Body Systems Directly Involved (Give at Least 2)
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13. Ouch! You step on a tack and jump away without even thinking. Then you decide to pick up the tack and place it back in a desk drawer.
I need the second one the nervous system and...

Explanation:

Given parameters:

Distance hopped  = 84m

Displacement  = 84m due east

Time  = 7s

Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

    Speed  = [tex]\frac{distance}{time }[/tex]   = [tex]\frac{84}{7}[/tex]  = 12m/s

  Velocity  = [tex]\frac{displacement}{time}[/tex]   = [tex]\frac{84}{7}[/tex]   = 12m/s due east

Answer:

b

Explanation:

i took the quiz

Both the transverse and longitudinal waves move faster at higher temperatures.

A wave in which the motion of the particles is perpendicular to the direction of the wave propagation is referred to as a transverse wave.

Here,

As a result of the shear stress that is produced, transverse waves are frequently observed in elastic materials.

In this situation, the oscillations are caused by the displacement of the solid particles from their relaxed state in directions perpendicular to the wave's propagation.

The wave in which the particles of the medium oscillate parallel to the direction of propagation of the wave is called a longitudinal wave.

Sound waves similarly oscillate parallel to the direction of propagation, forming the compressions and rarefactions. Hence sound waves are called longitudinal waves.

Hence,

Both the transverse and longitudinal waves move faster at higher temperatures.

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Answer:

KITTEEENNSSSSS last one is what i got for critsmas KlikBot Hexagon Special Pack

Explanation:

Answer:

False

Explanation:

Electromagnetic waves are transverse waves. That means that the electric and magnetic fields oscillate in a plane that is perpendicular to the direction of wave propagation.

Answer:

false electromagnetic waves are not classified as longitudinal waves

Answer:

Explanation:

When the mass

m

is being accelerated with an acceleration of

a

,we can say the net force acting in the direction of acceleration is

F

=

m

a

here,it is given that only one force

F

was applied to cause this acceleration, and also given,

m

=

2

K

g

,

a

=

2

m

s

−

2

So,

F

=

2

⋅

2

=

4

N

Answer:

4N

Explanation:

given formula solution

m=2kg F=ma F=2kg×2m/s^2

a=2m/s^2 =4N

can you please show a picture

Answer:

B. 90km/hr

Explanation:

The formula for finding velocity =

Displacement/time

The displacement of the car has been given to be = 1215 km West

Time it took to go from Dallas to Paso = 13.5 hours

Then velocity = 1215/13.5

= 90

Therefore velocity = 90km/hour

Option B is the correct answer to this question.

Thank you!

Answer:

B

Explanation:

Speed is distance divided by time.

Answer:

Chemical energy is converted to thermal energy and electrical energy.

Explanation:

Answer:

Which identifies the energy transformations that take place in Anna’s body as this process takes place?

Mechanical energy is converted to kinetic energy, which is then converted to potential energy.

*******Chemical energy is converted to thermal energy and electrical energy. *******CORRECT*******

Electrical energy is converted to chemical energy and thermal energy.

Mechanical energy is converted to potential energy which is then converted to kinetic energy.

Explanation:

Feb 2021 Edge 100% test

Answer: impulse and momentum

Explanation:

Impulse and momentum-  two quantities can be expressed using the same units. Hence, option (4) is correct.

In physics, the term "impulse" is used to characterize or measure the impact of force operating gradually to alter an object's motion. It is often stated in Newton-seconds or kilograms per second and is denoted by the symbol J.

Because a body with momentum cannot be halted, it must be forced to move in the opposite direction for a predetermined amount of time. The harder it is to stop, the more momentum there is. Consequently, more force must be applied and more time must be spent to stop the body.

Mathematically,

impulse = force· time

= mass × acceleration × time

= mass × ( change in velocity/time) × time

= mass ×  change in  velocity

=  change in momentum.

Hence, both Impulse and momentum have same unit.

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Answer:

Answer:

Vf = final velocity = 1.96 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}^{2}=v_{o}^{2}-2*g*x[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity = 9.98 [m/s]

g = gravity acceleration = 9.81 [m/s²]

x = vertical distance [m]

[tex]v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s][/tex]

Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.

Answer:

A

Explanation:

Answer:

Explanation:

distance (km)

a) As near as I can tell from the graph, the distance travelled was 4km

b) I would answer 40 minutes, but don't be surprised if your instructor says 30 minutes.

c) The average speed is 4 km/40 minutes = 0.1 km/minute

Answer:

Superficial anatomy.

Explanation:

Superficial anatomy can be defined as the physical examination of the external parts of a living organism such as ankle, nose, skin, knee, toes, fingers, cornea etc.

Hence, superficial anatomy is also popularly referred to as surface anatomy.

In this scenario, a patient arrives at an emergency room complaining of pain in her ankle. The nurse examines the patient’s ankle, looking for skin discoloration or swelling. The nurse is relying mostly on his knowledge of superficial anatomy by studying or examining the patient's ankle for any sign of decoration or swelling on the skin.

Answer:

VR = [tex]\frac{Radius of the wheel}{Radius of the axle}[/tex]

Explanation:

Velocity ratio (VR) of a machine is a term that compares the distance moved by effort put into the machine to the distance moved by the load.

A wheel and axle is a device for lifting of a load through a height. It is made up of two circular parts called wheel and axle. Its velocity ratio (VR) can be determined by:

VR = [tex]\frac{Radius of the wheel}{Radius of the axle}[/tex]

For a practical wheel and axle, the diameter of the wheel is greater than the diameter of the axle.

Answer:

property of low melting point

Explanation:

When too much current flows through the low resistance element of the fuse, the element melts and breaks the circuit

Answer:

From the poem Black woman what does it mean by Savannah stretching to clear horizons, Savannah shuddering beneath the East wind's eager caresses.​

Explanation:

Answer:

Answers below--

Explanation:

1. F/Force

2.H/Contact force

3.A/Non-contact force

4.C/electric force

5.D/gravity

6.I(i)/magnetic force

7.J/kilogram

8.G/newton

9.B/friction

10.E/lubricant

Answer:

[tex]h_m=5 \ m[/tex]

Explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.

The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:

[tex]\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}[/tex]

Where:

vo = initial speed of the object

θ   = initial launch angle

g   = acceleration of gravity ([tex]10\ m/s^2[/tex])

The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:

[tex]\displaystyle h_m=\frac{20^2\cdot \sin^2 30^\circ}{2*10}[/tex]

[tex]\displaystyle h_m=\frac{400\cdot 0.5^2}{20}[/tex]

[tex]\boxed{h_m=5 \ m}[/tex]

Answer:

B

Explanation:

objects are conductors with unbalanced charges

Answer:

D & A

Explanation:

Answer:

[tex]6.18\:\mathrm{m/s}[/tex]

Explanation:

The momentum of an object is given by [tex]p=mv[/tex].

Plugging in values, we have:

[tex]218=35.2v,\\v=\frac{218}{35.2}=\fbox{$6.18\:\mathrm{m/s}$}[/tex].

Answer:

The torque necessary to bring the wheel to rest in 40 seconds is 10.4 N·m

Explanation:

The question is with regards to rotational motion

The rotary motion parameters are;

The mass of the wheel = 50 kg

The radius of the wheel = 0.4 m

The rate of rotation of the wheel = 480 rpm

The time in which the wheel is to be brought to rest = 40 s

The rotational rate of the wheel in rotation per second is given as follows;

480 r.p.m = 480 r.p.m × 1 minute/(60 seconds) = 8 revolution/second

1 revolution = 2·π radians

Therefore, we have the angular velocity, ω, given as follows;

ω = 2·π × 8 revolutions/second ≈ 50.3 rad/s

The angular acceleration, α, is given as follows;

[tex]\alpha = \dfrac{\Delta \omega}{\Delta t} = \dfrac{\omega _2 - \omega_1}{t_2 - t_1}[/tex]

Whereby the wheel is brought to rest from its initially constant rotational motion in 40 seconds, we have;

ω₁ ≈ 50.3 rad/s, ω₂ = 0 rad/s, and t₂ - t₁ = 40 seconds

Plugging in the values for the variables of the equation for the angular acceleration, "α", we get;

[tex]\alpha = \dfrac{0 - 50.3 \ rad/s}{40 \ s} \approx 1.3 \ rad/s^2[/tex]

The torque on the wheel, τ, is given as follows;

τ = m·r²·α

Where;

m = The mass of the object = 50 kg

r = The radius of the wheel = 0.4 m

α = The acceleration of the wheel ≈ 1.3 rad/s²

Therefore;

τ = 50 kg × (0.4 m)² × 1.3 rad/s² ≈ 10.4 N·m

The torque necessary to bring the wheel to rest in 40 seconds = τ ≈ 10.4 N·m.

Answer:

-10.048 N m

Explanation:

Answer:

50 Mph.

Explanation:

According to the National Severe Storms Laboratory, winds can really begin to cause damage when they reach 50 mph. But here’s what happens before and after they reach that threshold, according to the Beaufort Wind Scale (showing estimated wind speeds): - at 19 to 24 mph, smaller trees begin to sway.

The experimental group and treatment group are the same group. It's just two different names for the same thing. If you apply a treatment to a group, then that's where you're performing the experiment.

For instance, if you are testing a fertilizer, then the independent variable would be "use of fertilizer or not using fertilizer". So that means the control group doesn't get any fertilizer. The dependent variable would be the heights of the plants between the two groups, so we can see if the fertilizer has an effect or not. This is the result of the experiment. So in other words, the input is the fertilizer (or no fertilizer), and the output is measuring the heights of the plants. The output is the result we analyze.

Keep in mind that the heights of the plants are likely to be randomly distributed. So this is where statistics comes into play. If the plants grow due to some random chance, and not necessarily the fertilizer, then you can use the control group to determine if that's the case or not. The control group helps you do this comparison.

As the name implies, "dependent" means it relies on something else. The height of the plant relies on if you used fertilizer or not. The independent variable is able to change without relying on any other variable.

Answer:

[tex]F=683.790939[/tex]N

Explanation:

From the Question we are told that

Earth mass [tex]m_1= 5.98 * 10^2^4 kg[/tex]

Students mass [tex]m_2=70kg[/tex]

Distance of student from earth center Radius [tex]r=6.39 * 10^6 m[/tex]

Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by

 [tex]F=\frac{Gm_1m_2}{r^2}[/tex]

 [tex]F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}[/tex]

Therefore the force of attraction b/w the student and the earth is

 [tex]F=683.790939N[/tex]

 [tex]F\approx 684N[/tex]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2 × 9.8

We have the final answer as

Hope this helps you

Answer:

[tex]V_{B/A}=2i+2k[/tex]

Explanation:

The relative velocity can be calculated by means of the difference between vector B minus vector A.

[tex]V_{A}=i+2j-3k\\V_{B}=3i+2j-k\\V_{B}-V_{A}=(3-1)i + (2-2)j+(-1-(-3))k\\V_{B/A}=2i+2k[/tex]

Answer: 74.7 N

Explanation:

Both approaches yield the same result: the magnitude of the applied force is approximately 74.7 N, and its direction is forward.

To solve this problem, we'll use two different approaches: Newton's second law and the work-energy principle.

Approach 1: Newton's Second Law

Newton's second law states that the force applied to an object is equal to the change in momentum of the object over time.

Step 1: Calculate the initial momentum (pinitial) of the curling rock.

pinitial = m * vinitial

pinitial = 18 kg * 0 m/s (since it's initially stationary)

pinitial = 0 kg m/s

Step 2: Calculate the final momentum (pfinal) of the curling rock.

pfinal = m * vfinal

pfinal = 18 kg * 8.3 m/s

pfinal = 149.4 kg m/s

Step 3: Calculate the change in momentum (Δp).

Δp = pfinal - pinitial

Δp = 149.4 kg m/s - 0 kg m/s

Δp = 149.4 kg m/s

Step 4: Calculate the magnitude of the applied force (Fapplied).

Fapplied = Δp / Δt

Fapplied = 149.4 kg m/s / 2.0 s

Fapplied = 74.7 N

Step 5: Determine the direction of the applied force.

The direction of the applied force is forward since the curling rock is released with a velocity of 8.3 m/s forward.

So, according to Newton's second law, the magnitude of the applied force is 74.7 N, and its direction is forward.

Approach 2: Work-Energy Principle

The work-energy principle states that the work done on an object is equal to the change in its kinetic energy.

Step 1: Calculate the initial kinetic energy (KEinitial) of the curling rock.

KEinitial = 0.5 * m * [tex]vinitial^2[/tex]

KEinitial = 0.5 * 18 kg * (0 [tex]m/s)^2[/tex]

KEinitial = 0 J

Step 2: Calculate the final kinetic energy (KEfinal) of the curling rock.

KEfinal = 0.5 * m * [tex]vfinal^2[/tex]

KEfinal = 0.5 * 18 kg * (8.3 [tex]m/s)^2[/tex]

KEfinal = 0.5 * 18 kg * 69.0 [tex]m^2/s^2[/tex]

KEfinal = 621.0 J

Step 3: Calculate the work done on the curling rock (W).

W = KEfinal - KEinitial

W = 621.0 J - 0 J

W = 621.0 J

Step 4: Calculate the magnitude of the applied force (Fapplied) using the work done.

Fapplied = W / d

Fapplied = 621.0 J / 2.0 s

Fapplied = 310.5 N

Step 5: Determine the direction of the applied force.

The direction of the applied force is forward since the curling rock is released with a velocity of 8.3 m/s forward.

So, according to the work-energy principle, the magnitude of the applied force is 310.5 N, and its direction is forward.

Both approaches yield the same result: the magnitude of the applied force is approximately 74.7 N, and its direction is forward.

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