a.) Determine the work done by Zach on the bull.

 [tex]\huge\text{Graphs:}[/tex]

The graph of  

• The I-V for Ohmic Metal wire conductor at constant temperature  always shows a straight line between the Current(I) plotted at Y axis and Voltage(V) plotted at X axis. Picture 1

• The I-V graph for Diode shows that first the current is zero but as we increase the potential difference(voltage), it results in the increase in the current. Picture 2

[tex]\Large\textbf{Diode:}[/tex]  

A diode is a device that allows current to flow in only one direction.

[tex]\Large\textbf{Forward and Reverse Biasing:}[/tex]  

Forward Bias, When a diode is forward bias (a voltage in the "forward" direction) then the P-side of the diode is attached to the positive terminal and N-side is fixed to the negative side of the battery which is connected, current flows freely through the device. The forward bias decreases the thickness of potential barrier(The potential barrier barrier in which the charge requires additional force for crossing the region)

Reverse Bias, When a diode is Reverse bias(a voltage in the "backward direction) then the P-side of the diode is connected to the negative terminal and N-side is connected to the positive terminal of the battery which is connected. The reverse bias increases the thickness of the potential barrier resulting in the flow of no current.

 [tex]\Large\textbf{Answer to the Question "Resistance"}[/tex]

The Forward bias decreases the resistance of the diode whereas the reversed bias increases the resistance of the diode. As in forward biasing the current is easily flowing through the circuit whereas reverse bias does not allow the current to flow through it.

Answer:

30m³

Explanation:

Calculation for the volume the balloon would have

First step is to calculate the Constant

Constant=30pka*5m³

Constant=150m³

Now let calculate the Volume using this formula

Balloon Volume=Constant/ Pressure

Let plug in the formula

Balloon Volume=150m³/5kpa

Balloon Volume=30m³

Therefore the volume that the balloon would have when the pressure inside the ballon has fallen to 5kpa is 30m³

Answer:

If you going to ask a question ask it accurately.

Explanation:

Answer:

Respiration and excretion

Explanation:

Respiration. When animals breathe, their lungs release water vapour to the atmosphere.

Animals excrete water by respiration and by passing urine.

Answer:

No work is done since no distance is given

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

Answer:

4.22 m

Explanation:

Una rampa es una máquina que se utiliza para levantar un objeto con una fuerza menor a la que realmente necesitarías. Cuanto mayor sea la longitud de la rampa, menor será la magnitud de la fuerza necesaria para levantar el objeto.

Dado que:

altura de la rampa = 1.5 m, carga = 4900 N, fuerza aplicada = 1633.33 N.

La fórmula de la rampa se da como:

fuerza aplicada * longitud de la rampa = peso de la carga * altura de la rampa

1633.33 * longitud de la rampa = 4900 * 1.5

longitud de la rampa = 4900 * 1.5 / 1633.33

longitud de la rampa = 4.22 m

Answer: Diagram 2

In diagram 1, the person in the northern hemisphere gets more sunlight compared to someone in the southern hemisphere. So diagram 1 has summertime in the northern hemisphere.

Conversely, diagram 2 has the southern hemisphere get more sunlight, so the northern hemisphere is experiencing winter.

Answer:

7.5 units

13 units

Explanation:

[tex]|v|=5\ \text{units}[/tex]

[tex]|u|=3\ \text{units}[/tex]

[tex]\theta[/tex] = Angle between the vectors = [tex]60^{\circ}[/tex]

Scalar product is given by

[tex]u\cdot v=|u||v|\cos\theta\\ =3\cdot 5\cdot \cos60^{\circ}\\ =7.5\ \text{units}[/tex]

The scalar product of the vectors is 7.5 units.

Vector product is given by

[tex]u\times v=|u||v|\sin\theta\\ =3\times 5\sin60^{\circ}\\ =13\ \text{units}[/tex]

The vector product of the vectors is 13 units.

Answer:

the work function of the metal is 4.167 x 10⁻¹⁹ J .

Explanation:

Given;

wavelength of the incident light, λ = 450 nm = 450 x 10⁻⁹ m

kinetic energy, K.E = 2.5 x 10⁻²⁰ J

The energy of the incident light is calculated as;

[tex]E = hf = \frac{h c}{\lambda} \\\\where;\\\\c \ is \ speed \ of \ light = 3 \times 10^8 \ m/s\\\\ h \ is \ Planck's constant = 6.626 \times 10^{-34} Js \\\\E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{450 \times 10^{-9}} \\\\E = 4.417 \times 10^{-19} \ J[/tex]

Apply Einstein photoelectric equation to determine the work function of the metal;

E = W + K.E

where;

W is the work function of the metal

W = E - K.E

W = 4.417 x 10⁻¹⁹ J - 2.5 x 10⁻²⁰ J

W = 44.17 x 10⁻²⁰ J -  2.5 x 10⁻²⁰ J

W = 41.67 x 10⁻²⁰ J

W = 4.167 x 10⁻¹⁹ J

Therefore, the work function of the metal is 4.167 x 10⁻¹⁹ J .

The work function of the photon is 4.167*10^19J

The energy of this photon can be calculated as

E = hc/λ

Data given;

substituting the values into the equation;

[tex]E = hc / y\\E = \frac{6.626*10^-^3^4*3.0*10^8}{450*10^-^9} \\E = 4.42*10^-^1^9J[/tex]

The work function of the photon can be calculated as;

E = K.E + Ф

4.42*10^-19 = 2.5*10^-20 + Ф

Ф = [tex]4.42*10^-^1^9 - 2.5*10^-^2^0=4.167*10^-^1^9J[/tex]

The work function of the photon is 4.167*10^-19 J

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Answer:

9508.1kg

Explanation:

Given parameters:

Gravitational force  = 6.7 x 10⁻⁴N

Distance of separation  = 3m

Unknown:

Mass of one of the truck  = ?

Solution:

Let the mass of one of the truck be  = m

According to the Newton's law of universal gravitation:

   Fg  = [tex]\frac{G m1 m2}{d^{2} }[/tex]  

 G is the universal gravitation constant  = 6.67 x 10⁻¹¹

  m1 and m2 are the masses of the two bodies, here m1  = m2  = m

  d is the distance of separation between them

 6.7 x 10⁻⁴   = [tex]\frac{6.67 x 10^{-11} x m^{2} }{3^{2} }[/tex]  

          6.67 x 10⁻¹¹m²   = 9 x   6.7 x 10⁻⁴  

                          m   = 9508.1kg

The mass of one of the trucks is 9510 kg.

The problem above can be solved using the mathematical expression of newton's law of universal gravitation

Using Newton's law of universal gravitation,

F = Gm²/r²................... Equation 1

Where F = Gravitational force on the truck, m = mass of each truck, r = distance between the trucks, G = universal constant

make m the subject of the equation

m = √(Fr²/G)................ Equation 2

From the question,

Given: F = 6.7×10⁻⁴ N, r = 3.0 m.

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 2

m = √[(6.7×10⁻⁴×3²)/(6.67×10⁻¹¹)]

m = √(9.04×10⁷)

m = 9.51×10³ kg.

m = 9510 kg

Hence, The mass of one of the trucks is 9510 kg

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Complete question:

A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity​ after 10s ?

Answer:

the final velocity of the train is 4 m/s.

Explanation:

Given;

initial velocity of the train, u = 44 m/s

acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)

time of motion, t = 10 s

let the final velocity of the train = v

The final velocity of the train is calculated using the following kinematic equation;

v = u + at

v = 44 + (-4 x 10)

v = 44 - 40

v = 4 m/s

Therefore, the final velocity of the train is 4 m/s.

Answer:

Average speed will be 50km/hr

Explanation:

Distance/Time

100/2

50kmph

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Answer:

50km/hr

Explanation:

avgspeed=Δdistance/Δtime

Δd=100km

Δt=2hr

=100km/2hr

=50km/hr

Answer:..........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................Volosity???????

Explanation: THINK THATS IT PROBABLY MISPELLED IT SORRY IN ADVANCE IF WRONG

Answer:

Density is equal to mass divided by volume.

Explanation:

Density = mass / volume

or

p=m/v

Answer:

Use the formula D=m/v

Explanation: In order to find the volume for these objects, use a ruler and measure the length, width, and height. Proceed to multiply them all together, L*W*H. To find the mass of an object, I would say to use a triple beam balance. After finding both the mass and volume of you object, use the formula D = m/v and you'll get your answer.

Explanation:

Hope it helps..........

Answer:

Negative feedback caused his pancreas to produce more insulin.

Explanation:

Positive feedback is a feedback that causes an increase due to change, that is it results in more product while negative feedback is a feedback that causes a decrease due to change, that is it result in lesser product.

Blood sugar control in the body is a negative feedback, because as the blood sugar increases, the nerves sense a change which causes the pancreas to secrete insulin until homeostasis and then the secretion stops.

Answer:

[tex]\boxed {\boxed {\sf 1646.4 \ J }}[/tex]

Explanation:

Gravitation potential energy can be found using this formula:

[tex]E_P=m*g*h[/tex]

where m is the mass, g is the gravtiational acceleration, and h is the height.

The mass of the apple is 14 kilograms and it is 12 meters above the ground. Since this is on Earth, the acceleration due to gravity is 9.8 m/s².

[tex]m= 14 \ kg \\g= 9.8 \ m/s^2 \\h= 12 \ m[/tex]

Substitute the values into the formula.

[tex]E_p= ( 14 \ kg )( 9.8 \ m/s^2)(12 \ m)[/tex]

Multiply.

[tex]E_p= (137.2 \ kg*m/s^2)(12 \ m )[/tex]

Multiply again.

[tex]E_P= 1646.4 \ kg*m^2/s^2[/tex]

[tex]E_p=1646.4 \ J[/tex]

This is already rounded to the tenth place, so it's the final answer.

The apple has 1,646.4 Joules of gravitational potential energy.

Answer: macroscopic outputs

Explanation:

When fireworks explode, sound and light are produced. These are examples of macroscopic outputs. Because, explosion from fireworks is an exothermic process which releases massive heat energy to the surroundings.

Exothermic reaction are those which evolve heat energy to the surroundings.  The change in enthalpy of the reaction is negative here. Whereas, in an endothermic reaction energy is absorbed by the reactants.

Exothermic reactions sometimes results in massive explosion. The heat energy released to the surroundings from the fire works is macroscopic level.

The small scale process or quantity that cannot be measured using normal scales are called microscopic units. Therefore, the sound, light, and heat from the explosion all are macroscopic outputs.

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Rolling friction causes a ball to roll more slowly when it rolls on a horizontal surface. Since static friction is to blame for the friction force, it produces no net work and has no effect on energy dissipation. Thus, option A is correct.

On a frictionless horizontal surface, the ball could neither speed up no slow down because the horizontal surface was intermediate between downhill and uphill. Galileo concluded that in the absences of friction, a ball that once started rolling on a horizontal surface would roll forever.

Friction causes a ball rolling on a flat surface to slow down. The ball finally comes to a stop as a result of friction, which operates in opposition to the ball's motion. If not, it will continue to roll indefinitely.

Therefore, The friction force is brought on by static friction; it has no effect on releasing energy or producing net work.

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Answer:

[tex]v_f=0.15\:\mathrm{m/s}[/tex]

Explanation:

From the Law of Conservation of Momentum, we can write the following equation:

[tex]m_1v_1+m_2v_2=m_fv_f[/tex]

Because the toy car was initially at rest, [tex]m_2v_2=0[/tex].

Therefore, we can plug in given values and solve for [tex]v_f[/tex]:

[tex]m_1v_1=m_fv_f,\\0.050\cdot 0.20 = (0.050+0.015)v_f,\\v_f=\fbox{$0.15\:\mathrm{m/s}$}[/tex] (two significant figures).

Answer: 100

Explanation: 20 *5=100

Hope this helps!!Brainlist?plz

Explanation:

= 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

When displacement is y, then acceleration, a=−ω2y

Velocity, V=ωr2−y2

Case (a)    When y=5cm=0.05m

a=−(10π)2×0.05=−5π2m/s2

V=10π×(0.05)2−(0.05)2=0

Case (b)    When y=3cm=0.03m

a=−(10π)2×0.03=−3π2m/s2

V=10π×(0.05)2−(0.03)2=10π×0.04=0.4π m/s

Case (c)    When y=0

a=−(10π)2×0=0

V=10π×(0.05)2−02=

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TOTAL FLIGHT TIME

Rising Projectile

vi = initial velocity = 58.8 m/s

vf = final velocity = 0

g = gravity acceleration = -9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (0 - 58.8)/-9.81

t = -58.0/-9.81

t = 5.99 s ≈ 6.00 s

Falling Projectile

vi = initial velocity = 0

vf = final velocity = 58.8 m/s

g = gravity acceleration = 9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (58.8 - 0)/9.81

t = 58.0/9.81

t = 5.99 s ≈ 6.00 s

t(total) = t(up) + t(down) = 6.00 s + 6.00 s = 12.0 s Total Flight Time

HORIZONTAL DISTANCE TRAVELED

v = velocity, horizontal = 20.0 m/s

d = to be determined

t = elapsed time = 12.0 s

v = d/t

vt = d

d = vt

d = (20.0 m/s)(12.0 s)

d = 240 m Horizontal Distance Traveled

00

Answer:

A. Plane mirror and piece of paper

Explanation:

Diffuse reflection is the reflection of light or other waves or particles from a surface such that a ray incident on the surface is scattered at many angles rather than at just one angle as in the case of specular reflection. An ideal diffuse reflecting surface is said to exhibit Lambertian reflection, meaning that there is equal luminance when viewed from all directions lying in the half-space adjacent to the surface.

Answer:

Air Resistance

Explanation:

Because air gives a much greater resistance to the falling motion of the feather than it does to the brick.

Answer:

6839.17 N

Explanation:

From the question given above, the following information were obtained:

Distance apart (r) = 0.5 m

Charge 1 (q₁) = +3.4×10¯⁴ C

Charge 2 (q₂) = -5.6×10¯⁴ C

Electrical constant (K) = 8.98×10⁹ Nm²/C²

Force (F) =.?

F = Kq₁q₂ / r²

F = 8.98×10⁹ × 3.4×10¯⁴ × 5.6×10¯⁴ / 0.5²

F = 1709.792 / 0.25

F = 6839.17 N

Thus, the force of attraction between the two charged spheres is 6839.17 N

Answer:

moment's equilibrium required

moment = force x perpendicular distance from force's line of action (from pivot)

counter clockwise = clockwise moments

=> 15g(1.5) = F(0.3)

=> F = 15*9.81*5 = 735.75 ~= 736 N

Explanation:

Answer:

1.5m/s²

Explanation:

Given parameters:

Mass of the wheelbarrow = 50kg

Net force applied  = 75N

Unknown:

Acceleration of the barrow = ?

Solution:

From Newton's second law of motion, we know that:

       Force  = mass x acceleration

 Now insert the parameters and find the acceleration

       75  = 50 x acceleration

      Acceleration  = 1.5m/s²

Answer:

0

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

 Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

Answer:

two method of increasing efficiency of machine are 1st is give lubricants to machine to reduce friction or heat loss and

2nd. is by increasing the input of energy