At the Sparta Fault in Greece, the hanging wall is below the footwall. This type of fault is called a .

Answers

Answer 1
The answer that would best complete the given statement above would be option A. Normal Fault. At the Sparta fault in Greece, the hanging wall is below the footwall and this type of fault is called a normal fault. Hope this answers your question. Have a great day ahead!
Answer 2

Answer:

1 a

Explanation:


Related Questions

What is the new concentration for 25mL added to 135mL of .150M

Answers

Answer:

The concentration for 25 mL is 0.81 M

Explanation:

Given data:

Initial volume = 135 mL

Initial molarity = 0.150 M

New volume added = 25 mL

Concentration for 25 mL = ?

Solution:

M₁V₁    =    M₂V₂

0.150 M × 135 mL = M₂ × 25 mL

M₂ = 0.150 M × 135 mL / 25 mL

M₂ = 20.25 M.mL/25 mL

M₂ = 0.81 M

The concentration for 25 mL is 0.81 M.

Can you answer these two questions right please and thank you

Answers

Answer:

B. LZAQD

A. Younger than A but older than Q

Explanation:

To solve this problem, we simply apply the stratigraphic laws which are the law of superposition and principle of cross cutting.

According to the law of superposition, in an undeformed sequence of strata, the oldest layer is always at the bottom and the youngest on top. In this case, we have a little disturbance but it did not affect much of the original bedding. So, the rock ages from L to Z to A to Q and D. L is the oldest and D is the youngest.

According to the principle of cross-cutting "features that cuts through a rock are younger than the layers they cut through". In this problem, the fault cuts through layers LZ and A which suggests that these layers are older than the faulting event. Layer Q is unaffected by the faulting so, the fault is older than the layer.

to make a solute dissolve more quikly in a solvent wich whould you do? a. stir it in cold water b.stir it in warm water c.solvent d.lets the solute settle down d. nothing to do with the solute?​

Answers

Answer:

b.stir it in warm water

Explanation:

the slobility will be faster in the high temperture

How do her cells use these molecules to release energy for her body to run?

Answers

In cells use oxygen to release energy stored in sugars such as glucose. In fact, most of the energy used by the cells in your body is provided by cellular respiration. Just as photosynthesis occurs in organelles called chloroplasts, cellular respiration takes place in organelles called mitochondria.

Her cells use oxygen, in the oxidation of sugar(glucose) to provide energy in the body's admissible form (i.e ATP).

Her cells, like that of every animal depend on the oxidation of sugars particularly glucose by Oxygen, O2 to provide energy in a process termed Cellular respiration.

The process of cellular respiration in her cell occurs in the mitochondria although the first part of cellular respiration occurs in the cytoplasm.

Essentially, the process of cellular respiration is made of 3 metabolic pathways as follows;

GlycolysisKreb's cycleThe Electron Transport Chain

Ultimately, the admissible form of energy, the Adenosine Tri Phosphate-ATP is the end result of this glucose metabolism.

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12.5 mL of 6.0 M KCl is diluted to make a 1.5 L solution. The molarity of the dilution solution is ___ M. (Round atomic masses to the nearest whole number. Include 2 sig figs total in your answer.)

Answers

The molarity of the dilution solution is 0.050 M

Further explanation

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

Dilution formula :

[tex]\tt M_1.V_1=M_2.V_2[/tex]

M₁=6 M

V₁=12.5 ml

V₂=1.5 L=1500 ml

[tex]\tt 6\times 12.5=M_2\times 1500\\\\M_2=\dfrac{6\times 12.5}{1500}=0.05~M\\\\for~sig.fig\rightarrow 0.050~M[/tex]

A 2kg metal cylinder is supplied with 1600J of energy to heat it from 5*C to 13*C. What is the SHC of the metal?

Answers

Answer:

100Jkg/°C

Explanation:

Given parameters:

Mass of metal  = 2kg

Amount of heat energy  = 1600J

Initial temperature  = 5°C

Final temperature = 13°C

Unknown:

Specific heat capacity of the metal  = ?

Solution:

Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.

  H  = m x C x (T₂ - T₁ )

H is the amount of heat

m is the mass

C is the unknown specific heat capacity

T is the temperature

     Insert the parameters and solve;

  1600 = 2 x C x (13 - 5)

   1600  = 16C

        C = 100Jkg/°C

Many materials, such as rocks, expand (get larger) when they are heated and contract (shrink) when they are cooled. This change
in size can cause cracks to form and break large rocks into smaller pieces.
In this example, what is caused by heating and cooling?
OA. decay
ОВ.
weathering
OC.
erosion
OD
earthquakes

Answers

Answer:

OB: weathering

Explanation:

the cycle of heating and cooling causes stresses called thermal fatigue, this causes the material to break down. In hand, weathering is a physical and chemical process that causes rocks and minerals on the Earth's surface to break down and decompose. Therefore, this matches the process you have described.

Answer:

weathering fun way to imagen it: just imagen u saw ur worst enemie and pretende it is the rock and the wind and ice and water are ur best friends THEN BAM wind and ice and water(ur best friends) make the rock(worst enemie) to dust :D

2.00 mL of a 12.00 M HCL solution was reacted with 0.0450 grams of magnesium.?
Which reactant is the limiting reactant? Mathematically document your answer.

Answers

Answer:

Magnesium Mg will be the limiting reagent .

Explanation:

The limiting reagent is one that is first consumed in its entirety, determining the amount of product in the reaction. When the limiting reagent ends, the chemical reaction will stop.

In other words, the limiting reagent is that reagent that is consumed first in a chemical reaction, determining the amount of products obtained. The reaction depends on the limiting reagent, because the other reagents will not react when one is consumed.

In this case, the balanced reaction is:

Mg + 2 HCl ⇒ MgCl₂ + H₂

You know tha 2.00 mL of a 12.00 M HCl solution was reacted with 0.0450 grams of magnesium.

Being Molarity (M) the number of moles of solute that are dissolved in a certain volume, calculated by the expression:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]  ( Molarity is expressed in units [tex]\frac{moles}{liter}[/tex])

then the number of moles can be calculated as:

number of moles of solute=molarity* volume

So, being:

molarity= 12 Mvolume= 2 mL= 0.002 L (being 1,000 mL= 1 L)

The number of moles of HCl that react is:

number of moles of HCl= 12 M*0.002 L= 0.024

On the other hand, since the molar mass of magnesium is 24.305 g / mol, then if 0.0450 grams of magnesium react, it indicates that they must react:

[tex]0.0450 grams*\frac{1 mol}{24.305 grams} = 0.00185 moles[/tex]

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), and a simple rule of three as follows: if by stoichiometry 1 mole of Mg reacts with 2 moles of HCl, how much moles of Mg will be needed if 0.024 moles of HCl react?

[tex]moles of Mg=\frac{0.024 moles of HCl*1 moles of Mg}{2 moles of HCl}[/tex]

moles of Mg= 0.012

But 0.012 moles of Mg are not available, 0.00185 moles are available. Since you have less moles than you need to react with 0.024 moles of HCl, magnesium Mg will be the limiting reagent .

what is aluminum’s nuclear charge?

Answers

Answer:All six of the ions contain 10 electrons in the 1s, 2s, and 2p orbitals, but the nuclear charge varies from +7 (N) to +13 (Al)

Explanation:

hope this helped if it did may i have brainliest

What they said^^^^^^^

Which statement describes an example of a chemical property of a metal statue?
O It is metal.
O It can tarnish.
OIt is solid.
OIt is shiny.


Answers

Answer:

The answer is "it can tarnish"

Explanation:

The statement describes an example of a chemical property of a metal statue is that it can tarnish.

Chemical properties are defined as those properties which become evident during or after a chemical reaction  has taken place.

These properties cannot be determined externally just by viewing the substance ,these change immensely after a substance undergoes a chemical change.These are used for identification of unknown substances and used for building up chemical classifications.

The major chemical properties include flammability,toxicity,reactivity,acidity and heat of combustion.For a chemical property to be apparent , it is necessary that the structure of the substance is altered.

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What might happen if you mixed a strong acid with an equally strong base? Question 2 options:
A.You'd wind up with a pH-neutral salt and water.
B.You would see an explosive chemical reaction.
C.The base would destroy the acid.
D.The acid would destroy the base.

Answers

Answer:

b  

Explanation:

The correct answer is B

A reaction vessel is charged with 0.50 atm of A and 0.030 atm of B. Once the reaction reaches equilibrium, what is the equilibrium partial pressure of B? Kp for this reaction is 67.2A (g) ⇌ 2 B (g)

Answers

Answer:

1.000 atm

Explanation:

Step 1: Write the reversible reaction

A(g) ⇌ 2 B(g)

Step 2: Calculate the reaction quotient

Q = [B]²/[A]

Q = 0.030²/0.50

Q = 0.0018

since Q < Kp, the reaction will proceed to the right

Step 3: Make an ICE chart

       A(g) ⇌ 2 B(g)

I      0.50      0.030

C       -x          +2x

E    0.50-x    0.030+2x

Step 4: Find the value of "x"

We will use the definition of the pressure equilibrium constant.

Kp = 67.2 = [B]²/[A] = (0.030+2x)²/0.50-x

33.6 - 67.2x = 0.0009 + 0.12x + 4x²

4x² + 67.32x -33.5991 = 0

We solve this quadratic equation and we get x=0.485112  and x=−17.3151 (neglected).

Step 5: Find the partial pressure of B at equilibrium

pB = 0.030+2x = 0.030+2(0.485112) = 1.000 atm

The equilibrium partial pressure of B would be:

[tex]1.000 atm[/tex]

Reversible Reaction

Given that,

Reaction

[tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex]

Charge on the reaction vessel [tex]= 0.50 atm[/tex] of A

[tex]0.030 atm[/tex] of B

To find,

Reaction quotient first

[tex]= B^2/A\\= (0.030)^2/0.50\\= 0.0018[/tex]

This shows that the reaction quotient is greater than Kp.

Through the reaction [tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex], ICE can be drawn

I      [tex]0.50[/tex]      [tex]0.030[/tex]

C    [tex]-x[/tex]        [tex]+2x[/tex]

E    [tex]0.50-x[/tex]   [tex]0.030+2x[/tex]

Now,

We will determine the value of [tex]x[/tex],

Kp [tex]= 67.2[/tex]

[tex]= [B]^2/[A][/tex]

[tex]= (0.030+2x)^2/0.50-x[/tex]

⇒ [tex]33.6 - 67.2x[/tex] [tex]= 0.0009 + 0.12x + 4x^2[/tex]

⇒ [tex]4x^2 + 67.32x -33.5991 = 0[/tex]

∵ [tex]x = -17.3151[/tex]

Therefore, Equilibrium Partial Pressure

[tex]= 0.030+2x[/tex]

[tex]= 0.030+2(0.485112)[/tex]

= [tex]1.000[/tex] atm

Learn more about "Partial Pressure" here:

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I need HALP so yea halp mee please

Answers

Carbon: atomic number 6, non-metal, solid, period 2.

Platinum: atomic number 78, metal, solid, group 10, period 6.

Iron: atomic number 26, metal, solid, group 8, period 4.

Hydrogen: atomic number 1, nonmetal, gas, group 1, period 1.

Cobalt: atomic number 27, metal, solid, group 9, period 4.

Arsenic: atomic number 33, metalloid, solid, group 15, period 4.

Hope this helps!! (:


Weathering is a constructive process.
True or false

Answers

Answer: true

Explanation: Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.

In the metallurgic industry one of the processes to get pure iron takes tree steps.


a) CaCO3→CaO + CO2


b) CO2 + C → CO


c) Fe2O3 + CO → Fe + CO2


Calculate the kilograms of iron that would be produced from 1340 g of calcium carbonate.

Answers

Mass of Iron produced : 1.5 kg

Further explanation

Reaction

a) CaCO3→CaO + CO2

b) CO2 + C → 2CO

c) Fe2O3 + 3CO → 2Fe + 3CO2

From the reaction above : 1 mol CaCO₃ = 2 mol Fe

mol CaCO₃ :

1340 : 100 g/mol = 13.4

mol Fe :

2 x 13.4 = 26.8

mass Fe :

26.8 x 56 g/mol=1500.8 g⇒1.5 kg

Scenario Three: Carbon dioxide emissions increase
• Set the carbon dioxide emissions rate to 9.8 gigatons.
• Set the time step size to 10 years.
• Select the step forward button once.
• Increase the carbon dioxide emissions by 0.2 and press step forward.
• Continue stepping forward once, increasing the carbon emissions each time, until you reach 2110.
• Record the data in the table below.

Answers

Maintain carbon dioxide emissions at 9.8 for the rest of scenario one.

2020                               9.8                             58

2030                               9.8                             58.5

2040                               9.8                             58.9

2050                               9.8                             59.1

2060                               9.8                             59.5

2070                               9.8                             59.8

2080                               9.8                             60

2090                               9.8                             60.1    

2100                                9.8                            60.5

2110                                 9.8                            60.9

3. Theoretically how many grams of magnesium is required to produce to 5.0 g of

Magnesium oxide?

Answers

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2  → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

Stoichiometric coefficients indicate the ratio between ________of given substances in a chemical reaction
a) moles

b) molecules

c) molar masses

d) masses


both a) and b)


any of the a), b), c) and d)


both a) and c)


only b)


only a)

Answers

Answer:

b

Explanation:

A 75 mL solid is estimated by a student to be 81 mL. Calculate the percent error.

Answers

Answer:

8 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]

From the question

error = 81 - 75 = 6 mL

actual volume = 75 ml

We have

[tex]p(\%) = \frac{6}{75} \times 100 \\ = \frac{2}{25} \times 100 \\ = 2 \times 4 \\ = 8 \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

8 %

Hope this helps you

plz help me.......
questiion: Following are the correct statements for actual yield except
1:amount of product obtained in a chemical reaction
2:always less than theoretical yield
3:none
4:product calculated from the balanced chemical equation

Answers

i think it’s 4 ........

Which isomer of 1-bromo-4-tert-butylcyclohexane reacts faster when refluxed with potassium tert-butoxide?

Answers

Answer:

See explanation.

Explanation:

Since potassium tert-butoxide is a strong bulky base, we expect that an elimination reaction predominates.

This reaction is expected to occur by E2 mechanism. The cis isomer of  1-bromo-4-tert-butylcyclohexane is known to react faster by E2 mechanism because it fulfills the anticoplanar arrangement required for for E2 mechanism, where the leaving group and adjacent proton must be anti to each other and in the same plane. The trans isomer can not fulfill this requirement.

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 725 mL of a solution that has a concentration of Na ions of 1.30 M

Answers

Answer:

51.53 grams .

Explanation:

Na₃PO₄    ⇄  3Na⁺¹   +    PO₄⁻³ .

1 mole           3 mole

725 mL of 1.3 M Na⁺  ions

= .725 x 1.3 moles of Na⁺ ions

= .9425 moles

3 mole of Na⁺  is formed by 1 mole of Na₃PO₄

.9425 mole of Na⁺  is formed by .9425/3  mole of Na₃PO₄

Na₃PO₄ needed =  .9425/3  moles = .3142 moles

Molecular weight of Na₃PO₄ = 164

grams of Na₃PO₄ needed = .3142 x 164 = 51.53 grams .

Calculate molecules in 1dm^3 of oxygen

Answers

Number of molecules in 1 dm³ Oxygen = 2.71 x 10²²

Further explanation

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

1 dm³ of oxygen = 1 L Oxygen

mol Oxygen :

[tex]\tt \dfrac{1}{22.4}=0.045`mol[/tex]

molecules of Oxygen :

n=mol=0.045

No = 6.02.10²³

[tex]\tt N=n\times No\\\\N=0.045\times 6.02\times 10^{23}\\\\N=2.71\times 10^{22}[/tex]

What are two cases when a cell must use active transport in order to move materials?

Answers

Answer:

A cell must use active transport in order to move materials in the process Phagocytosis and Pinocytosis

1. A physician ordered 2.0 milligrams tetracycline to be given to a patient. If the tetracycline was available as 0.75 mg/mL of solution, how many milliliters would you give to the patient

Answers

Answer:

2.67 mL

Explanation:

The following data were obtained from the question:

Mass of tetracycline = 2 mg

Density of tetracycline = 0.75 mg/mL

Volume of tetracycline =?

We can obtain the volume of the tetracycline that should be given to the patient by applying the following equation:

Density = mass /volume

0.75 = 2 / volume

Cross multiply

0.75 × Volume = 2

Divide both side by 0.75

Volume = 2/0.75

Volume = 2.67 mL

Therefore, the volume of the tetracycline that should be given to the patient is 2.67 mL

A student has a balloon with a volume of 2.5 liters that contains 4.0 moles of air. The ballon has a small leak, allowing one mole to escape, leaving just 3.0 moles of air inside the balloon. What is the balloon's new volume after the air has escaped?

Answers

Answer:

1.9 L

Explanation:

Step 1: Given data

Initial number of moles of air (n₁): 4.0 molInitial volume of the balloon (V₁): 2.5 LFinal number of moles of air (n₂): 3.0 molFinal volume of the balloon (V₂): ?

Step 2: Calculate the final volume of the balloon

According to Avogadro's law, the volume of an ideal gas is directly proportional to the number of moles. We can calculate the final volume of the balloon using the following expression.

V₁ / n₁ = V₂ / n₂

V₂ = V₁ × n₂ / n₁

V₂ = 2.5 L × 3.0 mol / 4.0 mol

V₂ = 1.9 L

How many moles of KCI would be dissolved in 4 L of water to make a 2 M
solution?
1
A.
mole
B. 2 moles
C. 8 moles
D. 4 moles

Answers

The answer is the second one

Answer:

C. 8 Moles

Explanation:

give the balanced chemical reaction for the preparation of black oxide from blue vitriol​

Answers

Answer:

Blue vitriol is crystal copper sulphate

Explanation:

The black oxide is the higher oxide of Copper i.e Cu. It is also called as tenorite. It is solid black in color. It is formed by heating copper with air.

[tex]$2Cu +O_2 \rightarrow 2CuO$[/tex]

Blue vitriol is the crystalline form of copper sulphate. It is also known as copper (II) sulphate.

When heating, the blue vitriol undergoes various steps of changes to the black oxide of copper.

The chemical reaction is --

[tex]$CuSO_4 \cdot5H_2O \rightarrow CuSO_4\cdot 3H_2O {\rightarrow} CuSO_4\cdot H_2O \rightarrow CuSO_3 \rightarrow CuO +SO_2+O_2[/tex]

why do we need air? If you know please answer this

Answers

Answer:

I found this on the internet People need to breathe, and so do lots of other animals—and plants! Breathing is part of a process called respiration. During respiration, a living thing takes in oxygen from the air and gives out carbon dioxide.

Explanation:

10 Interesting Things About Air | NASA Climate Kidsclimatekids.nasa.gov › 10-things-air

Your welcome!

to breath

with out air we can't live here

The phase of the moon you see depends on

Answers

Answer:

The phases of the Moon depend on the moon's position compared to the Earth and the Sun. Remember that the moon revolves around the Earth. As the moon goes around the Earth, half of the moon is always illuminated by the Sun.

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