as the glacier melts, water travels toward the ocean along the geological feature labeled x. when water erodes soil along this feature, the feature will most likely become —

Answers

Answer 1

When water erodes soil along the feature, the feature will most likely become wider.

What does the volcanoes' tectonic behavior imply?

The creation of an island arc by the volcanoes indicates a converging plate boundary. A diverging plate boundary is shown by the line of volcanoes. Two plates clashing results in faulting and magma formation. These tectonic motions result in earthquakes, mountain formation, and volcanism.

How does the water change when a glacier melts?

Temperature increases cause mountain glaciers to melt, changing the water supply. As the glacier melts, more water first moves lower and away from the glacier. The water supply will be diminished as the glacier retreats, and towns, cities, and farms could lose a significant source of water.

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Related Questions

A 5kg block of iron with a specific heat capacity of 450 J/kg °C recieves 0.03 MJ of energy. What is the temperature rise of the iron?

Answers

The temperature rise of the iron is 13.33°C

How to calculate temperature in calorimetry?

Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.

The heat gained or released during a calorimetry procedure can be calculated as follows:

Q = mc∆T

Where;

Q = quantity of heat (J)m = massc = specific heat capacity∆T = change in temperature

According to this question, a 5kg block of iron with a specific heat capacity of 450 J/kg °C recieves 0.03 MJ of energy. The change in temperature can be calculated as follows:

30,000J = 5 × 450 × ∆T

30000 = 2250∆T

∆T = 30000 ÷ 2250

∆T = 13.33°C

Therefore, 13.33°C is the temperature rise.

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PLEASE HELP!

Jadee pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg.

Answers

The acceleration of the luggage across the airport is 0.42 m/s².

What is the acceleration of the luggage?

The acceleration of the luggage across the airport is calculated by applying Newton's second law of motion as follows;

Mathematically, the Newton's second law of motion is given as;

F(net) = ma

where;

F(net) is the net force on the luggagem is the mass of the luggagea is the acceleration of the luggage

F - Ff = ma

where;

F is the applied force on the luggageFf is the force of friction

33.3  - 12.3  = 50a

21 = 50a

a = 21/50

a = 0.42 m/s²

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The complete question is below:

Jadee pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg. find the acceleration of the luggage.

need urgent help with this!!!! ​please provide working

Answers

Answer:

Heat Loss = Heat Gain

(60 - T) K1 M1 = (T - 10) K2 M2

M1 = metal        M2 = liquid

K1 = metal         K2 = liquid

(60 - T) K1 * 1 = (T - 60) K2 * 5

60 K1 - T K1 = 5 T K2 - 300 K2

T (5 K2 + K1) = 300 K2 + 60 K1

T = (300 K2 + 60 K1) / (5 K2 + K1)

Need to find largest T

(probably ethanol and iron - you will need to check)

An object is rolled horizontally off a table. It lands on the floor 1 meter away from the base of the table. The height of the table is 2.5m. What is the initial vertical velocity of the object?

Answers

The initial vertical velocity of the object is 2.5 m/s .

How to calculate intial velocity?

Initial Velocity, denoted as u, is the velocity at time period t = 0. It is the speed at which motion first occurs. There are four equations for starting velocity: (1) The starting velocity is expressed as u = v - at if time, acceleration, and final velocity are given.

Keep in mind that the INITIAL VERTICAL VELOCITY of the projectile is equal to ZERO because it is launched horizontally.

Given,

base  =1m

height = 2.5

vertical velocity =2.5/1

The initial vertical velocity of the object is 2.5 m/s .

A projectile's initial velocity has both a horizontal component and a vertical component if it is thrown at an angle to the horizontal. The projectile's displacement horizontally as a result of velocity is shown by the horizontal velocity component (vx).

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to study problems concerned with the motion of matter under the influence of forces, i.e., dynamics, it is necessary to locate a point called

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The center of mass must be found in order to analyze issues involving the flow of matter when subjected to forces, or dynamics.

Motion: A Simple Definition

Motion is the alteration of a skin's position or orientation over time. The movements of people and animals is just one illustration of how everything in the cosmos is always moving. In addition, the fundamental building block of matter, the atom, is likewise constantly in motion.

Describe a motion example.

Motion is the free flow of a body in relation to time. For instance, the fan, the carpet's dust blowing off of it, the water running from the faucet, a ball rolling about, a moving car, etc. Even just the universe is always changing.

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a. If there is to be no relative motion between the train and the edge of the platform, how fast must
the train move compared to the rim speed of the rotating platform?
b. Why is the stairway located at the center of the platform?

2. The design below shows a train that makes round trips from Station A to Station B in a
continuous loop.

a. How is the size of the round platform and train speed related to the amount of time that
passengers have for boarding?
b. Why would this rotating platform be impractical for high-speed trains?
CONCEPTUAL PHYSICS

Answers

Train must move with equal speed as of platform in opposite direction i order to maintain zero relative velocity.

What is velocity?

Velocity is the speed in which something move in a paticular Direction.

From the question it is given that

relative velocity between platform and train = 0

since relative velocity of train with respect to platform is given by

where,  is the velocity of train and  is the velocity of platform

⇒ vt = vp

since platform is always at stationary i.e.,

thus train velocity  = 0

Therefore, train does not move

If, Platform is moving then train must move with equal speed as of platform in opposite direction.

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What is the kinetic energy of a 1,854.50 kg car that travels at 8.61 m/s?

Answers

Answer:

[tex] \huge{\boxed{68,738.99 \: J}} [/tex]

Explanation:

The kinetic energy of the car can be found by using the formula

[tex] \bold{k = \frac{1}{2} \times m \times {v}^{2} \\ }[/tex]

m is the mass in kg

v is the velocity in m/s

From the question

m = 1854.5 kg

v = 8.61 m/s

[tex]k = \frac{1}{2} \times 1854.5 \times {8.61}^{2} \\ k = 927.25 \times 74.1321 \\ \\ k = 68738.989[/tex]

We have the final answer as

68,738.99 J

1. jupiter has a mass approximately 300 times greater than earth's and a radius about 11 times greater. how will the gravitational acceleration at the surface of jupiter compare to that at the surface of the earth?

Answers

surface gravity formula

[tex]g=\frac{GM}{r^{2} }[/tex]

[tex]g[/tex] is the surface gravity in m/s²

[tex]G[/tex] is the gravitational constant 6.67408x10⁻¹¹ m³/kgs²

[tex]M[/tex]  is the mass of the object in kg

[tex]r[/tex] is the radius of the object in  m

The Earth’s mass is 5.972x10²⁴kg,

Jupiter’s mass is 1.898x10²⁷ kg,

the Earth’s radius is 6371 km,

Jupiter’s radius is 69911 km

Calculation for earth's surface gravity

[tex]g=\frac{6.67408X10^{-11}X5.972X10^{24} }{(6.371X10^{6} )^{2} }[/tex]

[tex]g=9.82 m/s^{2}[/tex]

Calculation for Jupiter's surface gravity

[tex]g=\frac{6.67408X10^{-11}X1.898X10^{27} }{(6.9911X10^{7} )^{2} }[/tex]

[tex]g=25.92 m/s^{2}[/tex]

conclusion

[tex]\frac{25.92}{9.82} = 2.63[/tex]

the surface gravity of Jupiter is 2.63 times that of Earth.

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a floating leaf oscillates up and down three complete cycles in one second as a water wave passes by. the wave's wavelength is 10 meters. what is the wave's speed?

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This water wave passes past while a floating leaf cycles down and up three times in a second. The wave's velocity will be 2 hertz.

What does that mean 2 hertz?

Use this illustration The amount of waves that travel through a fixed location in a specific amount of time is known as frequency. The duration of a wave passing is therefore half a second. If so, the rate is 2 Hertz per second. Four Hertz is the frequency if 240 waves per hour are sent.

What does one Hz represent?

One cycle per second, or hertz, is the SI unit for frequency (Hz). Cycles per second are represented as a hertz.

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Fill in the blanks using the appropriate letters from the bottom.

A mass m is attached to an ideal spring with a spring constant k.
It has a period of [tex]T_{A}[/tex]=1.00 seconds measured in Boston, where g=9.80 [tex]m/s^{2}[/tex].
A simple pendulum of mass m and L has the exact same period [tex]T_{B}[/tex] =1.00s right there.
What will happen to the period of (A) the spring-mass system and (B) the pendulum,
A. when they are both moved to the moon; [tex]T_{A}[/tex]___, [tex]T_{B}[/tex]___

B. when they are both moved to the north pole where g = 9.83 m/s2; [tex]T_{A}[/tex]___
,[tex]T_{B}[/tex] ___
C. or when they are both moved to the equator where g = 9.78 m/s2? [tex]T_{A}[/tex]___
, [tex]T_{B}[/tex] ___


Select from below:
A. Stay the same.
B. Reduce by a factor of 6.
C. Increase by a factor of 6.
D. Reduce by a factor of 2.45.
E. Increase by a factor of 2.45.
F. Reduce by roughly 0.1%
G. Increase by roughly 0.1%

Answers

The force required to extend or compress a spring, divided by the lengthening or shortening of the spring, is known as the spring constant.

If a vertical is coupled to a mass M, when?

A vertical spring with mass M that is attached steadily lowers to its equilibrium position. This causes the spring x to lengthen. Suppose the same thing was still tied to the same vertical spring, but it was allowed to fall suddenly instead.

How can you determine a spring's top speed?

The maximum velocity is equal to the amplitude times the angular frequency, or v max=A v max = A, since the sine function oscillates between -1 and +1. The mass is travelling toward x=+A when the maximum velocity occurs at the equilibrium location (x=0).

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Explain how a convection current can enable a hawk or eagle to soar upward without flapping its wings.

Answers

Answer:hope this helps

pleasee i need the brainliest

Explanation: Warm air rises and is replaced by cooler air from the surrounding area. The warm air eventually cools off, falling down and replacing more warm air. This causes a constant upward flow sometimes called a thermal that allows large birds to soar without effort.

the total magnification achieved using a 10× objective lens with a 10× eyepiece lens is 20×.

Answers

The given statement that 'The total magnification achieved using a 10x objective lens with a 10x eyepiece lens is 20x' is false.

A stereomicroscope is a good option for viewing large and opaque specimens.

The magnification of eyepiece is either 10x or 15x.

The magnification of objective lens can be 10x, 40x or 100x.

The total magnification is nothing but the multiplication of the magnification of eyepiece and the magnification of objective lens.

Given that, magnification of objective lens is 10x

Magnification of eyepiece lens is 10x

So, the total magnification is,

⇒ 10x × 10x = 100x

But the total magnification is given as 20x.

Thus, the given statement is false.

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A 14 kg box is being pushed across a floor with an applied force of 12 N at a constant velocity of 6 m/s. The surface then becomes very rough, and with the same applied force, the box comes to rest in 2 seconds. What is the acceleration of the box while at constant velocity?
*

Answers

acceleration during the constant speed is the  friction acceleration which is 3 ms^-2.

What is accelaration?

Accelaration is the eate of the change of the velocity of an object with respect by time.

Accelaration (a) id the reason that change in velocity over to the change in time.

Represented by the equation to a= ∆v/∆t. This is allowa you to measure how fast velocity by the changes in meters per second squars (m/s^2).

Here mass is 14 KG box

Here friction force applied by the  because of rough place so that it stopped in 2 seconds

So acceleration by friction is negative sense and 6/2 or 3 ms^-2

So static frictional force is = 14×3 or 54 which is greater  than the  applied force

So the acceleration during the constant speed is the  friction acceleration which is 3 ms^-2.

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Insert tab A into slot B" is something you might read in the assembly instructions for pre-fabricated bookshelves. Suppose that tab A varies in size according to a Normal distribution with a mean of 30 mm. And a standard deviation of 0. 5 mm. , and the size of slot B is also Normally distributed, with a mean of 32 mm. And a standard deviation of 0. 8 mm. The two parts are randomly and independently selected for packaging. What is the probability that tab A won’t fit into slot B?

Answers

0.017 is the probability that tab A won’t fit into slot B

What is probability?

Probability is related to possibility. Random event generation is the subject of this branch of mathematics. Values ​​range from 0 to 1. Probabilities are built into mathematics to predict the likelihood of certain events.

P(tab A won't fit into slot B) = P (A>B)

                                                = P( A-B > 0)

Given that, A ≈ N(30,0.5)   B ≈ N(32, 0.8)

Here,

E (A-B) = 30-32 = -2

V(A-B) = V(A) + V(B) = (0.5)² + (0,8)²

                                   = 0.89

SD (A-B) = [tex]\sqrt{0.89}[/tex]

So, (A-B) ≈ N (-2, 0.9433)

P( A-B > 0) = 1 - P(A-B ≤ 0)

= 1 - P [(A - B +2 / 0.9433) ≤ (+2 / 0.9433)]

= 1 - P (Z₁ ≤ 2.12)

= 1 - 0.98300

= 0.017

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when a wave pulse on a string reflects from a boundary, how is the reflected pulse related to the incident pulse

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The reflected pulse will be equal to or less than incident pulse when wave pulse on a string reflects from a boundary.

A rigid wall causes an object, like a ball, to bounce back when it is thrown against it. In terms of momentum and energy conservation, the object's "reflection" can be examined. The ball will bounce back at the same speed if the collision between the ball and the wall is perfectly elastic and all incident energy and momentum is reflected. The ball does not bounce back with the same speed if the collision is inelastic because the wall (or ball) absorbs some of the incident energy and momentum.Additionally carrying energy and momentum, waves are reflected by obstacles whenever they come into contact with them. Echoes, radar detectors, and standing waves—which are crucial for musical instrument sound production—are all caused by waves that have been reflected.

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If only 10% of the energy gets passed to the next tropic level, what happens to the rest of the energy?.

Answers

Answer:

As little as 10 percent of the energy at any trophic level is transferred to the next level; the rest is lost largely through metabolic processes as heat.

Explanation:

Find A mass of 10 kg is moving in a circular path of radius 2 m with a uniform speed of 50 ms the centripetal acceleration and the corresponding centripetal force​

Answers

Answer:

Centripetal acceleration: [tex]1250\; {\rm m\cdot s^{-2}}[/tex].

Resultant force on the object should be [tex]12500\; {\rm N}[/tex].

(Assuming that the speed of the object is [tex]50\; {\rm m\cdot s^{-1}}[/tex].)

Explanation:

For an object that travels along a circle path of radius [tex]r[/tex] at a speed of [tex]v[/tex], (centripetal) acceleration will be [tex]a = (v^{2} / r)[/tex].

In this example, speed is [tex]v = 50\; {\rm m\cdot s^{-1}}[/tex] while the radius of the circular path is [tex]r = 2\; {\rm m}[/tex]. The (centripetal) acceleration of this object will be:

[tex]\begin{aligned}a &= \frac{v^{2}}{r} \\ &= \frac{(50\; {\rm m\cdot s^{-1}})^{2}}{(2\; {\rm m})} \\ &= 1250\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].

For an object of mass [tex]m[/tex], the resultant force to achieve acceleration [tex]a[/tex] is [tex]F(\text{net}) = m\, a[/tex]. In this example, [tex]m = 10\; {\rm kg}[/tex] while [tex]a = 1250\; {\rm m\cdot s^{-2}}[/tex]. The required resultant force will be:

[tex]\begin{aligned}F(\text{net}) &= m\, a \\ &= (10\; {\rm kg})\, (1250\; {\rm m\cdot s^{-2}}) \\ &= 12500\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 12500\; {\rm N} \end{aligned}[/tex].

scouts at a camp shake the rope bridge they have just crossed and observe the wave crests to be 5.45 m apart. if they shake the bridge three times per second, what is the propagation speed of the waves (in m/s)?

Answers

The propagation speed of the waves is v = 1.1009 m/s

What is propagation of wave ?

Waves' progression and transformation through space and time. The article will examine several definitions in addition to the usual one for wave propagation.

There are numerous crests and troughs that sound waves travel over. II Sound waves need a physical medium to travel through. III The movement of particles is thought to be responsible for the propagation of sound waves.

Transverse waves include electromagnetic waves like X-rays, radio waves, and visible light. Electric and magnetic fields moving in a perpendicular direction make up these waves. The best examples of longitudinal waves, which vibrate parallel to the direction of the wave, are sound waves.

The formula is

v = fλ

given distance is 5.45 m

and the number of times the bridge is shaken is 3 times

this implies

v = 3 / 5.45 × 2

v = 1.1009 m/s

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g what best describes the camera motion in the scenes directly prior to the old man's defiant hand gesture?

Answers

The action that best describes the camera motion in the scenes directly prior to the Old Man's Defiant hand gesture is: "Zooming in and out" (Option C)

What are the various types of Camera Motions and why are they important?

Some interesting camera motions are:

Static shot -  The camera is stationary and does not move during the shot. This can create a sense of stability and calm.Panning shot - The camera moves horizontally from left to right or vice versa, following the action or moving to reveal a new part of the scene.Tilt shot  - The camera moves vertically up or down, following the action or revealing a new part of the scene.Tracking shot - The camera moves horizontally, vertically, or diagonally while following the action or a moving object.

Note that the different camera motions described above are important because they allow filmmakers to convey mood and emotion, create visual interest, and guide the audience's attention within a scene.

For example, a static shot can create a sense of calm or stability, while a handheld shot can create a sense of intimacy or instability. A panning shot can follow the action and keep the audience engaged, while a zoom shot can draw attention to a specific part of the scene.

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Full Question:

What best describes the camera motion in the scenes directly prior to the old man's defiant hand gesture?

O Static and secured on a tripod

O Moving chaotically

O Zooming in and out

O Filming at 96 frames a second

disregarding air drag, how fast must you toss a ball straight up in order for it to take 2 seconds to return to the level from which you tossed it?

Answers

The ball should be tossed with speed 10 m/s in order for it to take 2 second to return to the level from which it was tossed.

The Time of flight of projectile motion is defined as the total time taken during ascent and fall to the ground.

Here, time of flight is given 2 seconds. So, Time of ascent is 1 second. Time of ascent is time taken to reach the highest height.

We have to apply the formula

v= u +at

At the maximum height, v =0 m/s.

0 = u - 10×1

So, u = 10 m/s

So, our answer depends on the value of g. If we take the value of g as 9.8, then speed required will be 9.8 m/s

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A carousel with a radius of 4.0 m spins at 7.2 revolutions per minute. What centripetal force would a child with a mass of 45 kg feel when standing 1.0 m from the outer edge of the carousel

Answers

The centripetal force that a child with a mass of 45 kg feel when standing 1.0 m from the outer edge of the carousel is 127.9 N.

What is the centripetal force of the child?

The centripetal force of the child is the inward force that must maintain the circular motion of the child at the given point in the circular axis without falling.

Mathematically, the formula for centripetal force is given as;

Fc = ma

where;

m is the mass of the childa is the centripetal acceleration of the child

The centripetal acceleration of the child is calculated as;

a = v²/r

where;

v is the linear speed of the childr is the radius of the circular path from point of the child

a = (ω²r²) / r

a = ω²r

where;

ω is angular speed of the childr is the distance from the circle center to point of the child = 4 m + 1 m = 5 m

ω = 7.2 rev/min = 7.2 rev/min x 2π rad/rev x 1 min/60s = 0.754 rad/s

Fc = ma

Fc = m(ω²r)

Fc = 45(0.754² x 5)

Fc = 127.9 N

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According to ___ in the nec®, unused knockouts and other openings in electrical boxes and cabinets are required to be closed.

Answers

According to sect 110.12 (A) in the NEC, unused knockouts and other openings in electrical boxes and cabinets are required to be closed.

What do you understand by national electrical code?

A United States standard for the secure installation of electrical wiring and equipment is the National Electrical Code (NEC), also known as NFPA 70. It is a component of the National Fire Protection Association's National Fire Codes series (NFPA). While the NEC does not represents a U.S. law, NEC use is typically mandated by state or municipal legislation, as well as in many jurisdictions outside of the United States. The NEC standardizes and codifies the specifications for secure electrical installations. The "authority having jurisdiction" checks to see if these minimum requirements have been met.

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The mean weight of 500 college students is 70 kg and the standard deviation is 3 kg. Assuming that the weight is normally distributed, students who weigh between 60 kg and 75 kg is 476.

Answers

It is true that when weights is normally distributed, students who weigh between 60 kg and 75 kg is 476.

Mean is the average of given observations and we can calculate mean by dividing sum of observation by the total number of observation.

A standard deviation shows how much data is dispersed in relation to mean. Low deviation indicates that data are clustered and high deviation means data are scattered.

Mean weight is 70 kg and standard deviation is given 3 kg.

α1 = 75 - 70 / 3 = 1.67

α2 = 60- 70/3 = 3.33

So, P( α2- α1) = 0.9375- (1- 0.9666)

                      = 0.9371

The number = 500 ×0.9371

                     = 467

So, the statement is true.

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Which of the following is not a benefit of stressing

a. Poor circulation

b. Increase speed and power

c.Increased flexibility

d. Minimized change injuries

Answers

Poor circulation is not a benefit of stretching.

How many minutes of stretching should a person perform before participating in physical activities?

Stretching for 5 to 10 minutes is probably enough for most activities. It's important, however, to adequately stretch all the muscles you'll be using. Three benefits of stretching before a workout include increased blood flow.

What are the 5 benefits of stretching?

Improve your performance in physical activities.Decrease your risk of injuries.Help your joints move through their full range of motion.Increase muscle blood flow.Enable your muscles to work most effectively.Improve your ability to do daily activities.

Which benefit comes with flexibility?

Activities that lengthen and stretch muscles can help you prevent injuries, back pain, and balance problems. A well-stretched muscle more easily achieves its full range of motion.

Thus, poor circulation is the correct option.

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Calculate the gravitational force between two objects when they are 0.750m
apart. Each object has a mass of 5.00kg.

A- 2.23x10^-8N

B- 3.00x10^-6N

C- 2.22x10^9N

D- 2.96x10^-9N

Answers

I think maybe it’s A but I am not completely sure

The gravitational force of attraction between two objects is 2.964 x 10⁻9 N. So, the correct option is D.

What is meant by gravitational force ?

Gravitational force is defined as the force of attraction experienced by a body due to the gravity of earth.

Here,

Mass of each body,

m₁ = m₂ = 5 kg

Distance between the masses, r = 0.75 m

The equation for gravitational force is given by,

F = Gm₁m₂/r²

where G is the gravitational constant.

Therefore,

F = (6.67 x 10⁻¹¹x 5 x 5)/(0.75)²

F = 166.75 x 10⁻¹¹/0.5625

F = 2.964 x 10⁻9 N

Hence,

The gravitational force of attraction between two objects is 2.964 x 10⁻9 N.

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A 5-ohm resistor is connected to a 1.5 V battery. The 5-ohm resistor is replaced with a smaller resistor. In order to keep the current through the resistor the same, what should be done to the voltage of the battery

(A) Increase it

(B) Decrease it

(C) Keep it the same

Explain why

Answers

Answer:

Below

Explanation:

V = IR

V/R = I  

    Now you can see that if you decrease R, you will need to decrease V to have the same value of I

two straight rods 50-cm long with axes 1.5-mm apart in a current balance carry currents of 15 a each in opposite directions. what mass must be placed on the upper rod to balance the magnetic force of repulsion?

Answers

After doing the equation the total mass is 1.53×10^-3kg .

What is the magnetic force of attraction?

Similar poles or charges will typically repel one another. Thus, the two magnets will push against one another. Repulsion is the name given to a force that causes objects to move apart from one another.

between two or more comparable or similar charges there is a force. Similar charges are attracted to one another. Charges that share a similar appearance separate. Chemical bonding is characterized by repulsive forces.

Create a formula for the magnetic force to equal the normal force, and then enter the necessary values into the expression to obtain the mass.

FN=F

mg=µo I1 I2 L÷2πr

m=µo I1 I2 L÷2πrg

 = 4π×10^-7T-m/A (15A) (15A)(0.50m)÷2π(0.0015m)(9.8m/s²)

= 1413÷0.0923×10^-7

= 1.53×10^-3kg

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what is the angular momentum of a hydrogen atom in (a) a state and (b) a state? give your answers as a multiple of

Answers

According to the given statement [tex]\sqrt{2h}[/tex] and [tex]2\sqrt{3h}[/tex] and is the angular momentum of a hydrogen atom.

What does the word "momentum" mean?

Momentum may be viewed as a body's "power" while it is moving, or the amount of force it can exert on another body. For instance, a slow-moving bowling ball might have the same acceleration as a baseball being thrown fast.

Briefing:

The angular momentum of a hydrogen atom can be defined as:

[tex]L=\sqrt{l(l+1)}h,[/tex]

where l represents the orbital quantum number which defines the subshells s, p, d, f.

The 4p subshell has an orbital quantum number of 1 . This means that the angular momentum according to equation (I) equals to:[tex]L=\sqrt{1(1+1)}h=\sqrt{2h}[/tex]The 5f subshell has an orbital quantum number of 3 . This means that the angular momentum according to equation (I) equals to:[tex]L=\sqrt{3(3+1)}h=\sqrt{12}h=2\sqrt3h[/tex]

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2 The speed-time graph shows the movement of a car.
speed
0
0
T
time
Which feature of the graph represents the distance travelled by the object whilst
moving at a constant speed?
A
area S
B
area S+ area T
C
area T
D the gradient at point X

Answers

Area T represents the distance travelled by the object whilst moving at a constant speed. Option (C) is correct.

What is speed?

The distance an object travels in a unit of time is its speed. Speed is a scalar quantity since it has simply magnitude and no direction. SI unit of speed is meter per second.

Hence, mathematically:

Speed = distance travelled/time interval.

Distance travelled = speed × time interval.

In the given graph, area T represents  constant speed × time interval. Hence, area T is equal to the distance travelled by the object moving at a constant speed.

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A tow truck pulls a 1225 kg car and accelerates at a rate of 3 m/s^2. What
is the force of the tow truck?
F = ma

Answers

Answer:

[tex] \huge{\boxed{3675 \: N}} [/tex]

Explanation:

The force acting on the tow truck can be found by using the formula

[tex] \bold{F = mass × acceleration} [/tex]

From the question

mass = 1225 kg

acceleration= 3 m/s²

F = 1225 × 3 = 3675

We have the final answer as

3675 N
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