An athlete whirls a 6.41 kg hammer tied to the end of a 1.3 m chain in a simple horizontal circle where you should ignore any vertical deviations. The hammer moves at the rate of 1.64 rev/s. What is the centripetal acceleration of the hammer

Answers

Answer 1

The chain makes a circle of radius 1.3 m as it spins, so that 1 revolution of the hammer amounts to it moving a linear distance of 2π (1.3 m) = 2.6π m. Then the hammer's linear speed is

(1.64 rev/s) • (2.6π m/rev) = 4.264π m/s

and so the centripetal acceleration has magnitude

a = v²/r = (4.264π m/s)² / (1.3 m)

a ≈ 140 m/s²


Related Questions

how many significant figures are in 46 m?​

Answers

The significant figures in 46 is two.
The first is 4
And the second is 6

Why is science important for society? (2 points)

a
It helps make decisions based on scientific reasoning.

b
It proves that all questions can be answered using science.

c
It emphasizes the importance of human choice in decision making.

d
It shows that all social problems can be solved using scientific knowledge.

Answers

Answer:

i think its d

Explanation:

i took this quiz and got 100 percent

what are some possible results of constructive forces on earth's surface

Answers

Answer:

what are the choices

Explanation:

Answer:

Landforms are a result of a combination of constructive and destructive forces. Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.

Explanation:

A mass M is attached to a spring with spring constant k. When this system is set in motion with amplitude A, it has a period T. What is the period if the mass is doubled to 2M

Answers

Answer:

T' = o.707T

Explanation:

[tex]T = 1/2\pi \sqrt{k/m} \\\\m'=2m then\\T' = 1/2\pi \sqrt{k/m'}\\ = 1/2\pi \sqrt{k/2m}\\T' = \frac{(1/2\pi \sqrt{k/m}\\)}{1.4} T' = \frac{T}{1.4}\\T' = 0.707T[/tex]

Calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30 meter per seconds?

Answers

Explanation:

u = 0m/s

v = 30m/s

a = g = 10m/s²

s = H = ?

using the formula,

v² = u² + 2as

30² = 0² + 2(10)(H)

900 = 20H

H = 900/20

H = 45m

Answer:

the answer is

45m - height

A hollow ball, rolls down a hill that is 9 meters high. What is the velocity at the bottom of the hill?

Answers

Answer:

13.28m/s

Explanation:

Given

Distance covered by the ball S = 9m

initial velocity u = 0m/s

Required

velocity at the bottom of the hill (final velocity)

Using the equation of motion

v² = u²+2gS

v² = 0²+2(9.8)(9)

v² = 18(9.8)

v² = 176.4

v = √176.4

v = 13.28m/s

Hence the velocity at the bottom of the hill is 13.28m/s

PLEASE HELP!
A Cadillac Escalade car and a Mini Cooper car are both making a sharp right turn. The Escalade is four times more massive than the Mini Cooper. If both cars make the turn with the same constant speed, how do the centripetal forces acting on the two cars compare? Hint: use the Fc equation to consider how increasing the mass will affect the force.
The centripetal force cannot be determined without more information.
The centripetal force on the Mini Cooper is four times greater than that of the Cadillac Escalade.
The centripetal force on the Cadillac Escalade is four times greater than that of the Mini Cooper.
The centripetal force is the same for both cars.

Answers

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Suppose we wish to use a 8.0 m iron bar to lift a heavy object by using it as a lever. If we place the pivot point at a distance of 1.0 m from the end of the bar that is in contact with the load and we can exert a downward force of 562 N on the other end of the bar, find the maximum load that this person is able to lift (pry) using this arrangement (neglect the mass of the bar in this problem).

Answers

Answer:

W = 3934 N ,     m = 401.43 kg

Explanation:

This problem can be solved using the rotational equilibrium relation, where we place the reference system at the pivot point and assume that the counterclockwise turns are positive.

     ∑τ = 0

     F 7 - W 1 = 0

    W = F 7/1

     W = 562 7

     W = 3934 N

   

W = mg

     m = W / g

     m = 3934 / 9.8

     m = 401.43 kg

THIS QUESTION Blow my brains out I need helpppp y'all

Answers

Answer:

I am a math genus and this one is hard 3142 i think you multiple

A car traveling at point k the car travels south for 8.0 km it then travels west for 5.0 km next it travels for 4,0 what is the total displacement of the car

Answers

What is this?

Explanation:

A student walks 4 block east, 7 blocks west, 1 blocks east then 2 blocks west in an hour her average speed is____ block/hour

Answers

Answer:

2 m/s

Explanation:

The total time = 1 hour

The vertical displacement = 1 - 1

Vertical displacement = 0

Horizontal displacement = 4 - 2

Horizontal displacement = 2

Total displacement = sqrt (2^2 - 0^2)

Displacement - 2

Average velocity is displacement/time

= 2x1

=  2 m/s

The average velocity is 2 metres per second.

A block with a mass of 10 kg is pulled at a 20 degree angle with a force of 75 N. The force of friction acting on the block is 15 N. What is the acceleration of the block in m/s??
Round your answer to the nearest tenth. (Numbers Only!
Type your answer

Answers

There are 4 forces acting on the block:

• its weight (magnitude w = m g = 98 N, where m = 10 kg and g = 9.80 m/s²), pointed downward

• the normal force (mag. n), pointed upward

• friction (mag. f = 15 N), pointing opposite the direction of motion

• the pulling force (mag. p = 75 N), pointing at a 20° angle with the positive horizontal direction

Let the direction in which the block is being pulled be the positive horizontal direction, and upward the positive vertical direction. Split up each force into their horizontal and vertical components, then apply Newton's second law. We have a net horizontal force of

F = p cos(20°) - f = m a

where a is the acceleration of the block. The net vertical force is 0, since the block gets dragged along the surface and doesn't move up or down (presumably).

Solve for a :

(75 N) cos(20°) - 15 N = (10 kg) a

a ≈ 5.4 m/s²

The mass of Jupiter is 0.001 solar mass. The orbital period of Jupiter is 11.9 Earth years.

What is the distance between Jupiter and the Sun?

5.2 AU
41 AU
52 AU
410 AU

Answers

Answer:

The distance between Jupiter and the Sun is 5.2 AU.

The answer would be A: 5.2 Au away from the sun (AU is the unit that is the same length as the distance between Earth and the Sun)

WILL MARK BRAINLIEST -- The Earth’s velocity is shown by a red vector. Which best describes the Earth’s velocity?
a. It is constant in magnitude and direction
b. It is constant in magnitude but not constant in direction
c. It is not constant in magnitude but is constant in direction
d. It is not constant in magnitude or direction

Answers

i would choose C. i’ve had this on my test :)

A stone sphere of radius 7.00 m rests in a flat field. Relative to the ground, what is the gravitational potential energy of a 90.0-kg person sitting on the very top of the sphere?
a. 7.76 x 104 J
b. 1.23 x 104 J
c. 3.88 x 104 J

Answers

Answer:

(B)  1.23 x 10 J

Explanation:

Given;

radius of the sphere, r = 7.0 m

diameter of the sphere, d = 2r = 14.0 m

mass of the person sitting on the sphere, m = 90.0 kg

The gravitational potential energy of the person is given by;

P.E = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

h is the height above the ground level = d = 14.0 m

P.E = mgh

P.E = (90)(9.8)(14)

P.E = 12348 J

P.E = 1.2348 x 10 J

Therefore, the gravitational potential energy of the person is 1.2348 x 10 J

Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.400 mmmm wide. The diffraction pattern is observed on a screen 2.90 mm away. Define the width of a bright fringe as the distance between the minima on either side.

Required:
a. What is the width of the central bright fringe?
b. What is the width of the first bright fringe on either side of the central one?

Answers

Answer:

a

 [tex]y_1 = 0.004589 \ m[/tex]

b

 [tex]y_2 =0.009179 \ m[/tex]

Explanation:

From the question we are told that

   The wavelength of the red light is  [tex]\lambda _r = 633 \ nm = 633 *10^{-9} \ m[/tex]

    The width of the slit is  [tex]d = 0.40 mm = 0.40 *10^{-3} \ m[/tex]

    The distance of the screen from the point of diffraction is [tex]D = 2.9 \ m[/tex]

Generally the width of the central bright fringe is mathematically represented as

       [tex]y_1 = \frac{\lambda * D}{d}[/tex]

=>    [tex]y_1 = \frac{633 *10^{-9} * 2.90 }{0.40 *10^{-3}}[/tex]

=>    [tex]y_1 = 0.004589 \ m[/tex]

Generally the width of the first bright fringe on either side of the central one is mathematically represented as

     [tex]y_2 = 2 * y_1[/tex]

=>   [tex]y_2 = 2 * 0.004589[/tex]

=>   [tex]y_2 =0.009179 \ m[/tex]

What is the index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum

Answers

Explanation:

We need to find the index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum.

The wavelength in any medium is given by :

[tex]\lambda_m=\dfrac{\lambda}{n}[/tex]

Where, [tex]\lambda[/tex] is wavelength in vacuum and n is refractive index of the medium.

[tex]n=\dfrac{\lambda}{\lambda_m}\\\\n=\dfrac{\lambda}{0.671\lambda}\\\\=\dfrac{1}{0.671}\\\\=1.49[/tex]

So, the medium can be PMMA (acrylic, plexiglas, lucite, perspex) which have a refractive index of 1.49.

The index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

What is the index of refraction of a material?

The index of refraction of a material is the ratio of wavelength of the wave in vacuum to the wavelength of the wave in the given medium.

The index of refraction is inversely proportional to the wavelength. It can be find out using the following formula.

[tex]n=\dfrac{\lambda}{\lambda_m}[/tex]

Here, (λ) is the wavelength in vacuum and (λm) is the wavelength in a medium.

The index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum (0.671×λ).

Plug in the values in the above formula,

[tex]n=\dfrac{\lambda}{0.671\times\lambda}\\n=1.49[/tex]

Thus, the index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

Learn more about the index of refraction here;

https://brainly.com/question/10729741

A cannonball is launched horizontally with an initial speed of 48.0m/s. Determine
all unknowns.
m/s
initial speed:
initial horizontal speed:
initial vertical speed:
A/s
m/s
A

Answers

• initial speed: 48.0 m/s

The cannonball is shot horizontally, so

• initial horizontal speed: 48.0 m/s

• initial vertical speed: 0

big ideas
key questions and terms notes

Answers

Answer:

what i and confused

Explanation:

Answer:

nerd

Explanation:

I H4+3 U

2. What are the three phases of water?
solid, liquid, gas
conduction, convection, radiation
high, medium, low
positive, negative, neutral

Answers

Answer:

solid, liquid, gas

Explanation:

The three phases of water are the three states of matter water can be found in, and that is:

solid (as in ice)

liquid (as in water)

gas (as in water vapor)

Scientists monitoring and predicting future volcanic eruptions can givr people living near Mt/ St. Helens prior warning so that they can take action. What additional measures could help reduce the negative impacts of a future eruption?

Answers

Answer:

first thing first they really have to concern about this,

and second one is people should leave those hazardous places

Answer:

-Emergency evacuation roadways could be designed.

-An Evacuation plan could be organized.

-Warning Sirens could be designed.

Explanation:

Those 3 are the answer.


A block of cheese is pulled on by a string and slides to the right along a rough surface.
What is the correct free body diagram for the block of cheese?

Answers

Answer:

Explanation:

KHAN ACADEMY

The free body diagram of the cheese block is attached with the answer.

What is free body diagram?

A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.

Given is a block of cheese is pulled on by a string and slides to the right along a rough surface.

The free body diagram of the cheese block is given with the image attached. The force applied for the forward motion of the block is greater in magnitude than the frictional force. The weight of the block is balanced by the normal reaction force. The following mathematical relations can be written -

F - F(f) = ma

and

mg = N

m = N/g

So -

F - F(f) = (N/g)a

Therefore, the free body diagram of the cheese block is attached with the answer.

To solve more questions on Free body diagram, visit the link below-

https://brainly.com/question/18936554

#SPJ2

Average formula is...?

Answers

Answer:

total sum of all numbers/ number of items in the set

Explanation:

Scientists from NASA discovered a Nebula with doubled the mass as the Nebula from which our Solar System formed. Explain the similarities and differences between the Solar System that will form from that Nebula and our Solar System. (Note: your response must include a discussion of gravity.)

Answers

Answer:

it forms another one

Explanation:

our solar system was formed by a nebula so that nebula is supposed to form another one

Some nitrogen at 80.0 psi gauge pressure occupies 13.0 ft^3. Find its volume, in ft^3, at 50.0 psi gauge pressure.

Answers

Answer:

20.8 ft³

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 80 psi

Initial volume (V1) = 13 ft³

Final pressure (P2) = 50 psi

Final volume (V2) =?

The new volume of the gas can be obtained by using the Boyle's law equation as shown below:

P1V1 = P2V2

80 × 13 = 50 × V2

1040 = 50 × V2

Divide both side by 50

V2 = 1040 / 50

V2 = 20.8 ft³

Thus, the volume of the gas at a pressure of 50 psi is 20.8 ft³

What is the critical angle for light traveling from crown glass (n = 1.52) into water (n = 1.33)?

42 degrees
48 degrees
57 degrees
61 degrees

Answers

Answer:

61 degrees, I just did the test.

Explanation:

Answer: 61 degrees

Explanation:

I just did the question and got it right

A rock of mass 0.340 kg is spun horizontally at the end of a wire that has a diameter of 1.00 mm. If the wire gets stretched by 2.00 mm when the rock moves at a speed of 19.0 m/s, what is the Young's modulus of the wire?

Answers

Answer:

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Explanation:

First we will find the centripetal force acting on the wire as follows:

F = mv²/r

where,

F = Force = ?

m = mass of rock = 0.34 kg

v = speed = 19 m/s

r = length of wire

Therefore,

F = (0.34)(19)²/r

F = 122.74/r  

now, we find cross-sectional area of wire:

A = πd²/4

where,

A = Area = ?

d = diameter of wire = 1 mm = 0.001 m

Therefore,

A = π(0.001)²/4

A = 7.85 x 10⁻⁷ m²

Now, we calculate the stress on wire:

Stress = F/A

Stress = (122.74/r)/(7.85 x 10⁻⁷)

Stress = 1.56 x 10⁸/r

Now, we calculate strain:

Strain = Δr/r

where,

Δr = stretch in length = 2 mm = 0.002 m

Therefore,

Strain = 0.002/r

now, for Young's modulus (Y):

Y = Stress/Strain

Y = (1.56 x 10⁸/r)/(0.002/r)

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Is a man kicking ball potential or kinetic?

Answers

Kinetic because the man is using energy to kick the ball

Hope this helps :)

A laser (electromagnetic wave) has the maximum electric field strength of 1.0x1011 V/m. What is the force the laser applies on a mirror (totally reflective) of 5.0 mm2 area? A. 2.76 x105N B. 1.21 x106N C. 1.94 x106N D.4.43 x105 N E. 7.82 x104N

Answers

Answer:

The correct option is  D

Explanation:

From the question we are told that

  The maximum electric field strength is  [tex]E = 1.0 *10^{11} \ V/m[/tex]

   The  area is  [tex]A = 5.0 \ mm^2 = 5.0 *10^{-6} \ m^2[/tex]

Generally the force the laser applies is mathematically represented as

       [tex]F = \epsilon_o * E ^2 * A[/tex]

Here  [tex]\epsilon_o = 8.85*10^{-12} C/(V \cdot m)[/tex]

      [tex]F = 8.85*10^{-12} * (1.0 *10^{11}) ^2 * 5.00*10^{-6 }[/tex]

=>   [tex]F = 4.43 *10^{5} \ N[/tex]

Is a bow and arrow by themselves potential or kinetic?

Answers

Answer:

Potential energy

Explanation:

When the string is released, the potential energy is converted to kinetic energy in the movement of the arrow. The string pushes the arrow out and is the driving force behind the motion.

It is potential energy until u pick it up and fire an arrow.
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