Bon Air Elementary School has 300 students. The principal of the school thinks that the average IQ of students at Bon Air is at least 110. To prove her point, she administers an IQ test to 20 randomly selected students.

Among the sampled students, the average IQ is 108 with a standard deviation of 10. Based on these results, should the principal accept or reject her original hypothesis? Assume a significance level of 0.01.

Answer:

I give bases example the triangle pyramid

Answer:

276 in^2

Step-by-step explanation:

2((6*6)/2) + 2(6*12) + (8*12) = 276 in^2

Answer:

10

Step-by-step explanation:

Answer:

what do you mean?

Step-by-step explanation:

Yes, based on the information, it should be noted that social recommendations can increase ad effectiveness.

The study you mentioned found that viewers who arrived at an advertising video through social media recommendations were more likely to correctly recall the brand being advertised than viewers who arrived by browsing. This is because social recommendations come from people we trust, and we are more likely to be influenced by their opinions.

First, social recommendations are more personalized. They are based on the interests of the person who is making the recommendation, so they are more likely to be relevant to the person who is receiving the recommendation. Second, social recommendations are more credible. We trust the opinions of our friends and family, so we are more likely to believe their recommendations. Third, social recommendations are more timely. They are shared in real time, so they are more likely to be relevant to the current moment.

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Answer:

the error is ( 4-17) is equal -13 not 13

so if she used - 13 the right answer is 17/34

Step-by-step explanation:

see attached

hope it helps

Answer:

Your question is Incomplete....

Answer:

It is based on history

Step-by-step explanation:

Answer: the answer is based on history

Step-by-step explanation:

Answer:

negative

positive

negative

zero

positive

Step-by-step explanation:

Situation 1: A football team's first play resulted in a loss of 15 yards.

negative

Situation 2: A store marks up the price of a calculator $5.20.

positive

Situation 3: Nina withdrew $50 from her bank account.

negative

Situation 4: A porpoise is swimming at sea level.

zero

Situation 5: Kylie scored 2 goals in yesterday's soccer game.​

positive

relation R on set A = {23, 51, 36, 75, 35, 11, 102, 9, 10, 29}, aRb means a ≡ b (mod 3), which indicates that a and b have the same remainder when divided by 3.

In the given relation R on set A = {23, 51, 36, 75, 35, 11, 102, 9, 10, 29}, aRb means a ≡ b (mod 3), which indicates that a and b have the same remainder when divided by 3.

To represent this relation R in digraph notation, we can draw a directed graph where each element of set A is represented as a node, and there is a directed edge from node a to node b if aRb holds true.

Let's go through each element of set A and determine the directed edges based on the given relation R:

1. For 23, its remainder when divided by 3 is 2. Therefore, there will be an edge from 23 to itself.

2. For 51, its remainder when divided by 3 is 0. There will be an edge from 51 to itself.

3. For 36, its remainder when divided by 3 is 0. There will be an edge from 36 to itself.

4. For 75, its remainder when divided by 3 is 0. There will be an edge from 75 to itself.

5. For 35, its remainder when divided by 3 is 2. There will be an edge from 35 to itself.

6. For 11, its remainder when divided by 3 is 2. There will be an edge from 11 to itself.

7. For 102, its remainder when divided by 3 is 0. There will be an edge from 102 to itself.

8. For 9, its remainder when divided by 3 is 0. There will be an edge from 9 to itself.

9. For 10, its remainder when divided by 3 is 1. There will be an edge from 10 to itself.

10. For 29, its remainder when divided by 3 is 2. There will be an edge from 29 to itself.

In this digraph, each node represents an element from set A, and the directed edges indicate the relation R (a ≡ b mod 3).

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The angular frequency of the sinusoidal function that approximates the temperature profile when t is large is 7π.

The general solution to the heat equation with boundary conditions is u(x,t) = A sin(kx) e^(-kt) + B cos(kx) e^(-kt), where k is the wavenumber and t is time. The wavenumber is related to the angular frequency by k = 2π/a, where a is the length of the rod. In this case, k = 7π/a. Therefore, the angular frequency is 7π.

The amplitude of the sinusoidal function will decay to 0 as t approaches infinity. This is because the exponential term e^(-kt) will decrease as t increases.

The initial condition u(x,0) = 10 + sin 3x + 20 sin 5x + 2 sin 7x can be matched to the general solution by setting A = 10, B = 0, k = 3, and k = 5.

The boundary conditions u(0,t) = u(a,t) = 0 can be satisfied by setting A sin(3a) e^(-kta) + B cos(3a) e^(-kta) = 0 and A sin(5a) e^(-kta) + B cos(5a) e^(-kta) = 0. These equations can be solved to find A = 0 and B = 0.

The solution u(x,t) = 0 is a sinusoidal function of x whose amplitude is decaying to 0. The angular frequency of this function is k = 2π/a = 7π.

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Answer:

B

Step-by-step explanation:

The small triangle is half the size of the entire triangle. 27/2 = 13.5

Answer:

i think 2

Step-by-step explanation:

A) 12 and 33 can be divided by 3 so 12:33 = 4:11

B= 20 and 5 can be divided by 5 so 20mm:5mm = 4mm:1mm

Answer:

A. 4: 11

B. 4: 1

Step-by-step explanation:

What are these? These are ratios, which show proportion. For example, for every two dogs, there is one cat. They can be written as words, fractions, or with colons, such as in these problems.

How to simplify: To simplify, think of the highest common factor. If you can't think of the highest, just think of a factor both numbers have in common and keep going until the numbers don't have any factors in common.

In this case, for A, the common factor was 3. 12/3=4 and 33/3=11. This cannot be simplified further because 11 is prime, which means it has no factors besides 1 and 11.

For B, the common factor was 4, so it is 4:1.

The ratio of the lateral area of the cone to the cylinder will be √(h²+r²)/2h.

The solid formed by two congruent closed curves in parallel planes along with the surface created by line segments connecting the corresponding points of the two curves is known as a cylinder.

A cylinder with a circular base is known as a circular cylinder. Based on the form of its base, a cone is given a name.

It is given that a cone and a cylinder have equal radii,r, and equal altitudes, h. The ratio of the lateral surface area of the cone to the cylinder will be calculated as below:-

The lateral area of the cone = πr√(h²+r²)

The lateral area of the cylinder = 2πrh

The ratio will be calculated as:-

R = πr√(h²+r²)  /   2πrh

R = √(h²+r²) / 2h

Therefore, the ratio of the lateral area of the cone to the cylinder will be √(h²+r²)/2h.

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Answer:

40

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

the lines on the very end are your subtrct the the lowest one from the highest one

A)the required formula is r(x) = -3x² + 24x + 15.B)the worker will be assembling 36 units per hour at 10:00 A.M.C)the worker will assemble 70 units between 10:00 A.M. and 11:00 A.M.

a) Derive a formula for the rate at which the worker will be assembling units after x hours. The worker assembles f(x)= −x³ + 12x² + 15x units in x hours.

To determine the formula for the rate at which the worker will be assembling units after x hours, we can differentiate the given function with respect to time t.

We can write this function as:f(x) = -x³ + 12x² + 15xf'(x) = -3x² + 24x + 15

On differentiating the given function, we get the rate at which the worker will be assembling units after x hours is:r(x) = -3x² + 24x + 15

Therefore, the required formula is r(x) = -3x² + 24x + 15.

b)The worker arrives at 9:00 A.M. and we want to determine the rate at which the worker will be assembling units at 10:00 A.M, which means the worker will be assembling units after 1 hour.

We can use the formula:r(x) = -3x² + 24x + 15

To find the answer:r(1) = -3(1)² + 24(1) + 15r(1) = -3 + 24 + 15r(1) = 36 units per hour

Therefore, the worker will be assembling 36 units per hour at 10:00 A.M.

c)To find the number of units assembled by the worker between 10:00 A.M. and 11:00 A.M., we need to integrate the function r(x) = -3x² + 24x + 15 with limits 1 and 2.

We can use the formula:Integral of r(x)dx = f(x)

Using the formula, we get:f(2) - f(1) = Integral of r(x)dx between 1 and 2f(x) = -x³ + 12x² + 15x

Substituting the limits, we get:

f(2) - f(1) = [-2³ + 12(2²) + 15(2)] - [-1³ + 12(1²) + 15(1)]f(2) - f(1) = [−8 + 48 + 30] - [−1 + 12 + 15]f(2) - f(1) = 70

Therefore, the worker will assemble 70 units between 10:00 A.M. and 11:00 A.M.

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Given that the sample mean is 100, the sample mean is 39, and the sample standard deviation is 13.

To find the 95% confidence interval for the population mean, we use the formula as follows:

Confidence Interval formula: CI = X ± Z* σ/√nWhere CI = Confidence IntervalX = Sample Mean

Z* = Z-Scoreσ = Standard Deviationn = Sample SizeHere, the sample size(n) is 100, the sample mean(X) is 39, and the sample standard deviation (σ) is 13.The formula for finding the Z-Score is:Z = 1 - α/2,

where α is the level of significance. α is the probability of the event not occurring, so we subtract it from one to get the probability of the event occurring.

Here, the level of significance is 0.05 since we need to find the 95% confidence interval.

Z = 1 - α/2 = 1 - 0.05/2 = 0.975Then we find the Z-Score from the Z-Score table, which is 1.96.

Therefore, the 95% confidence interval is:CI = X ± Z* σ/√n= 39 ± 1.96 (13/√100)= 39 ± 2.548Thus, the 95% confidence interval for the population mean is (36.452, 41.548).

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The 95% confidence interval for the population mean is

[tex]\[\large \left( 36.452,41.548 \right)\][/tex].

Sample size = 100

Sample mean = 39

Sample standard deviation = 13

Confidence level = 95%

To find the confidence interval, we use the formula given below:

Confidence interval formula is as follows:

[tex]\[\large \left( \overline{X}-z\frac{\sigma }{\sqrt{n}},\overline{X}+z\frac{\sigma }{\sqrt{n}} \right)\][/tex]

We are given, sample mean is 39

[tex]\(\overline{X}=39\)[/tex],

sample standard deviation is 13

[tex]\(\sigma=13\)[/tex],

sample size is 100

i.e. n=100, and confidence level is 95%

z=1.96 (From Z table)

By substituting all the given values in the formula, we get the confidence interval as,

[tex]\[\large \left( 39-1.96\frac{13}{\sqrt{100}},39+1.96\frac{13}{\sqrt{100}} \right)\][/tex]

Simplifying the above expression, we get,

[tex]\[\large \left( 39-2.548,39+2.548 \right)\][/tex]

Therefore, the 95% confidence interval for the population mean is

[tex]\[\large \left( 36.452,41.548 \right)\][/tex].

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The formula for C(x) is `C(x) = 4.75x + 500,000`.

The total cost of producing 100,000 items is $5,250,000.

The marginal cost of the items to be produced in this plant is $4.75.

Given, Company analysts have determined that a linear function is a reasonable estimation for the total cost C(x) in dollars of producing x items. They estimate the cost of producing 10,000 items as $547,500 and the cost of producing 50,000 items as $737,500.

(a) Find a formula for C(x)

For the given data, let C(x) be the cost of producing x items, we have the two points (10,000, 547,500) and (50,000, 737,500).

We have to find the slope of the line passing through these points.

slope of the line `

m = (y2 - y1) / (x2 - x1)`m = (737,500 - 547,500) / (50,000 - 10,000)m = 190,000 / 40,000m = 4.75

Formula for C(x) can be found by using the slope-intercept form of the equation of a line.

C(x) = mx + b

We know, m = 4.75

Using the point (10,000, 547,500), we get

547,500 = 4.75 (10,000) + b.b = 547,500 - 47,500

b = 500,000

Therefore, the formula for C(x) is `

C(x) = 4.75x + 500,000`

So, the formula for C(x) is `C(x) = 4.75x + 500,000`.

(b) Find the total cost of producing 100,000 items.

Total cost of producing 100,000 items is C(100,000).

C(x) = 4.75x + 500,000

C(100,000) = 4.75 (100,000) + 500,000= 4,750,000 + 500,000= 5,250,000

Therefore, the total cost of producing 100,000 items is $5,250,000.

(c) Find the marginal cost of the items to be produced in this plant.

Marginal cost is the cost incurred for producing one additional item. It can be found by taking the first derivative of the cost function with respect to x.

C(x) = 4.75x + 500,000 `

=>` `dC(x)/dx = 4.75`

The marginal cost of the items to be produced in this plant is $4.75.

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Step-by-step explanation:

If x=10

2(10)²(10-5)

200 × 5

=1000

10x=10(10)

=100

Step-by-step explanation:

Answer:

When light strikes an object, its rays can be either absorbed or reflected. A solid black object absorbs almost all light, while a shiny smooth surface, such as a mirror, reflects almost all light back. When reflected off a flat mirror, light bounces off at an angle equal to the angle it struck the object.

Step-by-step explanation:

28.571429% that is 2

hope this helped

Answer:

50% Is the answer

Answer:

if you learned, PEMDAS then it be easier! soo I'll help.

Step-by-step explanation:

-2 ( 52- 4 ) is 48. 48 + 62= 110

if that's wrong, then I'm sorry!

1

62

48

——

110

To find the 90% confidence interval for the true proportion of adults in the town with health insurance, we can use the formula:

[tex]\[\text{{Confidence Interval}} = \left( \hat{p} - Z \cdot \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}, \hat{p} + Z \cdot \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \right)\][/tex]

where:

- [tex]\(\hat{p}\)[/tex] is the sample proportion (69/88 in this case)

- [tex]\(Z\)[/tex] is the Z-score corresponding to the desired confidence level (90% corresponds to [tex]\(Z = 1.645\)[/tex] for a two-tailed test)

- \(n\) is the sample size (88 in this case)

Substituting the values into the formula, we have:

[tex]\[\text{{Confidence Interval}} = \left( \frac{69}{88} - 1.645 \cdot \sqrt{\frac{\frac{69}{88} \cdot \left(1-\frac{69}{88}\right)}{88}}, \frac{69}{88} + 1.645 \cdot \sqrt{\frac{\frac{69}{88} \cdot \left(1-\frac{69}{88}\right)}{88}} \right)\][/tex]

Evaluating the expression, we find the confidence interval to be approximately (0.742, 0.892).

The confidence interval is approximately (0.742, 0.892).

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Answer:

6 apples

Step-by-step explanation:

3 apples cost $1.00

so for $2.00, 2x3÷1=6

hope it helps. plz mark me as brainliest.

Answer:

6 apples

Step-by-step explanation:

if three apples are 1 dollar then every time you add a dollar you would get three more apples

so it would look somthing like

1$ = 3 apples

2$= 6 apples

3$= 9 apples  

4$= 12 apples

so on

Answer:

Step-by-step explanation:

Complete question

A) Sebastian's account will have about $28.67 less than Yolanda's account. B) Sebastian's account will have about $9.78 less than Yolanda's account. C) Yolanda's account will have about $28.67 less than Sebastian's account. D) Yolanda's account will have about $9.78 less than Sebastian's account.

For Sebastian

Amount = [tex]P (1 + \frac{r}{n})^{nt}[/tex]

Substituting the given values we get

A =

[tex]790 (1 + \frac{6.8}{100*1})^{3*1} \\962.367[/tex]

For Yolanda

Amount  [tex]= P(1+rt)[/tex]

[tex]A = 815 (1 + \frac{7.2}{100}*3)\\A = 991.04[/tex]

Yolanda's account will have about $28.67 less than Sebastian's account

Option C is correct

The expected value of X(t), E{X(t)}, is 0, indicating that on average, the process X(t) fluctuates around the zero mean. The autocovariance function R(t₁, t₂) is given by R(t₁, t₂) = e^(-ω₀|t₁-t₂|), which signifies that the covariance between X(t₁) and X(t₂) decays exponentially with the difference in time values |t₁-t₂|.

To find E{X(t)}, we need to calculate the expected value of the given process X(t) = Acos(ω₀t) + Bsin(ω₀t), where A and B are independent random variables with mean 0.

E{X(t)} = E{Acos(ω₀t) + Bsin(ω₀t)}

Since E{A} = E{B} = 0, the expected value of each term is 0.

E{X(t)} = E{Acos(ω₀t)} + E{Bsin(ω₀t)}

          = 0 + 0

          = 0

Therefore, E{X(t)} = 0.

To find R(t₁, t₂), the autocovariance function of X(t), we need to calculate the covariance between X(t₁) and X(t₂).

R(t₁, t₂) = Cov[X(t₁), X(t₂)]

Since A and B are independent random variables with σ²_A = σ²_B = 1, the covariance term becomes:

R(t₁, t₂) = Cov[Acos(ω₀t₁) + Bsin(ω₀t₁), Acos(ω₀t₂) + Bsin(ω₀t₂)]

Using trigonometric identities, we can simplify this expression:

R(t₁, t₂) = Cov[Acos(ω₀t₁), Acos(ω₀t₂)] + Cov[Bsin(ω₀t₁), Bsin(ω₀t₂)] + Cov[Acos(ω₀t₁), Bsin(ω₀t₂)] + Cov[Bsin(ω₀t₁), Acos(ω₀t₂)]

Since A and B are independent, the covariance terms involving them are 0:

R(t₁, t₂) = Cov[Acos(ω₀t₁), Acos(ω₀t₂)] + Cov[Bsin(ω₀t₁), Bsin(ω₀t₂)]

Using trigonometric identities again, we can simplify further:

R(t₁, t₂) = cos(ω₀t₁)cos(ω₀t₂)Cov[A,A] + sin(ω₀t₁)sin(ω₀t₂)Cov[B,B]

Since Cov[A,A] = Var[A] = σ²_A = 1 and Cov[B,B] = Var[B] = σ²_B = 1, the expression becomes:

R(t₁, t₂) = cos(ω₀t₁)cos(ω₀t₂) + sin(ω₀t₁)sin(ω₀t₂)

          = cos(ω₀(t₁ - t₂))

Therefore, R(t₁, t₂) = e^(-ω₀|t₁-t₂|).

The expected value of X(t), E{X(t)}, is 0, indicating that on average, the process X(t) fluctuates around the zero mean. The autocovariance function R(t₁, t₂) is given by R(t₁, t₂) = e^(-ω₀|t₁-t₂|), which signifies that the covariance between X(t₁) and X(t₂) decays exponentially with the difference in time values |t₁-t₂|.

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To determine which functions are solutions of the given differential equation y'' + y = 3 sin(x), we need to check if plugging each function into the differential equation satisfies the equation. We will examine each option and identify the functions that satisfy the equation.

The differential equation y'' + y = 3 sin(x) represents a second-order linear homogeneous differential equation with a particular non-homogeneous term.
(a) Plugging y = 3 sin(x) into the differential equation gives 0 + 3 sin(x) ≠ 3 sin(x). Therefore, y = 3 sin(x) is not a solution.
(b) Plugging y = (3/2)x sin(x) into the differential equation gives (3/2) sin(x) + (3/2)x sin(x) = (3/2)(1 + x) sin(x), which is not equal to 3 sin(x). Therefore, y = (3/2)x sin(x) is not a solution.
c) Plugging y = 3x sin(x) - 4x cos(x) into the differential equation gives 6 cos(x) - 4 sin(x) + 3x sin(x) - 3x cos(x) = 3 sin(x), which satisfies the equation. Therefore, y = 3x sin(x) - 4x cos(x) is a solution.
(d) Plugging y = 3 cos(x) into  the differential equation gives -3 sin(x) + 3 cos(x) = 3 sin(x), which is not equal to 3 sin(x). Therefore, y = 3 cos(x) is not a solution.
(e) Plugging y = (-3/2)x cos(x) into the differential equation gives (3/2) sin(x) - (3/2)x cos(x) = (-3/2)(x cos(x) - sin(x)), which is not equal to 3 sin(x). Therefore, y = (-3/2)x cos(x) is not a solution.
Based on the analysis, the only function that is a solution to the given differential equation is y = 3x sin(x) - 4x cos(x) (option c).

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