An automobile travels for 90 minutes along a highway. The graph shows the progress of the automobile, with its start point designated as distance = 0 km.



What is the automobile's instantaneous velocity at time = 60 seconds?
0.50 km/min
1.0 km/min
−0.40 km/min
0.33 km/min

The acceleration at the moment the train speed reaches 50.0 km/h is -0.74 m/s².

The acceleration of an object is the change in the velocity of the object with time.

a = Δv/Δt

where;

a = (vf - vi) / t

where;

Substitute the given parameters and solve for the acceleration of the train.

a = (13.89 m/s - 25 m/s) / (15 s)

a = -0.74 m/s²

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a)It is possible for the magnetic force on a charge moving in a magnetic field to be zero. The force acting on the charge is zero when a charge is moving in the same or opposite direction of the magnetic field.  When a is charge moving parallel in the same direction of the magnetic field, then the magnetic force  is zero.

b)It is not possible for the electric force on a charge moving in an electric field to be zero. If there's a charged particle in a magnetic field, it's impossible for this force to become zero.

c)It is not possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero. The magnetic force can be zero but the electric force cannot be zero because it is not affected by the motion of the particles.

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If you have a tire blowout when driving on the highway, you should not use your brakes until the vehicle has nearly rolled to a stop.

If you have a tire blowout when driving on the highway, you should not use your brakes until the vehicle has nearly rolled to a stop because at high speed the deviation is more.

Rolling is a type of motion that combines rotation and translation of that object with respect to a surface, such that, if ideal conditions exist, the two are in contact with each other without sliding. Rolling where there is no sliding is referred to as pure rolling.

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The ratio of the kinetic energy of particle b of mass 2m and a speed 2v to the kinetic energy of particle a of mass m and a speed v is 8 : 1

K = 1 / 2 m v²

K = Kinetic energy

m = Mass

v = Velocity

Let kinetic energy of particle a be K1 and kinetic energy of particle b be K2.

For particle a,

K1 = 1 / 2 m v²

For particle b,

m = 2m

v = 2v

K2 = 1 / 2 ( 2 m ) ( 2 v )²

K2 = 4 m v²

The ratio of the kinetic energy of particle b to the kinetic energy of particle a,

K2 / K1 = ( 4 m v² ) / ( 1 / 2 m v² )

K2 / K1 = 8 / 1

Therefore, the ratio of kinetic energy of particle b to the kinetic energy of particle a is 8 : 1

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If the coefficient of kinetic friction between two sliding surfaces is μ and the normal force between them is N, then the kinetic friction between them is given by μ = F/N . Therefore N= 800.

Given

kinetic friction μ = 0.3

and kinetic friction μ = F/N

N =  normal force

where F = frictional force

F = 240 n

N = F/μ

= 240 n/0.3

N = 800 n

There are two types of friction kinetic friction, also known as dynamical friction, and static friction. A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' coefficient of kinetic friction will determine how much force is applied.  Kinetic friction occurs whenever two surfaces slide past one another. The application of brakes to tyres, the movement of an object across the ground, such as a box, or the rubbing of sandpaper all cause kinetic friction. The coefficient of friction, which measures the relationship between the frictional force and the normal force, provides a good description of friction. It obstructs the motion of several different items.

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The gas's internal energy rises by 250 J when the value is positive. So, the increase in temperature of the gas is 250 J.

Any device addressing the relationship between heat and work must be designed with a working knowledge of thermodynamics. This method ignores actions that take place at the molecular level in favor of considering a particular amount of matter.

In macroscopic thermodynamics, the effects are based on observable, quantifiable quantities, and the attributes of the system are given to the system as a whole.

Work cannot "store" energy like the aforementioned forms can. It is merely a momentary manifestation process of energy transmission. Heat cannot transport energy either; it is merely a temporary manifestation process. Therefore, other types of energies in transition include heat and work.

by setting a limit, identifies the subject of the manifestation analysis. Either "a distinct collection of substance" or "a region in space" must be handled consistently.

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The average electric power consumption of a machine is 29.4 watt.

Kinetic Energy is defined as the object which has because of its motion.

It is represented as

K = 1/2 mv²

where,

K = Kinetic Energy

m = mass

V = Velocity

Now by putting the value we get the kinetic energy as

K = 1/2 mv²

= 0.5 × 0.3 × (7)²

= 7.35 J

It is given in the question that the machine throws 2 snowballs per second.

Poutput = 2 × 7.35

= 14.7 J/s

= 14.7 watt

According to the question the efficiency is given as 50%. So average electric power is

Avg. Electric power = 2 × 14.7

= 29.4 watt

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You used insight in this situation to find a solution to which you struggling to solve.

On the three aspects of process, task, and phenomenology, there are various definitions of insight (Llinger and Knoblich, 2009). Process is concerned with the cognitive processes that result in clever answers. An analytical process emphasises a deliberate and systematic evaluation of the problem, emphasising logical deduction and strategic thinking, as opposed to descriptions of insightful problem solving processes that emphasise a sudden certainty of a correct response with little to no conscious access to the processing of the solution. It is widely recognised that it is difficult to measure a subjective experience like insight objectively (Llinger and Knoblich, 2009; Ash et al., 2009). In the past, researchers have made use of "classic insight problems," vague issues that Gestalt psychologists first utilised to induce feelings of insight upon realising the solution.

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tan0=1.95 and tan0=0.605 are two solutions. 0 = 63 and theta 0 = 31 are the corresponding (first quadrant) angles.

The elevation angle is the angle between the horizontal line of sight and the object when standing and looking at something. The angle of depression is the angle between the horizontal line of sight and the object if the person is standing and looking down at the object. The rise or rise of something is called elevation. Mountains have an elevation based on their height, and your mood rises the happier you are. Elevation is a noun that describes the height of something above a surface or ground line. It is also a term of measurement for things like temperatures or degrees.

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The acceleration of an unwary football player during uniform motion is 21.675 m/s² with a positive direction.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 5.1 m/s

s = 0.6 m

vt = 0 m/s

By substituting the given parameters, we can calculate the acceleration

vt² = vo² + 2a . s

0² = 5.1² + 2a . 0.6

1.2a = - 26.01

a = 21.675 m/s²

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A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. and in a longitudinal wave particles are displaced parallel to the wave direction.

In a transverse wave, the displacement of the individual medium particles occurs in a direction that is perpendicular to the wave's direction of propagation. Imagine holding a slinky and moving your hand up and down, and the slinky follows. However, the actual wave itself travels from left to right.

Transverse waves are created when a medium's particle oscillations are perpendicular to the wave's direction of propagation. An ocean wave is a typical illustration of a transverse wave. The direction of the water molecules' motion in an ocean wave is vertical.

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If we have an ideal spring and attach a mass of 3.75 kg to it such that the spring extends from 12 cm to 13.40 cm, then its spring constant is 2678.57 N/m

When a force applied to a spring, then according to the Hooke's Law:

F = - k. x

Where:

F = applied force

k = spring constant

x = change in spring's length

The minus sign indicates that the displacement and the restoring force is in the opposite direction.

The given parameters:

x1 = 12 cm

x2 = 13.4 cm

Hence,

x = x2 - x1 = 13.4 - 12 = 1.4 cm = 1.4 x 10⁻² m

F = 3.75 . 10 = 37.5 N

Then,

k = F/x = 37.5 / (1.4 x 10⁻² ) = 2678.57 N/m

Complete question:

An ideal spring of negligible mass is 12.00 cm long when nothing is attached to it. when you hang a 3.75 kg object from it, you measure its length to be 13.40 cm. What is the spring constant?

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Answer:

Knees to Chest

Be consistent. Setting and committing to a regular practice of yoga is absolutely essential if you want to make improvements. ..

Answer: Dog pose was really easy, but tree pose was really difficult because it was hard to balance.

11.4m/s^2 is the magnitude of the acceleration of the jet while taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per second.

[tex]v^2-u^2=2as[/tex] in this

v = final velocity

u =initial velocity

a = acceleration

s =displacement

the data, we have got

u = 0 (it starts from rest)

v = 40 m/s (final velocity)

s = 70 m ( run-way length)

now, put in the equation

[tex]a=v-u/t=(40^2-0)/2(70)=11.4m/s^2[/tex]

When a point or object accelerates or decelerates, it is moving straight forward. Motion on a circle increases despite the same speed because the direction is always changing. All other movements accelerate as a result of these factors.

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a) The time taken is 4.44 s

b) The force that keeps it moving is 15188 N

c) The centripetal force is responsible for the motion in the circular path.

d) The coefficient of the friction is 1.03

The centripetal force is the force that keep the object moving in a circular path. In this case, we need to find the how long does it take the car to do a lap around the track.

a) The time that is taken is the radio of the distance to the speed of the object. Thus the time that is taken =  200 m/45 m/s = 4.44 s

b) The net force that acts on the car as it is negotiating the circular path is given as; mv^2/r = 1500 * (45)^2/200

= 15188 N

c) The centripetal force keeps the car on the circular path

d) The coefficient of static friction is; 15188 N/1500 kg * 9.8 m/s^2

= 1.033

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The velocity as a function of time is 0, and displacement between t = 10.0 s and t = 35.0 s is 0.

The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).

as S= 0, then

[tex]V_{total}[/tex] = [tex]\frac{ Final Speed - initial speed}{total_time }[/tex]

V=0.

Displacement is defined as the final position minus the starting position.

Displacement = Final distance- initial distance

S= 0

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Answer:

F = 20 N

Explanation:

Given:

m = 0.12 kg

H = 2.3 m

S = 0.067 m

g = 9.8 m/s²

____________

F - ?

1)

Potential energy over grass:

Wp = m*g*H = 0.12*9.8*2.3 ≈ 2.7 J

2)

Work against the friction force of the grass:

A = F₁*S

3)

According to the law of conservation of energy:

A = Wp

F₁*S = Wp

F₁ = Wp / S = 2.7 / 0.067 ≈ 40 N

4)

Average grass resistance strength:

F = F₁ / 2 = 40 / 2 = 20 N

Answer: 00.99m

Explanation:

because

Answer: 0.099

Explanation: Khan

The statement that describes what happens in the graph is option (B).

The lander's velocity decreases toward the reference.

Velocity time graph is a type of graph that describes the change in velocity with respect to time of motion of an object.

Below is the basic explanation of the behavior of the average velocity of the particle with time.

Thus, we can conclude that between 20 and 25 seconds in the velocity tike graph, the average velocity of the object decreased towards the reference point (reference velocity = - 40 m/s.).

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Answer: [tex]2666.67 \text{ (or in 2 sigfigs, }2.7\times10^{3})[/tex]

Explanation: [tex]1\text{ }\dfrac{\text{N}}{\text{m}^2} = 1 \text{ Pa}\\\\P=\dfrac{F}{A}\\\\P=\dfrac{800\text{ N}}{0.3\text{ m}^2} = 2666.\overline6 \text{ N/m}^2 \approx 2666.67 \text{ Pa} \approx 2.7 \text{ kPa}[/tex]

Don't know if you need to convert to other units but typically in physics it's left as N/m^2 or Pa.

Answer:

23.6

Explanation:

The net force applied on the truck is 267.8 N.

The acceleration of the truck is 3.15 m/s².

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

Given parameters:

Force applied on the truck: F = 295 N.

Mass of the trick: m = 85 kg.

Weight of the truck: W = mg = 85 kg × 10 m/s² = 850 N.

The coefficient of friction between the rock and the ground is μ = 0.32.

Frictional resistance force applied on the truck: f = μ N =  μW

= 0.32×85 N

= 27.2 N.

Hence, net force applied on the truck = F - f = 295 N - 27.2 N = 267.8 N.

Hence, acceleration of the truck is = 267.8 N/85 kg = 3.15 m/s².

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Answer:

Explanation:

Given:

V₁ = 20 m/s

V₂  = 20 m/s

____________

V - ?

V = √ (V₁² + V₂²) = √ ( 20² + 20²) = 20·√2 ≈ 28 m/s

The magnitude of the resultant velocity of the ship is 40m/s. The correct option is B.

The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration.

Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. As the rate at which velocity changes, acceleration is likewise a vector quantity.

The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.

Here, it is given that,

Initial velocity = 20m/s

Final velocity = -20m/s, as current in the water begins to move from East to West.

We know that,

ΔV = Initial velocity - Final velocity

ΔV = 20 - (-20)

ΔV = 20+20

ΔV = 40m/s

Thus, the correct option is B.

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Answer:

candle for chemical energy.

Loudspeakers are the best example of electrical energy to sound energy conversion

Explanation:

The speed of the ball during centripetal motion is 4.75 m/s.

We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is

Fc = m . v²/R

where Fc is the centripetal force, m is mass, v is velocity and R is the radius.

From the question, we know that

m = 0.11 kg

F = 4 N

R = 0.62 m

The tension in the string is equal to centripetal force

T = Fc

4 = m . v²/R

4 = 0.11 . v² / 0.62

v² = 22.55

v = 4.75 m/s

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Forward thrust has positive values and reverse thrust has negative values.

Thrust is a sudden push or pull in a certain direction.

a)

Flight speed u = 150 km/h

1 km/h = [tex]\frac{1}{3.6}[/tex] km/s

therefore, 150 km/h =  41.67 km / s

The thrust force represents the horizontal or x-component of momentum equation:

[tex]T = m_{exhaust} * U_{exhaust} - U_{flight}[/tex]

T = 50 * (150 - 41.67)

T = 5416.67 N

Therefore, the value of forward thrust is 5416.67 N.

b)

Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,

thus thrust equation is:

[tex]T = m_{exhaust} * U_{exhaust} - U_{flight}[/tex]

T = 50 * (0 - 41.67)

T = -2083.5 N

Therefore, the thrust force T is -2083.5 N in the reverse direction.

c)

Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero because[tex]U_{exhaust} = U_{flight} = 0\\[/tex]

T = 0

Therefore, there is no difference in two velocities in x direction.

The given question is incomplete, the complete question is,

"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.

a. What is the forward thrust of this engine?

b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?

c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"

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The amount of work the two tugboats completed on the supertanker W = 3.12 × 10^9 joules .

Work is a physics term used to describe the energy transfer that takes place when an object is moved over a distance by an external force, at least some . The component of the force acting along the path multiplied by the length of the path can be used to calculate work if the force is constant. Mathematically, this idea is expressed as W = fd, where W is the work and f is the force multiplied by d, the distance. Work is completed when the force is applied at an angle of with respect to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as other methods.  However, the work is thought to be negative if the applied force is in opposition to the item's motion, indicating that energy is being pulled away from the object

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It is more difficult to get the object to move or keep moving on a rough surface.

The term friction has to do with the opposition to the motion of an object. We know that friction could lead to a reduction in the speed of the object. If the surface is so rough, the motion an object would be difficult due to a greater resistive force that keeps the object from moving.

We can then see that it would be more difficult for the object to begin to move on the rough surface rather, motion could easily start and be sustained on quite a smooth surface as we can see.

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On a rough surface, it is more challenging to move or maintain the motion of the object due to friction between the object and the surface due to contact.

An object experiences a push or pull as a result of interacting with another object. Each object is subject to a force whenever two objects interact.

According to newton's law, an object tries to maintain its position whether it is at resting or it is in motion. If the body is at rest then it tries to maintain its rest position and if the body is in motion then again it tries to maintain its motion. So, if the box is at rest, it is difficult to move the box in starting because of inertia, but once it is in motion it is easy to keep on going with the flow.

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a) The eccentricity of the orbit is 1.086. b) The orbital speeds at perigee and apogee is 5088 km/s. c) The period of the orbit is 8.516 minutes.

As a property, velocity is used to describe the characteristics of moving objects. It is the amount of movement of an object over a reasonably long period of time.

The satellite orbits the planet in an elliptical pattern. The semi-major axis and eccentricity of an elliptical orbit can be used to identify it.

The apogee distance (the distance between the satellite and the center of the Earth) and the perigee distance (the distance between the satellite and the edge of the planet) are, respectively, R a =R E +d a =6.3710 6 m+36010 3 m=6.7310 6 m.

R p = R E + d p =6.37 10 6 m + 180 10 3 m =6.55 10 6 m

R a =a(1+e) and R p =a(1e) are the relationships between the apogee and perigee distances and eccentricity e, respectively.

E is so little that the orbit is almost round.

The orbit would be a long, thin ellipse, on the other hand, if e is close to unity.

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The youngster may calculate the total distance the cart has travelled using the metre rule by exerting a constant force.

He can calculate how long it took the cart to travel that distance using the stopwatch.

The equation of constant acceleration motion can be used to determine the acceleration of the cart during that motion if the distance travelled by the cart and the time it takes to travel that distance is known.

S = ut + 1/2at²

S = mileage travelled

a = the cart's acceleration, and

t represents the amount of time spent.

The formula for this law is F=ma, where F is the applied force, m is the object's inertial mass, and an is the object's acceleration.

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The volume of the cylinder is 1.57 x 10⁻³ m³.

V = πr²h

V = π(5cm)²(20cm)(1m/100cm)³

V = 1.57 x 10⁻³ m³

The mass of the cylinder is 12.25 kg.

ρ =  m/v

m = ρv

m = (7800 kg/m³)(1.57 x 10⁻³ m³)

m = 12.25 kg