Answer: The mass of [tex]CO_2[/tex] produced is 12.32 g
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
For ethane:Given mass of ethane = 4.21 g
Molar mass of ethane = 30 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of ethane}=\frac{4.21g}{30g/mol}=0.140mol[/tex]
For oxygen gas:Given mass of oxygen gas = 31.9 g
Molar mass of oxygen gas= 32 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen gas}=\frac{31.9g}{32g/mol}=0.997mol[/tex]
The chemical equation for the combustion of ethane follows:
[tex]2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O[/tex]
By stoichiometry of the reaction:
If 2 moles of ethane reacts with 7 moles of oxygen gas
So, 0.140 moles of ethane will react with = [tex]\frac{7}{2}\times 0.140=0.49mol[/tex] of oxygen gas
As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.
Thus, ethane is considered a limiting reagent because it limits the formation of the product.
By the stoichiometry of the reaction:
If 2 moles of ethane produces 4 moles of [tex]CO_2[/tex]
So, 0.140 moles of ethane will produce = [tex]\frac{4}{2}\times 0.140=0.28mol[/tex] of [tex]CO_2[/tex]
We know, molar mass of [tex]CO_2[/tex] = 44 g/mol
Putting values in above equation, we get:
[tex]\text{Mass of }CO_2=(0.28mol\times 44g/mol)=12.32g[/tex]
Hence, the mass of [tex]CO_2[/tex] produced is 12.32 g
What will be the pH change when 20.0 mL of 0.100 M NaOH is added to 80.0 mL of a buffer solution consisting of 0.163 M NH3 and 0.188 M NH4Cl
Answer:
[tex]pH=9.32[/tex]
Explanation:
Hello there!
In this case, according to the given scenario, it turns out necessary for us to realize that the addition of NaOH consumes the conjugate base, NH4Cl, and produces more base, NH3; that is why the reaction taking place is:
[tex]NH_4^++OH^-\rightarrow NH_3+H_2O[/tex]
Thus, the reacting moles of ammonium and hydroxide ions are:
[tex]n_{NH_4^+}=0.0800L*0.188mol/L=0.01504mol\\\\n_{OH^-}=0.0200L*0.100mol/L=0.00200mol[/tex]
Thus, the resulting moles of ammonium and ammonia are respectively:
[tex]n_{NH_4^+}=0.01504mol-0.00200mol=0.01304mol\\\\n_{OH^-}=0.0800L*0.163mol/L+0.00200mol=0.01504mol[/tex]
Then, by using the Henderson-Hasselbach equation and recalling the pKb of ammonia (4.74), we first calculate the pOH as follows:
[tex]pOH=pKb+log(\frac{n_{NH_4^+}}{n_{NH_3}} )\\\\pOH=4.74+log(\frac{0.01304mol}{0.01504mol} )\\\\pOH=4.68[/tex]
And finally the pH:
[tex]pH=14-4.68\\\\pH=9.32[/tex]
Regards!
Identify whether longhand notation or noble-gas notation was used in each case below.
Answer:
The given electronic configuration is long hand notation.
Explanation:
Long-hand notation of representing electronic configuration is defined as the arrangement of total number of electrons that are present in an element.
Noble-gas notation of representing electronic configuration is defined as the arrangement of valence electrons in the element. The core electrons are represented as the previous noble gas of the element that is considered.
The given electronic configuration of potassium (K):
The above configuration has all the electrons that are contained in the nucleus of an element. Thus, this configuration is a long-hand notation.
Refer to your completed Table 1d of the recitation guide of ionic compound naming rules to determine whether this statement is true or false. A Roman numeral in a compound name tells you how many of that ion appear in the formula. Select one: True False
Answer:
False
Explanation:
Roman numerals are seen in the names of several compounds. They often appear immediately after the name of central atom in the molecule.
These Roman numerals are used to depict the oxidation state of the central atom in the molecule and not to show how many of that ion appear in the formula.
For instance, in carbon IV oxide, the Roman numeral IV shows that the central atom in the compound-carbon is in the +4 oxidation state.
A mixture of sulfuric acid and nitric acid will produce small quantities of the nitronium ion (NO2 ): The nitronium ion has a central nitrogen atom with a positive charge double bonded to two oxygen atoms on both sides. Each oxygen atom carries two lone pairs of electrons. Does the nitronium ion have any significant resonance structures
Answer:
A mixture of sulfuric acid and nitric acid will produce small quantities of the nitronium ion (NO2 ): The nitronium ion has a central nitrogen atom with a positive charge double bonded to two oxygen atoms on both sides. Each oxygen atom carries two lone pairs of electrons. Does the nitronium ion have any significant resonance structures?
Explanation:
The structure of nitronium ion is shown below:
Any molecule to exhibit resonance, it should have alternating double bonds.
Resonance is the phenomenon in which the structure of a molecule can be represented in two or more forms and each form is called canonical form.
The canonical forms do not differ in the position of atoms and they differ only in the position of double bonds.
For the given molecule, there are no alternating double bonds.
Hence, nitronium ion does not exhibit any significant resonance structures.
If the H3O is 4.950 x 10-12 what is the ph?
Answer:
pH = 11.3
Explanation:
From the question given above, the following data were obtained:
Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M
pH =.?
The pH of a solution is defined by the following equation:
pH = –Log [H₃O⁺]
Thus, with the above formula, we can obtain the pH of the solution as follow:
Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M
pH =.?
pH = –Log [H₃O⁺]
pH = –Log 4.950×10¯¹²
pH = 11.3
3CaCl2 + 2AlF3 --> 3CaF2 + 2AlCl3 3CaCl2 + 2AlF3 --> 3CaF2 + 2AlCl3 How many grams of CaF2 will form from 36.5 grams of AlF3?
Answer:
32.1 g
Explanation:
3CaCl₂ + 2AlF₃ → 3CaF₂ + 2AlCl₃
First we convert 36.5 g of AlF₃ into moles, using its molar mass:
36.5 g ÷ 133.34 g/mol = 0.274 mol AlF₃
Then we convert 0.274 moles of AlF₃ into moles of CaF₂, using the stoichiometric coefficients of the reaction:
0.274 mol AlF₃ * [tex]\frac{3molCaF_2}{2molAlF_3}[/tex] = 0.411 mol CaF₂
Finally we convert 0.411 moles of CaF₂ into grams, using its molar mass:
0.411 mol * 78.07 g/mol = 32.1 g
A bag of gumdrops contains 17 orange gumdrops, 10 yellow gumdrops, and 18 black gumdrops.
What is the percent of yellow gumdrops?
Express your answer to two significant figures and include the appropriate units.
Answer:
Total number of gum drops = 10 + 17 +18
= 45
Explanation:
[tex] \frac{10}{45} \times 100 \\ = 22.222222\ \ \% \\ 22\% \: gum \: drops \: \\ to \: 2 \: sf[/tex]
Describe the three freezing points. Is there a relationship between the amount of solute in the solution and the freezing temperature
Answer:
The three freezing points will all be slightly different. It is given that a water solution has a freezing point of zero degrees Celsius, so water would have a freezing temperature below that. Salt will lower the freezing point, the more that is added.
Explanation:
explain how the solid liquid line in the phase diagram of water differs in character from the solid liquid line in the phase diagrams of most other substances such as CO2
Answer:
The solid-liquid line in the water phase diagram has a negative slope, whereas for most other substances it has a positive slope.
The ice has a lower density as compared to water still they have in the solid phase.
Reason how the solid-liquid line in the phase diagram as compared to other:In the solid-liquid line in the water phase diagram it contains the negative slope. While the most other substance should have the positive slope.
Also, when the pressure is applied so the higher density should be favored. In the water, the highest density phase should be likely the liquid water.
Learn more about liquid here: https://brainly.com/question/17109464
What are the free moving, charged particles in a molten mixture of aluminium oxide and cryolite?
Answer:
Ions.
Explanation:
Ions are the free moving, charged particles in a molten mixture of aluminum oxide and cryolite because the liquid state loosely held the molecules and the the molecules can easily move from one place to another. These ions helps in the conduction of electricity in the solution due to its free movement so we can say that ions are the charge particles that moves freely in the mixture of aluminum oxide and cryolite.
The free moving, charged particles in a molten mixture of aluminium oxide
and cryolite are known as Ions.
Ions are referred to an atom or compound which possesses an electrical
charge.The charge could be positive or negative and the positive ions are
called cations while the negative ions are referred to an anions.
Ions are usually free moving, take part in chemical reactions and help to
conduct electricity as a result of them being transferred from one point to
another.
Read more on https://brainly.com/question/7222067
is Decanitrogen tetroxide Ionic or Molecular
Answer:
Decanitrogen is molecular
Explanation:
Answer:
Dec a nitrogen is Molecular
Explanation:
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"A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
"
Answer:
42000km
Explanation:
Average Speed (v) can be calculated using the formula as follows:
Average speed = distance (d) ÷ time (t)
According to this question, a space shuttle travels around the Earth at a constant speed of 28000 km/hr in 90 minutes.
Since 60 minutes = 1 hr
90 minutes = 90/60
= 3/2 or 1.5hours.
Using speed = distance/time
Distance (km) = speed × time
Distance = 28000 km/hr × 1.5hr
Distance = 42000km
how to calculate moles
Explanation:
First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.
For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.
Answer:
Number of moles : Mass (g) ÷ relative atomic mass
The table below provides data about a gas sample.
Volume
1.0 L
Pressure
303.9 kPa
Temperature
323 K
Which of the following can be determined using the data?
A the chemical composition of the gas
B. the condensation temperature of the gas
C. the distance between gas molecules in the sample
D. the number of gas molecules in the sample
Answer:
the number of gas molecules in the sample
which of the following illustrates a reversible change a cooking corn be rusting c frying egg and the boiling water
Cyclopropane is more reactive than most cycloalkanes. What factors lead to cyclopropane being less stable than the other cycloalkanes
Answer: The factor that lead to cyclopropane being less stable than the other cycloalkanes is the presence of a RING STRAIN.
Explanation:
In organic chemistry, the end carbon atoms of an open aliphatic chain can join together to form a closed system or ring to form cycloalkanes. Such compounds are known as cyclic compounds. Examples include cyclopropane, cyclobutane, cyclopentane and many among others.
Cyclopropane is less stable than other cycloalkanes mentioned above because of the presence of ring strain in its structural arrangement. The ring strain is the spatial orientation of atoms of the cycloalkane compounds which tend to give off a very high and non favourable energy. The release of heat energy which is stored in the bonds and molecules cause the ring to be UNSTABLE and REACTIVE.
The presence of the ring strain affects mainly the structures and the conformational function of the smaller cycloalkanes. cyclopropane, which is the smallest cycloalkane than the rest mentioned above, contains only 3 carbons with a small ring.
A man of 450 N covers an area of 0.0015m2 while standing on his feet.calculate the pressure exerted by him on the ground.
Answer:
3×10⁵ N/m²
Explanation:
From the question given above, the following data were obtained:
Force (F) = 450 N
Area (A) = 0.0015 m²
Pressure (P) =?
Pressure is simply defined as the force per unit area. Mathematically, it is expressed as:
Pressure (P) = Force (F) / Area (A)
P = F/A
With the above formula, we can obtain the pressure exerted by the man on the ground. This can be obtained as follow:
Force (F) = 450 N
Area (A) = 0.0015 m²
Pressure (P) =?
P = F/A
P = 450 /0.0015
P = 3×10⁵ N/m²
Thus, the pressure exerted by the man on the ground is 3×10⁵ N/m².
Name an alkene that would yield the alcohol above on hydration. (Submit a single name even if there is more than one correct answer. Ignore double bond stereochemistry.) Name: fill in the blank 75a878faaf91fe7_1 2,3-Dimethylpentane . Specify whether you would use hydroboration/oxidation or oxymercuration.
Answer:
Enzyme ? ...............
someone answer please
Answer:
A
Explanation:
9. The formular for finding the area
of an object is
A. Length + Width
B. Length - Width
C. Length : Width
D. Length x Width
E. 2 (Length + Width)
ans
Answer:
D. length × width
Explanation:
eg. 30 cm(length) × 20cm(width) = 600cm²
The combination of isotopes of hydrogen characterized by emmision of radiation is believed to take place in the
a. sun
b. galaxy
c. moon
d. star
Which of the following would eat a dead rabbit?
Herbivore
Carnivore
Omnivore
Detritivore
Please help
Detritivore
Explanation:
they eat the dead things
The most intense line in the emission spectrum for sodium appears at a wavelength of 589 nm. What color would you expect to observe when a solution that contains sodium ions is heated strongly in the flame of a Bunsen burner
Answer:
The most intense line in the emission spectrum for sodium appears at a wavelength of 589 nm.
What color would you expect to observe when a solution that contains sodium ions is heated strongly in the flame of a Bunsen burner?
Explanation:
Put a clean wire loop in a solid sample of the compound containing sodium ions, then keep it on the blue flame of the Bunsen burner.
The color of sodium ions in the Bunsen burner shows charactrestic yellow color.
True or false? An organism may play more than one role in a food web
Answer:
true
Explanation:
because an organism have many roles in food web
54.56 g of water at 80.4 oC is added to a calorimeter that contains 47.24 g of water at 40 oC. If the final temperature of the system is 59.4 oC, what is the calorimeter constant (C calorimeter)
Answer:
49.5J/°C
Explanation:
The hot water lost some energy that is gained for cold water and the calorimeter.
The equation is:
Q(Hot water) = Q(Cold water) + Q(Calorimeter)
Where:
Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J
Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J
That means the heat gained by the calorimeter is
Q(Calorimeter) = 4794J - 3834J = 960J
The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:
59.4°C-40°C = 19.4°C
And calorimeter constant is:
960J/19.4°C =
49.5J/°C
What is the overall charge of an ion that has 31 protons, 36 electrons, and 30 neutrons?
Answer:
(d) the ion with 24 electrons, 30 neutrons, and a 3+ charge ... (b) the ion with 36 electrons, 35 protons, and 45 neutrons.
what is the importance of energy in humans
Explanation:
Energy is essential to life and all living organisms. The sun, directly or indirectly, is the source of all the energy available on Earth. Our energy choices and decisions impact Earth's natural systems in ways we may not be aware of, so it is essential that we choose our energy sources carefully
How do I balance this?
_CuC12 + _NaNO3 → _CU(NO3)2 + _ NaC1
[tex]CuCl_2+2NaNO_3 \rightarrow Cu(NO_3)_2 + 2NaCl[/tex]
propose a synthetic route for the synthesis of a named alkanal starting with ethyl formate and grignard reagent.
Answer:
See explanation and image attached
Explanation:
A Grignard reagent is an alkyl magnesium halide. If it reacts with ethyl formate, an intermediate is formed as shown.
This intermediate can undergo water hydrolysis to form a diol, ethanol and MgBrOH.
Oxidation of the diol obtained now yields the corresponding alkanal which in this case is ethanal.
The scheme of the reaction is shown in the image attached to this answer.
Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4.
What is the percent yield for Scientist A?
What is the percent yield for Scientist B?
You must show all work to receive full credit.
The equation for the production of potassium permanganate is as follows:
2 MnO2 + 2 KOH + O2 → 2 KMnO4 + H2
Answer:
[tex]Y_A=92.1\%\\\\Y_B=89.6\%[/tex]
Explanation:
Hello there!
In this case, according to the given chemical equation for the reaction for the production of potassium permanganate, we can see a 2:2 mole ratio of this product to the starting manganese (II) oxide, which means, we can calculate the theoretical yield of the former via stoichiometry:
[tex]m_{KMnO_4}=50.0gMnO_2*\frac{1molMnO_2}{86.94gMnO_2}*\frac{2molKMnO_4}{2molMnO_2} *\frac{158.034gKMnO_4}{1molKMnO_4} \\\\m_{KMnO_4}=90.9gKMnO_4[/tex]
Now, we are able to compute the percent yields, by using the actual yield each scientist got:
[tex]Y_A=\frac{83.67g}{90.9g} *100\%=92.1\%\\\\Y_B=\frac{81.35g}{90.9g} *100\%=89.6\%[/tex]
Regards!