Lenses:
reflect light.
can only be concave.
do not have an optical axis.
None of the choices are correct.

[tex]\huge{\green}\fcolorbox{blue}{black}{\bf{\underline{\red{\color{brown}Answer}}}}[/tex]

4.44l

Explanation:

[tex] \sf Volume \: of \: gas \: before(V_1) = 2.7 \: l \\ \sf Pressure \: of \: gas \: before(P_1) = 0.63 \: atm \\ \sf 0.63 \times 101.3 = 63.8 \: kPa \\ \sf Volume \: of \: gas \: after(V_2) = ? \\ \sf Pressure \: of \: gas \: after( P_2) = 105 \: kPa[/tex]

[tex] \textsf{ By using Boyle's law} \\ \\ \tt{ \frac{P_1}{V_1} = \frac{P_2}{V_2} }[/tex]

[tex] \sf \longrightarrow \frac{2.70}{63.8} = \frac{V_2}{105} \\ \\ \\ \sf \longrightarrow \frac{2.7 \times 105}{63.8} = V_2 \\ \\ \\ \sf \longrightarrow \frac{283.5}{63.8} = V_2 \\ \\ \\ {\orange {\boxed{ \longrightarrow 4.44 \: l = V_2}}}[/tex]

Answer:

1.47

Explanation:

acellus

The correct procedure is:

Dissolving 45 g of NaOH in enough water to make up to 750 mL of solution

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = Molarity x Volume

Mole of NaOH = 1.5 × 0.75

Mole of NaOH = 1.125 mole

Mass = mole × molar mass

Mass of NaOH = 1.125 × 40

Mass of NaOH = 45 g

Thus, to obtain 750 mL of 1.5 M NaOH solution, 45 g of NaOH will be dissolved in enough water to make up to 750 mL of solution

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The weather station is a place which contain instrument that collect data of atmospheric pressure, wind, humidity, etc to forecast weather. The weather station is powered by solar power.

A weather station is a place that measure atmospheric conditions, on the basis of temp., pressure, wind speed, etc conditions.

They can be based either in land or sea. They are necessary to forecast any disaster, so we can prepare for the disaster.

Thus, the weather station is a place which contain instrument that collect data of atmospheric pressure, wind, humidity, etc to forecast weather. The weather station is powered by solar power.

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The rate law depends on only A because it is the reactant in the rate-determining step.

The rate law is a representation of the rate of reaction. The fast reaction is  E+B ------> A+ D. The slow reaction is A + A ----->C + E. The overall reaction is A + B ------> C + D.

We know that the rate law depends  only on the  the slow reaction hence the rate law depends on only A because it is the reactant in the rate-determining step.

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The statement that describes what makes a base weak is that the base will be unable to dissociate completely in water.

A base is any of a class of generally water-soluble compounds, having bitter taste, that turn red litmus blue, and react with acids to form salts.

Bases usually dissociate into hydroxide ions (OH-) when in an aqueous solution.

However, a base is termed weak or strong depending on it's ability to dissociate completely. A weak base does not dissociate completely into hydroxide ions when in an aqueous solution.

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Answer:

sdfffffffff

Explanation:

dfffffgsdsdsdsdsdsdsdsdsdsdsdsdsdsdsd

No of moles

[tex]\\ \rm\Rrightarrow \dfrac{No\:of\: molecules}{Avagadro\:no}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{10.82\times 10^{23}}{6.023\times 10^{23}}[/tex]

[tex]\\ \rm\Rrightarrow 1.80mol[/tex]

So

[tex]\boxed{\sf No\:of\: molecules=No\:of\:moles\times Avagadro\:no}[/tex]

[tex]\\ \tt{:}\longrightarrow 10.82\times 10^{23}=n\times 6.023\times 10^{23}[/tex]

[tex]\\ \tt{:}\longrightarrow n=\dfrac{10.82}{6.023}[/tex]

[tex]\\ \tt{:}\longrightarrow n=1.8mol[/tex]

Answer:

6.850767 grams is the answer

[tex]0.987 ~ \text{moles of Li} = 0.987 \times \text{Molar mass of Li}\\\\~~~~~~~~~~~~~~~~~~~~~~~=0.987 \times 6.941~ g\\\\~~~~~~~~~~~~~~~~~~~~~~~=6.850767~ g[/tex]

Answer:

Solid have the lowest entropy

The role of oxygen in cellular respiration is to make water molecules. hence, option (D) is correct.

Cellular respiration is the process in which cells break down molecules for energy.

The cells use oxygen to break down food in the form of glucose to produce water and release carbon dioxide.

During aerobic cellular respiration, glucose reacts with oxygen, forming ATP that can be used by the cell. Carbon dioxide and water are created as byproducts.

In this reaction, energy is produced in the form of ATP that is used by the cell for its various activities.

Thus the correct answer is option D.

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Answer: It is approximately 24.985837

Answer:

0.625 moles MgCl₂

Explanation:

Since you were given a molarity value and volume, you should use the molarity equation to find moles. The equation looks like this:

Molarity (M) = moles / volume (L)

To find moles, you need to (1) convert mL to L (by dividing by 1,000) and then (2) plug the numbers into the formula and simplify to find moles. The final answer should have 3 sig figs as the lowest amount of sig figs in a given value is 3.

Step 1:

650.0 mL / 1,000 = 0.6500 L

Step 2:

Molarity = moles / volume

0.962 M = moles / 0.6500 L

(0.962 M) x (0.6500 L) = moles

0.625 = moles

The central oxygen atom is a state of sp3 hybridization having only one available lone pair.

The term hybridization refers to the mixing of two or more atomic orbitals to yield hybrid orbitals that are suitable for bonding.

Looking at the ion H3O^+, we can see that the central oxygen atom is a state of sp3 hybridization having only one available lone pair. The image of the ion is shown here.

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The purpose of classification is to identify objects with common or similar properties.

A mixture is composed of one or more pure substances in varying compositions.

It's important for scientists to know the properties of matter because all things are made up of matter.

Each type of matter has different physical characteristics and scientists need to know and understand these characteristics to make calculations.

The main phases of matter are solid liquid and gas.

Hence, the purpose of classification is to identify objects with common or similar properties.

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Answer:

1,063 grams H₃PO₄

Explanation:

To find the mass of phosphoric acid (H₃PO₄), you should (1) convert molecules to moles (via Avogadro's number) and then (2) convert moles to grams (via molar mass from periodic table).

Molar Mass (H₃PO₄): 3(1.008 g/mol) + 30.974 g/mol + 4(15.998 g/mol)

Molar Mas (H₃PO₄): 97.99 g/mol

6.534 x 10²⁴ molecules H₃PO₄                       1 mole                         97.99 g
---------------------------------------------  x  -------------------------------------  x  --------------
                                                            6.022 x 10²³ molecules          1 mole

= 1,063 grams H₃PO₄

No of molecules=26.02×10²³molecules

No of moles

Molar mass

Mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{Molecules}{Avagadro\:no}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{26.02\times 10^{23}}{6.023\times 10^{23}}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=4.32mol[/tex]

We need the mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles\times molar\:mass[/tex]

[tex]\\ \tt{:}\longrightarrow 32(4.32)[/tex]

[tex]\\ \tt{:}\longrightarrow 138.24g[/tex]

Answer:

1.90 M

Explanation:

To find the molarity of the solution, you need to use the molarity equation. This formula looks like this:

Molarity (M) = moles / volume (L)

To use this equation, you need to perform some conversions. You should (1) convert mL to L (by dividing by 1,000), then (2) convert grams NaNO₃ to moles (via molar mass), then (3) plug moles and volume into the molarity equation.

155 mL / 1,000 = 0.155 L

25.0 g NaNO₃           1 mole
---------------------  x  -----------------  = 0.294 moles NaNO₃
                                  85.0 g

Molarity = moles / volume

Molarity = 0.294 moles / 0.155 L

Molarity = 1.8975....

Molarity = 1.90 M

The relation between the volume and the pressure of the gas can be given by the ideal gas equation. Warm air has more volume and low pressure that makes them rise above the equator.

Pressure present and exerted by the atmospheric gases are called atmospheric pressure. The volume of the gas is in inverse relation to the pressure of the gas.

Warm air has a high volume compared to cold air. More volume results in low pressure making them rise above the dense layer of the equator region.

Therefore, the warm air rises due to a decrease in pressure.

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The source that is unreliable is an advertisement for acne medication claims it can clear up acne in less than one week.

Citable sources are those sources that are gotten from places that are proven to be of good standards and not from mere claims such as:

Therefore, the source that is unreliable is an advertisement for acne medication claims it can clear up acne in less than one week.

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Answer:

since water boil at 100 °C .so 500gof water Will still boil at 100 °C

Answer:

194 mm Hg or 193.8mm Hg

Explanation:

273+18=291 K

2.35g /44

=0.0534 moles

P=0.0534 mol×0.082×29 / 5L

=0.2548 atm

0.255 × 760

=193.8 mmHg

Answer:

223.5 g

Explanation:

The formula between the number of moles, mass and Mr can be used to convert moles to grams.

Number of moles = mass ÷ Mr

So, mass = number of moles × Mr

  Mr of Li₂O = (6.9 × 2) + 16 = 29.8

∴ Mass = 7.5 × 29.8 = 223.5 g

Answer: 0

Explanation:

If 3 electrons were to be gained, then the number of protons would equal the number of electrons.

In one trial, the unique rate of reaction was 6.93 μmol⋅L−1⋅s−1, the initial rate is 17.4 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex] and rate of formation of sulfate ions was 11.6 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex]

Reaction rate, in chemistry, is the speed at which a chemical reaction proceeds.

[tex](S_2O_8)^-^2 (aq) + 3 I^-(aq)[/tex] → [tex]2 S0_4^-^2 (aq) + 3I^- (aq)[/tex]

Rate of the reaction = -Δ [[tex]S_20_8^-^2[/tex]] /Δ t = -1/3 Δ [[tex]I^-[/tex]] /Δ t

5.8  μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex] = -1/3 Δ [[tex]I^-[/tex]] /Δ t

-Δ [[tex]I^-[/tex]] /Δ t =17.4 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex]

So the rate of reaction of iodide ion =17.4 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex]

+1/2Δ [[tex]S0_4^-^2[/tex]] /Δ t  = rate of reaction

+1/2Δ [[tex]S0_4^-^2[/tex]] /Δ t  = 5.8 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex]

+ Δ [[tex]S0_4^-^2[/tex]] /Δ t  = 5.8 X 2 = 11.6 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex]

Rate of formation of sulfate ions=11.6 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex]

Hence, the initial rate is 17.4 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex] and rate of formation of sulfate ions was 11.6 μmol⋅[tex]l^-^1[/tex]⋅[tex]s^-^1[/tex]

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The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;

H₂CO3 ⇄ 2H⁺  + CO₃²⁻

x         :      2x        x

ksp = (2x)²x

ksp = 4x³

(1.8 x 10⁻¹⁴) = 4x³

(1.8 x 10⁻¹⁴) /4 = x³

4.5 x 10⁻¹⁵ = x³

x = (4.5 x 10⁻¹⁵)^¹/₃

x = 1.65 x 10⁻⁵ mol/dm³

Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

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The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

Solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

The equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is calculated as follows;

H₂CO3 ⇄ 2H⁺  + CO₃²⁻

x         :      2x        x

ksp = (2x)²x

ksp = 4x³

(1.8 x 10⁻¹⁴) = 4x³

(1.8 x 10⁻¹⁴) /4 = x³

4.5 x 10⁻¹⁵ = x³

x = [tex](4.5 X 10^{-15})^{\frac{1}{3} }[/tex]

x = 1.65 x 10⁻⁵ mol/dm³

Thus, the equilibrium solubility of cadmium carbonate in a solution at constant pH of 11 is 1.65 x 10⁻⁵ mol/dm³.

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Answer:

When we combine oxygen, and iron rust is produce.

Explanation:

The iron reacts with water and oxygen to form hydrated iron(III) oxide, which we see as rust. Iron and steel rust when they come into contact with water and oxygen – both are needed for rusting to occur.

Answer:

Discussion: Red cabbage is useful as a pH indicator because the leaves contain a pigment molecule from the family of anthocyanins (shown below) which are responsible for many of the red/purple/blue colors observed in fruits and vegetables. In neutral solutions, the color observed is purple.

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5.00 grams of solid citric acid (solute) is dissolved in 500.00 ml of water (solvent) to make aqueous citric acid (solution).

A solution is a homogeneous mixture prepared by dissolving a solute in a solvent.

5.00 grams of solid citric acid is dissolved in 500.00 ml of water to make aqueous citric acid.

In this example:

5.00 grams of solid citric acid (solute) is dissolved in 500.00 ml of water (solvent) to make aqueous citric acid (solution).

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