At WMS, 3 out of 4 students ride a bus to school. There are 600 students at WMS. How many students ride the bus?

If 0 < a < 12, then h(12 – a) = h(12 + a) is true. Then the correct option is D.

When a body is thrown in the air at an angle, then the term is known as projectile motion.

The table is given in the question.

A) h(4) < h(20), this statement is incorrect, because the h(4) = h(20).

B) The flight is symmetric about the line t = 10, this statement is incorrect, because symmetric about t = 12.

C) The projectile will hit the ground at some value of t less than 24. This is incorrect, because t > 24.

D) If 0 < a < 12, then h(12 - a) = h(12 + a).​ This statement is correct.

Then the correct option is D.

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Answer:

3a) 54/99

3b) 257/999

Hope this'll help you!

Answer:

hmm easy peesy

3x+6= 21

21-6=3x

15=3x

5 = X

meet my dog; (Frankie the sleeping beauty )

Answer:

x = 5

Step-by-step explanation:

Expand:

Use distributive property:

3x + 6 = 21

3x = 15

x = 5

Divide:

(x + 2) = 21/3

x + 2 = 7

x = 5

Check your work:

3(5 + 2) = 21

15 + 6 = 21

21 = 21

Correct

Answer:

answer: 117

Hope this helps!

Answer:

117

Step-by-step explanation:

Convert mixed numbers to improper fractions:

7 1/2 = 15/2

4 1/3 = 13/3

3 3/5 = 18/5

15/2 x 13/3 x 18/5

Multiply and cross-cancel:

18/2 x 13/1

Multiply again:

117/1 = 117

Given:

[tex]\cos A=\dfrac{4}{\sqrt{65}}[/tex]

[tex]\sin B=\dfrac{1}{\sqrt{2}}[/tex]

A and B both lies in I quadrant.

To find:

The value of [tex]\sin (A+B)[/tex].

Solution:

We know that, all trigonometric ratios are positive in first quadrant.

[tex]sin^2\theta +\cos^2\theta =1[/tex]

Using this we get

[tex]\sin^2A +\cos^2A =1[/tex]

[tex]\sin^2A +\left(\dfrac{4}{\sqrt{65}}\right)^2 =1[/tex]

[tex]\sin^2A +\dfrac{16}{65}=1[/tex]

[tex]\sin^2A =1-\dfrac{16}{65}[/tex]

Taking square root on both sides, we get

[tex]\sin A =\sqrt{\dfrac{65-16}{65}}[/tex]         [Only positive because A lies in I quadrant]

[tex]\sin A =\sqrt{\dfrac{49}{65}}[/tex]

[tex]\sin A =\dfrac{7}{\sqrt{65}}[/tex]

Similarly,

[tex]\sin^2B +\cos^2B =1[/tex]

[tex]\left(\dfrac{1}{\sqrt{2}}\right)^2 +\cos^2B =1[/tex]

[tex]\dfrac{1}{2}+\cos^2B =1[/tex]

[tex]\cos^2B =1-\dfrac{1}{2}[/tex]

Taking square root on both sides, we get

[tex]\cos B =\sqrt{\dfrac{2-1}{2}}[/tex]         [Only positive because B lies in I quadrant]

[tex]\cos B =\sqrt{\dfrac{1}{2}}[/tex]

[tex]\cos B =\dfrac{1}{\sqrt{2}}[/tex]

Now,

[tex]\sin (A+B)=\sin A\cos B+\cos A\sin B[/tex]

[tex]\sin (A+B)=\dfrac{7}{\sqrt{65}}\times \dfrac{1}{\sqrt{2}}+\dfrac{4}{\sqrt{65}}\times \dfrac{1}{\sqrt{2}}[/tex]

[tex]\sin (A+B)=\dfrac{7}{\sqrt{130}}+\dfrac{4}{\sqrt{130}}[/tex]

[tex]\sin (A+B)=\dfrac{11}{\sqrt{130}}[/tex]

Therefore, the exact value of [tex]\sin (A+B)[/tex] is [tex]\dfrac{11}{\sqrt{130}}[/tex].

Answer:

3.5

Step-by-step explanation:

n+7=3n

7=2n

n=3.5

Answer:

n=7/2

Step-by-step explanation:

n+7=3n

-n     -n

7=2n

/2  /2

7/2=n

Answer: Option b 121km

50% means half, so the half of 242km is 121km, so option B 121 is correct.

Step-by-step explanation:

242/2=121

Have a nice day!

and can I maybe have brainliest? Thanks!

Answer:

Step-by-step explanation:

36 - 4

Step-by-step explanation:

(6x - 2)(6x + 2)

= (6x)(6x) + (6x)(-2) + (2)(6x) + (-2)(2)

= 36 - 12x + 12x - 4

= 36 - 4

Answer:

13.4

Step-by-step explanation:

it is A square +b square =c square which is just 12×12=144 + 6×6=36 and then add them together which is 180, then just square root 180 can do it for every type of question like that and always remember the longest side is c, and the other two it doesn't matter which is A or B.

Answer:

blue

Step-by-step explanation:

There the most common eyes in the class?

Answer:the student would most likely have blue eyes

Step-by-step explanation:

8/20

6/20

5/20

1/20

Answer:

SIMPLE, −$14.75 + $36.25 = $21.50

Step-by-step explanation:

TO CHECK OURSELVES:

21.50 -  36.25 = -14.75

YOUR WELCOME

Answer:

Criteria.

Step-by-step explanation:

A series of criteria is a set of parameters established by whoever seeks to interpret a certain information or quantity of concepts, by means of which a set of interpretive rules is established that should be equal to all the concepts to be analyzed. Thus, the criteria allow a set of data to be analyzed under the same parameters or information processing requirements.

Step-by-step explanation:

[tex]to \: help \: you \\ \cot(A) = { (\tan(A)) }^{ - 1} = \frac{ \cos(A) }{ \sin(A) } \\ or : \\ \cot(A) = \sqrt{(1 + {( \tan(A) )}^{2} } [/tex]

Answer:

A is correct :)

Step-by-step explanation:

edge 2021

thank you! have a great day

Answer:

5.38516480 or  √ 29

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

5.385165 or sqrt 29

Step-by-step explanation:

d = distance

d= sqrt (7-2)^2+(2-4)^2

and when simplified fully you get

sqrt or 5.385165

Answer:

D

Step-by-step explanation:

1) remember that x indicates the independent variable, while y the dependent variable

2) remember that the first diagram represents the values of x, while the second the values of y

Mapping diagram A represent the number of tickets sold on that day. Therefore, option A is the correct answer.

The given set of ordered pairs are {(1,19), (2,23), (3,23), (4,29), (5,31)}.

In math, a relation defines the relationship between sets of values of ordered pairs. The set of elements in the first set are called domain which is related to the set of the element in another set, which is called range.

A mapping diagram consists of two parallel columns. The first column represents the domain of a function [tex]f[/tex], and the other column for its range. Lines or arrows are drawn from domain to range, to represent the relation between any two elements.

Diagram A represents the given ordered pair

Mapping diagram A represent the number of tickets sold on that day. Therefore, option A is the correct answer.

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Answer:

D: Point A is 1 unit to the right of the origin and point B is 3 units to the right of the origin.

Step-by-step explanation:

The coordinate (1, 3) is in quadrant 1 with a positive y, moving the point up, and a positive x, moving the point right. Because the x is 1, the point moves 1 unit right from the origin.

The coordinate (3, 1) is also in quadrant 1 with a positive y and x, but this time the x is 3, moving the point 3 units right from the origin.

Answer:

12(x+5)=

12x+60=

12x÷12 & 60÷12

x=5

Answer:

it would be 100 rounded because 14x8=112 and 112 is rounded to 100 to the nearest hundreth. Please subscribe to Amiredagoat Yt

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

because when you multiply 3x3 (the base) times 18(the height) you get= 162

Answer:

Step-by-step explanation:

1=71

2=70

3= 68 and 75, they both appear twice

4= 8

Answer:

6g/cm^3

Step-by-step explanation:

The density of the cube would be 6 grams/cm^3. I got this answer by first finding the volume of the cube, 2^3 which gives me 8 cm as the initial volume of the cube. Then, the 48 grams of mass the cube has allows me to divide 48 / 8 which gave me 6. And 6 would be the density of the cube in grams.

Answer: 6g/cm^3

Hope this helps!

Answer:

p = 6 g/cm³

Step-by-step explanation:

Given: cube sides= 2 cm and 48 g

To find: The cube's density

Formula: [tex]{p} \frac{m}{V}[/tex]

Solution: Measure the height, width, and depth of the shipment in inches.

Multiply the three measurements (height x width x depth).

Divide the total cubic inches by 1,728 (the number of cubic inches in a cubic foot).

Divide the weight (in pounds) of the shipment by the total cubic feet.

p = density

m = mass

V = volume

Answer:

48 boxes

Explanation:

First, find the volume of the rectangular prism (l*w*h) to find out how much it can hold.

15*40*10= 6,000

Then, find the volume of the cubic boxes (l*w*h) to find how much space each of them take up.

5*5*5= 125

Finally, divide the rectangular prism's volume by the boxes' to find out how many can fit inside.

6,000/125= 48 boxes

Answer:

height of second rectangular prism is 5 meters

Step-by-step explanation:

Answer:

The amplitude is 1/5

Step-by-step explanation:

Given

[tex]y = -\frac{1}{5}\sin(x)[/tex]

Required

Determine the amplitude

The general cosine function is:

[tex]y = A\sin(k(x + c)) +d[/tex]

Where

[tex]Amplitude = |A|[/tex]

Compare [tex]y = A\sin(k(x + c)) +d[/tex] and [tex]y = -\frac{1}{5}\sin(x)[/tex]

[tex]A = -\frac{1}{5}[/tex]

So:

[tex]Amplitude = |-\frac{1}{5}|[/tex]

[tex]Amplitude = \frac{1}{5}[/tex]

Answer:

The circle should be open and the arrow should go the other way.

The given scatter plot has a positive correlation.

Given that, the scatter plot shows the number of hours worked and money spent on entertainment by every 24 students.

A scatter plot is a means to represent data in a graphical format. A simple scatter plot makes use of the coordinate axes to plot the points, based on their values. The following scatter plot excel data for age (of the child in years) and height (of the child in feet) can be represented as a scatter plot.

A positive correlation—when the correlation coefficient is greater than 0 signifies that both variables move in the same direction.

The blanks for the given questions are filled below:

a) increase

b) strong positive

c) $22.50

Therefore, the given scatter plot has a positive correlation.

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Answer:

Step-by-step explanation:

i think you forgot to link or import the question

Answer:

$32.40

Step-by-step explanation:

45% = 0.45

72(0.45) = 32.4

Based on the amount Kristian had and the percentage spent on the game, the price of the game is $32.40.

The price of the game can be found as:

= Amount Kristian has x Percentage spent on game

Solving gives:

= 45% x 72

= $32.40

In conclusion, the price of the game is $32.40.

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Answer:

D.

Step-by-step explanation:

Answer:

[tex] \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ [/tex]

by using Pythagoras law:

h²=p²+b²

x²=16²+12²

x=√400

x=20 units.

Answer:

a-The probability that item A is discovered as a defective item by method 1 is 0.4

b. The probability that item A is discovered as a defective item by method 2 is 0.4

c-As the probability of detecting A as a defective item is same for the two methods, thus it can be stated that each of the methods is equally effective.

Step-by-step explanation:

a-

The first method where the inspector chooses two of the five items randomly, so the total pairs are as given below:

[tex]N_{total}=n(S_{total})\\N_{total}=n(\{AB,AC,AD,AE,BC,BD,BE,CD,CE,DE\})\\[/tex]

As the total experiments in the overall space is 10 so [tex]N_{total}[/tex] is 10.

As A comes in 4 of these experiments, thus the value of [tex]N_{A}[/tex] is 4.

So the Probability of A is given as

[tex]P(A)=\dfrac{N_{A}}{N_{total}}\\P(A)=\dfrac{4}{10}\\P(A)=0.4[/tex]

The probability that item A is discovered as a defective item by method 1 is 0.4.

b-

Now in order to find the probability of finding item A as defective by method 2, first consider the probability of not finding item A as defective.

This is given as

[tex]P(A)=1-P(A)'[/tex]

Here P(A)' is given as

[tex]P(A)'=P(A)'_{1^{st}}\times P(A)'_{2^{nd}}[/tex]

Here

P(A)'_1st is the probability that the first inspector fails to detect A as a defective item which is given as

[tex]P(A)'_{1^{st}}=1-\dfrac{1}{N_{total\ items}}[/tex]

Here N_total items is 5. so the equation becomes

[tex]P(A)'_{1^{st}}=1-\dfrac{1}{N_{total\ items}}\\P(A)'_{1^{st}}=1-\dfrac{1}{5}\\P(A)'_{1^{st}}=\dfrac{5-1}{5}\\P(A)'_{1^{st}}=\dfrac{4}{5}[/tex]

Similarly

P(A)'_2nd is the probability that the second inspector fails to detect A as a defective item which is given as

[tex]P(A)'_{2^{nd}}=1-\dfrac{1}{N_{total\ items}}[/tex]

Here N_total items is 4 as 1 item has already been checked. so the equation becomes

[tex]P(A)'_{2^{nd}}=1-\dfrac{1}{N_{total\ items}}\\P(A)'_{2^{nd}}=1-\dfrac{1}{4}\\P(A)'_{2^{nd}}=\dfrac{4-1}{4}\\P(A)'_{2^{nd}}=\dfrac{3}{4}[/tex]

So the main equation becomes

[tex]P(A)=1-P(A)'\\P(A)=1-(P(A)'_{1^{st}}\times P(A)'_{2^{nd}})[/tex]

Substituting the values give

[tex]P(A)=1-(P(A)'_{1^{st}}\times P(A)'_{2^{nd}})\\P(A)=1-(\dfrac{4}{5}\times \dfrac{3}{4})\\P(A)=1-\dfrac{3}{5}\\P(A)=\dfrac{5-3}{5}\\P(A)=\dfrac{2}{5}\\P(A)=0.4[/tex]

The probability that item A is discovered as a defective item by method 2 is 0.4.

c-

As evident from the above, that the value of probabilities for both the methods is same therefore the overall effectiveness of each of the methods is same.