Assume that the population proportion is 0.46. Compute the standard error of the proportion, σp, for sample sizes of 500,000; 1,000,000; 5,000,000; 10,000,000; and 100,000,000. (Round your answers to five decimal places.)sample size of 500,000 __________sample size of 1,000,000_________sample size of 5,000,000_________sample size of 10,000,000_________sample size of 100,000,000 ___________

Answers

Answer 1

Answer:

a) 0.00070

b) 0.00050

c) 0.00022

d) 0.00016

e) 0.00005

Step-by-step explanation:

Standard error for proportion formula

S.E = √P(1 - P)/n

Where P = proportion

n = number of samples

Assume that the population proportion is 0.46. Compute the standard error of the proportion, σp, for sample sizes of a) 500,000

S.E = √P(1 - P)/n

= √0.46 × 0.54/500000

= √ 4.968 ×10^-7

= 0.0007048404

≈ 0.00070

b) 1,000,000

√P(1 - P)/n

= √0.46 × 0.54/1000000

= 0.0004983974

≈ 0.00050

c) 5,000,000

√P(1 - P)/n

= √0.46 × 0.54/5000000

= √ 4.968 ×10^-8

= 0.0002228901

≈ 0.00022

d) 10,000,000

√P(1 - P)/n

= √0.46 × 0.54/10000000

= √2.484 ×10^-8

= 0.0001576071

≈ 0.00016

e) 100,000,000

√P(1 - P)/n

= √0.46 × 0.54/100000000

= √2.484 × 10^-9

= 0.0000498397

= 0.00005


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Step-by-step explanation:

6(x+4)+1 =

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Answers

Answer:

The correct option is  a

Step-by-step explanation:

Generally the null hypothesis is  rejected (that the result is significant ) when the p-value is less that the the level of significance

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Applicants to a psychology department have normally distributed GRE scores with a mean, LaTeX: \muμ, of 544 and a standard deviation, LaTeX: \sigmaÏ, of 103. What percentage of applicants scored between 500 and 700? Round to the nearest percent.A. -24% B. 78% C. 2296 D. 24% E. 5%

Answers

Answer:

The probability is P(500 < X  < 700 ) =  0.60044

Step-by-step explanation:

From the question we are told that

    The mean is  [tex]\mu = 544[/tex]

     The standard deviation is  [tex]\sigma = 103[/tex]

Generally the percentage of applicant that scored between 500 and 700 is mathematically represented as

      [tex]P(500 < X < 700 ) = P(\frac{500 - 544}{103} < \frac{X - \mu }{\sigma } < \frac{700 - 544}{103} )[/tex]

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=>   [tex]P(500 < X < 700 ) = P( Z< 1.5146 ) - P ( Z < -0.4272 )[/tex]

Generally from the z-table, the area under the normal curve to the left corresponding to    1.5146 and     -0.4272  is

  P(  Z<  1.5146 )  =  0.93506

   P ( Z <   -0.4272 ) = 0.33462

So

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=>    P(500 < X  < 700 ) =  0.60044

need help please full question in image

Answers

the answer should be 23.5 hoped this helped :)

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Answers

Answer:

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Answers

Answer:

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Alg I

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Answers

The question is incomplete. The complete question is :

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Answers

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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Trust me!

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Answers

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