A(n) ____________ stretch is one done where antagonist muscles are used to stretch the muscles. But the _____________ stretch is one that is done that the muscle needs help from something or someone to stretch the muscle.

Answers

Answer 1

Answer: Dynamic - Static Flexibility

Explanation:


Related Questions

Four measurements of the file card's width are made. Of the measurements given below, the LEAST precise.
O 7.62
O 7.63
O 7.34
O 7.6

Answers

7.6 is the least precise

a force of 50 newtons pulls a rope attached to a 150 newton sled across a horizontal surface at a constant velocity of 5 meters per second. The rope is at an angle of 35 degrees above the horizontal. calculate the magnitude of the frictional force acting on the sled? Show all work, including the equation and substitution with units.

Answers

Answer:

I don't know the answer I hope you find it tho good luck##

A shopper in a supermarket pushes a loaded 32 kg cart with a horizontal force of 12 N.
a) How far will the cart move in 3.5 s, staring from rest? (Disregard any friction)
b) How far will the cart move in 3.5 s if the shopper places an 85 N child in the cart before pushing?

Answers

Answer: A

Explanation:

A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the following forces does only negative work on the crate?

Answers

Answer:Fn

Explanation:

why is physics to study the heat absorbed by the ocean​

Answers

Answer:

Heat is a source of energy

Explanation:

Just took the test

A 5-kg object is sliding to the right and encountering a friction force that slows it down. The coefficient of friction (μ) between the object and the surface is 0.1. What is the acceleration of the object? Note: There is no applied force here.

Answers

Answer:

The friction force is 4.9 N

[tex]a = 0.98\ m/s^2[/tex]

Explanation:

Friction Force

When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration or speed because the friction force opposes motion.

The friction force when an object moves on a horizontal surface is calculated by:

[tex]Fr=\mu N[/tex]

Where [tex]\mu[/tex] is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

Thus, the friction force is:

[tex]Fr=\mu W[/tex]

The object has a mass of m=5 Kg, calculate the weight:

W = 5 * 9.8 = 49 N

It encounters a friction force that slows it down. We are given the coefficient of friction μ = 0.1, thus the friction force is:

Fr=0.1 49 N = 4.9 N

The friction force is 4.9 N

Since the only force acting on the object is the friction force, thus the net force is F = 4.9 N, and the acceleration can be calculated by using the equation of Newton's second law:

F = m.a

Solving for a:

[tex]\displaystyle a = \frac{F}{m}[/tex]

[tex]\displaystyle a = \frac{4.9}{5}[/tex]

[tex]\mathbf{a = 0.98\ m/s^2}[/tex]

how much force would be needed to move a 100 kg object at the acceleration rate of 2 m/s

Answers

Answer: 200 N

Hope this helps! :)

Can u anser 5,6 on the picture

Answers

Answer: Number 6 is Periods

Explanation:

An object that falls and accelerates solely as a result of gravity is said to be in
(2 points)
A. terminal velocity
B. free fall
C. air resistance
D. terminal acceleration

Answers

I think the answer is c

A shopper in a supermarket pushes a cart with a force of 35 N directed parallel to the ground. Find the work done by the shopper on the cart as the shopper moves along a 50.0 m length of aisle.

Answers

Answer:

W = 1750 N

Explanation:

Given that,

A shopper in a supermarket pushes a cart with a force of 35 N directed parallel to the ground.

We need to find the work done by the shopper on the cart as the shopper moves along a 50.0 m length.

Let W is the work done. As the force is parallel to the ground, angle between force and distance is 0 degrees.

W = Fd

W = 35 N × 50 m

= 1750 N

So, the work done by the shopper on the cart is 1750 N.

A student releases a marble from the top of a ramp and the marble increases speed steadily and travels 190 cm in 4.10 s what's the marbles final speed

Answers

Answer:

The value is  [tex]v = 92.68 \ cm/s[/tex]

Explanation:

From the question we are told that

     The distance traveled is [tex]d = 190 \ cm = 1.9 \ m[/tex]

     The  time taken is  [tex]t = 4.10 \ s[/tex]

Generally from kinematic equation we have that

      [tex]s = ut + \frac{1}{2} at^2[/tex]

Here u is the initial velocity of the marble and the value is [tex]u = 0 \ m/s[/tex]

So

      [tex]1.90 = 0* t + \frac{1}{2} a (4.10 )^2[/tex]

=>   [tex]1.90 = 0* t + \frac{1}{2} a (4.10 )^2[/tex]

=>    [tex]a = 0.226 \ m/s^2[/tex]

Generally from kinematic equations we have that

     [tex]v = u + at[/tex]

=>   [tex]v = 0 +0.226 * 4.10[/tex]

=>   [tex]v =0.9268 \ m/s[/tex]

Converting to  cm/s

=>    [tex]v =0.9268 * 100[/tex]

=>    [tex]v = 92.68 \ cm/s[/tex]

Question 6 of 15
6
The rate at which work is done is called power.
O A True
O B. False

I believe it’s true?

Answers

Answer: A) True, you are correct

==================================================

Explanation:

Power in physics is defined as

power = (change in work)/(change in time)

which shows that power is basically the rate of work done. We can think of it like a speed of sorts.

------------

For example, if you apply 100 joules of work over 2 seconds, then,

power = (100 joules)/(2 seconds)

power = (100/2) joules per second

power = 50 watts

A watt is defined to be a joule per second, and it's often used to measure how much electricity is consumed, but it has broader uses in physics as well.

There is an accident up the road from your car. You see other cars ahead of you. Who will stop first?

A fully-loaded big rig truck

An empty truck

A midsized van

A small car

Answers

Answer:

According to the 2010 U.S. Census, there are approximately 8 million people living in Virginia. This is 2.8 million less than 4 times the population of Nevada.

What is the population of Nevada?

The first step is to  on both sides.

The second step is to  on both sides.

The population of Nevada is  million.

Explanation:

a small car!! hope this helps

A train going 14m/s moves 250 m while accelerating to a stop. What is the train’s deceleration?

Answers

Answer:

-0.056 is the deceleration

how many teeth shows signs of decay?​

Answers

Answer:

what do you mean

Explanation:

which number is larger value : 5.6*10^23 or 8.9*10^6

Need Help

Answers

Answer:

5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps

Explanation:

If 200 ml of a gas at 27 degrees celsius is cooled to -33 degrees Celsius at a constant pressure , the volume will be
A 250ml
B 204ml
C 196ml
D 160ml

Answers

Given that,

Volume of gas, V₁ = 200 mL

Initial temperature, T₁ = 27°C

Final temperature, T₂ = -33°C

To find,

New volume of the gas.

Solution,

Initial temperature, T₁ = 27°C = 300 K

Final temperature, T₂ = -33°C = 240 K

Let V₂ is the new volume.

The relation between volume and temperature is given by :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\=\dfrac{200\times 240}{300}\\\\=160\ mL[/tex]

Hence, the volume will be 160 mL.

Help i will do anything for this. its a serious grade

Answers

Answer: 10 has more potential energy because its longer

1 has less potential energy because its shorter

Explanation:

Potential energy directly depends on height of body as

[tex]\\ \sf\longmapsto P.E=mgh[/tex]

[tex]\\ \sf\longmapsto P\propto h[/tex]

Higher the height higher the potential energy

Object at height 10m has more potential energy.

tenses of
write=
read=

Answers

Answer:

present

Explanation:

read doesn't change but write is in present tense

3) A school bus traveling at 12 m/s has a momentum of 144,000 kg.m/s.
What is the mass of the bus?

Answers

Answer:

does this have picture so I can solve

The mass is 12,000

144,000 divided by 12 = 12,000

Momentum = mass × velocity

Brainliest would be appreciated. :)

Explain why different types of musical instruments sound different, even though they play the same notes.

Answers

each musical instrument is build differently which allows it to portray a different sound kinda like humans with their voices

A billiard ball moving at 5 m/s strikes another ball which is initially at rest. After the collision, the first ball moves at a velocity of 4.35 m/s at an angle of 30o below its original motion. Find the velocity and angle of the second ball after the collision. Assume that the collision is perfectly elastic.

Answers

Answer:

The velocity of the second ball is approximately 2.588 m/s

The angle direction of the second ball is 75° counterclockwise from the horizontal

Explanation:

The initial velocity of the first billiard ball = 5 m/s

The initial velocity of the billiard ball the first billiard ball strikes = 0 m/s

The final velocity of the first billiard ball = 4.35 m/s

The final direction of motion of the first billiard ball = 30° below its original motion

For perfectly elastic collision, whereby the target is at rest initially, by conservation of momentum, we have;

m₁ × [tex]\underset{v_1}{\rightarrow}[/tex] = m₁·[tex]\underset{v'_1}{\rightarrow}[/tex] + m₂·[tex]\underset{v'_2}{\rightarrow}[/tex]

Which gives;

m₁ × 5·i = m₁·((√3)/2×5·i - 2.5·j) + m₂·[tex]\underset{v'_2}{\rightarrow}[/tex]

∴ m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁ × 5·i - m₁·((√3)/2×5·i - 2.5·j)

m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁ × 5·(1 - √3/2)·i + m₁·2.5·j = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

Therefore, given that the mass of both billiard balls are equal, we have, m₁ = m₂, which gives;

m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁·[tex]\underset{v'_2}{\rightarrow}[/tex]  = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

∴ [tex]\underset{v'_2}{\rightarrow}[/tex] = 2.5·(2 - √3)·i + 2.5·j

The magnitude of the velocity of the second ball is [tex]\underset{v'_2}{\rightarrow}[/tex] = √((2.5·(2 - √3))² + 2.5²) ≈ 2.588 m/s

The direction of the second ball, θ = arctan(2.5/((2.5·(2 - √3))) = 75° counterclockwise from the horizontal.

A skier skids to a stop at the bottom of a mountain.
What is the equal and opposite force for the force of the skier's friction pushing on the mountain as
described by Newton's third law?

Answers

Answer:

Friction of the mountain on the skier in the opposite direction

Explanation:

answered it on khan academy

Friction of the mountain on the skier in the opposite direction.

What is Newton's  third law?

A force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions.

Forces result from contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces) and other forces are the result of action-at-a-distance interactions (gravitational, electrical, and magnetic forces).

There are two forces resulting from this interaction - a force on the chair and a force on your body. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

Therefore, Friction of the mountain on the skier in the opposite direction.

To learn more about Friction, refer to the link:

https://brainly.com/question/13000653

#SPJ6

where is the centre of mass of a system of two particles is situated?​

Answers

Answer:

In a two particle system, the center of mass lies on the center of the line joining the two particles.

an object has an mass of 15 kg and is falling at a rate of 2.0 m/s what is the momentum?

Answers

Answer:

30 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 15 × 2

We have the final answer as

30 kg.m/s

Hope this helps you

What disease did Isaac Newton barely escape?

Answers

Answer:

the great plague

Explanation:

4. Bob creates his personal profile collage by drawing his favorite things. This is his ___________.

A. artistic self
B. social self
C. professional self
D. private self

Answers

Artistic self because it says by drawing his favorite things hope this helps
A. Kdkdjdhshshdhdhdhd

a snowball thrown at an ice cream truck at Valley Forge in January sticks to the side. Into what form of energy was the mechanical energy changed

Answers

Answer:

Thermal Energy

Explanation:

I majored in Physics

When a snowball thrown at an ice cream truck at Valley Forge in January sticks to the side, the mechanical energy was  changed into thermal energy.

What is law of conservation of energy?

Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.

The law of energy conservation is adhered to by all energy forms. The law of conservation of energy essentially says that all energy is conserved in closed systems, or systems that are isolated from their surroundings.

When a snowball thrown at an ice cream truck at Valley Forge in January, the mechanical energy was  changed into thermal energy and the edges of the ice melts and again due to temperature of the surrounding they freezes together and the snowball sticks to the side.

Learn more about energy here:

https://brainly.com/question/1932868

#SPJ6

can you answer the b. thanks

Answers

Answer:

current going into a junction in a circuit is EQUAL TO the current comming out of the junction.

Explanation:

Krichhoff's Current Law

Kirchhoff's current law (1st Law) states that current flowing into a node (or a junction) must be equal to current flowing out of it.

If it requires E joules of energy to raise a mass from the surface of the Earth to an altitude of 6,000 km above the Earth, how much energy is required to raise it from the surface to an altitude of 12,000 km?​

Answers

Answer:

To raise the mass to an altitude of 12,000 Km 2E joules are required.

Explanation:

Gravitational Potential Energy

It's the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where:

m = mass of the object

h  = height with respect to a fixed reference

g  = acceleration of gravity, or [tex]9.8 m/s^2[/tex].

If a mass has a height h1, its potential energy is

[tex]U_1=m.g.h_1[/tex]

If a mass has a height h2, its potential energy is

[tex]U_2=m.g.h_2[/tex]

The ratio of both potential energies is:

[tex]\displaystyle \frac{U_2}{U_1}=\frac{m.g.h_2}{m.g.h_1}[/tex]

Simplifying:

[tex]\displaystyle \frac{U_2}{U_1}=\frac{h_2}{h_1}[/tex]

Solving for U2:

[tex]\displaystyle U_2=U_1.\frac{h_2}{h_1}[/tex]

Since U1=E:

[tex]\displaystyle U_2=E.\frac{12,000~Km}{6,000~Km}[/tex]

[tex]U_2 = 2E[/tex]

To raise the mass to an altitude of 12,000 Km 2E joules are required.

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