An airplane starts from rest and accelerates at a constant 3.00 m/s2
for 20.0 s. What is its displacement in this time?
Answers
Answer:600 m
Explanation:
Related Questions
To crack a pecan, you apply a force of 55 N to the nutcracker. The nutcracker applies a force of 740 N to the pecan. What is the mechanical advantage of the nutcracker?
Answers
Answer:
Explanation:
mechanical advantage = output force / input force
= 740 N / 55 N
= 13.45
surface?
What is the mass of an object that experiences a gravitational force of 700 N near the Earth's surface
Answers
Answer:
70kg
Explanation:
Given parameters:
Gravitational force = 700N
Unknown:
Mass of the person = ?
Solution:
The weight is gravitational force on the person and can be expressed as;
W = mg
m is the mass
g is the acceleration due to gravity = 10m/s²
So;
700 = m x 10
m = 70kg
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → 2H2O + 2CO2?
Answers
Answer:
The equation needs to be balanced. There are fewer oxygen atoms in the equation than hydrogen or carbon. ... There is an equal number of each element on both sides of the equation.
Explanation:
how do pteropods get energy
Answers
Answer:
Pteropods are little mollusks (related to snails, slugs and squid) that drift around in ocean currents, feeding on nutrient-rich plankton. Their rich diet makes them delicious to many fish. Seals eat many fish, and sharks eat seals and fish, so there it is: not even 6 degrees of shark separation.
Explanation:
You are an astronomer on planet tirth, which orbits a distant star. it has recently been accepted that tirth is spherical in shape, though no one knows its size. one day, you learn that on the equinox your sun is directly overhead in the city of tyene, located 750 kilometers due north of you. on the equinox, you go outside in alectown and observe that the altitude of your sun is 87.0 ∘.
Answers
Answer:
The circumference of planet tirth is [tex]C = 90000 \ km[/tex]
Explanation:
From the question we are told that
The distance of tyene from the observer is [tex]d = 750 \ km[/tex]
The altitude of the sun from the equinox is [tex]\theta_s = 87.0^o[/tex]
Generally given that on the equinox your sun is directly overhead in the city of tyene , then the altitude of the tyene from the equinox is [tex]\theta_e = 90 ^o[/tex]
Generally the angular distance between tyene and the sun as observed from the equinox is mathematically represented as
[tex]\theta _d = \theta_e - \theta_s[/tex]
=> [tex]\theta _d = 90 -87[/tex]
=> [tex]\theta _d =3^o[/tex]
Generally the ratio of [tex]\theta _d =3^o[/tex] to [tex]360^o[/tex] which is the total angle in a circle is equal to the ratio of [tex]d = 750 \ km[/tex] to the circumference of the planet
So
[tex]\frac{\theta_d}{360} = \frac{750}{C}[/tex]
=> [tex]\frac{3}{360} = \frac{750}{C}[/tex]
=> [tex]C = 90000 \ km[/tex]
PLEASE HELP!!!!!!!!
Answers
Answer:
the is D
Explanation:
An action-reaction force pair
Answer:
An action-reaction force pair
different types of families and describe each
Answers
Answer:
there are many types of family but main is 2
Explanation:
1). joint family 2). nucleic family joint family has mother father grandfather grandmother uncle aunty children. and nucliec family has mother father and childrens
Answer: Childless family, Extended family, Step family, Grandparent family, Single parent family, and Nuclear family.
Explanation:
A rock is thrown upwards at 13.5 m/s. How long does it take to fall back to the ground?
Answers
Un auto se mueve con velocidad constante de 20 m/s y la mantiene durante 20 s. Después se le aplica una aceleración constante y aumenta su velocidad a 40 m/s, recorriendo durante el cambio de velocidad una distancia de 200 m ¿Cuál es el tiempo empleado en el recorrido total?
Answers
Answer:
26.67 s
Explanation:
v = Velocidad final = 40 m/s
u = Velocidad inicial = 20 m/s
[tex]t_1[/tex] = Tiempo inicial = 20 s
[tex]t_2[/tex] = Tiempo empleado durante la aceleración
a = Aceleración
s = Desplazamiento del automóvil durante la aceleración = 200 m
De las ecuaciones lineales de movimiento tenemos
[tex]v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{40^2-20^2}{2\times 200}\\\Rightarrow a=3\ \text{m/s}^2[/tex]
[tex]v=u+at_2\\\Rightarrow t_2=\dfrac{v-u}{a}\\\Rightarrow t_2=\dfrac{40-20}{3}\\\Rightarrow t_2=6.67\ \text{s}[/tex]
El tiempo necesario para acelerar es 6.67 s
El tiempo total necesario para toda la ruta es [tex]t=t_1+t_2=20+6.67=26.67\ \text{s}[/tex].
Determine the magnitude of the force for each direction. A. Add the forces that are applied in the same direction. B. Subtract forces applied in the opposite direction
Answers
Answer:
A) R = F1 + F2
B) R = | F1 - F2 |
Explanation:
A) For forces acting in the same direction
we will add up the forces : lets assume the forces to be F1 , F2
Then the magnitude of the forces acting in the same direction will be
R = F1 + F2
B) For forces acting in the opposite direction
we will subtract the forces i.e. stronger force - weaker force . assuming the forces to be F1 , F2
Hence the magnitude of the resultant force = R = | F1 - F2 |
Un automóvil se mueve hacia el norte siguiendo una trayectoria rectilínea con una velocidad constante, recorre 195 Km cada 1.3 h. ¿Calcula la velocidad con que se mueve?
Answers
Answer:
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Explanation:
La velocidad es una magnitud que expresa la relación entre el espacio recorrido por un objeto, el tiempo empleado para ello y su dirección.
Es decir, la velocidad se define como la relación que se establece entre la distancia recorrida y el tiempo transcurrido en el movimiento de un móvil.
Se puede calcular la magnitud de la velocidad utilizando la siguiente expresión:
[tex]velocidad=\frac{distancia}{tiempo}[/tex]
En este caso:
distancia= 195 kmtiempo= 1.3 hReemplazando:
[tex]velocidad=\frac{195 km}{1.3 h}[/tex]
Resolviendo:
velocidad=150 [tex]\frac{km}{h}[/tex]
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
While rowing in a race, John uses his arms to exert a force of 155 N per stroke
while pulling the oar 0.7500 m. How much work does he do in 25 strokes?
Answers
Answer:
Workdone = 2906.25J
Explanation:
Given the following data;
Force, F = 155
Distance, d = 0.75
Stroke, s = 25
Mathematically, work done is given by the formula;
Work done = force * distance * stroke
[tex] W = F * d * s[/tex]
Where,
W is the work done
F represents the force acting on a body.
d represents the distance covered by the body.
s is the number of strokes.
Substituting into the equation, we have;
[tex] Workdone = 155*0.75*25[/tex]
Workdone = 2906.25J
A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum height reached by the ball?
Answers
Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]
Therefore, the maximum height reached by the ball is 2.84 m
The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.
By drawing appropriate lines on the diagram using a ruler to determine:
a.)The horizontal component of the 5N force.
b.)The vertical component of the 5N force .
Answers
Given :
The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.
To Find :
By drawing appropriate lines on the diagram using a ruler to determine:
a.)The horizontal component of the 5N force.
b.)The vertical component of the 5N force.
Solution :
Horizontal component is given by :
=F cos θ
=5 cos 30°
= 5×0.866
= 4.33 N
Vertical component is given by :
= F sin θ
= 5 sin 30°
= 5×0.5
= 2.5 N
Therefore, horizontal and vertical component are 4.33 N and 2.5 N.
Hence, this is the required solution.
a small asteroid of mass 125 kg is orbiting a planet that has a mass of 3.52x 10^13 what is the radial distance between the asteroid and the planet of the tangential velocity of the asteroid is 0.034m/s
Answers
Answer:
r = 2.031 x 10⁶ m = 2031 km
Explanation:
In order for the asteroid to orbit the planet, the centripetal force must be equal to the gravitational force between asteroid and planet:
Centripetal Force = Gravitational Force
mv²/r = GmM/r²
v² = GM/r
r = GM/v²
where,
r = radial distance = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Planet = 3.52 x 10¹³ kg
v = tangential speed = 0.034 m/s
Therefore,
r = (6.67 x 10⁻¹¹ N.m²/kg²)(3.52 x 10¹³ kg)/(0.034 m/s)²
r = 2.031 x 10⁶ m = 2031 km
Calculate the power of a crane if it lifts a load of 2400N through a height of 10m in 15 seconds.Also express the power in horse power.
Answers
Answer:
2.08 hpExplanation:
The power of the crane can be found by using the formula
[tex]p = \frac{f \times d}{t} \\ [/tex]
f is the Force
d is the distance
t is the time taken
From the question we have
[tex]p = \frac{2400 \times 10}{15} = \frac{24000}{15} \\ [/tex]
We have
power = 1600 W
But 1 W = 0.0013 hp
So 1600 = 2.08 hp
We have the final answer as
2.08 hpHope this helps you
Please help ill give you 30 points
Answers
Answer: 14 inches.
Explanation: The radius of this circle is 7 inches, so the diameter is 2(7) = 14 inches. The diameter is 14 inches.
Zero is the freezing temperature of water on which temperature scale?
Kelvin
Fahrenheit
Pascal
Celsius
Answers
Answer:
Celsius. i think! I might be wrong
Which has the most momentum?
Select one:
A. 100 kg at rest
B. 20 kg at 2 m/s
C. 5 kg at 50 m/s
D. 10 kg at 5 m/s
Answers
Answer: C
Explanation:
A: 100kg*0m/s (obviously not answer)
B: 20kg*2m/s (=40)
C: 5kg*50m/s (=250, safe bet this one is it)
D: 10kg*5m/s (=50)
5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
To calculate momentum, we use the formula:
Momentum (p) = Mass (m) × Velocity (v)
Let's calculate the momentum for each option:
A. 100 kg at rest
Momentum = 100 kg × 0 m/s = 0 kg m/s
B. 20 kg at 2 m/s
Momentum = 20 kg × 2 m/s = 40 kg m/s
C. 5 kg at 50 m/s
Momentum = 5 kg × 50 m/s = 250 kg m/s
D. 10 kg at 5 m/s
Momentum = 10 kg × 5 m/s = 50 kg m/s
Therefore, 5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
To know more about momentum here
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Which describes the positions on a horizontal number line?
Answers
Answer:
All points to the left of zero are negative numbers. All points to the right of the zero are positive numbers. Zero is generally considered the center of the number line since both positive and negative numbers (more specifically integers) are considered to go to infinity. (Negative infinity or positive infinity)
Explanation:
Whoops sorry I accidentally commented the first time
How do the individual forces compare when the rider experiences a sensation being lighter than his normal weight ? What is the acceleration direction when this occurs ?
Answers
Answer:
When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.
Explanation:
A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.
Two forces are acting on the person; the force of gravity and the upward normal force from the elevator.
When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight. N = mg + ma
When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight. N = mg - ma
However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight. N = mg
When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness. N = (mg - mg) = 0
El extremo de una cuerda se mueve de tal manera que las partículas de la cuerda emplean 0.25 segundos para producir una vibración. ¿Cuál es el periodo? Y ¿Cuál es la frecuencia de la vibración producida
Answers
Responder:
T = 0.25 segundos
f = 4 Hz
Explicación:
Paso uno:
datos dados
se nos dice que las partículas tardan 0,25 segundos en completar una vibración
por lo tanto, el período es de 0,25 segundos
¿Qué es un período de vibración?
Un período T es el tiempo necesario para que un ciclo completo de vibración pase por un punto determinado.
la expresión para el período se da a continuación.
T = 1 / f
¿Cuál es la frecuencia de vibración?
Básicamente, se refiere a la frecuencia con la que ocurren las vibraciones.
la frecuencia es una tasa, se expresa como la inversa del período
f = 1 / T
t = 1 / 0.25
f = 4 Hz
which event is an example of melting?
Answers
Answer:
welding metal
Explanation:
HELP PLZ IM BEING TIMED!!
What is the vertical acceleration of a dart that is launched horizontally with an initial velocity of 2.3 m/s?
-9.8 m/s
2 0 m/s2
2.3 m/s2
9.8 m/s2
Answers
Answer:
-9.8
Explanation:
EDGE 2021
The vertical acceleration of a dart is equal to the negative of acceleration due to gravity (- g). The vertical acceleration of the dart is equal to -9.8m/s². Therefore, option (1) is correct.
What is the acceleration due to gravity?Acceleration due to gravity is the acceleration acquired by a body due to gravitational force. As gravity has both magnitude and direction, so it is a vector quantity. Acceleration due to gravity is expressed by the symbol 'g'. The SI unit of g is m/s² and the value of g (acceleration due to gravity) on the surface of the earth is 9.8 m/s².
Let us suppose a body with mass (m) is dropped from a height ‘h’ above the surface of the earth with mass (M), it starts to move downwards with an increase in velocity to the earth's surface.
The body starts to accelerate toward the earth’s center under the action of gravitational force which is at a distance ‘r’.
Then, ma = GMm/r²
a = GM/r²
Therefore, the value of the acceleration due to gravity (g) = GM/r2.
Any object freely falling to the surface of the earth has acceleration due to gravity is 9.8m/s².
If the object moves away from the surface of the earth then it experiences the gravitational pull of the earth. Therefore, the acceleration of dart vertically is equal to -g.
Therefore, the vertical acceleration of the dart is equal to -9.8m/s².
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In the diagram below, a 10-kilogram ball is fired with a
velocity of 500 meters per second from a 1,000 kilogram
cannon. What is the recoil velocity of the cannon?
A. 5 m/s
B. B) 2 m/s
C. C) 10 m/s
D. D) 500 m/s
Answers
Answer:
A) 5m/s
Explanation:
Momentum of ball in one direction=momentum of cannon in other direction
mv = mv
(10)(500)=(1000)v
5000=1000v
∴v=5m/s
When a ball is fired with a velocity its momentum remains conserved. The recoil velocity of the cannon is 5m/s.
What is recoil velocity?
The velocity with which the cannon is pushed backwards after firing is called the recoil velocity.
The momentum remains conserved . So, according to the momentum conservation principle, initial momentum is equal to the final momentum.
Mu +mu=Mv +mv
where, M is the mass of cannon and m is the mass of ball.
u is the initial velocity and v is the final velocity.
10 kg ball is fired with a velocity of 500 meters per second from a 1,000 kg cannon.
mu = Mv
(10)(500)=(1000)v
5000=1000v
v=5m/s
Thus, the recoil velocity of the cannon is 5 m/s.
Learn more about recoil velocity.
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Which choice is not an example of a molecule? O3 NCl3 F H2O2
Answers
Answer:
The answer is F
Explanation:
F stands for Fluorine, which is an element and consists of one atom.
Answer:
f
Explanation:
i took quiz
what is a science book
Answers
Answer:
A book containing information on various types of science related topics.
Answer: a science book is a textbook you use for science.
Si unit of thermal conductivity is
Answers
Answer: Watts
Explanation: In the International System of Units (SI), thermal conductivity is measured in watts per meter-kelvin (W/(m•k)).
I need help on this question
Answers
Answer:
the 3rd one im pretty sure
Explanation:
Answer:the answer is answer 3
Explanation:
A 100 Watt lightbulb uses 360000 Joules ever hour. How many lightbulbs could be powered for one hour by the energy from the Hiroshima bomb?
Answers
Answer:
200 million electric light bulbs.
Explanation:
First, we must calculate the power of the electric bulb, for this, we use the following equation that relates the energy as a function of time.
[tex]P=E/t[/tex]
where:
P = power [W] (units of watts)
E = energy = 360000 [J] (units of Joules)
t = time = 1 [h] = 3600 [s]
[tex]P = 360000/3600\\P= 100[W][/tex]
In 1 hour 1 electric lightbulb produces 100 [W], now we need to know the amount of energy produced by the Hiroshima bomb. A search made by the internet give us the data of 20 [GW] or [Gigawatts].
We need to remember that 1 Giga = 1 x10⁹
Energy Hiroshima explosion= 20*10⁹[W]
Amount = (20x10⁹)/100
Amount = 200 x10⁶ [bulbs]
That is, we would need an amount of 200 million electric light bulbs.