if the final acceleration increases by a factor of 11, then the final rotation should be 3.32[tex]w_{1}[/tex] times the initial rotation.
The relation between the centripetal acceleration and rotation speed of the particle is given as
a=rω²
Where ω is the angular speed and r radius of the circle
Now, rearranging the above equation we will get
ω = √[tex]\frac{a}{r}[/tex]
The initial acceleration is given by
a₁ =100g
But then, the acceleration increases by a factor of 11. Which means the final acceleration of the particle is
a₂ = 11 (100g)
= 1100g
The final and initial rotation speeds are related as
[tex]\frac{w1}{w2}[/tex] = √[tex]\frac{a2}{a1}[/tex]
[tex]w_{2}[/tex] = √[tex]\frac{1100g}{100g}[/tex] x [tex]w_{1}[/tex]
[tex]w_{2}[/tex] = 3.32 [tex]w_{1}[/tex]
The final rotation should be 3.32[tex]w_{1}[/tex] times the initial rotation.
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An object is thrown up from the top of a building of height h with an initial velocity v,. The object reaches its maximum height and then returms down to the ground. The velocity of this object when it reaches the maximum height is equal to:
Maximum height of the object is the highest vertical position along its trajectory. The object is flying upwards before reaching the highest point - and it's falling after that point. It means that at the highest point of projectile motion, the vertical velocity is equal to 0 (Vy = 0)
What would be the acceleration of gravity (in m/s2) at the surface of a world with nine times Earth's mass and three times its radius?
Answer:
Explanation:
Given:
M = 9*M₃
R = 3*R₃
g₃ =9.8 m/s²
_______
g - ?
g₃ = G*M₃ / R₃²
g = G*M / R² = G*9·M₃ / (3*R₃)² = G*9·M₃ / (9*R₃²) = G*M₃ / R₃² = g₃
Accelerations are the same
A rocket is fired with an initial velocity of 100m/s at angle of 55degree above the horizontal it expodes on the mountain side 12 second after it's firing what is the x and y coordinates of the rocket relative to it's final point
The coordination of the rocket relative to its firing point is 688.32m and 277.44m.
What is coordination?
The purpose of organizing people or groups so they work together properly.
Sol-
The X and Y coordinates of the rocket relative of firing
As per the given question
Velocity (vi)=100ms-1
Angle=55.0
Time (t)=12
The horizontal range of projectile at X is
X=vxi×t
x=vi×cos×t
Now substituting the required value we get
X=300×cos 55×12
X=100×0.5756×12
X=688.32 m
Now substituting the recauird value
We get
Y= 983.04-705.6
Y=277.44m
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two boxes sit side-by-side on a smooth horizontal surface. the lighter box has a mass of 5.56 kg, the heavier box has a mass of 7.51 kg. calculate the contact force between these boxes when a horizontal force of 5.02 n is applied to the light box.
Answer:
18.09
Explanation:
add all the numbers together
When you drop a .44 kg apple earth exerts a force on it that accelerates it at 9.8 m/s^2 towards the earth's surface. newtons third law, the apple must exert an equal but opposite force on earth. if the mass of earth is 5.98 x 10 ^24 what is the magnitude of the earths acceleration towards the apple
If the mass of earth is 5.98 x 10 ^24 Then magnitude of the earths acceleration towards the apple 6.56 * 10^(-25) m/s²
A key concept in science is the concept of magnitude in physics. The general quantity or distance is referred to as magnitude. When it comes to the elements of movement, we can tie magnitude to an object's size and motion speed.
A particular object's magnitude is determined by its size or quantity. For instance, when it comes to speed, if a car is moving at a quicker rate than a nearby motorcycle, the magnitude of the automobile's speed is greater than the speed of the motorcycle. Although they contain directions as well as magnitude, vector quantities. Vector quantities include things like force, acceleration, speed, velocity, and many others. A vector's absolute value is referred to as its magnitude.
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In 1934, the wind speed on Mt.Washington in New Hampshire reached a record high. Suppose a very sturdy glider is launched in this wind, so that in 45.0 s the glider reaches the speed of the wind. If the glider undergoes a constant acceleration of 2.29 m/s2,what is the wind’s speed? Assume that the glider is initially at rest
The wind's speed at the given constant acceleration is 103.05 m/s.
What is velocity of an object?
The velocity of an object is defined as the rate of change of displacement of the object with time.
Mathematically, the velocity of an object is given as;
v = u + at
where;
a is the acceleration of the objectv is the final velocity of the objectt is time of motion of the objectu is the initial velocity of the objectSince the object started from rest, the initial velocity = 0
v = 0 + (2.29 x 45)
v = 103.05 m/s
Thus, the final velocity of the glider will be greater than his initial velocity moving at the constant acceleration.
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a plane travels 360 km in 3 hours. what is its velocity
The velocity of the plane is 120 km/hr.
How would you define velocity?Velocity is the pace at which an object's location is changing as perceived from a particular point of view and as measured by a certain unit of time (for example, 60 km/h northbound). Velocity is the direction at which an object is traveling. Velocity is a fundamental concept in kinematics, the branch of classical mechanics that deals with the motion of bodies. In order to be defined, the physical vector quantity known as velocity needs to have both a magnitude and a direction. Speed is a coherent derived unit whose quantity is measured in metres per second (m/s or m/s1) in the SI. Speed is the scalar absolute value (magnitude) of velocity (metric system). As opposed to "5 meters per second east," which is a vector, "5 meters per second," for instance, is a scalar.
Distance traveled = 360 km
Time taken = 3 hours
Hence, velocity = 360/3 = 120 kmph
Thus, the velocity of the plane is 120 km/hr.
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if solar radiation is 1190 w/m2 , how many photons strike the leaf every second? assume three significant figures and an average wavelength of 504 nm for solar radiation.
7.15 x 10^17 photons strike the leaf every second if solar radiation is 1190 w/m2 strike .
Solar radiation intensity = 1200 W/m2
= 1200 J/m2 s-1 (1 W = 1 J/s)
Area of leaf = 2.35 cm2
= 2.35 x 10-4 m2 (1 cm2 = 10-4 m2)
Total energy striking leaf per second = intensity x area x time
= 1200 J/m2 s-1 x 2.35 x 10-4 m2 x 1 s
= 0.282 J
Wavelength λ = 504 nm = 504 x 10-9 m (1 nm = 10-9 m)
Energy of 1 photon E = hc/λ
= 6.626 x 10-34 x 2.998 x 108/504 x 10-9
= 3.9414 x 10-19 J
where h is Planck constant and c is speed of light
Number of photons striking leaf per second = total energy/energy of 1 photon
= 0.282/3.9414 x 10-19
= 7.15 x 10^17 photons
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A motor car having a mass of 2 tonnes is being accelerated up a gradient of 1 in 25. At an engine speed of 4 000 rimin the b. P. Is 57 kw the effective tyre radius is 330 mm, the rolling res?stance is 180 n/tonne, and the rear-axle ratio is 4. 4 to 1 assuming a transmission efficiency of 90 % and neglecting air resistance, determine the value of the acceleration at the given speed 262 mls1.
The value of the Acceleration at the given speed of 262 m/s will be 0.245 m / s²
Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second. An object is considered to be accelerating if its velocity is changing; it has acceleration.
Given that:
Mass of car = 2 Tonnes = 2000 kg.
Wheel's power transfer = Efficiency * b.P.
Power = 0.9 * 57000
Therefore, Power = 51300 W
Wheel's angular velocity = (2[tex]\pi[/tex]N / 60) * (1 / rear-axle ratio)
Angular Velocity = (2[tex]\pi[/tex] * 4000) / 60 * (1 / 4.4)
Therefore, Angular Velocity = 95.15 rad / sec
Wheel:
Power = Torque * Angular Velocity
P = F * Tyre Radius * W
⇒ 51300 = F * 0.33 * 95.15
F = 51300 / (0.33 * 95.15)
F = 51300 / 31.4
Therefore, Force = 1633.76 (by the engine)
Resistance:
Rolling Resistance (Fr) = 180 N/tonne * 2 = 360 N
F₁ = 360N
Gradient Resistance:
tanθ = 1 / 25
θ = 2.2906°
Fg = mg * sinθ
Fg = 2000 * 9.84 * sin (2.2906)
Fg = 783.37 N
Acceleration (a):
Net force = Mass * Acceleration
F - (Fr + Fg) = 2000 * a
1633.76 - (360 + 783.37) = 2000 * a
a = 490.39 / 2000
Therefore, Acceleration = 0.245 m / s²
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saturn orbits the sun at more than 50% of the speed of Mars 
true or false????
Answer:
(TRUE) Mars seems to pass the fastest, Jupiter next, and Saturn the slowest. But all exhibit that puzzling quirk--near the point of their celestial course precisely opposite the Sun ("opposition"), their action amongst the stars briefly turns around.
Explanation:
Mars: 24.077 km/s (53,853 miles per
hour), or a period of about 686.93 days.
Answer:is true
Explanation:
I NEED HELP URGENTLY! FOR 20 POINTS!
The law of definite proportion states that any sample of the compound will always have the same percentage of each element by weight or mass.
There are four elements that made up matter: air, water earth, and fire is not the main idea of dalton's atomic theory.
What is the law of definite proportion?The Law of Definite Proportion defines that the elements that composed a chemical compound are generally arranged in a definite mass ratio regardless of preparation.
The composition of compounds will always be the same by mass using the law of definite proportions. Chemical compounds are made of elements that are present at fixed ratios in terms of their mass.
In the nitrogen dioxide molecule (NO₂), Nitrogen and oxygen atoms are always present in a 1:2 ratio.
According to Dalton's atomic theory, all matter consists of atoms. The atoms of the same element have the same mass and the atoms of different have different masses and compounds are made of atoms of more than one element.
Therefore, for question (1) option (C) and for (2) option (C) is correct.
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a stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 40 cm/s. find the rate (in cm2/s) at which the area within the circle is increasing after each of the following.
Area of circular ripple is increasing after 2sec is 6400π cm²/s,
after 3 sec is 9600π cm²/s and after 6 sec is 19200π cm²/s
An individual who throws a pebble into a body of water will likely see a splash and hear the booming plop of the pebble. He might observe a center point where the stone struck the water, with concentric circles spreading outward from it. Other outcomes of the tossed pebble could include frightening a nearby duck that jumps out of the water, hitting another rock and rebounding, or frightening a school of fish as it sinks into the pond. The individual who throws the rock is linked to the pebble, the water, and the duck and fish through his deeds. Through a single, straightforward action, he has sparked change. The ripple effect is the term used to describe this idea in education.
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a crane lifts a 425 kg steel beam vertically a distance of 79.0 m . how much work does the crane do on the beam if the beam accelerates upward at 1.60 m/s2 ? neglect frictional forces.
The crane does increase the kinetic and potential energy of the beam: W=ΔK+ΔU. Potential energy fluctuates with height while kinetic energy changes with speed W=mΔv2/2+mgΔh.
We should figure out v before moving on. We are aware that the beam is moving 95 meters away at an acceleration of 1.8 text m/s/s. Assuming that the acceleration is uniform and that the initial velocity was 0 m/s.
v2f=v2i+2aΔx
v2f=(0 m/s)
2+2(1.8 m/s2)(95 m) (95 m)
v2f=342 m2/s2 (saving one additional sign. for calculations in the future)
vf=18.5 m/s
Now that we are aware of acceleration vf and v, we may proceed to calculate W.
W=mΔv22+mgΔh
W=m(Δv22+gΔh)
W = 425 kg((18.5 m/s)22+(9.81 m/s2)(95 m))+(9.81 m/s2)
W=(425 kg)(171 + 932 m2/s2)
W=(425 kg)(1103 m2/s2)
W=469000 J→4.7×105 J
The crane does make the beam's kinetic and potential energy higher: W=K+U. In contrast to kinetic energy, which changes with speed W=mv2/2+mgh, potential energy varies with height.
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Anya has 115 mangoes lauren has five times the the number of mangoes Anya has they put them together and sold them in the market at $450 to $15 the sold all the mangoes how much money was collected at the end of the sale
$10,350 is the amount of money that has been collected mangoes are sold by Anya and Lauren at $15.
Number of mangoes of Anya's = 115 mangoes
Number of mangoes of Lauren's = 5 × 115 = 575 mangoes
Total number of mangoes = Number of mangoes Anya has + Number of mangoes Lauren has
= 115 + 575
= 690 mangoes
Amount each mango sold = $15
The total amount of money collected = Total number of mangoes × Amount each mango were sold
= 690 × 15
= $10,350
So, therefore, Anya and Lauren sold their total mangoes for $10,350.
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would adding mass to the top of a slope in the form of houses or buildings make the mass more or less likely to slide?
adding mass to the top of a slope in the form of houses or buildings make the mass more likely to slide because the houses add weight to the slope making it more unstable.
When a slope breaks, there is mass waste. When a slope is excessively steep and unstable given the materials and environmental factors at play, it fails. The slope angle and the underlying material's strength are the two main criteria that eventually influence slope stability.
On the Earth's surface, the force of gravity, which contributes to mass wasting, is mostly constant, however there are minor fluctuations based on the height and density of the underlying rock. In the illustration, the force of gravity is seen pulling a rock block on a slope down toward the center of the Earth.
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Pls help with the questions in the photo, any of them will help :)
Answer: The velocity of the bird is 7m/s
Explanation: Since momentum is the total quantity of the motion which is contained in the body.
It is defined as the multiply of mass and velocity of the body
It is given in the question that mass of bird is 2.5 kg and momentum is 17.5 kg/s.
If an element starts off with an activity of 100Bq, and its half life is 10 minutes, what would the activity be after 5 minutes???
The radioactivity of the element after 5 minutes is 75 Bq.
What is radioactivity?Radioactivity is a phenomenon exhibited by radioactive elements or isotopes by emitting energy and subatomic particles spontaneously.
The radioactivity of a radioactive element or isotope in becquerels is denoted by decay per second.
The radioactivity of the isotope in becquerels is calculated as follows;
Bq = decay / time
Half life = 10 min
This implies that after 10 minutes, the activity of the element will be; ¹/₂(100 Bq) = 50 Bq
The given time, 5 minutes is not up to 10 minutes, so the element will not be reduced to 50 Bq.
5 minutes = half of 10 minutes
half of 50 Bq = 25 Bq
So after 5 minutes, the element will decay 25 Bq, and the activity will be 75 Bq.
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adjacent antinodes of a standing wave on a string are 15.0 cmcm apart. a particle at an antinode oscillates in simple harmonic motion with amplitude 0.850 cmcm and period 0.0750 ss. the string lies along the xx-axis and is fixed at xx
D = 15 cm , b) λ = 30.0 cm , c) 0.0850 cm, d) v = 400 cm / s , e) v = 80.43 cm / s , v = -80.43 cm / s, f) D₂= 7.5 cm
Standing waves form when two waves of the same frequency traveling in opposite directions,
A) in the waves the distance of the nodes and antinode is the same since the wavelength is constant
D = 15 cm
B) the wavelength is the distance for which the wave repeats itself, in the case of a standing wave, the distance between two nodes is the lamina of the wavelength.
D = λ / 2
λ= 15 2
λ = 30.0 cm
C) the amplitude of each wave is 0.0850 cm, and the amplitude of the standing wave is double A = 0.17 cm
D) Let's use the speed ratio
v = λ f
f = 1 / T
v = λ / T
v = 30.0 /0.0750
v = 400 cm / s
E) the transverse speeds are the speed of the oscillatory movement
y = A cos (wt)
w = 2π f = 2π / T
w = 2π / 0.0750
w = 83.78 rad / s
y = 0.850 cos (83.78 t)
Speed is
v = dy / dt
v = -A w cost wt
v = - 0.850 83.78 cos (83.78 t)
v = -80.43 cos (83.78 t)
The maximum speed when the cosine values ±1
v = 80.43 cm / s
v = -80.43 cm / s
F) if we draw a drawing, the distance between two nodes is half the wavelength, at the distance between an antinode synod is half this, it occupies a quarter of the wavelength
D₂ = ¼ λ
D₂ = 30.0/4
D₂= 7.5 cm
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Physical science please help me I’m begging
Answer: the displacmen is 2 blocks north
Explanation:
Mr. Mangan is in freefall on Planet Y. His velocity increases from rest to 30 m/s in 1.2 s. If his mass is 86 kg, what is his weight on Planet Y? What is the gravitational field strength on Planet Y?
Explanation:
First, we need to calculate the gravitational field strength g on Planet Y. So, we will use the following e
an aluminum wire having a cross-sectional area equal to 5.10 10-6 m2 carries a current of 7.50 a. the density of aluminum is 2.70 g/cm3. assume each aluminum atom supplies one conduction electron per atom. find the drift speed of the electrons in the wire.
1.29×10^-4 m/s is the drift speed of the electrons in the wire.
volume=molar mass/density= 26.98g/2.7g/cm3 = 9.99 cm3
n=(6.02E23 electron/volume)*(1.00E6 cm3/ 1 m3) = 6.024E28 m3
V= I/neA= 7.50 A/(6.024E28 m3)×(1.60E-19 C)×(5.60E-6 m2))
V= 1.29×10^-4 m/s
Electrons and other subatomic particles constantly migrate in arbitrary ways. When exposed to an electric field, electrons do travel randomly, but they do so slowly in the direction of the applied electric field. The drift velocity refers to the overall speed of these electrons.
M/s is the SI unit for drift velocity. It can also be expressed in m2/ (V.s). The relationship between the electrons' current density and their drift velocity is straightforward. Additionally, when the strength of the electric field grows, the drift velocity and current flowing through the conductor do as well.
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What is the mass of an object that has a weight of 61.1 N?
Answer:
6.23kg
Explanation:
61.1/9.8 = 6.23kg
9.8 is the amount of gravity acting on the object so divide the weight by the gravity to get mass.
An airplane at 70 m/s in the direction 133 degrees counterclockwise from east. What are the east and north components of the plane's velocity?
Answer:
See below
Explanation:
East is 70 cos 133 = -47.7 m/s East
North is 70 sin 133 = 51.2 m/s North
Can you explain for me Colomb's Torsion Balance Experiment
The two experiments that Coulomb's to show the relationship between electrostatic force and that law carries Coulomb's name today to include this relationship as a fundamental component.
Torsion balance is used to study the repulsion and attraction forces of charged particles and found that the strength of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
A bar is suspended from the centre of the torsion balance by a thin fibre. The fibre functions as a flimsy torsion spring.
The torsion balance in Coulomb's experiment was a suspended metal-coated ball attached to one end of an insulating rod.
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what is the correct answer for this ?
Answer: the correct answer is option "C"
Explanation:
Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have four (4) total responses to this question (labeled A, B, C, and D).
Answer:
A) 3 N [south]
B) 0 N
C) 5 N [south]
D) 4 N [east]
Explanation:
A) 5 - 2 = 3
B) equal forces
C) 0 + 5 = 5
D) 7 - 3 = 4
pingus pingus pingus pingus pingus pingus
Answer: pingus
Explanation: pingus
a train slows down as it rounds a sharp horizontal turn, going from 96.0 km/h to 58.0 km/h in the 16.0 s that it takes to round the bend. the radius of the curve is 120 m. compute the acceleration at the moment the train speed reaches 58.0 km/h. assume the train continues to slow down at this time at the same rate.
The acceleration vector will be the vector sum of the tangential and radial acceleration components because the train is changing both its speed and direction.
Since the train is altering both its speed and direction, the vector sum of the tangential and radial acceleration components will represent the acceleration vector.
The radius of curve and the train's speed can be used to calculate the tangential acceleration, while the elapsed time and changing speed can be used to calculate the radial acceleration.
Let's first convert the speed measurements from km/h to m/s:
v I = 90.0 km/h
= (90.0 km/h) (10 3 m/km) (1 hour and 36 minutes)
= 25.0
m/s v f = 50.0 km/h
= (50.0 km/h) (10 3 m/km) (1 hour and 36 minutes)
= 13.9 m/s
Backwards, the tangential acceleration is equal to a t = t v = 15.0s (13.9 m/s 25.0 m/s = 0.741 m/s 2), and the radial acceleration is equal to a r = r v 2.
Consequently, an is equal to 1.48 m/s 2 inward and 29.9 0 backward.
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A metal rod 800mm long is heated from 10°C to 95°C.If it expands by 1.36mm,the linear expansivity of the metal is?
Answer:
2 x 10^(-5)
Explanation:
The linear expansivity α can be calculated using the following equation:
[tex]\Delta L=\alpha\cdot\Delta T\cdot L[/tex]Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:
[tex]\begin{gathered} 1.36=\alpha(95-10)(800) \\ 1.36=\alpha(85)(800) \end{gathered}[/tex]Then, solving for α, we get:
[tex]\begin{gathered} 1.36=\alpha(68000) \\ \frac{1.36}{68000}=\frac{\alpha(68000)}{68000} \\ 2\times10^{-5}=\alpha \end{gathered}[/tex]Therefore, the linear expansivity of the metal is 2 x 10^(-5)
2. A peregrine falcon dives 83 m/s to the South-East at a 30 degree angle. What is the x-axis component (East/West) of its velocity? What is the y-axis component (North/South) of its velocity?
The x - component and the y - component of the falcon will be 71.88 a[x] m/s and 41.5 a[y] m/s respectively.
What are the components of a vector?Any vector (say [V]) can be resolved along the axes of two - dimensional coordinate system such that the vector components along this direction will be -
[x] = VcosФ a[x]
[y] = VsinФ a[y]
Given is peregrine falcon dives 83 m/s to the South-East at a 30° angle.
Now, the x - component of the falcon will be -
[x] = 83 cos (30) = 71.88 a[x] m/s
Similarly, the y - component of the falcon will be -
[y] = 83 sin(30) = 41.5 a[y] m/s
Therefore, the x - component and the y - component of the falcon will be 71.88 a[x] m/s and 41.5 a[y] m/s respectively.
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