Please help me solve this problem
What is the area of a regular pentagon with an 8-cm
apothem and 11.6-cm sides?
✓
Sub
Answers
Answer:
232.5 cm²
Step-by-step explanation:
232.5
The required area of the regular pentagon with an 8-cm apothem and 11.6-cm sides is 232 cm².
What is surface area?The surface area of any shape is the area of the shape that is faced or the Surface area is the amount of area covering the exterior of a 3D shape.
Here,
To find the area of a regular pentagon, we can use the formula:
Area = (1/2) x Apothem x Perimeter
where Apothem is the distance from the center of the pentagon to the midpoint of any side, and Perimeter is the sum of the lengths of all the sides.
In this case, the apothem is given as 8 cm, and the length of each side is given as 11.6 cm.
To find the perimeter, we can simply multiply the length of one side by 5:
Perimeter = 5 x 11.6 cm = 58 cm
Now, we can plug in these values into the formula:
Area = (1/2) x 8 cm x 58 cm
Area = 232 cm²
Therefore, the area of the regular pentagon with an 8-cm apothem and 11.6-cm sides is 232 cm².
Learn more about the surface area here: https://brainly.com/question/2835293
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Answer:
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Step-by-step explanation:
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3
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Explanation:
Density of an object is defined as the mass occupied per unit volume. “Density” is represented by “ρ”. Mathematically, \rho=\frac{m}{v}ρ=
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\text { Volume of the block is } l \times b \times h Volume of the block is l×b×h
\text { Volume of the block is } 20 \times 5 \times 10 Volume of the block is 20×5×10
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.
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Substitute the given values in \rho=\frac{m}{v}ρ=
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m
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1000
2700
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3
\text { "Density" of the given granite block is } 2.7 \mathrm{g} / \mathrm{cm}^{3} "Density" of the given granite block is 2.7g/cm
3