Below is the work a student completed with an error. Identify the step where the error first occured an
Step 1: (7 - 10) – 2(6y - 5) + 17
Step 2: (3) - 12y – 5 + 17
Step 3:3 - 12y + 12
Step 4: - 12y + 15
А
Step 2
B
Step 3
C
Step 4
D
Answer should be 12y - 9
E
Answer should be 12y + 9
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Answer:

3

Step-by-step explanation:

4 layers 15 cubes

the total amount of cubes =5*3*4

Step-by-step explanation:

got the answer see in the image :)

Answer:

  ∠CBA =90°; ∠CAD =65°; ∠ACD =25°; ∠CBD = 65°

  ∠BWA = 130°; ∠AWD = 50°

Step-by-step explanation:

The diagonals of a rectangle divide the figure into two pairs of congruent isosceles triangles. The figure is symmetrical about both the vertical and horizontal centerlines. Each corner angle of the rectangle is 90°. Of course, the sum of angles in any of the triangles is 180°.

__

The above descriptions tell you ...

  ∠ABD =∠ACD =∠BAC =∠BDC = 25°

  ∠CBA =∠BCD =∠CDA =∠DAB = 90°

  ∠CAD =∠CBD =∠ACB =∠ADB = 90° -25° = 65°

  ∠BWA =∠CWD = 180° -25° -25° = 130°

  ∠AWD = ∠BWC = 180° -65° -65° = 50°

Answer:

h=52 and h is the shortest

Step-by-step explanation:

180-f-g=h    step 1. -f from 180

180-60=120   step 2. -g from 120

120-68= 52

h=52 degrees

Answer:

x = -14

Step-by-step explanation:

Divide each side by -3.

Subtract 9 from each side.

Answer:

x = -14

Step-by-step explanation:

-3(x + 9) = 15

Answer:

1/2

Step-by-step explanation:

number of required outcome ÷number of possible outcomes

1/2

Answer:

The population was 600 in 1968

Step-by-step explanation:

The population of an island decreased by 40% over 50 years, so the population in 1968 will be equal to 600.

The Latin term "per centum," which signifies "by the hundredth," was the source of the English word "percentage." Segments with a denominator of 100 are considered percentages. In other terms, it is a relationship where the worth of the entire is always considered to be 100.

As per the data provided by the question,

The current population in 2018 = is 360

which is 40% less than the population in 1968.

So, 60% of the total population will be equal to 360.
Let the total population is x.

60% × x = 360

x = (360 × 100)/60

x = 600

Therefore, the population at that time was 600.

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No he is wrong

If he is referring to table only then correct else wrong

Always 2^x can't have less intercept.

After some while it will cross 5(x)².

You can observe it from graphs

Answer:

S = (-6, -1)

T = (-7, 4)

U = (-6, 9)

V = (-4, 4)

Answer:

put the line on y= -2

Step-by-step explanation:

The figure ABC is reflected along the line y = -2 and the new coordinated will be A(-2, -4), B (3, 0), and C (-2, -7).

Reflection is a type of transformation that flips a shape along a line of reflection, also known as a mirror line, such that each point is at the same distance from the mirror line as its mirrored point.

Given:

The coordinates of the figure of ABC is given as A(-2, 0), C(-2, 3), and B(3, -4),

The new coordinates of A'B'C' are A(-2, -4), B(3, 0), and C(-2, -7),

If the given figure is reflected as y = -x,

Then, the coordination will change like (-y, -x),

Thus, the new coordinates of ABC will be A(-2, -4), B (3, 0), and C (-2, -7).

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Answer:

mode

is the most common frequent value

There are 10 number of 1 cubic inches box required to fill the container completely.

It is defined as the six-faced shape, a type of hexahedron in geometry.

It is a three-dimensional shape.

We have:

A prism with a length of 4 inches, height of 4 inches, and width of 3 inches.

The volume of the prism box = 4×4×3 = 48 cubic inches

Here some data are missing.

We are assuming there are 38 1 cubic inches box already in the big box.

So,

= 48 - 38

= 10

Thus, there are 10 number of 1 cubic inches box required to fill the container completely.

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The value of p is equal to 76 when q is equal to 4

Given :

If p is inversely proportional to the square of q

when y is inversely proportional to x then [tex]y=\frac{k}{x}[/tex]

given that p is inversely proportional to the square of q. the equation becomes

[tex]p=\frac{k}{q^2}[/tex]

when p is 19 the value of a is 8

Replace the values and find out q

[tex]p=\frac{k}{q^2}[/tex]

[tex]22=\frac{k}{8^2}[/tex]

[tex]22=\frac{k}{64}[/tex]

Multiply both sides by 64

k=1216

Now we find out p when q is 4

Replace k value and q value to find out p

[tex]p=\frac{k}{q^2}[/tex]

[tex]p=76[/tex]

The value of p is equal to 76 when q is equal to 4

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Answer:

P = 88.

Step-by-step explanation:

P = k/q^2

22 = k/ 8^2

k = 22 * 64 = 1408.

So P = 1408/q^2

When q = 4:

P = 1408/4^2

q = 88

Answer: = 3 acres per day

Showing Work

This is a fraction equal to

3 acres ÷ 1 days

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 1

3 acres ÷ 1

__________

1 days ÷ 1

=

3 acres

_____

1 day

=

3 acres

______

day

= 3 acres per day

Answer:

see explanation

Step-by-step explanation:

the equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

x² + y² = 9 ← is in this form

with centre (0, 0 ) and r = [tex]\sqrt{9}[/tex] = 3

this then is the equation of a circle whose centre is (0, 0 ) with radius 3

Answer:

Step-by-step explanation:

Discussion

Using it's formula, it is found that the accuracy of the test was of 0.85 = 85%.

The accuracy of a test is given by the number of correct results divided by the number of results.

In this problem, there are 80 tests, and of those, 5 + 7 = 12 had incorrect results, hence 68 had correct results.

Hence the accuracy of the test is given by:

a = 68/80 = 0.85 = 85%.

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Answer:

  23.6 ft

Step-by-step explanation:

In the right triangle, an acute angle, the hypotenuse, and an adjacent side are marked. We went to know the length of the adjacent side. The trig relation involved is ...

  Cos = Adjacent/Hypotenuse

__

Filling in the given information, this relation tells us ...

  cos(29°) = x/(27 ft)

Solving for x, we get ...

  x = (27 ft)cos(29°) ≈ 23.614 ft

The value of x is about 23.6 ft.

The probability that both I and my best friend get the 100 classroom credits is 0.06%.

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Since Mr Q's class is having a give-away where his students can receive 100 classroom credits, he will pull names out of a hat and select two winners, and once a student wins, they are not eligible to win a second time, if there are 40 total people in the class, including me and my best friend, to determine what is the probability that both I and my best friend get the 100 classroom credits, the following calculation must be performed:

I = 1/40 = 0.025

my best friend = 1/39 = 0.02564

0.02564 x 0.025 = X

0.0006410 = X

X x 100 = 0.064

Therefore, the probability that both I and my best friends get the 100 classroom credits is 0.06%.

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Using the together rate, it is found that the value that must be discarded is given by x = -9.

It is the sum of each separate rate.

In this problem, the rates are given as follows:

Hence:

[tex]\frac{1}{x} + \frac{1}{x + 18} = \frac{1}{40}[/tex]

[tex]\frac{x + 18 + x}{x(x + 18)} = \frac{1}{40}[/tex]

[tex]x^2 + 18x = 80x + 720[/tex]

[tex]x^2 - 72x - 720 = 0[/tex]

Then, we have a quadratic function, with coefficients a = 1, b = -72, c = -720, so:

[tex]\Delta = (-72)^2 - 4(1)(-720) = 8064[/tex]

[tex]x_1 = \frac{72 + \sqrt{8064}}{2} = 80.9[/tex]

[tex]x_2 = \frac{72 - \sqrt{8064}}{2} = -9[/tex]

They cannot have a negative rate, hence the value that must be discarded is given by x = -9.

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Answer:

X = -10

Step-by-step explanation:

PLATO

Answer:

9.5 feet

Step-by-step explanation:

Area of square garden = side length²

⇒ 90 = l²

⇒ l = √90

⇒ l = 3√10

⇒ l = 9.5 feet (nearest tenth)

The length of one side lies between the whole numbers 9 and 10.

Answer:

9 and 10

side length = 9.5 ft (nearest tenth)

Step-by-step explanation:

Area of a square = s²  (where s is the side length)

Therefore, if the square garden measures 90 ft², the length of one side will be √90.

To find the two whole numbers that √90 lies between, find the perfect square either side of 90.

Perfect squares: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, ...

Therefore, 90 lies between 81 and 100:  

⇒ 81 < 90 < 100

Square root the numbers:

⇒ √81 < √90 < √100

⇒ 9 < √90 < 10

Therefore, the length of one side of Grandma's garden is between 9 and 10.

To estimate √90 to the nearest tenth, find the difference between the three numbers:

[tex]81 \overset{+9}{\longrightarrow} 90 \overset{+10}{\longrightarrow} 100[/tex]

As 90 is almost in the middle of 81 and 100,

⇒ √90 = 9.5 (nearest tenth)

According to the calculator, √90 = 9.486832981... = 9.5 (nearest tenth)
which verifies the estimation.

Answer:

The Third Angle theorem is not enough to prove that two triangles are congruent.

Step-by-step explanation:

It establishes that if two angles of one triangle are congruent with two angles of another triangle, then the third angles are also congruent. This indicates that the two triangles are similar but not identical.

Answer:

Fourth one

Step-by-step explanation:

You can find the x coordinate of the vertex (which is the axis of symmetry)

  by calculating    x =    - b/ 2a  

 ( when equation is arranged into   y =   a x^2 + bx + c    form  )

     first one   - -2/4  = 1/2

     second one   -2/ -4  = 1/2

        third one  - -2 / 4    = 1/2

          fourth one   - 2 / 4   = - 1/2   BINGO !

What we get to know by looking at picture :

[tex] \\ \\\\ [/tex]

To find :

[tex] \\ \\ \\ [/tex]

Given:

[tex] \\ \\ \\ [/tex]

Concept:

So as we can orange doesn't lies inside circle. And the wall of circle touches all four sides of circle. So first we have to find area of circle and then Area of square. And then we will subtract the ares. The result will be Area of orange part.

[tex] \\\\ \\ [/tex]

[tex] \\ \\\\ [/tex]

[tex] \red{ \textsf{ \textbf{Area of circle: }}}[/tex]

[tex] \\ [/tex]

To find area of circle we need radius of it i.e Length of OP.

As BC = AB

∴AB = 6.84

As O is the center of square ∴it's center of circle too

Therefore:

[tex] \\\\ [/tex]

Now Let's find area :

[tex] \\\\ [/tex]

[tex] \star \boxed{ \rm Area~of~circle = \pi {r}^{2} }[/tex]

here :

[tex] \\ [/tex]

[tex]: \implies\sf Area~of~circle = \pi {r}^{2} \\ \\ \\ : \implies\sf Area~of~circle = \dfrac{22}{7} \times {3.42}^{2} \\ \\ \\ : \implies\sf Area~of~circle = \dfrac{22}{7} \times {3.42}^{2} \\ \\ \\ : \implies\sf Area~of~circle = \dfrac{22}{7} \times11.7\\\\\\: \implies\sf Area~of~circle = \dfrac{257.4}{7} \\ \\ \\ : \implies \boxed{ \orange{\tt{ Area~of~circle = 36.6 \{approx \}}}} \bf \dag[/tex]

[tex] \\ \\ [/tex]

[tex] \red{ \textsf{ \textbf{Area of square: }}}[/tex]

[tex] \\\\ [/tex]

[tex] \star \boxed{ \rm Area~of~square = {side}^{2} }[/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Area~of~square = {side}^{2} \\ \\ \\ : \implies\sf Area~of~square = {6.84}^{2} \\ \\ \\ : \implies\sf Area~of~square = {6.84} \times 6.84 \\ \\ \\ : \implies \boxed{\tt{ \orange{Area~of~square = 46.8 \{aprox \}}}}\bf\dag[/tex]

[tex] \\ \\ [/tex]

[tex] \red{ \textsf{ \textbf{Area of orange \: part: }}}[/tex]

[tex] \\ [/tex]

[tex] \star\sf \boxed{ \rm Area_{(orange \: part)} = Area_{(square)} - Area_{(circle)}}[/tex]

[tex] \\ \\ [/tex]

[tex]: \implies\sf Area_{(orange \: part)} = 46.8 - 36.6 \\ \\ \\ : \implies \boxed{ \blue{\tt{Area_{(orange \: part)} = 10.2}}}\bf\dag[/tex]

As tangents from a single point to the circle are equal in measure

ABC is isosceles

<A=60°

We know the radius hits any tangent on right angles

So

Now

accurate value

Answer:

[tex]x=4\sqrt{3}[/tex]

Step-by-step explanation:

If two tangents to a circle meet at one exterior point, the tangent segments are congruent.   Therefore, AC = BC

This means that ΔABC is an isosceles triangle and so
∠ABC = ∠BAC = 60°

The tangent of a circle is always perpendicular to the radius.

Therefore, ∠PAC = 90°

With this information, we can calculate ∠PAD:

⇒ ∠PAD + ∠BAC = ∠PAC

⇒ ∠PAD + 60° = 90°

⇒ ∠PAD = 90° - 60°

⇒ ∠PAD = 30°

We now have a side length and an angle of ΔPAD (shown in orange on the attached diagram).  So using the cos trig ratio, we can calculate [tex]x[/tex]:

[tex]\sf \cos(\theta)=\dfrac{A}{H}[/tex]

where:

Given:

[tex]\implies \cos(30^{\circ})=\dfrac{6}{x}[/tex]

[tex]\implies x=\dfrac{6}{\cos(30^{\circ})}[/tex]

[tex]\implies x=\dfrac{6}{\frac{\sqrt{3}}{2}}[/tex]

[tex]\implies x=4\sqrt{3}[/tex]

Answer:

See below ~

Step-by-step explanation:

Completing the square :

Graph :

Answer:

x = 9(y - 1)² + 1

see attached for graph

Step-by-step explanation:

Given equation:

9y² - x - 18y + 10 = 0 ​

As there is a y² in the equation, this implies it is a sideways parabola.

To complete the square for a sideways parabola, collect the y variable terms on the left and everything else on the right:

⇒ 9y² - 18y = x - 10

Factor out the leading coefficient from the left side:

⇒ 9(y² - 2y) = x - 10

Take the coefficient of y, half it, then square it:  (-2 ÷ 2)² = 1

Add this inside the parentheses, and add the distributed value of this to the right side:

⇒ 9(y² - 2y + 1) = x - 10 + 9

Factor the parentheses and simplify the right side:

⇒ 9(y - 1)² = x - 1

Add 1 to both sides to make x the subject:

⇒ x = 9(y - 1)² + 1

Conic form of a sideways parabola with a horizontal axis of symmetry:

x = a(y - k)² + h

(where (h, k) is the vertex and y = k is the axis of symmetry)

If a > 0, the parabola opens to the right, and if a < 0, the parabola opens to the left.

Therefore, for  x = 9(y - 1)² + 1

To find the x-intercept, set y = 0 and solve for x:

⇒ x = 9(0 - 1)² + 1

⇒ x = 9(-1)² + 1

⇒ x = 9(1) + 1

⇒ x = 10

Therefore, the y-intercept is (10, 0)

As the axis of symmetry is y = 1, the other value of y when x = 10 is y = 2

Plot the vertex and points. Add an axis of symmetry to help draw the curve.  Draw the parabola opening to the right.

**graph attached**

If the height of the trapezium is 7 units. Then the area of the trapezium will be 31.5 square units.

It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a trapezium, one pair of opposite sides are parallel.

The quadrilateral ABCD whose vertices are A(-2,-1), B(-2,-3), C( 5,6), and D(5,-1).

The lines AB and CD are parallel to the y-axis. Then the quadrilateral ABCD is a trapezium.

The height of the trapezium will be 7 units.

The area of the trapezium will be

Area = 1/2 (2 + 7) x 7

Area = 0.5 x 9 x 7

Area = 31.5 square units.

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