(1) = 0

P(2) = 0

P(3) = 0.00000001468

P(4) = 0.00000040161

P(5) = 0.00000781232

P(6) = 0.00011081163

P(7) = 0.00115477385

P(8) = 0.00877476184

Thus;

P(x ≤ 9) = 0 + 0 + 0 + 0.00000001468 + 0.00000040161 + 0.00000781232 + 0.00011081163 + 0.00115477385 + 0.00877476184 + 0.04741450256

P(x ≤ 9) = 0.05746

E) P(x ≤ 9) = 0.05746 is more than the significance level of 0.05, thus we will say it is not unusual.

F) from online binomial probability calculator, probability of getting only 9 out of 12 is more than the significance value of 0.05. Thus, we will say it is not unusual

Answer:

Option B

Step-by-step explanation:

9514 1404 393

Answer:

  f(x) = x(x-1) does not have an inverse function

Step-by-step explanation:

As you know, a function must be single-valued. That is, it can only have one y-value for each x-value.

If the inverse relation is to be a function, the original function must have only one x-value for each y-value. In general, even-degree polynomials, such as quadratic equations, cannot satisfy this requirement. This is often described as "the horizontal line test." That is, if a horizontal line intersects the graph in more than one place, the inverse relation is not a function.

The attachment shows a horizontal line intersecting f(x) = x(x-1) in more than one place. The inverse of this relation is not a function.

[tex] \rm{f(x) = x(x - 1)}[/tex]

[tex] \\ [/tex]

Answer:

Will take 8hrs.

Step-by-step explanation:

if pipe 1 takes 6 hrs then the 2nd pipe drains it 3x slower

Which means pipe 1 will take 1 hr slower every 3 hrs taken

and will be at ratio 3:2 for when pipe 2 is used

6 + 2 = 8 (hrs)

Will take 8hrs.

Answer:

the y-coordinate will be at (0, 2.4)

the x-coordinate will be at (6, 0)

Step-by-step explanation:

y coordinate of the graph is the point where the curve cuts the y axis

According to the graph, the curve cuts the y axis at y = 2.4. Hence the y-coordinate will be at (0, 2.4)

Similarly, the x-coordinate of the graph is the point where the curve cuts the x-axis

According to the graph, the curve cuts the x-axis at x = 6. Hence the x-coordinate will be at (6, 0)

Answer:

[tex] P \geq 1000 \; meters [/tex]

Step-by-step explanation:

Given the following data;

Length = 312 meters

Breadth = 186 meters

To find the perimeter of the rectangle;

Mathematically, the perimeter of a rectangle is given by the formula;

Perimeter = 2(L + W)

Perimeter = 2(312 + 186)

Perimeter = 2(498)

Perimeter = 996 meters

To the nearest meters, we have;

Perimeter = 996 ≈ 1000 meters

Let P represent the perimeter of a rectangular field.

900 < P > 1000

Therefore, [tex] P \geq 1000 \; meters[/tex]