Angle Relationship

Use a calculator to find the approximate value of the expression. Round the answer to two decimal places.

The sine of the complimentary angle of 34°

a. -0.52
b. 0.83
c. 0.97
d. -0.66

Please select the best answer from the choices provided

Answer:

LCM of (4800, 1350, 2646) = 2116800

Step-by-step explanation:

Factorización prima de los números:

4800 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5 × 5

1350 = 2 × 3 × 3 × 3 × 5 × 5

2646 = 2 × 3 × 3 × 3 × 7 × 7

MCM (4800, 1350, 2646)

2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 × 5 × 7 × 7

2116800

MCM de (4800, 1350, 2646) = 2116800

Answer:

Mr. Russo takes three minutes less than Mr. Lloyd to pack a case when each works alone.

One day, after Mr. Russo had spent six minutes in packing the case, the boss called him away, and Mr. Lloyd finished packing the case in four more minutes.

How many minutes would it take Mr. Russo alone to pack the case?

:

Let t = time required by Russo alone

then

(t+3) = time required by Lloyd alone

:

Let completed job = 1; (a packed case)

:

Russo + Lloyd = completed job

6%2Ft + 4%2F%28%28t%2B3%29%29 = 1

:

Multiply by t(t+3)

t(t+3)*6%2Ft + t(t+3)*4%2F%28%28t%2B3%29%29 = 1t(t+3)

:

Cancel the denominators, and you have:

6(t+3) + 4t = t^2 + 3t

6t + 18 + 4t = t^2 + 3t

10t + 18 = t^2 + 3t

:

Arrange as a quadratic equation on the right:

0 = t^2 + 3t - 10t - 18

t^2 - 7t - 18 = 0

Factors to

(t-9)(t+2) = 0

:

The positive solution is what we want here:

t = 9 minutes, time required by Russo alone

:

:

Check solution in original shared work equation (Lloyd requires 12 min)

Solution :

Let x be student will be left handed

P = 0.09

Using the normal approximation to binomial distribution,

a). n = 108,

    μ = np = 9.72

    [tex]$\sigma = \sqrt{np(1-p)}$[/tex]

       [tex]$=\sqrt{8.8452}$[/tex]

       = 2.9741

Required probability,

P(x=8) = P(7.5 < x < 8.5)

[tex]$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$[/tex]

[tex]$=P(-0.75 < z < -0.41)$[/tex]

Using z table,

= P(z<-0.41)-P(z<-0.75)

= 0.3409-0.2266

= 0.1143

b). P(x=12) = P(11.5 < x < 12.5)

[tex]$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$[/tex]

[tex]$=P(0.60 < z < 0.94)$[/tex]

Using z table,

= P(z< 0.94)-P(z< 0.60)

= 0.8294 - 0.7257

= 0.1006

Answer:

90 mm^2

Step-by-step explanation:

Divide it in 2 figures

Get the area of the one of 5 * 6 mm = 30mm^2

Then the one of 6 * 10 mm = 60 mm^2

Then just add it up. 90 mm^2

Answer:

80.45 miles

Step-by-step explanation:

Divide and multiply

Answer:

-13 + 4

Step-by-step explanation:

For the sum to be negative, the absolute value of the negative integer has to be 9 more than the positive integer. There are an infinite number of equations, but here is one:

-13 + 4

Answer:

36

Step-by-step explanation:

multiple by the length value by 3

Answer:

with what plz explain the question

Answer:

60%

Step-by-step explanation:

5 hours - 100%

1 hour - 100/5 = 20%

3 hours - 20 x 3 = 60%

wheres the picture

Step-by-step explanation:

john has $3.05 he subtracts $1.18 and is left over with $1.87

first john subtracts the 8 from the five but he cant do that so he takes from the 3 and makes it a 2 he then moves over that ten that he had taken away from the 3 and places it at the 0. Now john needs to move over the 10 on the 0 to the 5 so he can subtract the 8 from the 5. John moves one ten from the nine that had replaced the 0 and gave it to the 5. that 5 is now a 15 because you've added ten to it.  John now subtracts the 8 from the 15 to get 7 . next john subracts the 9 from the 1 in the tens place to get 8. Now john subracts the 1 from the 2 in the hundereds place to get a total sum of $1.87.

or

3.05

-1.18

---------

1.87

Answer:

1288 c m 3

Step-by-step explanation:

To work out volume, you just do the simple calculation of height x width x length. So what we need to do here is 6 x 7.5 x 22.9 =  

1212.5 c m 3  .

The decimal is a 5 so that is rounded up to give the nearest meter hence the answer to the question is  

1288 c m 3  .

Answer:

Heyaa!! My name is Pinky and im here to tell you that the answer is..

Step-by-step explanation:

!!(b)  P( x < 4)  =     ( 5 + 10 + 2 + 9 )  / ( 5 + 10 + 2 + 9 + 33 + 12 + 15 + 3 + 1 ) =  13/45!!

!!(c)  P(x  = 6)  =  15 / (5 + 10 + 2 + 9 + 33 + 12 + 15 + 3 + 1)  =  1/6!!

!!(d) P( x ≥ 5 ) =  (12+ 15 + 3 + 1) /  (5 + 10 + 2 + 9 + 33 + 12 + 15 + 3 + 1) =  7/30!!

Have and Amazing Day now!!

                                                  ~Pinky~

Answer:

[tex]\sigma (y_1-y_2)=39[/tex]

Step-by-step explanation:

From the question we are told that:

Urn 1 :2 Red, 3 Yellow

Urn 2:3 Red, 7 Yellow

Sample 1 [tex]n_1=75\ balls[/tex]

Sample 2 [tex]n_2=100\ balls[/tex]

Generally the Probability of Red ball drawn is mathematically given by

For Urn 1

[tex]P(R)_1=\frac{2}{5}[/tex]

[tex]P(R)_1=0.4[/tex]

For Urn 2

[tex]P(R)_1=\frac{3}{10}[/tex]

[tex]P(R)_1=0.3[/tex]

Generally the equation for Variance of two independent variables [tex]\sigma (y_1-y_2)[/tex] is mathematically given by

 [tex]\sigma (y_1-y_2)=\sigma y_2 +(-1)^2 \sigma(x_1)[/tex]

    Where red balls drawn from both Urn is Modeled

    [tex]Urn_1\ is\ Modeled\ as (n_1=75,p_1=0.4)[/tex]

   [tex]Urn_2\ is\ Modeled\ as\ (n_2=100,p_2=0.3)[/tex]

 [tex]\sigma (y_1-y_2)=n_2 p_2(1_p_2)+n_1*p_1(1-p_1)[/tex]

 [tex]\sigma (y_1-y_2)=100*0.3(1-0.3)+75*0.4(1-0.4)[/tex]

 [tex]\sigma (y_1-y_2)=39[/tex]

Therefore the variance of the random variable defined as the number of red balls is

 [tex]\sigma (y_1-y_2)=39[/tex]

Answer:

c.25-c/4

Step-by-step explanation:

because all the other expressions are suggesting another equation they said Emma made 25 cookies and gave her mom c so that will be 25-c and then she divided it between her four friends so therefore 25-c,c=the amount she gave her mom,it is unknown so 25-c =the amount remaining after she gave her mom divided by 4

Answer: no solution

Step-by-step explanation:

Answer:

10 × 0.5 x = 5x

10 × -2 = - 20

(5x-(-20)) = 5x + 20

-3x + 8x + 20 = 5x + 20

Answer

:A(2,2) _scale factor ½--A'(1,1)

B(4,6)_scale factor ½--B'(2,3)

C(6,2)_scale factor ½--C'(3,1)

is a required coordinate

Answer:

Step-by-step explanation:

Let the first number = x

Let the second number = 8x

Let the third number = x + 100

x + 8x + x + 100 = 480              Combine like terms

10x + 100 = 480                        Subtract 100

      - 100    -100

10x = 380                                   Divide by 10

x = 380/10

x = 38

First number = 38

Second number = 8*38 = 304

The third number = 38 + 100 = 138

Answer:

ω= 0.01 rad/s

Step-by-step explanation:

The given data is question is ,

Firstly let's find the linear speed. Which is

=> v = Circumference/time

=> v = 2πr/180s

=> v = 3.14 × 100ft ./ 90

=> v = 3.48 ft/s ≈ 1m/s

=> v = r[tex]\omega[/tex]

=> [tex]\omega[/tex] = v/r

=> [tex]\omega[/tex] = 1/100

=> [tex]\omega[/tex] = 0.01 rad/s

Step-by-step explanation:

sin 240° = -½√3 = -0.866

_______

Answer:

"0.9999" is the correct solution.

Step-by-step explanation:

The given values in the question are:

Mean,

= 55

Standard deviation,

= 9.1

Now,

⇒ [tex]z=\frac{X-mean}{sd}[/tex]

By putting the values, we get

⇒    [tex]=\frac{90-55}{9.1}[/tex]

⇒    [tex]=\frac{35}{9.1}[/tex]

⇒    [tex]=3.8461[/tex]

hence,

[tex]P(X<90)[/tex]

= [tex]P(Z<3.8461)[/tex]

= [tex]NORMSDIST(3.8461)[/tex]

then the value will be:

= [tex]0.9999[/tex]

9514 1404 393

Answer:

  3/8 pizza

Step-by-step explanation:

If 1/4 of the 4/4 of the pizza was gone, 3/4 remained. When that is split in half, each half is (3/4)(1/2) = 3/8 of the pizza.

Each gets 3/8 of the pizza.

Answer:

∠K ≅ ∠N

Step-by-step explanation:

Since you are given ΔJKL ≅ ΔMNO, you can say the corresponding angles are congruent:

∠J ≅ ∠M

∠K ≅ ∠N

∠L ≅ ∠O

So, the answer is ∠N

Given:

The expression is:

[tex]\dfrac{-10v^5x+6v^5x^4}{2v^3x^2}[/tex]

To find:

The simplified form of the given expression.

Solution:

We have,

[tex]\dfrac{-10v^5x+6v^5x^4}{2v^3x^2}[/tex]

It can be written as:

[tex]=\dfrac{-10v^5x}{2v^3x^2}+\dfrac{6v^5x^4}{2v^3x^2}[/tex]

Cancel out the common factors.

[tex]=\dfrac{-5v^2}{x}+3v^2x^2[/tex]

Therefore, the simplified form of the given expression is [tex]\dfrac{-5v^2}{x}+3v^2x^2[/tex].

Answer:

0.209 x 12 is that answer but their really is no answer because i have tried about every way i can think of to get the answer so yeah sorry

Step-by-step explanation:

brainliest pls

Answer:

The calculated value of t= -0.21 does not lie in the critical region t= ± 2.120 Therefore we accept our null hypothesis that there's no difference between strength (psi) of liner specimens when a certain fusion process was used and when this process was not used at the 0.05 significance level

Step-by-step explanation:

The given data is

No Fusion :: 2748 2700 2655 2822 2511 3149 3257 3213 3220 2753

Yes Fusion :: 3027 3356 3359 3297 3125 2910 2889 2902

The calculated Means are

x1`= 2902.8

X2`= 3108.125

The standard deviations are

s1= 277.265

s2= 205.87

We are using Student's t- test

We formulate null and alternate hypotheses are

H0 : u1 - u2= 0 against Ha: u1 - u 2≠0

The Significance level alpha is chosen to be ∝ = 0.05

The critical region t  ≥ t (0.025, 16) = ± 2.120

Degrees of freedom is calculated df = υ= n1+n2- 2= 10+8-2= 16

Here the difference between the sample means is x`1- x`2

=2902.8-3108.125

= -205.325

The pooled estimate for the common variance σ² is

Sp² = (n1-1) s1² + (n2-1) s2²/ n1+n2-2

=  9( 277.265)² + 7(3108.125)²/ 16

Sp² = 691,882.922+67,623,087.109/16

Sp= 2066.321

The test statistic is

t = (x`1- x` ) /. Sp √1/n1 + 1/n2

t= -205.325/ 2066.321 √1/10+ 1/8

t= -205.325/980.142

t= -0.2095= -0.21

Conclusion

The calculated value of t= -0.21 does not lie in the critical region t= ± 2.120 Therefore we accept our null hypothesis that there's no difference between strength (psi) of liner specimens when a certain fusion process was used and when this process was not used at the 0.05 significance level

Answer:

c.prism is not solid figure

Answer:

rectangle

Step-by-step explanation:

rectangle isn't a solid figure