The first three terms of the binomial expansion of (2 – ax)" are 64 – 16bx +100bx?.
Find the value of each of the integers n, a and b.

Ans: n=6, a=5, b=60

The First Three Terms Of The Binomial Expansion Of (2 Ax)" Are 64 16bx +100bx?.Find The Value Of Each

Answers

Answer 1

Answer:

n = 6, a = 5, b = 60

Step-by-step explanation:

In a binomial function (a + b)ⁿ expression that represents the terms,

(a + b)ⁿ = [tex]\sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^k[/tex]

By this formula,

1st term = [tex]\binom{n}{0}a^{n-0}b^0[/tex] = aⁿ

2nd term = [tex]\binom{n}{1}a^{n-1}b^1[/tex] = [tex]n.a^{n-1}b^1[/tex]

3rd term = [tex]\binom{n}{2}a^{n-2}b^2[/tex] = [tex]\frac{n(n-1)}{2}.a^{n-2}.b^2[/tex]

For the binomial expansion initial 3 terms of (2 - ax)ⁿ = 64 - 16bx + 100bx²

Terms of (2 - ax)ⁿ = [tex]2^n+n(2)^{n-1}(-ax)+\frac{n(n-1)}{2}(2)^{n-2}(-ax)^2[/tex]

                             = [tex]2^n-n(2)^{n-1}(ax)+n(n-1)(2)^{n-3}(a^2x^2)[/tex]

Comparing the terms of both the expansions,

1st term

2ⁿ = 64

2ⁿ = 2⁶

n = 6

2d term

[tex]n(2)^{n-1}(ax)=16bx[/tex]

[tex]6(2)^{6-1}(a)=16b[/tex]

192a = 16b

b = 12a -----(1)

3rd term

[tex]n(n-1)2^{n-3}(a^2x^2)=100bx^2[/tex]

[tex]6(6-1)2^{(6-3)}(a^2)=100b[/tex]

[tex]30(2)^3(a^2)=100b[/tex]

240a² = 100b

b = 2.4a² -----(2)

From equation (1) and (2),

b = 12a = 2.4a²

a = [tex]\frac{12}{2.4}=5[/tex]

From equation (1)

b = 12a = 60

Therefore, n = 6, a = 5, b = 60


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1. 133 1/3% of 36=?
2. 260% of 360=?

Answers

Answer:

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2. 260% of 360=936

Step-by-step explanation:

1. 133 1/3% of 36

=(133 1/3)%  of 36

=(133/1+1/3)% of 36

=(399+1/3)% of 36

=(400/3)% of 36

=(400/3 *100) *36

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---------------------------------------------------------------------------------------

2. 260% of 360

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=26/1*36

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Answers

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Step-by-step explanation:

Answer: Figure J

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Answer:

Step-by-step explanation:

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A rectangular frame has length (x+2) units and width (x-2) units. If the area is 96 square units, what is the value of x?

Answers

Answer:

x=10

Step-by-step explanation:

according to the question

(x+2)(x-2)=96

=>x^2-4=96

=>x^2=96+4

=>x^2=100

=>x=√100

Therefore

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Answer:

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Step-by-step explanation:

As we know that the area of a rectangle is defined by multiplying the length by the width.

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Given

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[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{100},\:x=-\sqrt{100}[/tex]

[tex]x=10,\:x=-10[/tex]

Putting x = -10 in the length and width will make the length and width negative, which can not be possible.

i.e.

length = l = x+2 = -10+2 = -8 units

width = w = x-2 = -10-2 = -12 units

Therefore, x=-10 must be excluded.

Now, putting the length of x = 10.

i.e.

length = l = 10+2 = 10+2 = 12 units

width = w = x-2 = 10-2 = 8

[tex]A=l\times w[/tex]

96 = 12 × 8

96 = 96

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Step-by-step explanation:

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Answers

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25

Step-by-step explanation:

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Step-by-step explanation:

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1/4

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Answers

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no

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NO

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