1. A 12 kilogram block is sitting on a platform 24 m high. How much Potential energy does
it contain?

Answers

Answer 1

The amount of potential energy the block contains is 2,822.4 Joules

Given the following data:

Mass of block = 12 kgHeight of platform = 24 meters.

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex].

To determine the amount of potential energy the block contains:

Mathematically, potential energy (P.E) is given by the formula;

[tex]P.E = mgh[/tex]

Where:

m is the mass of object.g is the acceleration due to gravity.h is the height of an object.

Substituting the parameters into the formula, we have;

[tex]P.E = 12 \times 9.8 \times 24[/tex]

Potential energy (P.E) = 2,822.4 Joules

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Related Questions

The right to gather to advance some political or social cause is known as

Answers

Answer:

the first amendment

Explanation:

the first amendment to the United States constitution allows the freedoms concerning religion, expression, assembly, and the right to gather and petition.

At what tension, in newtons, must the D-string must be stretched in order for it to be properly tuned

Answers

The fundamental frequency, wavelength of the wave, and mass per unit

length of the string, determines the tension in the string.

The tension to which the D-string must be tuned is approximately 19.718 Newtons

Reasons:

From a similar question, we have;

Fundamental frequency, f₁ = 146.8 Hz

Oscillating length on the D-string, λ₁ = 0.61 m

Mass of the string = 1.5 × 10⁻³ kg.

We have;

[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]

Therefore;

[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]

Which gives;

[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]

The tension to which the D-string must be tuned, T ≈ 19.718 Newtons

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The parameters given in a similar question obtained online are;

The fundamental frequency of the tone, f₁ = 146.8 Hz

The oscillating length on the D-string, λ₁ = 0.61 m

The mass of the string = 1.5 × 10⁻³ kg.

which term is most applicable to a discussion of angular momentum in the context of black holes?


A: Photon

B: Curvature

C: Spin

D: Time

Answers

Answer:

c:   spin

Explanation:

it's not curvature

The most applicable term to a discussion of angular momentum in the context of black holes is Spin. Thus, the correct option is C.

What is angular momentum of black holes?

Angular Momentum is defined as the property of any rotating object which is given by the product of the moment of inertia of an object and the angular velocity of the rotating object. Angular momentum is a vector quantity and it has both the magnitude and direction. The examples of angular momentum are the rotation and revolution of the Earth.

When the astronomers claim that they have estimated the spin of a black hole, this means they have measured its angular momentum. This is the total angular momentum of all the materials on the Universe that ever crossed the event horizon and got trapped inside it.

Therefore, the correct option is C.

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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!


Imagine that a car is speeding down the highway and it hits a large bump in the road that forces it off the road. What would Newton call that object?
A.
a physical object
B.
a course interrupter
C.
an unbalanced force
D.
an unfortunate event


PLEASE NO LINKS OR I WILL REPORT YOU

Answers

Answer:

C. unbalanced force

Explanation:

it is called unbalanced force because it has changed direction of the moving object

I need help quickly pls

Answers

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

5. How are electromagnetic waves similar to ocean waves?.

Answers

Answer:

Electromagnetic waves have crests and troughs similar to those of ocean waves. The distance between crests is the wavelength. The shortest wavelengths are just fractions of the size of an atom, while the longest wavelengths scientists currently study can be larger than the diameter of our planet!

Explanation:

hope it's helps u ...........!

Which is the force that results from use of a machine?
O a. input force
Oc. input work
Ob. output force
Od. output work

Answers

Answer:

D. Output force

Explanation:

The input force is the effort used to run the machine and this results in an output force.

The c-c sigma bond in acetylene is formed by the overlap of which two orbitals.

Answers

Answer:When carbon atom tends to form single bonds then its hybridization is , when carbon atom tends to form double bond then its hybridization is  and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.

For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.

So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.

Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:

Explanation:

If you eat cheese are you 1 percent cheese?

Answers

Answer:

No. Exactly what you eat doesn’t make up your internal structure.

:)

Answer:

Explanation:

Light cheeses are less than 20 %, low fat cheeses are 20 to 30%, fat cheeses are 50 to 60%, double-cream cheeses are at least 60% and triple-cream cheeses are at least 75 %.

How long would it take a 500 w electric motor to do 150,000 j of work

Answers

Explanation:

300 second = 5 minutes

details

500 watts = 500 joules per second

Time = (1.50 x 10^5 joules)/(5 x 10^2 joules per second) = .3 x 10^3 seconds =300 second

We know the power is equal to the work done over time (that is, P=W/t)

Plugging in the given values, 500=150000/t
=> t=300 s

Help help fast please first answer gets brainiest also needs to be clearly stated

Answers

They do because they use it like a system to group living things the groupings are based on common traits this helps scientists study organisms and classify a new species when found

5. An acrobat, starting from rest, swings freely on a trapeze of
length 3.7 m (Figure 6). If the initial angle of the trapeze is
48°, use the law of conservation of energy to determine
(a) the acrobat's speed at the bottom of the swing
(b) the maximum height, relative to the initial position, to
which the acrobat can rise

Answers

The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.

               Em = K + U

Let's write the energy in two points.

Starting point. Highest part of the oscillation

            Em₀ = U = m g h

Final point. Lower part of the movement

            [tex]Em_f[/tex] = K = ½ m v²

Energy is conserved.

            Emo = [tex]Em_f[/tex]  

            m g h = ½ m v²

            v² = 2 gh

Let's use trigonometry to find the height, see attached.

         h = L - L cos θ

         h = L (1- cos θ)

They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.

         h = 3.7 (1- cos 48)

          h = 1.22 m

this  is the maximum height of the movement.

Let's calculate the velocity.  

          [tex]v= \sqrt{2 \ 9.8 \ 1.22}[/tex]  

          v = 4.89 m / s

In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

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How much would a 70 kg student weigh on Pluto? (massPluto = 1.25 x 1022 kg, radiusPluto = 1.20 x 106 m)

Answers

Answer: the weight would be 4.6 (I think i don’t know))

Explanation:

What acceleration occurs if the friction force in #4 is now 4N?

Answers

The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.

What is force?

We define the force that acts on a body as that which is able to cause an acceleration or that which is able  to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.

Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.

Now;

F = ma

a = F/m

a = 20 N/3Kg

a = 6.67 m/s^2

If the force is 4N;

a = F/m

a = 4N/3Kg

a = 1.33 m/s^2

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Missing parts;

How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?

a ball is thrown vertically up ward with a velocity of 25m/s. a/how fast was it moving after 2sec?​

Answers

Answer:

12.5

Explanation:

given

distance=25

time=2sec

required

=speed

solution

=v=s/t

25/2

=12.5m/s

How much force is required to move a tractor 60m, when using 250J of work?

Answers

Answer:

Work done,W= 250J

Displacement , s = 60

We know that, Work done = Force x displacement

i.e , W = Fxs

250 J = F x 60m

F = 250/60

=4.16 N

Hence , 4.16 N of Force is applied on the body.

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

The magnitude of vector A is 2.5 m and is directed towards east. The magnitude and direction of A /2 will be​

Answers

The magnitude and direction of half of the given vector A is 1.25 m east.

The given parameters;

magnitude of vector A = 2.5 m east

A vector can be described with both magnitude and direction. The magnitude of the vector is the scalar or numeric representation of the vector.

When the scalar representation has direction, we term the quantity a vector quantity.

The magnitude of half of the given vector is calculated as follows;

[tex]\frac{A}{2} = \frac{2.5 \ m}{2} = 1.25 \ m\ east[/tex]

Thus, the magnitude and direction of half of the given vector A is 1.25 m east.

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A cyclist accelerates from 0m/s to 8m/s in 3 seconds.

Answers

Answer:

the rate of acceleration is 2.6666(and so on) if thats your question

Explanation:

Jade has a refractive index of 1.61. If light approaches the gem at an angle of 80.0°, what is the angle of refraction?

Calculate the index of refraction of a material if the angle of incidence is 60° and the angle of refraction is 50°

Answer using calculations & full work and thoughts shown.

Answers

From Snell's law,  the angle of refraction is 38 degree approximately and the index of refraction is 1.13

The given refractive index is 1.61

If light approaches the gem at an angle of 80.0°, that means the angle of incidence is 80.0°

To calculate the angle of refraction, we will use Snell's law which state that:

n = sin i / sin r

where n = refractive index

Substitute all the parameters into the formula

1.61 = sin 80 / sin r

make sin r the subject of formula

sin r = sin 80 / 1.61

sin r = 0.611

r = [tex]Sin^{-1}[/tex](0.611)

r = 37.7

r = 38 degree (Approximately)

We will use the same formula to calculate the index of refraction of a material if the angle of incidence is 60° and the angle of refraction is 50°. That is,

n = sin i / sin R

Where n = index of refraction

i = Incidence

R = refraction

Substitute all the parameters to the formula

n = sin 60 / sin 50

n = 0.866 / 0.766

n = 1.13

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The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32. 50 N/m, is 0. 640 J. Find by how much is the spring is compressed.

Answers

The spring in the dart gun is compressed by 0.16 m

From the question given above, the following data were obtained:

Spring constant (K) = 50 N/m

Potential Energy (PE) = 0.640 J

Compression (e) =?

The compression experience by the spring can be obtained as follow:

PE = ½ke²

0.64 = ½ × 50 × e²

0.64 = 25 × e²

Divide both side by 25

e² = 0.64 / 25

Take the square root of both side

e = √(0.64 / 25)

e = 0.16 m

Therefore, the spring is compressed by 0.16 m

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if you were planning to escape from someone and you were tied to a chair what would you do

Answers

I would rub the rope against the chair or a hard surface to create friction, causing the rope to sever due to the heat and thus allowing me to escape or remove bonds
I will ask him to untie the rope and escape .

How far can a mother push a 20.0 kg baby carriage, using a force of 62 N, if she can only do 2920 J of work?

Answers

Please find attached photograph for your answer.

Hope it helps.

One thing I have to mention is that here we do not need to calculate the mass because the amount of force is already given.

Please do comment if you have any query.

Suppose you were able to take measurements of current through the
resistor and voltage across the resistor. Your record of numerical values is written in a

tabular data below​

Answers

Answer:

  see attached

Explanation:

It will be easier to plot the data if you have grid lines to work with.

In the attached, we had to reverse the order of entries in the table, because the graphing program likes the independent variable listed first.

What is a net force on an object that has a mass of 20.0 kg, an applied force of 100 n moving on a surface with a friction coefficient of 0.21?

Answers

The net force on the object as described is; 58.84N

Two forces acting on the object are;

The applied force and the frictional force.

In essence; the frictional force can be evaluated as;

Frictional force; = coefficient × Weight of object.

Frictional force = 0.21 × 20 × 9.8.

Frictional force = 41.16N

The Net force = Applied force - frictional force

Net force = 100 - 41.16N

Net Force = 58.84 N.

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Leverrier predicted that an invisible planet was pulling the planet Uranus off its predicted course around the sun. Likewise, human beings are pulled off course by the invisible forces of their ____________.

Answers

Human beings are pulled off course as a result of the invisible forces of the unconscious.

According to Leverrier, he stated that an invisible planet was pulling the planet Uranus off its predicted course around the sun.

In such a way, human beings are pulled off course by the invisible forces of their unconscious minds. The unconscious minds of people control the thoughts of people.

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What is the disappearance of a wave into a medium.
A. Signal
B. Amplitude
C. Absorption
D. Transmission

Answers

Answer:

Absorption

Explanation:

the disappearance of an EM wave into the medium. scattering – the spreading out of light rays in all directions because particles reflect and absorb the light.

What is a thought experiment?​

Answers

Answer:

A thought experiment is an experiment carried out only in the imagination

Explanation:

PLS HELP ASAP it's just 2 questions and they are multiple choice!

Answers

It’s the first option heat factories (A)

I couldn't answer this question may someone please help me

Answers

Distance (s) =20 m

Initial velocity =0 m/s

g=10 m/s²

By using the formula:

v²= u²+ 2as

v²=0²+ 2×10×15

v²= 300

V= 10root over 3

[tex]10 \sqrt{3} [/tex]

For calculating time,

v= u+ at

10 root over 3 = 0+ 10t

10 root over= 10t

t = 1 root over 3

t = 1.73 s

[tex]1 \sqrt{3} [/tex]

The the stone will hit the ground with a velocity of 10 root over 3 m/s in 1 root over 3 sec.

A child, m = 25. 0 kg, swings from a rope, l = 9. 43 m, which hangs above water, d = 1. 9 m, when vertical. The child is h = 4. 8 m above the water when she begins to swing.

Answers

The velocity at the bottom of the swing is [tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]. The time it took the child to reach the river is 0.62 seconds.

The objective of this question is to determine:

The expression for the velocity of the child at the bottom of the swing.Suppose the child lets go at the bottom of the swing, how long does she take to reach the river at t seconds.

At the bottom of the swing, there is an equal change in both the Kinetic energy as well as the potential energy and the expression can be computed as:

[tex]\mathbf{\dfrac{1}{2}mv^2 = mg (h -d)}[/tex]

[tex]\mathbf{\dfrac{v^2}{2}= g (h -d)}[/tex]

[tex]\mathbf{v^2= 2gh -2gd}[/tex]

[tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]

According to the second equation of motion;

[tex]\mathbf{S = ut +\dfrac{1}{2}at^2}[/tex]

where;

distance s = d = 1.9 macceleration due to gravity = 9.8 m/s²initial velocity (u) = 0

[tex]\mathbf{1.9 = 0(t) +\dfrac{1}{2}(9.8) t^2}[/tex]

[tex]\mathbf{1.9 = \dfrac{1}{2}(9.8) t^2}[/tex]

[tex]\mathbf{t^2 =\dfrac{1.9\times 2}{9.8} }}[/tex]

[tex]\mathbf{t = \sqrt{\dfrac{1.9\times2}{9.8}}}[/tex]

[tex]\mathbf{t =0.62 \ s}[/tex]

Therefore, we can conclude that the velocity at the bottom of the swing is [tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]. The time it took the child to reach the river is 0.62 seconds.

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