Answer:
slowing the transfer of thermal energy from the food inside the bag to the air outside the bag.
Explanation:
Answer:
D
Explanation:
slowing the transfer of thermal energy from the food inside the bag to the air outside the bag.
A chair is pushed backward with a force of 100 N. The gravitational force of Earth on the
chair is 120 N downward, and the floor exerts a force of 120 N upward on the chair.
Draw a free-body diagram showing the forces acting on the chair.
Explanation:
he fell down with telling any one,
Why is soccer a great athletic sport
Answer:
that is the answer
Explanation:
look at it
An object weighing 120 n is set on a rigid beam of negligible mass at a distance of 3 m from a pivot, as shown above. A vertical force is to be applied to the other end of the beam a distance of 4 m from the pivot to keep the beam at rest and horizontal. What is the magnitude f of the force required?.
The force required to keep the beam in equilibrium is 90 N.
Principle of moments of forcesIt states that for a system at equilibrium, the sum of the clock-wise moment is equal to the sum of anti clock wise moment.
To calculate the magnitude of the force required to keep the beam at equilibrium, we use the Formula below.
Formula:
Fd = fD............... Equation 1Where
F = Force/ weight of the objectd = Distance of the object from the pivotf = Vertical force applied on the other endD = Distance of the vertical force from the pivot.Make f the subject of the equation
f = Fd/D............... Equation 2From the question,
Given:
F = 120 Nd = 3 mD = 4 mSubstitute the given values into equation 2
f = (120×3)/4f = 90 NHence, The force required to keep the beam in equilibrium is 90 N.
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A lightening rod saves us from lightening give reason
Can you tell me by looking this book
Please fast
Answer:
Because Rod protect house from burning down and people from electrocution.
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars’s orbital period is 687 days, and Mars’s distance from the Sun is 2. 279 × 1011 m. 1. 49 × 1011 m 1. 49 × 1033 m 3. 34 × 1011 m 3. 34 × 1033 m.
Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.
The distance of the earth from the sun is [tex]1.50 \times 10^{11}\;\rm m[/tex].
What is Kepler's third law?
Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.
[tex]T^2 \propto R^3[/tex]
Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.
By using Kepler's third law, this can be written as,
[tex]T^2 \propto R^3[/tex]
[tex]T^2 = kR^3[/tex]
Substituting the values, we get the value of constant k for mars.
[tex]687^2 = k\times (2.279 \times 10^{11})^3[/tex]
[tex]k = 3.92 \times 10^{-29}[/tex]
The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.
[tex]365^3 = 3.92\times 10^{-29} R^3[/tex]
[tex]R^3 = 3.39 \times 10^{33}[/tex]
[tex]R= 1.50 \times 10^{11}\;\rm m[/tex]
Hence we can conclude that the distance of the earth from the sun is [tex]1.50 \times 10^{11}\;\rm m[/tex].
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What is the basis for the sounds referred to as korotkoff sounds?.
Answer:Korotkoff Sounds. -tapping sounds created by turbulent blood flow in arm. -pressure is slowly being released from cuff, so systolic pressure is above that of the cuff, but diastolic is still below, so the artery opens in systole and collapses in diastole.
Explanation:
A car driver traveling at a speed of 108km per hour ,sees a traffic light and stopped after travelling for 20seconds .Find the acceleration of the car
Answer:
– 2.5 m/s²
Explanation:
We have,
• Initial velocity, u = 180 km/h = 50 m/s
• Final velocity, v = 0 m/s (it stops)
• Time taken, t = 20 seconds
We have to find acceleration, a.
[tex]\longrightarrow[/tex] a = (v ― u)/t
[tex]\longrightarrow[/tex] a = (0 – 50)/20 m/s²
[tex]\longrightarrow[/tex] a = –50/20 m/s²
[tex]\longrightarrow[/tex] a = – 5/2 m/s²
[tex]\longrightarrow[/tex] a = – 2.5 m/s² (Velocity is decreasing) [Answer]
During a lightning storm, the bottom of a cloud gains a strong negative electric charge. If you were to measure the charge at the top of a tall metal pole directly under the cloud, what would you expect to observe?.
During a lightning storm, the bottom of a cloud gains a strong negative electric charge. If you were to measure the charge at the top of a tall metal pole directly under the cloud, what would you expect to observe? The top of the pole would have no charge. The top of the pole would have a positive charge.
In the given scenario, the positive charges within the pole concentrate at the top of the pole to be near the negatively charged cloud bottom.
What is lightning storm?A thunderstorm, also widely recognized as an electrical storm or even a lightning storm, is a type of storm that is distinguished by the presence of lightning and its acoustic effect on the Earth's atmosphere, which is known as thunder.
Thundershowers are thunderstorms that are relatively weak. Warm air rises and cools, condensing into small droplets of water.
If the air is sufficiently unstable, the updraft of warm air is rapid, and the water vapor forms a cumulonimbus cloud quickly. These cumulonimbus clouds typically form in less than an hour.
In the given scenario, the positive charges within the pole concentrate near the negatively charged cloud bottom at the pole's top.
Thus, this is the observation that can be expected.
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You drive your car for 2.0 h at 40.0 km/h, then for 2.0 h at 60.0 km/h. What is your average
velocity?
Answer:
Simple as 50 km/h
Explanation:
Since the average being measured is of the hours and not distance, it is simply (60+40)/(2+2)
A ball is dropped from the top of a building. When does the ball have the LEAST kinetic energy?
A: After it has hit the ground
B: Just before it hits the ground
C: Halfway through the fall
D: Just after it is released
Answer:
The answer is probably A
A circular disk of moment of inertia [tex]I_t[/tex] is rotating in a horizontal plane, about its axis , with a constant angular speed [tex]\omega_i[/tex] . Another disc of moment of inertia [tex]I_b[/tex] is dropped coaxially onto the rotating disk. Initially the 2nd disc has 0 angular speed. Eventually both the disks rotate with a constant angular speed [tex]\omega_f[/tex] . The energy lost initially rotating disk to friction is ?
The kinetic energy of the circular disc in initial state is,
[tex]K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]
The initial kinetic energy of the other disc dropped on the first disc is,
[tex]K^{2r} = \frac{1}{2}I^{b}(0)^{2}[/tex]
[tex] = > K^{2r} = 0J[/tex]
As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,
[tex]E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }[/tex]
The net kinetic energy in the initial state is,
[tex]E^{i} = K^{1r} + K^{2r}[/tex]
[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0[/tex]
[tex] = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }[/tex]
Thus, the change in the kinetic energy during the change of state is,
[tex]dE = E^{f} - E^{i}[/tex]
[tex] = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } [/tex]
[tex] = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]
This change in value of energy is the energy lost initially rotating the disk to friction.
Hence, the energy lost in the given case is [tex]dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } [/tex]
The energy lost initially by the rotating disk to friction is equal to [tex]\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]
Given the following data:
Angular speed = 0How to calculate the energy lost.At the initial state, the kinetic energy of the circular disc is given by this formula:
[tex]K.E = \frac{1}{2} I_t\omega_i^2[/tex]
For the second disc, the initial kinetic energy is given by this formula:
[tex]K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0[/tex]
At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:
[tex]E_f = \frac{1}{2} (I_t + I_b)\omega_f^2[/tex]
For the energy lost:
Also, the change in the kinetic energy is given by this formula:
[tex]\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2[/tex]
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if a 2 kg balls thrown straight upward with a KE of 500 j. what maximum height will it reach?
Answer:
I think its 25.51 m!!
Explanation:
Help pls I dont want to fail my class
How fast would a penny be falling when it reaches ground level if dropped from rest off the 102nd floor observation deck of the empire state building? (381 meters above the ground) You may treat air resistance as negligible.
Air resistance is negligible
Distance=381m=sAcceleration due to gravity=g=10m/s^2Initial velocity=u=0m/sFinal velocity=v=?Apply third equation of kinematics
[tex]\\ \tt\longmapsto v^2=u^2+2gs[/tex]
u=0[tex]\\ \tt\longmapsto v^2=2(10)381[/tex]
[tex]\\ \tt\longmapsto v^2=7620[/tex]
[tex]\\ \tt\longmapsto v=87.29ms^{-1}[/tex]
Answer:
According to the Given Statement
Penny is dropped from rest of the 102nd floor which is 381 metres above from the ground.
we 'll take here the acceleration due to gravity (g ) is 9.8m/s²
Its initial velocity u be 0 m/s ( as it is at rest)
Using Kinematic Equation
v² = u² + 2ghhere h is the height of 102nd floor
➥ v² = 0² + 2 × 9.8 × 381
➥ v² = 0 + 19.6 × 381
➥ v² = 7467.6
➥ v = √7467.6
➥ v = 86.41 m/s
So, 86.41 m/s penny would be fall.
A car accelerates from to at a constant rate of How far does it travel while accelerating?.
Distance is the measure of the length of ground covered by an object during its motion. Distance is a scalar quantity. The car will travel 69 m while accelerating.
What is the distance?
Distance is the measure of the length of ground covered by an object during its motion. While the displacement is defined as the shortest distance between the two paths.
Distance is a scalar quantity. While displacement is a vector quantity. Mathematically it is given as the product of speed and time.
The following data are given in the problem as
u is the initial speed=5.0 m/sec
v is the final speed=21 m/sec
s is the distance covered by the car =?
a= Acceleration of car =3.0 m/sec²
According to Newton's third equation of motion, the formula derived will be
[tex]\rm{v^2=u^2+2as \\\\[/tex]
[tex]\rm s = \frac{v^2-u^2}{2a} \\\\\rm s = \frac{(21)^2-(5)^2}{2\times3.0} \\\\ \rm s=69 m[/tex]
Hence the car will travel 69 m while accelerating.
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Difine velocity?
Thnx~~[tex] \: \: \: [/tex]
Velocity is simply defined as the rate of change of displacement per unit time. Mathematically, it can be expressed as
Velocity = displacement / time
How to determine velocityFor example: A car travels 400 m due north in 40 s. What is the velocity of the car.
From the question given above, we can obtain the velocity as follow:
Displacement = 400 m due north Time = 40 sVelocity =?Velocity = displacement / time
Velocity = 400 / 40
Velocity = 10 m/s
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The area of a room that is 10 feet wide and 12 feet long is
13.3 square feet
14 square yards
120 square feet
12 squa2 yards
Potential energy is the energy an object has due to its:.
Answer:
its position relative to some zero position
Explanation:
your welcome
May I get an answer?
Answer:
Explanation: all of them have made sentence structure (grammar point view) and from the physical aspect.
any two difference between negative and positive charge of class 7 please fast
Answer:
any two difference between negative and positive charge
➢The matter is positively charged if it contains more protons than electrons, and it is negatively charged if it contains more electrons than protons.
Explanation:
I hope it will help you.....
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Determinati rezistenta unui conductor electric daca prin el circula un curent de 0,3 a, iar tensiunea masurata la capetele lui este 0.05 v
WHAT? I DON'T UNDERSTAND WHAT ARE YOU SAYING
Jill runs for 20 seconds at 10 m/s, how far did she travel?
Answer:
200 (m) for 20 seconds
10 times 20 is 200
Answer:
200
Explanation:
Jill is running at 10 meters per second
20 * 10 = 200
After the softball leaves your hand, it rises, slowing down.
Answer:
yes it do rises and then fall down due to gravitational
When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00 10 5J of work are done. Find this final speed.
Apply Newton's second law
[tex]\\ \tt\hookrightarrow F=ma[/tex]
[tex]\\ \tt\hookrightarrow F=1167(4)=4668N[/tex]
Now
[tex]\\ \tt\hookrightarrow W=Fd[/tex]
[tex]\\ \tt\hookrightarrow d=\dfrac{W}{F}[/tex]
[tex]\\ \tt\hookrightarrow d=\dfrac{105}{4668}[/tex]
[tex]\\ \tt\hookrightarrow d=0.022m[/tex]
Now
d be sAccording to third equation of kinematics
[tex]\\ \tt\hookrightarrow v^2=u^2+2as[/tex]
[tex]\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)[/tex]
[tex]\\ \tt\hookrightarrow v^2=100+8(0.022)[/tex]
[tex]\\ \tt\hookrightarrow v^2=100+0.176[/tex]
[tex]\\ \tt\hookrightarrow v^2=100.176[/tex]
[tex]\\ \tt\hookrightarrow v=10.001m/s[/tex]
What is the frequency of a wave with a time period of 0.08
s?
O
8 Hz
O
1.25 Hz
O
12.5 Hz
Answer:
12.5 hz
Explanation:
What are the characteristics of terristrial animals?
Answer:
They are provided with keen senses of sight, smell and hearing.
Answer:
Terrestrial animals
breathe through skin or nostrils, have differently adapted bodies, and exchange of gases is done from air, whereasHow much power does it take to do 400 joules of work in 5 seconds?
Answer:
Explanation:
Power = work / time
P = 400 J / 5 s
P = 80 watts
A charged particle moves at 2. 5 × 104 m/s at an angle of 25° to a magnetic field that has a field strength of 8. 1 × 10–2 T. If the magnetic force is 7. 5 × 10–2 N, what is the magnitude of the charge? 3. 7 × 10–5 C 4. 1 × 10–5 C 8. 8 × 10–5 C 1. 0 × 10–4 C.
The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.
What is the force exerted on the charge?Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.
when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.
Mathematically the force exerted on the charge will be
F=qvBsinα
F= force acting on the charge= 7.5 ×10⁻²
v = velocity of charge=2.5 ×10⁴
q = charge=?
B= 8.1 ×10⁻²
F=qvBsinα
[tex]\rm{q= \frac{F}{vBsina}}[/tex]
[tex]\rm{q= \frac{7.5\times 10^-2}{2.4\times 10^-2 \times 8.1\times 10^-2 sin25^0}}[/tex]
q = [tex]8.8 \times 10^ {-5}\rm C[/tex]
Hence the value of the charge will be [tex]8.8 \times 10^ {-5}\rm C[/tex].
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3. What appears to be creating the magnetic field being represented here? How can moving the compass around confirm that? Why do you suppose the magnetic field surrounding the compass is not being represented by the simulation in this instance?
Movement occurs on the compass when there is magnetic field in the surrounding environment.
The movement of the needle appears which represents the presence of magnetic field. The moving compass around confirm that there magnetic field present in that region because the magnetic field is detected by the compass.
What is magnetic field?A magnetic field is invisible force which can be detected by a compass. A compass contains a small bar magnet which can rotate when it experience magnetic field around it so we can conclude that movement occurs on the compass when there is magnetic field in the surrounding environment.
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how are magnetic domians and magnetic fields connected
What is the momentum of a 3-kg object moving at 5 m/s?
Answer: 15 kg*m/s
Explanation:
Momentum = mass*velocity
Momentum = 3kg*5 m/s
Momentum = 15 kg*m/s
Answer:
15 kg m/s
Explanation:
Momentum = mass xvelocity
Momentum = 3kgx 5 m/s
Momentum = 15 kg m/s