a) The probability that a customer waits less than a second for credit card approval is approximately 0.498.
b) The probability that a customer waits more than 3 seconds for credit card approval is approximately 0.049.
c) The minimum approval time for the slowest 5% of transactions is approximately 2.545 seconds.
How to find probability and minimum time?a) To find the probability that a customer waits less than a second for credit card approval, we can use the exponential density function. The exponential distribution is characterized by a single parameter, which is the average (or mean) waiting time.
In this case, the average waiting time for credit card approval is 1.5 seconds. Let's denote this parameter as λ (lambda), where λ = 1 / average.
λ = 1 / 1.5 = 0.6667 (approximately)
The exponential density function is given by:
f(x) = λ * e^(-λx)
To find the probability that a customer waits less than a second (x < 1), we need to integrate the density function from 0 to 1:
P(x < 1) = ∫[0, 1] λ * e^(-λx) dx
Solving this integral, we get:
P(x < 1) = 1 - e^(-λx) = 1 - e^(-0.6667 * 1) ≈ 0.498
Therefore, the probability that a customer waits less than a second for credit card approval is approximately 0.498.
b) To find the probability that a customer waits more than 3 seconds, we can again use the exponential density function.
P(x > 3) = 1 - P(x < 3)
Using the same value of λ (0.6667), we can calculate:
P(x > 3) = 1 - (1 - e^(-0.6667 * 3)) ≈ 0.049
Therefore, the probability that a customer waits more than 3 seconds for credit card approval is approximately 0.049.
c) To find the minimum approval time for the slowest 5% of transactions, we need to find the corresponding value of x.
We can use the quantile function of the exponential distribution. For the slowest 5% of transactions, the quantile is denoted as q, where P(x < q) = 0.05.
q = -ln(1 - 0.05) / λ ≈ -ln(0.95) / 0.6667 ≈ 2.545
Therefore, the minimum approval time for the slowest 5% of transactions is approximately 2.545 seconds.
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Part A is already answered
Part B asks: What is the length of the hypotenuse?
Answer:
52
Step-by-step explanation:
Using the Pythagorean theorem
a^2+b^2 = c^2
20^2 + 48^2 = c^2
400 +2304=c^2
2704=c^2
Taking the square root of each side
sqrt(2704) = sqrt(c^2)
52 = c
Answer:
[tex]hypotenuse^{2}[/tex] = [tex]altitude^{2}[/tex] + [tex]base^{2}[/tex]
[tex]hyp^{2}[/tex] = [tex]48^{2}[/tex] + [tex]20^{2}[/tex]
= 2304 + 400
= 2704
∴[tex]hyp[/tex] = [tex]\sqrt{2704}[/tex]
= 52
hope this answer helps you....
solve the system of substitution y=-2x y=5x-21
Answer:
x = 3 is the answerStep-by-step explanation:
1. Write the equation.
y = -2x
y = 5x - 21
2. Substitute the values.
(-2x) = 5x - 21
3. Solve the equation.
-2x = 5x - 21
-5x - 5x
-7x = -21
4. Both negatives cancel
7x = 21
5. Divide both sides by 7
7x = 21
/7 /7
6. x = 3
7. Check the answer.
-2(3) = 5(3) - 21
-6 = 15 - 21
-6 = -6
x = 3 is the answerHope this helped,
Kavitha
P.S Sorry for taking so long.
What is the solution to the system of
equations graphed below?
a.(-13,-20)
b.(-15,-22)
c.(-1,-8)
d.(-10,-15)
Answer:
(-13,-20)
Step-by-step explanation:
We know that the graph with x-intercept at (7,0) and y-intercept at (0,-7) is y = x-7
and the second equation is y = 2x+6
Therefore, we have two equations.
[tex] \large{ \begin{cases} y = x - 7 \\ y = 2x + 6 \end{cases}}[/tex]
Because both equations are equal (y=y)
x-7=2x+6
-7-6=2x-x
-13=x
We know the value of x, but not y-value. We substitute the value of x to get the value of y.
Substitute in any given equations which I will be substituting in the first equation.
y=-13-7
y = -20
Therefore when x = -13, y = -20
In coordinate form, we can write as (-13,-20).
If you have any questions, feel free to ask.
A box contains 12 cereal bars. The empty box weighs 1.75 oz. The box and cereal bars together weighs 18.55 oz. How much does each cereal bar weigh?
Answer:
Each cereal bar weighs 16.8 oz
Step-by-step explanation:
Multiply 12 times 1.4 to get 16.8
Add 16.8 and 1.75 to get 18.55
Hope this helps! Pls mark brainliest
evaluate sum in closed form
f(x) = sin x + 1/3 sin 2x + 1/5 sin 3x + ....
The sum of given series is infinity ∑(n = 1) sin(nx)/(2n - 1).
What is sum of series?
A series' sum is the sum of the words or list of numbers that make up the series. If a series has a sum, it will be one integer (or fraction), such as 0, 1/2, or 99.
As given series is,
f(x) = sinx + sin(2x)/3 + sin(3x)/5+.....
The series function is trigonometric function such as sinx, sin(2x), sin(3x).
The nth term of series is sin(nx).
The coefficient of series is 1, 1/3, 1/5.
The coefficient of nth terms is 1/(2n - 1).
Sum of series is,
= infinity ∑(n = 1) sin(nx)/(2n - 1).
Hence, the sum of given series is infinity ∑(n = 1) sin(nx)/(2n - 1).
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a lamina occupies the part of the disk 2 2≤16 in the first quadrant and the density at each point is given by the function (,)=3(2 2).
A lamina occupies the region of a disk in the first quadrant where 2 ≤ r ≤ 16, and the density at each point is given by the function ρ(r, θ) = 3[tex](r^2).[/tex] Further analysis is required to determine the mass and other properties of the lamina.
The given information describes a lamina occupying a region in the first quadrant of a disk. The radial distance from the origin is limited to the range 2 ≤ r ≤ 16. The density of the lamina at any point within this region is determined by the function ρ(r, θ) = 3[tex](r^2)[/tex], where r represents the radial distance and θ represents the angle in the polar coordinate system.
To fully analyze the lamina, additional calculations are necessary. One important calculation is determining the mass of the lamina, which involves integrating the density function over the given region. By integrating the function ρ(r, θ) = 3[tex](r^2)[/tex] over the appropriate range of r and θ, we can find the total mass of the lamina. Additionally, other properties such as the center of mass or moment of inertia of the lamina could be determined by using appropriate formulas and integration techniques.
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As a preliminary helper result, show by induction that for events E1, E2,..., EM, M P(E, or E2 or ... ог Ем) < Р(Еm). m=1
By applying the principle of inclusion-exclusion, we can show that for any events E1, E2,..., EM, the inequality P(E1 or E2 or ... or EM) < P(EM) holds. This result holds true for any integer M ≥ 1.
To prove the statement by induction, we will assume that for M = 1, the inequality holds true. Then we will show that if the statement holds for M, it also holds for M + 1.
Base case (M = 1):
For M = 1, we have P(E1) ≤ P(E1), which is true.
Inductive step:
Assuming that the inequality holds for M, we need to show that it holds for M + 1. That is, we need to prove P(E1 or E2 or ... or EM or EM+1) < P(EM+1).
Using the principle of inclusion-exclusion, we can express the probability of the union of events as follows: P(E1 or E2 or ... or EM or EM+1) = P(E1 or E2 or ... or EM) + P(EM+1) - P((E1 or E2 or ... or EM) and EM+1). Since events E1, E2, ..., EM, and EM+1 are mutually exclusive, the last term on the right-hand side becomes zero: P(E1 or E2 or ... or EM or EM+1) = P(E1 or E2 or ... or EM) + P(EM+1)
Since we assumed that P(E1 or E2 or ... or EM) < P(EM), we can rewrite the inequality as: P(E1 or E2 or ... or EM or EM+1) < P(EM) + P(EM+1)
Now we need to show that P(EM) + P(EM+1) < P(EM+1) for the inequality to hold. Simplifying the expression, we have: P(EM) + P(EM+1) < P(EM+1)
Since P(EM+1) is a probability and is always non-negative, this inequality holds true. Therefore, by the principle of mathematical induction, we have shown that for any integer M ≥ 1, the inequality P(E1 or E2 or ... or EM) < P(EM) holds.
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In sarah classroom, There are 6 girls or every 2 boys. What is the ratio of boys to the total number of student
Answer:
3:1 (Girls:Boys)
6 divided by 2
In a publication of a renowned magazine, it is stated that cars travel in
average at least 20,000 kilometers per year, but do you think the average actually
is minor. To test this claim, a sample of 100 car owners is asked
randomly selected to keep a record of the kilometers they travel. It would
If you agree with this statement, if the random sample indicates an average of 19,000
kilometers and a standard deviation of 3900 kilometers? Use a significance level of
0.05 and for its engineering conclusion use:
a) The classical method.
b) The P-value method as an auxiliary.
Both the classical method and the p-value method lead to the conclusion that the average distance cars travel per year is less than 20,000 kilometers,
a) t = -2.564
b) t = -2.564
How to thest the claim?To test the claim that the average distance cars travel per year is less than 20,000 kilometers, we can conduct a hypothesis test using the classical method and the p-value method.
a) The steps we need to follow are:
Step 1: Formulate the null and alternative hypotheses:
Null hypothesis (H₀): The average distance cars travel per year is 20,000 kilometers.
Alternative hypothesis (H₁): The average distance cars travel per year is less than 20,000 kilometers.
Step 2: Determine the test statistic:
Since we know the sample size (n = 100), the sample mean (x = 19,000 kilometers), and the sample standard deviation (s = 3900 kilometers), we can use the t-test statistic.
t = (x - μ₀) / (s / √n)
where μ₀ is the assumed population mean under the null hypothesis.
Step 3: Set the significance level:
The significance level is given as 0.05, which means we want to be 95% confident in our conclusion.
Step 4: Calculate the critical value:
Since the alternative hypothesis is one-tailed (less than), we need to find the critical t-value corresponding to a 0.05 significance level and degrees of freedom (df) = n - 1 = 99. From the t-distribution table or calculator, the critical t-value is approximately -1.660.
Step 5: Calculate the test statistic:
t = (19,000 - 20,000) / (3900 / √100)
t = -10 / (3900 / 10)
t ≈ -2.564
Step 6: Compare the test statistic with the critical value:
Since -2.564 is less than -1.660, the test statistic falls in the rejection region. We reject the null hypothesis.
Step 7: Make a conclusion:
Based on the classical method, since the test statistic falls in the rejection region, we conclude that the average distance cars travel per year is significantly less than 20,000 kilometers.
b) The P-value method:
Using the same test statistic t = -2.564 and the degrees of freedom (df) = 99, we can calculate the p-value. The p-value is the probability of observing a test statistic as extreme as the one obtained, assuming the null hypothesis is true.
From a t-distribution table or calculator, the p-value corresponding to t = -2.564 and df = 99 is approximately 0.0075 (or 0.75% if multiplied by 100).
Since the p-value (0.0075) is less than the significance level (0.05), we reject the null hypothesis. This suggests strong evidence that the average distance cars travel per year is significantly less than 20,000 kilometers.
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HURRY PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Answer:
48 is the answer
Step-by-step explanation:
9*4 +. 6*2
36 + 12
48
Which value of x satisfies the equation below? 1/2 (3x + 17) = 1/6 (8x-10)
Choice answers:
A. -61
B -55
C. -41
D-35
Plz answer quick need help. are the sums of double odd?
Can I get help with number 15 am stuck
Which one would result an integer
Answer:
c is the only one that would result in an integer
Step-by-step explanation:
i hope this helps :)
Option c ∛ 27 would result in an integer.
what are integers?An integer is the number zero, a positive natural number or a negative integer with a minus sign. The negative numbers are the additive inverses of the corresponding positive numbers.
Given here, ∛27= 3 while the other options ∛60 is not an integer because 60 is not cubic number similarly for 9 , 18 are not cubic numbers and thus their subsequent cubic roots will not yield an integer.
Hence, Option c ∛ 27 would result in an integer.
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yo i really need help please in order to pass this i’ll give a brainliest to anyway who knows the correct answer please no links
all i know is that it would not be 13.9
Answer:
12in
Step-by-step explanation:
this is the only subject i'm good at in math XDDD.
math because im very bad at it
Help!! Please!!!!!!!
Answer:
E
Step-by-step explanation:
Solve the system of differential equations S x1 = – 5x1 + 0x2 – 16x1 + 322 X2' x1(0) = 1, X2(0) = 5 21(t) = = 22(t) - = X2
The solution to the system of differential equations is x₁(t) = e⁻⁵ˣ + 3e³ˣ and x₂(t) = 2e⁻⁵ˣ + 5e³ˣ
Let's solve the given system of differential equations: x₁' = -5x₁ + 0x₂ ...(1) x₂' = -16x₁ + 3x₂ ...(2)
To solve this system, we can rewrite it in matrix form. Let's define the vector X = [x₁, x₂] and the matrix A as:
A = [[-5, 0], [-16, 3]]
The system can then be written as X' = AX, where X' is the derivative of X with respect to time.
Now, let's find the eigenvalues and eigenvectors of matrix A. The eigenvalues are obtained by solving the characteristic equation det(A - λI) = 0, where I is the identity matrix.
A - λI = [[-5 - λ, 0], [-16, 3 - λ]]
det(A - λI) = (-5 - λ)(3 - λ) - 0(-16) = λ² + 2λ - 15 = (λ + 5)(λ - 3)
Setting the characteristic equation equal to zero, we find the eigenvalues: λ₁ = -5 λ₂ = 3
To find the corresponding eigenvectors, we substitute each eigenvalue back into the matrix A - λI and solve the system of equations (A - λI)v = 0, where v is the eigenvector.
For λ₁ = -5: A - (-5)I = [[0, 0], [-16, 8]]
Using Gaussian elimination, we can solve the system of equations to find the eigenvector corresponding to λ₁: -16v₁ + 8v₂ = 0 => -2v₁ + v₂ = 0 => v₁ = (1/2)v₂
Let v₂ = 2, then v₁ = 1. Therefore, the eigenvector corresponding to λ₁ is v₁ = [1, 2].
For λ₂ = 3: A - 3I = [[-8, 0], [-16, 0]]
Solving the system of equations, we find: -8v₁ = 0 => v₁ = 0
Thus, the eigenvector corresponding to λ₂ is v₂ = [0, 1].
Now, let's express the solution of the system in terms of the eigenvalues and eigenvectors.
X(t) = c₁e(λ₁t)v₁ + c₂e(λ₂t)v₂
Substituting the eigenvalues and eigenvectors we found earlier, we have: X(t) = c₁e⁻⁵ˣ[1, 2] + c₂e³ˣ[0, 1]
Using the initial conditions, x₁(0) = 1 and x₂(0) = 5, we can find the values of c₁ and c₂.
At t = 0: [1, 5] = c₁[1, 2] + c₂[0, 1] 1 = c₁ 5 = 2c₁ + c₂
Solving these equations, we find: c₁ = 1 c₂ = 3
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Complete Question:
Solve the system of differential equations
x₁' = – 5x₁ + 0x₂
x₂' = – 16x₁ + 3x₂
x₁(0) = 1, x₂(0) = 5
Andrea constructed a triangle. Angle 1 and 3 are the same size and angle 2 has a measurement of 70 degrees. What is the measurement of angle 1 and 3
Answer:
Step-by-step explanation:
By triangle sum theorem,
Sum of all angles of a triangle is 180°.
m∠1 + m∠2 + m∠3 = 180°
(m∠1 + m∠3) + m∠2 = 180°
2(m∠1) + 70° = 180° {Given → m∠1 = m∠3]
2(m∠1) = 110°
m∠1 = 55°
Therefore, m∠1 = m∠3 = 55°
Four minutes is what percent of an hour?
Answer
6 and 2/3 percent of an hour OR 6.666.... hour
I don’t know if you have to round or not but if it does just round
Step-by-step explanation:
Well 4 minutes of an hour is basically 4/60
4/60=1/15
1/15=x/100
solve the proportion by cross multiplying
100=15x
x=6.66666666
That is yoru percent
OMG PLS HELP WITH THIS IM PANICKING OMG I GOT A F IN MATH MY MOM JUST YELLED AT ME IM CRYING PLS HELP WITH THS- PLSS TELL ME I ALREADY DID NUMBER 2 BTW SO NO NEED JUST PLS HELP IN THE BOTTOM :(
Answer:
3. The equivalent fractions are presented as follows;
[tex]\dfrac{2}{3} = \dfrac{2 \times 2}{3 \times 2} =\dfrac{4}{6}[/tex]
4. The equivalent fractions are presented as follows;
[tex]\dfrac{2}{3} = \dfrac{4 \times 2}{4 \times 3} =\dfrac{8}{12}[/tex]
5. The reason why it works is because [tex]\dfrac{1}{8} + \dfrac{1}{8} = \dfrac{1}{4}[/tex]
Step-by-step explanation:
3. Based on the shaded region of the given figures, the two fractions are equivalent
Mathematically, we can show the equivalency of the two fractions as follows;
[tex]\dfrac{2}{3} =\dfrac{2}{3} \times 1 = \dfrac{2}{3} \times \dfrac{2}{2} = \dfrac{2 \times 2}{3 \times 2} =\dfrac{4}{6}[/tex]
Therefore;
[tex]\dfrac{2}{3} = \dfrac{2 \times 2}{3 \times 2} =\dfrac{4}{6}[/tex]
4. From the shaded region of the given figure, the fractions are equivalent
Mathematically, we have;
[tex]\dfrac{2}{3} =\dfrac{2}{3} \times 1 = \dfrac{4}{4} \times \dfrac{2}{3} = \dfrac{4 \times 2}{4 \times 3} =\dfrac{8}{12}[/tex]
Therefore;
[tex]\dfrac{2}{3} = \dfrac{4 \times 2}{4 \times 3} =\dfrac{8}{12}[/tex]
5. The amount of salt required by the recipe = 1/4 teaspoon of salt
The measure of the spoon Jonas has = 1/8 teaspoon
When Jonas adds two 1/8 teaspoons, he gets;
[tex]\dfrac{1}{8} + \dfrac{1}{8} = \dfrac{1 + 1}{8} = \dfrac{2}{8} = \dfrac{2 \times 1}{2 \times 4} = \dfrac{2}{2} \times \dfrac{1}{4} = 1 \times \dfrac{1}{4} = \dfrac{1}{4}[/tex]
Therefore;
[tex]\dfrac{1}{8} + \dfrac{1}{8} = \dfrac{1}{4}[/tex]
Two 1/8 measuring teaspoons are equivalent to one 1/4 teaspoons and therefore Jonas is able to get the 1/4 teaspoons of salt the recipe asks for b combining two 1/8 measuring teaspoons of salt he has because 1/8 + 1/8 = 1/4.
round 3.060 to the nearest whole number.
Answer:
3
Step-by-step explanation:
dude kinda obv that its 3
Answer:
answer would be 3
Step-by-step explanation:
Write the integer that represents the opposite of each situation
100 feet above sea level
Find the total area.
Answer:
area = 164.52 cm²
Step-by-step explanation:
area = (12x6) + (12x3x0.5x2) + (3.14)(0.5)(6²) = 164.52 cm²
How many sides do 4 pentagons and 3 nonagons have in all?
Answer:
47
Step-by-step explanation:
^
Help please I need this today
Answer:
a = 15
t = 5
Step-by-step explanation:
[tex] \frac{12}{a} = \frac{16}{20} \\ \\ 16a = 12 \times 20 \\ \\16 a = 240 \\ \\ a = \frac{240}{16} \\ \\ a = 15 \\ \\ \\ \frac{2}{8} = \frac{t}{20} \\ \\ 8t = 40 \\ \\ t = \frac{40}{8} \\ \\ t = 5[/tex]
could any body help me with this
Answer:
1) 1.2 minutes
2) 8.3 laps
3) 25.2 minutes
i really need help so can you plz help meeee
Answer:
5/11 is 0.4555555555555555555555555
so basically the first option out of the two.
U do know you can just calculate this with the calculator right?
Solve the following equation for x.
Answer:
If you just solve normally, you will get x=2 and x=-3. But if you plug these in to check your work, you will find that they are wrong. Your answer is no solution
Step-by-step explanation:
ln(2x+3)+ln(x-2)=ln(x^2-2x)
Rule: log(a) + log(b) = log(a*b)
ln( (2x+3)(x-2) ) = ln(x^2-2x)
Rule: If log(a) = log(b) then a = b
(2x+3)(x-2) = x^2 - 2x
2x^2-x-6=x^2-2x
x^2+x-6=0
Using Quadratic Formula:
x = 2 and x = -3
But, plugging these numbers back into the original equation is false!
A UMass student is starting their junior year and has accumulated 60 credits so far. Their current cumulative average is a C, or a Grade Point Average (GPA) of 2.0. Their employer has a scholarship program for students who have GPAs of 2.3 or higher. This student wants to get that scholarship to help pay for their senior year. They plan on taking 15 credits each for the fall and spring semesters of their junior year.
a. Can they raise their cumulative average to 2.3 after completing 15 fall semester credits? What semester GPA would they need?
b. What average GPA would they need for their two junior year semesters combined (30 credits) to achieve their goal of a 2.3 cumulative GPA and 90 credits?
According to the information, we can infer that no, they cannot raise their cumulative average to 2.3 after completing 15 fall semester credits. On the other hand, they would need an average GPA of 3.25 for their two junior year semesters combined (30 credits) to achieve their goal of a 2.3 cumulative GPA and 90 credits.
How to calculate the new cumilative GPA?In order to calculate the new cumulative GPA, we need to consider both the current cumulative GPA and the GPA earned in the fall semester. Since the student's current cumulative GPA is 2.0 and they have already accumulated 60 credits, their total grade points earned so far would be 2.0 multiplied by 60, which equals 120 grade points.
To raise the cumulative GPA to 2.3, the student would need a total of 2.3 multiplied by (60 + 15) = 2.3 multiplied by 75 = 172.5 grade points by the end of the fall semester.
Since the student has already accumulated 120 grade points, they would need to earn an additional 52.5 grade points in the fall semester. To calculate the required semester GPA, we divide 52.5 by 15 credits, which gives us a required semester GPA of 3.5.
So, the student would need a semester GPA of 3.5 in order to raise their cumulative average to 2.3 after completing 15 fall semester credits.
What average gpa would they need for their two junior year semesters combined to achieve their goal?They would need an average GPA of 3.25 for their two junior year semesters combined (30 credits) to achieve their goal of a 2.3 cumulative GPA and 90 credits.
Explanation: To calculate the average GPA for the two junior year semesters, we need to consider the total grade points earned and the total number of credits taken.
Currently, the student has accumulated 60 credits and 120 grade points. In order to achieve a cumulative GPA of 2.3 after completing 90 credits, they would need a total of 2.3 multiplied by 90 = 207 grade points.
To calculate the required grade points for the two junior year semesters, we subtract the current grade points (120) from the desired total grade points (207), which gives us 207 - 120 = 87 grade points needed for the junior year.
Since the student plans to take 30 credits during their junior year, they would need to earn 87 grade points in those 30 credits. Dividing 87 by 30 gives us an average GPA of approximately 2.9 for the two junior year semesters.
According to the above, the student would need an average GPA of 3.25 (rounded up) for their two junior year semesters combined to achieve their goal of a 2.3 cumulative GPA and 90 credits.
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