At a construction site, a 68.0 kg bucket of concrete hangs from a light (but strong) cable that passes over a light friction-free pulley and is connected to an 85.0 kg box on a horizontal roof (see the figure (Figure 1)). The cable pulls horizontally on the box, and a 46.0 kg bag of gravel rests on top of the box. The coefficients of friction between the box and roof are shown. The system is not moving.

Answer:

Moment of a force is the product of the force and the perpendicular distance of force from axis of rotation.

The SI unit of force is newton (N).

Explanation:

Hope it helps you again!

Answer:

answer

transverse waves

Answer:

I think it's c but don't know for sure

Particle arrangement and movement

⇒ In terms of relative energy, gas particles have the most energy, solid particles have the least energy and liquid particles are somewhere in between. (All compared at the same temperature.)

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Answer:

Sorry, This Photo is not clear.

Answer: HOPE THIS HLEP YOU

Explanation:

Answer:

Answer below, hope this helps!

Explanation:

1. Chemical - e

2.Light - b

3. Sound - g

4. Mechanical - f

5. Kinetic - a

6. Potential - d

7. Energy - j

8. Thermal - c

9. Nuclear - i

10. Electrical - h

Answer:

Chemical - e

Light - b

Sound - g

Mechanical - f

Kinetic - a

Potential - d

Energy - j

Thermal - c

Nuclear - i

Electrical - h

Explanation:

From kinematic, the maximum height above ground a projectile of mass 0.79 kg, launched from ground level can achieve is 329 meters approximately.

The parameters given from the question are

mass m = 0.79kg

initial speed U = 80.3 m/s

Maximum height H = ?

The object will be going up under the influence of gravity. Acceleration due to gravity g = -9.8m/[tex]s^{2}[/tex]

At maximum height, final velocity V = 0  

From kinematic formula, the best formula to use is

[tex]V^{2} = U^{2} - 2gH[/tex]

Substitute all the parameters into the equation

0 = [tex]80.3^{2}[/tex] - 2 x 9.8 x H

19.6H = 6448.09

H = 6448.09 / 19.6

H = 328.98 m

Therefore, the maximum height above ground a projectile of mass 0.79 kg, launched from ground level can achieve is 329 meters approximately.

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Answer:

sorry for you

The ratio of the man's moment of inertia in the first case (arms extended) to that in the second case (arms drawn in) is 3.2.

The relationship between the rotational frequency [tex](\(\omega\))[/tex] and moment of inertia (I) is given by the equation:

[tex]\[I_1\omega_1 = I_2\omega_2\][/tex]

where [tex]\(I_1\)[/tex]and [tex]\(I_2\)[/tex] are the moments of inertia in the two cases, and [tex]\(\omega_1\) and \(\omega_2\)[/tex] are the corresponding rotational frequencies.

Let's denote the moment of inertia in the first case (arms extended) as [tex]\(I_1\)[/tex] and in the second case (arms drawn in) as [tex]\(I_2\)[/tex]. The given rotational frequencies are [tex]\(\omega_1 = 0.25 \, \text{rev/s}\) and \(\omega_2 = 0.80 \, \text{rev/s}\)[/tex].

Using the equation [tex]\(I_1\omega_1 = I_2\omega_2\)[/tex], we can rearrange it to solve for the ratio of moments of inertia:

[tex]\[\frac{I_1}{I_2} = \frac{\omega_2}{\omega_1}\][/tex]

Substituting the given values, we have:

[tex]\[\frac{I_1}{I_2} = \frac{0.80 \, \text{rev/s}}{0.25 \, \text{rev/s}}\][/tex]

Simplifying the expression, we get:

[tex]\[\frac{I_1}{I_2} = 3.2\][/tex]

Therefore, the ratio of the man's moment of inertia in the first case (arms extended) to that in the second case (arms drawn in) is 3.2.

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Answer:

The Estes C6-0 engine is a booster stage engine designed for model rocket flight and has to be used with a standard engine. This engine is for flights in rockets weighing less than 4 ounces, including the engines. Each package includes 3 engines, 4 starters and 4 plugs.

Answer:

5460000000 J OR 5460000 KJ

Explanation:

GPE = mgh

21000*10*26000

=5460000000J OR 5460000KJ

Answers

The car's forward motion is opposed by the friction between the road and the tires and by the resistance of the air.

Answer:

B

Explanation:

because when they are in opposite direction we subtract so 10N-10N=0 the second one is in the same direction so we simply add the 2 numbers so 10N+10N=20N the last one is as the same as the first picture we subtract 10N-8N=2N

Answer:

D. An area of low pressure might move more quickly on Tuesday and Wednesday than expected.

Explanation:

I took the test and got it wrong :/

The  average power produced by the soccer player is  710 Watts.

Given the data in the question;

Power; [tex]P =\ ?[/tex]

Power is simply the amount of energy converted or transferred per unit time. It is expressed as:

[tex]Power = \frac{Energy\ converted }{time}[/tex]

We substitute our given values into the equation

[tex]Power = \frac{5100000J}{7200s}\\\\Power = 708.33J/s \\\\Power = 710J/s \ \ \ \ \ [ 2\ Significant\ Figures]\\\\Power = 710W[/tex]

Therefore, the  average power produced by the soccer player is  710 Watts.

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conducts electricity (keeps it running)

Answer:

The material which allow heat and electricity to pass through them are called conductor.

Eg. In solids- copper, silver, gold etc

In liquids The liquid that conduct electricity are solutions of acid bases and salts in water. For example: Solution of sulphuric acid ,hydrochloric acid in water conduct electricity. Vinegar contains acetic acid and lemon juice contain citric acid also conduct electricity.

Explanation:

If you like my answer than please mark me brainliest thanks

Answer:

3h/4

Explanation:

At speed v/2 height will be 3/4 h

Equation that describes the motion of point , bodies , and system of bodies without considering the force that cause them to move is called equation of motion in kinematics

When block is at top of first ramp

u=0 ( block was at rest )

a = g ( acceleration due to gravity

using equation of motion                                                                                                                                                                                                                                                                    

2as = v^2 - u^2

2gh = v^2

Then the block continued and reached a speed of v1 = v/2 on second ramp

now , final velocity = v= v1 =[tex]\sqrt{2gh}[/tex] / 2

u= [tex]\sqrt{2gh\\}[/tex]

s= h1

using equation of motion , we get

2as = v^2 - u^2

2(-g)h1 =( [tex]\sqrt{2gh}[/tex]/2)^2 - [tex]\sqrt{2gh}[/tex]

2(-g)h1 = (g h - 4 g h) / 2

h1 = 3/4 h

At speed v/2 height will be 3/4 h

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Answer:

25.0 cm3

Explanation:

The volume is 25.0 cm3 .

Answer:b

Explanation:

Answer:

The lobster let the claw go. so, B.

Explanation:

i hope this helps.

Answer:

[tex]12.79 m/s^2[/tex]

Explanation:

1. Apply Newton's 2nd law:

[tex]F=ma[/tex]

2. Use the definition of weight to find the mass of the box:

[tex]W=mg=m=\frac{W}{g}[/tex]

3. Solve for acceleration in Newton's 2nd law and substitute for mass:

[tex]a=\frac{F}{\frac{W}{g} }[/tex]

4. Plug in the given values from the question and assume [tex]g=9.81m/s^2[/tex]:

[tex]a=\frac{777N}{\frac{596N}{9.81m/s^2} } } =12.79m/s^2[/tex]

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine

Explanation:

A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine

Answer:



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Join / LoginQuestionIn a lifting machine an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10000 N by a distance of 0.8 m Determine the velocity ratio and mechanical advantage

Determine the velocity ratio and mechanical advantageA

Determine the velocity ratio and mechanical advantageA10 and 35

Determine the velocity ratio and mechanical advantageA10 and 35B

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20Easy

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in App

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by Toppr

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option is

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8m

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEd

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25

Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25the load is 10,000N and effort=500N

MA=effortdloadd

MA=effortdloaddMA=50010000

MA=effortdloaddMA=50010000MA=20

Answer:

I'm pretty sure this is not a complete question. My guess is that you are trying to add/subtract vectors. Vectors have both magnitude and direction, so vector A is pretty clear, but a magnitude of 13 (i'm guessing a resultant) without a direction is weird.

IF 13 is the magnitude of the resultant, vector B added to vector A could have any magnitude 17 ≤ B ≤ 43

It could have any direction of

θ = (225 - 180) ± arcsin(13/30)

θ = 45 ± 25.679...

70.679 ≤ θ ≤ 19.321

components of vector B would be

Bx = |B|cosθ

By = |B|sinθ

My guess is that you are trying to add/subtract vectors. Vectors have both magnitude and direction, so vector A is pretty clear, but a magnitude of 13 (i'm guessing a resultant) without a direction is weird.

IF 13 is the magnitude of the resultant, vector B added to vector A could have any magnitude 17 ≤ B ≤ 43

It could have any direction of

θ = (225 - 180) ± arcsin(13/30)

θ = 45 ± 25.679...

70.679 ≤ θ ≤ 19.321

components of vector B would be

Bx = |B|cosθ

By = |B|sinθ

My guess is that you are trying to add/subtract vectors. Vectors have both magnitude and direction, so vector A is pretty clear, but a magnitude of 13 (i'm guessing a resultant) without a direction is weird. A vector has a magnitude of 30m at an angle of 225 degrees with respect to the positive x-axis and has a magnitude of 13m.

Therefore, My guess is that you are trying to add/subtract vectors. Vectors have both magnitude and direction, so vector A is pretty clear, but a magnitude of 13 (i'm guessing a resultant) without a direction is weird.

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From the relationship between acceleration a and g on an inclined plane, the angle of the slope is 13 degrees

Given that a solid sphere starts from rest and rolls down a slope that is 6.4 m long. The speed at the bottom of the slope is 5.3 m/s, the distance travelled is 6.4 m. That is,

Initial velocity U = 0 ( since it starts from rest)

Final velocity V = 5.3 m/s

distance S = 6.4 m

Let us first calculate its acceleration by using  third equation of motion.

[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS

[tex]5.3^{2}[/tex] = 0 + 2 x 6.4a

28.09 = 12.8a

a = 28.09 / 12.8

a = 2.2 m / [tex]s^{2}[/tex]

To calculate the angle of the slope, let us use the relationship between acceleration a and g on an inclined plane.

acceleration a = gsin∅

substitute all the relevant parameters

2.2 = 9.8 sin∅

sin∅ = 2.2/9.8

sin∅ = 0.224

∅ = [tex]Sin^{-1}[/tex](0.224)

∅ = 12.97 degrees

∅ = 13 degrees (approximately)

Therefore, the angle of the slope is 13 degrees

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Answer:

Correct option is

C

The listener is moving towards the source of sound

The Doppler effect (or the Doppler shift) is the change in frequency or wavelength of a wave (or another periodic event) for an observer moving relative to its source.

So if both listener and source of sound are stationary or are moving with the same velocity that is relative velocity is zero, there won't be any change in frequency.

Thus, in this case, the effect will arise when a listener is moving towards the source of the sound.

Answer:

N1 sin theta1 = N2 sin theta2       Snell's Law

For the refracted ray to be reflected then sin theta2 = 1

N1 sin theta 1 = N2

Also N2 must be less than N1 for complete reflection

sin theta1 = N2/N1

If you are considering air and glass then N2 = 1   (for air)

sin theta1 = 1 / N2    where N2 must be for glass in this case

Answer:

3.9m/s² is the acceleration

The acceleration of the object is 3.9m/s².

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

When you fall off a bridge. The car turning at the corner is an example of acceleration because the direction is changing. The quicker the turns, the greater the acceleration.

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Answer:

relating to or supporting democracy or its principles.

Explanation:

The acceleration due to gravity on the given planet is 8.71 m/s².

The given parameters;

The acceleration due to gravity on the planet is calculated by applying following formula as follows;

[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2 \pi } = \sqrt{\frac{l}{g}} \\\\\frac{T^2}{4\pi ^2} = \frac{l}{g} \\\\g = \frac{4\pi^2 l}{T^2} \\\\g = \frac{4 \times (\pi)^2 \times 0.45}{1.428^2} \\\\g = 8.71 \ m/s^2[/tex]

Thus, the acceleration due to gravity on the given planet is 8.71 m/s².

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