A rock is dropped from a hot air balloon at a height of 100 meters. The rock's
height from the ground in meters, h(t), is modeled by the formula
h(t) = -4.9ť + 100, where t is the time in seconds.
What is the average rate of change in m/s of the height of the rock between 2 and
4 seconds?
A. -4.9
B. -9.8
c.-29.4
D. -58.8

Answers

Answer 1

Answer:

-29.4

i was told trust me ig?

Answer 2

The average rate of change in m/s of the height of the rock between 2 and 4 seconds is -4.9.

What is average?

The average is defined as the mean value of the given data which is equal to the ratio of the sum of the data value to the total number of units present in the data.

Average = the sum of the data value / the total number of units

The rock's height from the ground in meters, h(t), is modeled by the formula h(t) = -4.9ť + 100,

where t is the time in seconds.

At t = 2 seconds

h(t) = -4.9ť + 100

h(t) = -4.9(2) + 100

     = 90.2

At t = 4 seconds

h(t) = -4.9ť + 100

h(t) = -4.9(4) + 100

     = 80.4

The average rate of change in m/s of the height of the rock is between 2 and 4 seconds

              = 80.4 - 90.2 / 2

              = - 4.9

Thus, the correct option is A.

Learn more about average here;

https://brainly.com/question/13496328


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Hello again! Your answer is C! (Sorry this is an edit)

Step-by-step explanation:

(8 x 10) + (9 x 1) + (4 x 1/10)

im not exactly sure how to explain this, but I studied this in 3rd grade so I believe I’m correct... if you solve the question, you’ll get 89.04

i can try my best to explain below...

I’ll start with the first part of the equation.

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now we already simplified the equation: 80 + 9 + 0.04

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