Answer:
Explanation:
From the given information;
The first objective is to derive an expression for the execution time in cycles
For an execution time T for the non-pipelined processor;
[tex]T = \dfrac{N \times S}{R}[/tex]
where
N = instruction count
S = average number of clock cycles to fetch & execute an instruction
R = clock rate
From the average number of clock
[tex]S = 1 + \delta _{branch\_penality }[/tex]
where;
[tex]\delta _{branch\_penality }= {Dynamic \ count \times Delay \ Slots}[/tex]
Similarly, we are given that the dynamic count is 20%
∴
The execution time required for all the delayed slots that is filled with NOP instructions can be estimated as:
[tex]\delta _{branch\_penality }=0.20 \times 1.00[/tex]
[tex]\delta _{branch\_penality }=0.20[/tex]
Therefore;
S = 1 + 0.20
S = 1.2
Recall that:
For an execution time T for the non-pipelined processor;
[tex]T = \dfrac{N \times S}{R}[/tex]
[tex]T = \dfrac{N \times 1.2}{R}[/tex]
[tex]T = \dfrac{ 1.2 \ N}{R}[/tex]
To derive another expression that reflects the execution time of 70% delay; we have:
[tex]\delta_{branch\_penality} = 0.20 \times ( 1-0.7)[/tex]
[tex]\delta_{branch\_penality} = 0.20 \times ( 0.3)[/tex]
[tex]\delta_{branch\_penality} = 0.06[/tex]
S = 1 + 0.06
S = 1.06
For an execution time T for the non-pipelined processor;
[tex]T = \dfrac{N \times S}{R}[/tex]
[tex]T = \dfrac{N \times 1.06}{R}[/tex]
[tex]T = \dfrac{ 1.06 \ N}{R}[/tex]
Finally, the compiler's contribution to the increase in speed up percentage for the above two cases is:
[tex]=\begin {pmatrix}\dfrac{T_{all \ delay \ slots }}{T_{70\% \ delay \ slots } } -1 \end {pmatrix} \times 100[/tex]
[tex]= \begin {pmatrix}\dfrac{1.2 }{1.06 } -1 \end {pmatrix} \times 100[/tex]
= (1.1320 - 1) × 100
= 0.1320 × 100
= 13.20%
Therefore, the compiler's contribution to increasing performance as expressed as speed up percentage is 13.20%
Describe the blade design for a wind turbine that you would choose. Why did you choose this design?
Answer: aerofoil type blades
Explanation: they are more difficult to make but offer better performance and higher rotational speeds making them ideal for electrical energy generation.
Under a subsection for geological hazards the buyer is encouraged to obtain an read the booklet
Answer:
Buyer is encouraged to obtain and read the booklet entitled "The Homeowners Guide to Earthquake Safety." In most cases a questionnaire within the booklet must be completed by Seller and the entire booklet given to the Buyer if the Property was built prior to 1960.
The insulator is the connection between the grounded circuit conductor and the equipment grounding conductor at the service.
What problem solving strategies don’t gaurentee solutions but make efficient use of time
A closed system of mass 20 kg undergoes a process in which there is a heat transfer of 1000 Q6: ki from the system to the surroundings. The work done on the system is 200 kl. If the initial 5 specific internal energy of the system is (250+R:) kl/kg, what is the final specific internal energy, in kj/kg? Neglect changes in kinetic and potential energy:
The final specific internal energy : 190 kJ/kg
Further explanationThe laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created
The equation is:
[tex]\tt E_{in}-E_{out}=\Delta E~system\\\\\Delta E=\Delta U+\Delta KE+\Delta PE\\\\\Delta U=m(U_2-U_1)\\\\Q-W=\Delta U+\Delta KE+\Delta PE[/tex]
Energy owned by the system is expressed as internal energy (U)
This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)
The sign rules for heat and work are set as follows:
• The system receives heat, Q +
• The system releases heat, Q -
• The system does work, W -
• the system accepts work, W +
A closed system of mass 20 kg⇒m=20 kg
Heat transfer of 1000 kJ from the system to the surroundings⇒Q=-1000 kJ
The work done on the system is 200 kJ⇒W=+200 kJ
The initial specific internal energy of the system is 250 kJ /kg⇒U₁ = 250 kj/kg
Neglect changes in kinetic and potential energy⇒ΔKE+ΔPE=0, so
Q-W = ΔU
Input in equation
[tex]\tt -1000-200=20(U_2-250)\\\\-1200=20U_2-5000\\\\3800=20U_2\\\\U_2=190~kJ/kg[/tex]
Which color of white light bends the most when it is refracted by a prism? red green yellow orange
The color of white light bends the most when it is refracted by a prism is green after the violet.
Why green bents towards the light?The shorter the wavelength of the mild, the greater its miles refracted. As a result, crimson mild is refracted the least, and violet mild is refracted the most - inflicting the colored mild to unfold out to shape a spectrum.
The hues of white mild withinside the order of lowering wavelength are crimson orange-yellow inexperienced blue indigo violet. Fro the listing we are given withinside the alternatives inexperienced has the shortest wavelength than others. Therefore inexperienced will bend the most.
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Consider a W21x93. Determine the moment capacity of the beam. Assume the compression flange is not laterally braced and that the unbraced length is 15 feet. Assume Cb
Answer:
The answer is "828.75"
Explanation:
Please find the correct question:
For W21x93 BEAM,
[tex]Z_x = 221.00 in^3 \\\\\to \frac{b_t}{2t_f} =4.53\\\\\to \frac{h}{t_w}=32.3[/tex]
For A992 STREL,
[tex]F_y= 50\ ks[/tex]
Check for complete section:
[tex]\to \frac{b_t}{2t_f} =4.53 < \frac{65}{\sqrt{f_y = 9.19}}\\\\\to \frac{h}{t_w} =32.3 < \frac{640}{\sqrt{f_y = 90.5}}[/tex]
Design the strength of beam =[tex]\phi_b Z_x F_y\\\\[/tex]
[tex]=0.9 \times 221 \times 50\\\\=9945 \ in \ \ kips\\\\=\frac{9945}{12}\\\\= 828.75 \ft \ kips \\[/tex]
6. You are an electrician working in an industrial plant. You are building a motor control cabinet that contains six motor starters and six pilot lamps. All control components operate on 120 volts AC. Two of the motor starters have coil currents of 0.1 amperes each and four have coil currents of 0.18 amperes each. The six pilot lamps are rated at 5 watts each. The supply room has control transformers with the following rating (in volt-amperes):
75, 100, 150, 250, 300, and 500.
Which of the available control transformers should you choose to supply the power for all the control components in the cabinet?
Answer:
It's indeed safer to suggest a 150 VA transformer. Following table however is the clarification given.
Explanation:
For 2 motors with 0.1 A, the Power will be:
P = [tex]2\times 120\times 0.1[/tex]
= [tex]24 \ W[/tex]
For 4 motors with 0.18 A, the Power will be:
P = [tex]4\times 120\times 0.18[/tex]
= [tex]86.4 \ W[/tex]
As we know, for 6 pilot lamps, the power is "5 W".
So,
The total power will be:
⇒ P = [tex]24+86.4+5[/tex]
= [tex]115.4 \ W[/tex]
Now,
Consider the power factor to be "0.95"
VA of transformer is:
= [tex]PF\times Power[/tex]
= [tex]115.4\times 0.9[/tex]
= [tex]109.63 \ VA[/tex]
Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.
This question is incomplete, the complete question is;
Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.
The 125-mm-diameter smooth pipe is transporting SAE 10W-30 oil with ρ=920 kg/m3 and µ=0.2 N.s/m2 .
Answer: the greatest pressure drop allowed is 14247 Pascals
Explanation:
LAMINAR FLOW INF PIPE
greatest pressure drop
(P1 - P2) = pressure drop
(P1 - P2) = 32uvl / D²
so (P1 - P2) ∝ V
greatest pressure drop is only at very high velocity
now Re (Reynold Number = svd / u
Re ∝ V
so velocity is high when Re is high
Re = 2000 ( Highest for LAMINAR)
Re = 2000 = svd / u
now in the question we were given that
s = 920 kg/m³, u = 0.2 NS/m², d = 125mm = 0.125m, l = 10m
so we substitute;
2000 = (920 × v × 0.125) / 0.2
v = 3.48 m/s
now pressure drop = (P1 - P2) = 32UVL / d²
we substitute
(P1 - P2) = (32(0.2) (3.48)(10)) / (0.125)²
(P1 - P2) = 14247 Pascals
therefore the greatest pressure drop allowed is 14247 Pascals
Read the following paragraph as quickly as you can, and see if you encounter any diculties.
Aoccdrnig to rscheearch at an Elingsh uinervtisy, it deosn't mttaer in waht oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer is at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit a porbelm. Tihs is bcuseae we do not raed ervey lteter by itslef but the wrod as a wlohe.
This has been presented as an example of a principle of human reading compre-hension. If you keep the rst letter and the last letter of a word in their correct positions, then scramble the letters in between, the word is still quite readable in the context of an accompanying paragraph. However, it seems that this is a bit of a myth and not truly based on solid research.1 In short, for longer words the task is much more dicult. Nonetheless, we are going to imitate the process on some English text.
The task will be to read in a paragraph from a le, scramble the internal letters of each word, and then write the result to a le. Handling punctuation is tricky. You are required to deal with punctuation that comes at the end of a word (period, question mark, exclamation, etc.)|that is, punctuation is left untouched and does not count as the nal unscrambled letter. Optionally, one can deal with the more dicult task of handling all punctuation, such as apostrophes for possessives or hyphenated words. Truly randomizing the order of letters is a task for later in the text, but we can do some reasonable approximations now. Attacking this problem in a divide-and-conquer way should begin by writing code to scramble the letters in a word.
Create a dierent solution by dening scrambling functions for each of the following approaches: (Each approach counts as a dierent problem)
(a) For each letter choose a random number and rotate that letter by the random amount. Import random and use the random.randint(a,b) function where `a' and `b' dene the range of random numbers returned.
(b) Implement a dierent method to scrambling the letters. You must clearly describe in the comments the process to scramble the letters in place.It must be dierent than the process from part a.
Answer:
a
Explanation:
just took the quiz
Why do the changes to the mass of the planet NOT AFFECT the orbital path of the Planet?
Answer:
changes of Mass affect the planet because... I'm sorry If this didn't help.
What are the two most important things to remember when at the end of your interview?
1. When the interviewer asked if you have any questions at the end of the interview don't say no. You should always say yes your interviewer is expecting you to ask a few good questions before ending the interview.
2. Always thank the interviewer for their time and effort to interview you. This would look very good for you and its a nice way to help wrap up the interview.
calculate the magnitude of the force acting on the pin at D. Pin C is fixed in DE and bears against the smooth slot in the triangular plate.
Answer:
hello your question lacks the required diagram attached below is the diagram
answer : 58.47 N
Explanation:
The magnitude of the force acting on the Pin D
Fd = [tex]\sqrt{Dx^2 + Dy^2}[/tex]
= [tex]\sqrt{16.80^2 + 56^2}[/tex]
= 58.465 N
Dx = 16.80 N
Dy = 56 N
hello attached below is the detailed solution
Don't break or crush mercury-containing lamps because mercury powder may be released.
A) TrueB) False
Suppose an underground storage tank has been leaking for many years, contaminating a groundwater and causing a contaminant concentration directly beneath the site of 0.30 mg/L. The contamination is flowing at the rate of 0.5 ft/day toward a public drinking water well 1 mile away. The contaminant degrades with a rate constant of 1.94 x 10^-4 1/day. Draw a picture of the system. Estimate the steady-state pollutant concentration expected at the well. If the slope factor is 0.02 (mg/kg-day)^-1.
Required:
Estimate the cancer risk for an adult male drinking the water for 10 years.
Answer: the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶
Explanation:
firstly, we find the time t required to travel for the contaminant to the well;
Given that, contamination flowing rate = 0.5 ft/day
Distance of well from the site = 1 mile = 5280 ft
so t = 5280 / 0.5 = 10560 days
k is given as 1.94 x 10⁻⁴ 1/day
next we find the Pollutant concentration Ct in the well
Ct = C₀ × e^-( 1.94 x 10⁻⁴ × 10560)
Ct = 0.3 x e^-(kt)
Ct= 0.0386 mg/L
next we determine the chronic daily intake, CDI
CDI = (C x CR x EF x ED) / (BW x AT)
where C is average concentration of the contaminant(0.0368mg/L), CR is contact rate (2L/day), EF is exposure frequency (350days/Year), ED is exposure duration (10 years), BW is average body weight (70kg).
now we substitute
CDI = (0.0368 x 2 x 350 x 10) / ((70x 365) x 70)
= 257.7 / 1788500
= 0.000144 mg/Kg.day
CDI = 1.44 x 10⁻⁴ mg/kg.day
Finally we calculate the cancer risk, R
Slope factor SF is given as 0.02 Kg.day/mg
Risk, R = I x SF
= 1.44 x 10⁻⁴ mg/kg.day x 0.02Kg.day/mg
R = 2.88 × 10⁻⁶
therefore the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶
Timken rates its bearings for 3000 hours at 500 rev/min. Determine the catalog rating for a ball bearing running for 10000 hours at 1800 rev/min with a load of 2.75 kN with a reliability of 90 percent.
Answer:
C₁₀ = 6.3 KN
Explanation:
The catalog rating of a bearing can be found by using the following formula:
C₁₀ = F [Ln/L₀n₀]^1/3
where,
C₁₀ = Catalog Rating = ?
F = Design Load = 2.75 KN
L = Design Life = 1800 rev/min
n = No. of Hours Desired = 10000 h
L₀ = Rating Life = 500 rev/min
n₀ = No. of Hours Rated = 3000 h
Therefore,
C₁₀ = [2.75 KN][(1800 rev/min)(10000 h)/(500 rev/min)(3000 h)]^1/3
C₁₀ = (2.75 KN)(2.289)
C₁₀ = 6.3 KN
What are the differences between separately and shunt DC motor?
Which type of design does not need special care for the placement of dimensions?
Answer:
cubes
Explanation:
Design for software engineering does not need special care for the placement of dimensions. Software engineering generally deals with arranging lines of coding.
What is Software Engineering Design?In order to achieve a software's goal by using lower-level, machine-understandable algorithms and a set of parameters based on project requirements or environmental constraints, software design is the process of outlining solutions, planning, and specifying a method of implementation based on the needs of the user.
Software engineering is the application of engineering principles, which are often employed in the design, development, testing, deployment, and management of physical systems to the design.
Therefore, the main focus of software engineering is organizing coded lines that are kept in a device's or computer's memory rather than in actual physical space.
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Explain why the scenario below fails to illustrate an understanding of the importance of metrology. Situation: Natalie is a calibration technician at a food production plant. Natalie: "The oven is just a couple of degrees off. I will just wait a few hours to see if it will level out on its own"
Answer:
Explanation:
The situation being described completely fails in regard to the importance of metrology. This is because the main importance of metrology is making sure that all of the measurements in a process are as accurate as possible. This accuracy allows an entire process to function efficiently and without errors. In a food production plant, each individual department of the plant relies on the previous function to have completed their job with the correct and accurate instructions so that they can fulfill their functions correctly and end up with a perfect product. If the oven (like in this scenario) is a couple of degrees off it can cause the product to come out burned or undercooked, which will then get transferred to the next part of production which will also fail due to the failed input (burned or undercooked product). This will ultimately lead to an unusable product at the end of the process and money wasted. Which in a large production plant means thousands of products in a single batch are thrown away.
In terms of the necessity of metrology, the situation stated absolutely fails. This is because metrology's primary goal is to ensure that all measurements in a process are as precise as feasible. This precision allows a whole process to run smoothly and error-free. If the oven temperature is wrong by a few degrees, the product will come out charred or undercooked, and the product will be sent to the next step of the process, which will also fail owing to the failed input. This will result in a useless product and a waste of money at the end of the procedure. In a big manufacturing facility, this means thousands of goods are discarded in a single batch.
Match each titration term with its definition.
Process of slowly adding a solution to react with another solution and determine the Choose... concentration of one of the solutions tased on the reaction between them
Solution of an unknown concentration that has another solution slowly added to it Choose...
When the required amount of one solution has been added to the second solution to Choose... complete the reaction
Solution of known concentration that is slowly added to a solution of unknown Choose... concentration
Glassware that allows a solution to be precisely and slowly added to another solution Choose...
A reagent added to the analyte solution that changes color when the reaction is Choose... complete
Answer:
1) titration
2) titrand
3) equivalence point
4) titrant
5) Burette
6) Indicator
Explanation:
The process of adding a known volume a standard solution to another solution to react with it in order to determine the concentration of the unknown solution is known as titration.
The solution to which another solution of known concentration is added is called the titrand while the solution of known concentration is called the titrant.
A burette is a glassware used to slowly add a known volume of the titrant to the titrand. An indicator shows the point when the reaction is complete by a color change. This is the point when the required amount of one solution has been added to the second solution. It is also called the equivalence point.
I. The process of slowly adding a solution to react with another solution and determine the concentration of one of the solutions based on the reaction between them: Titration.
II. A solution of an unknown concentration that has another solution slowly added to it: Analyte.
III. When the required amount of one solution has been added to the second solution to complete the reaction: Endpoint.
IV. A solution of known concentration that is slowly added to a solution of unknown concentration: Titrant.
V. A glassware that allows a solution to be precisely and slowly added to another solution: Burette.
VI. A reagent added to the analyte solution that changes color when the reaction is complete: Indicator.
Titration is also referred to as titrimetry or volumetric analysis and it can be defined as a chemical process in which a solution of known concentration is slowly added to a solution of unknown concentration, in order to determine the concentration or quantity of the analyte (solution of an unknown concentration)
For example, titration can be used to determine the concentration of a basic solution by titrating it with an acid solution of known concentration that is required to neutralize the basic solution.
In Chemistry, the following terms and apparatus are used for the titration of solutions:
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Seth wants to build a wall of bricks. Which equipment will help him in the process?
OA masonry pump
OB. hacksaw
OC. mortar mixer
OD. pressurized cleaning equipment
Answer:
it's B I think
Explanation:
hopefully that helps you
Answer: C
Explanation: A mortar mixer is the equipment that would help Seth in the process of building a wall of bricks. A mortar mixer is used to mix the mortar, which is the binding material used to hold the bricks together. It ensures the mortar is properly mixed to the right consistency for laying the bricks.
Which of the following is considered a bated standard
Answer:
is it multiple choice or....
Using a roof calculator or rafter length guidebook, calculate the theoretical length of the common rafters for a gable roof on a building which is 12’ wide by 36’ long, with a slope of 5/12.
Answer:
35 feet
Explanation:
A steam pipe passes through a chemical plant, where wind passes in cross-flow over the outside of the pipe. The steam is saturated at 17.90 bar and you can assume that the resistances to heat transfer inside the pipe and of the pipe itself are minimal, so that the outside surface temperature of the pipe is equal to the saturation temperature of the steam. The pipe is stainless steel and has an outside diameter of 6.75 cm and a length of 34.7 m. The air flows over the pipe at 7.6 m/s and has a bulk fluid temperature of 27 °C.
A. What is the rate of heat transfer from the pipe to the air?
B. would your answer change if the air flow direction changes to parallel flow? If so, calculate that q as well.
Answer:
a) the rate of heat transfer from the pipe to the air is 23.866 watts
b) YES, the rate of heat transfer changes to 3518.61 watt
Explanation:
Given that:
steam is saturated at 17.90 bar.
the pipe is stainless steel and has an outside diameter of 6.75 cm
length = 34.7 m
Air flows over the pipe at 7.6 m/s
Bulk fluid temperature of 27°C
we know that
hD/k = 0.028 (Re)^0.8 (Pr)^0.33
Outside diameter of pipe = 6.75 cm
length of the pipe = 34.7 m
velocity of air = 7.6 m/s
Cp of air = 1.005 kJ/Kgk
viscosity of air = 1.81 × 10⁻⁵ kg/(m.sec)
thermal conductivity of air = 2.624 × 10⁻⁵ kw/m.k
so as
hD/k = 0.028 (Re)^0.8 (Pr)^0.33
hD/k = 0.028 (Dvp / u)^0.8 (Cpu / k)^0.33
(h × 0.0675 / 2.624 × 10⁻⁵) = (0.028 ([0.0675 × 7.6 × 1.225] / [1.81 ×10⁻⁵])^0.8) (((1.005 × 1.81 × 10⁻⁵) / (2.624 × 10⁻⁵))^0.33))
h = 0.0414 w/m².k
a)
Now to find the rate of heat transfer Q
Q = hAΔT
Q = 0.0414 × (2π × 0.03375 × 34.7) × (105.383 - 27)
Q = 23.866 watts
therefore the rate of heat transfer from the pipe to the air is 23.866 watts
b)
Now the flow direction changes to parallel flow, then
(h × 0.0675 / 2.624 × 10⁻⁵) = (0.028 ([34.7 × 7.6 × 1.225] / [1.81 ×10⁻⁵])^0.8) (((1.005 × 1.81 × 10⁻⁵) / (2.624 × 10⁻⁵))^0.33))
h = 6.1036 w/m².k
so from the steam table, saturated steam at 17.70 bar, temperature of steam will be 105.383°C
so to find the rate of heat transfer Q
Q = hAΔT
Q = 6.1036 × (2π × 0.03375 × 34.7) × (105.383 - 27)
Q = 3518.61 watt
Therefore the rate of heat transfer changes to 3518.61 watt
A spherical ball has 3cm internal diameter and its inner surface temperature is 250˚C and the outer surface temperature is 30˚C. Calculate the outer diameter of the ball if the heat loss from the ball is 1600W and has 2.75W/m.˚C thermal conductivity.
Answer:
The outer diameter of the ball is 6.2138 cm
Explanation:
The formula to apply is ;
Heat loss ,
[tex]Q/t=kA*\frac{( T_1-T_2)}{d}[/tex]
where ;
Q/t=total heat loss from the ball = 1600 w
k=coefficient of heat transmission through the ball= 2.75 W/m.˚C
A=area in m² of the ball with the coefficient of heat transmission
T₁=Hot temperature
T₂=Cold temperatures
d=thickness of the ball
Area of spherical ball using internal diameter, 3cm= 0.03 m will be
Radius = half the diameter = 0.03/2 = 0.015
Area = 4 *π*r²
Area = 4*π*0.015² = 0.002827 m²
Apply the formula for heat loss to get the thickness as:
1600 = {2.75 * 0.002827 *(250-30 ) }/d
1600 =1.711/d
1600d = 1.711
d=1.711/1600 = 0.001069 m
d= 0.1069
Using internal radius and the thickness to get outer radius as;
3 + 0.1069 = 3.1069 cm
Outer diameter will be twice the outer radius
2*3.1069 = 6.2138 cm
Match each titration term with its definition.
Process of slowly adding a solution to react with another solution and determine the Choose... concentration of one of the solutions tased on the reaction between them
Solution of an unknown concentration that has another solution slowly added to it Choose...
When the required amount of one solution has been added to the second solution to Choose... complete the reaction
Solution of known concentration that is slowly added to a solution of unknown Choose... concentration
Glassware that allows a solution to be precisely and slowly added to another solution Choose...
A reagent added to the analyte solution that changes color when the reaction is Choose... complete
Answer:
1) titration
2) titrand
3) equivalence point
4) titrant
5) Burette
6) Indicator
Explanation:
The process in which a known volume of a standard solution is added to another solution so that the standard solution can react with the solution of unknown concentration such that its concentration is determined can be referred to as titration.
The solution which is added to another solution is called the titrant. The titrand is the solution of unknown concentration
A burette is a glassware used to slowly add a known volume of the titrant to the titrand.
The indicator used signals the point when the reaction is complete by a color change. At this point, a stoichiometric amount of titrant has been added to the titrand. This is also referred to as the equivalence point.
Common car loan duration
Answer:
In 2019, the average term length was 69 months for new cars and 65 months for used vehicles. Most car loans are available in 12 month increments, lasting between two and eight years. The most common loan terms are 24, 36, 48, 60, 72, and 84 months, according to Autotrader
Explanation:
Help!!
Which of the following describes the first and foremost guideline in dimensioning?
A. Legibility
B. Measurement
C. Accuracy
D. Sketching
Answer:
it should be accuracy
Explanation:
Answer:
option C
Explanation:
Assume you have a steel beam that is 20 feet long and carries a concentrated load of 500 pounds at a distance of 15 feet from Reaction (R ). Reaction (R ) is pinned 5 feet from the load. What are the values in lbs for R and R ? A. 475 and 25 B. 500 and 00 C. 375 and 125 D. 125 and 375
Answer:
The answer is "Option D".
Explanation:
[tex]\to \epsilon_T= 0\\\\\to R+R_1=500 \ lb \\\\\to \epsilon \ M_{pin} > 0\\\\\to -R \times 20 +(500 \times 5) =0\\\\\to 2500 =20R\\\\\to 20R= 2500\\\\\to R= \frac{2500}{20}\\\\\to R= \frac{250}{2}\\\\\to R= 125 \ lb \\\\\to R_1 =500-125\\[/tex]
[tex]=375 \ lb \\[/tex]
.
Describe a ways car manufacturers try to reduce drag and why.
Answer:
Aerodynamic drag can be reduced by altering the density of the air and the vehicle speed, but these factors are not easily controlled. Instead, to reduce drag, car manufacturers can make the height and width of the front of the car smaller. ... This shape reduces drag and the forces that try to propel the car backwards.
Answer:
Car manufacturers can make the height and width of the front of the car smaller.
Explanation:
The shape reduces drag and the forces it to propel the car backwards.