The radius of the circle in which the plane is flying is 1887 m.
What is aerodynamic lift?The aerodynamic lift is the force that keeps the aircraft flying in the air.
Let the aerodynamic lift be F1 sinθ= mv^2/R ---- (1)
and F1 cosθ= mg --------- (2)
Equating (1) and (2) and eliminating the mass;
R = v^2/ g tanθ
Where v = 490 km/h or 136 m/s
R = (136)^2/9.8 * tan 45
R = 18496/ 9.8
R = 1887 m
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Which layer of the sun can easily be viewed by visible light?.
The magnetic field 0.225 m from a
wire is 4.29 x 10-7 t. how much
current is flowing through the wire?
need asap please will give brainiest
Answer:
i = 0.483 A
Explanation:
B = [tex]\frac{U.i}{2pi*r}[/tex]
So, here the r is 0.225 m
The Magnetic field is 4.29 x [tex]10^{-7}[/tex] t
U. = 4π x [tex]10^{-7}[/tex] x i
4.29 x [tex]10^{-7}[/tex] = (4π x [tex]10^{-7}[/tex] x i) / (2π * 0.225)
Cutting [tex]10^{-7}[/tex]
4.29 = [tex]\frac{4π * i}{2π * 0.225}[/tex]
4π and 2π canceled, left with 2
4.29 = [tex]\frac{2i}{0.225}[/tex]
4.29*0.225 = 2i
0.96525 = 2i
i = [tex]\frac{0.96525}{2}[/tex]
i = 0.482625 A
Rounding to 3 digits after decimal, we get
∴ i = 0.483 A
A machine which has an energy loss of 10% will have efficiency of
Answer:
90%
Explanation:
if you lose 10% of a 100 you get 90
3
What increase in temperature will result if 225.0 g of copper absorbs 5000 J of
heat energy? The specific heat of copper is 0.385 J/g °C
Calculate: Q=m XCXAT
(2 points)
57.7 °C
433.125 °C
274.6 °C
22.2 °C
The increase in temperature that will result if 225.0 g of copper absorbs 5000 J of heat energy is 57.72°C.
How to calculate temperature change?The temperature change of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperature5000 = 225 × 0.385 × ∆T
5000 = 86.63∆T
∆T = 5000/86.63
∆T = 57.72°C
Therefore, the increase in temperature that will result if 225.0 g of copper absorbs 5000 J of heat energy is 57.72°C.
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______ is how something feels.
Color
Volume
Length
Temperature
Texture
Answer:
Texture is how something feels.
What will happen to the force between 2 charged objects if the mass of one of the charges is doubled and the distance between them is double?
The long structure of small intestine is accommodated in small space within our body. Comment.
Which of the following is correct for speed?
A vector
Depends on Distance
Unit is a meter/second (m/s)
A vector
Depends on Displacement
Unit is a meter/second (m/s)
A scalar
Depends on Distance
Unit is a meter/second (m/s)
A scalar
A
Depends on Displacement
Unit is a meter/second (m/s)
Answer:
Speed is a "scalar" quantity
(C) is the correct answer
An object could travel at 10 m/s to some point and then return to the origin at 10 m/s for an average speed of 10 m/s, however it's displacement over that time would be zero for a net velocity of zero.
A boy pushes a toy car along the floor at a steady speed. Are the forces on it balanced
or unbalanced?
Answer:
the forces are balanced :)
Explanation:
A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 32.5 m/s. With what maximum speed can it go around a curve having a radius of 66.0 m
Answer:
Approximately [tex]21.6\; {\rm m\cdot s^{-1}}[/tex], assuming that the coefficient of kinetic friction between the tires and the ground stays the same.
Explanation:
Let [tex]\mu_{k}[/tex] denote the coefficient of kinetic friction between the tires and the ground.
Let [tex]m[/tex] denote the mass of the truck. Let [tex]g[/tex] denote the gravitational field strength. The weight of this truck would be [tex]m\, g[/tex]. Since the curve is flat, the magnitude of the normal force [tex]F_\text{normal}[/tex] between the truck and the ground would also be [tex]m\, g\![/tex].
Let [tex]v = 32.5\; {\rm m\cdot s^{-1}}[/tex] denote the speed at which the truck goes around the curve with a radius of [tex]150\; {\rm m}[/tex]. The (horizontal) centripetal acceleration of the truck would be:
[tex]\displaystyle a = \frac{v^{2}}{r}[/tex].
The horizontal net force on the truck (of mass [tex]m[/tex]) would need to be exactly:
[tex]\displaystyle F_\text{net} = m\, a = \frac{m\, v^{2}}{r}[/tex].
The friction between the tires of the truck and the ground is the only horizontal force on the truck. Thus, this friction would need to supply the entirety of this horizontal net force:
[tex]\displaystyle F_\text{friction} = F_\text{net} = \frac{m\, v^{2}}{r}[/tex].
Notice that increasing [tex]v[/tex] would require an increase in the kinetic friction between the truck, [tex]F_\text{friction}[/tex]. However, since [tex]F_\text{friction}\![/tex] is at most [tex]\mu_{k}\, F_\text{normal}[/tex] (which is equal to [tex]\mu_{k}\, m\, g[/tex]):
[tex]\begin{aligned}\frac{m\, v^{2}}{r} &= F_\text{friction} \\ & \le \mu_{k}\, F_\text{normal} \\ &= \mu_{k}\, m\, g\end{aligned}[/tex].
Therefore, when the radius of the curve is [tex]r^{\prime}[/tex], the maximum velocity of this truck would be:
[tex]\begin{aligned}v^{\prime} &= \sqrt{\mu_{k}\, g\, r^{\prime}}\end{aligned}[/tex].
Likewise, it is possible to express [tex]\mu_{k}[/tex] in terms of [tex]r[/tex], [tex]g[/tex], and max speed [tex]v[/tex]:
[tex]\displaystyle \mu_{k} = \frac{v^{2}}{r\, g}[/tex].
Substitute this expression for [tex]\mu_{k}[/tex] back into the expression for [tex]v^{\prime}[/tex]:
[tex]\begin{aligned}v^{\prime} &= \sqrt{\mu_{k}\, g\, r^{\prime}} \\ &= \sqrt{\frac{v^{2}}{r\, g}\, g\, r^{\prime}} \\ &= \sqrt{v^{2}\, \frac{r^{\prime}}{r}}\end{aligned}[/tex].
Given that [tex]v = 32.5\; {\rm m\cdot s^{-1}}[/tex], [tex]r = 150\; {\rm m}[/tex], and [tex]r^{\prime} = 66.0\; {\rm m}[/tex]:
[tex]\begin{aligned}v^{\prime} &= \sqrt{v^{2}\, \frac{r^{\prime}}{r}} \\ &= \sqrt{(32.5\; {\rm m\cdot s^{-1}})^{2} \times \frac{66.0\; {\rm m}}{150\; {\rm m}}} \\ &\approx 21.6\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
2 Using the formula GPE = mxgxh, what are
you solving for?
A. Potential Energy
B. Kinetic Energy
C. Electromagnetic Energy
D. Mass Energy
Answer:
A
Explanation:
THAT is th equation for Potential Energy
A 100 kg object moving at 20 m/s comes to a stop over a distance of 40 m. what is the coefficient of kinetic friction between the object and the ground? (show work please)
Answer:
.5097
Explanation:
Original KE = 1/2 (100)(20)^2 = 20 000 J
the force of friction must work this hard to stop the object in 40 m
Ff *40 = 20 000
Ff = 500 = Fn u u = coeff of kinetic friction
500 = (100)(9.81) u
u = .5097
The kinetic friction coefficient between the object and the ground is 0.5097.
What is kinetic friction?The friction force to normal force ratio experienced by a body moving on a dry, non-smooth surface is denoted by the kinetic friction coefficient k.
Formula :
μk = [tex]\frac{Ff}{Fn}[/tex]
The types and values of the coefficient of friction are determined by the type of resistive force. The coefficient of friction can be determined through experiments such as calculating the amount of power required to overcome friction or calculating the angle at which an object begins to slide off an incline. The kinetic friction coefficient, or k, is the ratio of friction force to normal force felt by a body moving on a dry, uneven surface. Friction can be classified as static, kinetic, deformation, molecular, or rolling. Each one has a different coefficient of friction. Kinetic friction is the force that prevents normal motion after static friction has been overcome.Therefore,
Original KE = 1/2 (100)(20)^2 = 20 000 J
the force of friction must work this hard to stop the object in 40 m
Ff × 40 = 20 000
Ff = 500 = Fnμ μ = coeff of kinetic friction
500 = (100)(9.81) μ
μ = 500/(100 x 9.81)
μ = .5097
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6. What quantity does the gradient of the distance - time graph represent? Justify your answer.
Answer:
speed
Explanation:
In a distance-time graph, the gradient of the line is equal to the speed of the object. The greater the gradient (and the steeper the line) the faster the object is moving.
PLEASE HELP ME I ATTACHED A SCREEN SHOT PLS SOLVE ASAP
Answer:
B. Negative acceleration means this car is slowing down.
Explanation:
for the other screenshot
Average acceleration = change in velocity /change in time.
[a = ∆V/∆t] —this the formula.
NOTE:
u = initial velocity (velocity it started with)
v = final velocity (velocity it ended with)
t = time {the time you were given)
a = acceleration.
listing out our givens:
u =o —(the unit is m/s)
v = 40 —(the unit is also m/s)
t = 0.08 —(the unit is s) "s" means second(s).
Soo
a = 40-0 / 0.08 = 500 m/s² ( unit for velocity is m/s²)
( Remember when using the formula we subtract the initial from the final velocity.........I mean we remove the initial from final) if not you will get a negative answer or wrong answer).
also note: final velocity is always bigger in value than initial velocity EXCEPT it is in deceleration meaning for example a car that was speeding is gradually stopping then initial (the one it started with) will be bigger than the one it ended with (because as it gradually stops the speed reduces).
VELOCITY is speed in a specified direction.
you're super free to ask any questions
Good luck ✅.
What is an example of an analogue signal?
Examples of analog signals are Human voice, Thermometer, Analog phones etc.
What is signal?Signal is defined as an electromagnetic wave that carries information through a medium. In this, the data is converted into electromagnetic signal which may be analog or digital and then sent from sender to receiver.
Signal which are continuous as time varies are analog signals.
Thus, examples of analog signals are Human voice, Thermometer, Analog phones etc.
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Answer:
Examples of analog signals are Human voice, Thermometer, Analog phones etc. Examples of digital signals are Computers, Digital Phones, Digital pens, etc.
What is the radius of a cone with a volume of 96π cubic inches and a height of 18 inches? 1. rewrite the formula using the base area: 2. substitute the values into formula: 3. simplify the right side: 4. undo the multiplication of 6π: 5. undo the square: what is the radius of the cone? inches v = one-third pi r squared h. 96 pi = one-third pi r squared (18). 96 pi = 6 pi r squared. 16 = r squared. startroot 16 endroot = startroot r squared endroot.
Based on the calculations, the radius of this cone is equal to 4 inches.
How to calculate the radius of a cone?Mathematically, the volume of a cone is calculated by using this formula:
V = 1/3 × r²h
Where:
h is the height.r is the radius.Making r the subject of formula, we have:
r = √(3V/πh)
Substituting the given parameters into the formula, we have;
r = √(3 × 96π/π × 18)
r = √(288/18)
r = √16
Radius, r = 4 inches.
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What are the potential advantages and disadvantages of a major shift from the hard or traditional path of energy development to the soft or visionary path
Answer: Advantages of following the soft path, the argument here is alternative sources of power such as hydropower, geothermal energy , wind energy , and photovoltaic cells must be developed. This provides a alternative source to remain in a healthy environment and also function as the society we currently live in using the hard path. Disadvantages of following the hard path result with future generations fearing over the irreversible damage of climate change and the damage done to our atmosphere. The hard path argue that we should continue to operate in the future as we have in the past, except more efficiently. This is close to impossible and will only continue the negative effects the hard path( the path we have been following) results in. The major shift determines the outcome of this world, the futures worries or reliefs and ultimately the survival of humans.
What sport does not require a high level of fitness
A photon has an energy of 2.88 x 10^-18 j. convert this energy into ev.
Answer:
E = V Q voltage * charge
Since the charge on an electron is e = 1.6E-19 coulombs
the energy of 1 eV is 1.6E-19 joules
E = 2.88E-18 joules / 1.6E-19 joules/electron volt
E = 18 eV
Take the mechanical equivalent of heat as 4 J/cal. A 10-g bullet moving at 2000 m/s plunges
into 1 kg of paraffin wax (specific heat 0.7 cal/g ·C◦). The wax was initially at 20◦ C. Assuming
that all the bullet’s energy heats the wax, its final temperature (in ◦ C) is:
A. 20.14
B. 23.5
C. 20.006
D. 27.1
E. 30.23
Assuming that all the bullet’s energy heats the paraffin, its final temperature is 27.1 degree C. The correct option is D.
What is temperature?Temperature is the degree of hotness and coldness of the material.
The energy of the bullet E = 1/2 mv²
E = 1/2 x 10 x 10⁻³ x (2000)²
E = 2 x 10⁴ J
This heat is used in heating the paraffin
E = m x c ΔT = m x c (Tfinal -Tinitial)
2 x 10⁴ J = 1 x 2.8 x 10³ x (Tfinal -20)
Tfinal = 27.1°C
Thus, the final temperature is 27.1 degree C. The correct option is D.
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a satellite moves in a circular orbit around the earth at a speed of 5000 ms. determine the satellites altitude above the earths surface
Answer:
G M m / R^2 = m v^2 / R centripetal force = force of attraction
R = G M / v^2 radius of satellite orbit
R = 6.67E-11 * 5.98E24 / 5000^2
R = 6.67 * 5.98 / 25 * 10^7 m = 1.60 * 107 m = 16 * 10^6 m
Radius of earth = 6.37 * 10^6 m
H = R - r = (16 - 6.4) * 10^6 m = 9.6 * 10^6 m
The sun will spend most of its lifetime in which stage?.
The speed of light traveling through an unknown material is 1.98×108 m/s. Given that the speed of light in a vacuum is 3.00×108 m/s, what is the dielectric constant of the unknown material?
The dielectric constant of the unknown material is 2.3.
What is dielectric constant?Dielectric constant is referred as a relative permittivity or amount of charge required to produce one unit of electric flux in a given medium.
Given the speed of light in vacuum c =3 x 10⁸ m/s and the speed of light through an unknown material v = 1.98 x 10⁸ m/s.
The dielectric constant is related to the velocity by the following relation,
v = c/√K
Rearranging for dielectric constant, we get
K = (c/v)²
Substitute the value into the expression ,we get
K =(3 x 10⁸ / 1.98 x 10⁸)²
K = 2.3
Thus, the dielectric constant of the unknown material is 2.3.
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12
9. An empty, massless cube is measured to have all sides equal to 11 cm. It is floating in water and will slowly be filled with sand
that has a density of 3.5 g/cm'. What volume of sand will cause the box to sink?
Answer:
See below ~
Explanation:
An object will sink in water when its density is greater than that of water, which is 1 g/cm³.
Volume of the box is 1331 cm³. (11³)
Maximum mass of sand will be 1331 g. [because 1331/1331 = 1 g/cm³]
Volume of sand = Mass of sand / Density of sandVolume (sand) = 1331/3.5Volume (sand) = 380.29 cm³If the volume of sand is greater than 380.29 cm³, the box will sink in water.
What is the speed of light in quartz
Answer:
Approximately 2.06⋅108 meters per second.
Explanation:
i just can't get around physics T^T this is the last question i promise, I'd really appreciate the help <3
question; the work one by friction force to stop a car of mass 1000 kg moves with velocity 72km/h is ..........
a) 72 x 10³ J
b) 2 x 10⁴ J
c) 2 x 10⁵ J
d) 4 x 10⁵ J
an explanation for future reference would be great, thank you in advance!
Use the work-energy theorem. The total work W performed on the car as it it slows to a stop is equal to the change in the car's kinetic energy ∆K. So
W = ∆K
W = 0 - 1/2 (1000 kg) (72 km/h)²
W = - (500 kg) (20 m/s)²
W = - 200,000 J = -2 × 10⁵ J
The closest answer would be C, but friction opposes the car's motion so the work would be negative.
It would be really helpful if someone answered this.
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
According to first law of reflection, we know that :
Angle made by the incident ray and normal [ i.e angle of incidence ] is always equal to Angle made by the reflected ray and normal [ i.e Angle of reflection ]
Therefore, we can say that the missing angle (angle of reflection) has the same value as the angle of incidence which is equal to 45°
Please read the statement through to understand the procedure ~
Can someone please answer this, ill give you brainliest Would be very appreciated.
Water cycle basically involves the change of water into liquid to vapour and again to liquid states through a cyclic manner .
The answers are
EvaporationTranspirationCondensationprecipitationrunoffseapageground waterA dolphin leaps out of the water
at 6.25 m/s at a 45.0° angle.
How far away does it land?
(Unit = m)
x max = (vi² sin 2α) / g
x max = (6.25² sin 90)/10
x max = 39.0625/10 = 3.91 m
On an ice skating rink, a girl of mass 50 kg stands stationary, face to face with a boy of mass 80 kg. the children push off of one another, and the boy moves away with a velocity of 3 m/s. what is the final velocity of the girl? –1.9 m/s 1.9 m/s –4.8 m/s 4.8 m/s
The final velocity of the girl after the collision is determined as -4.8 m/s.
Final velocity of the girl
The final velocity of the girl is determined from the principle of conservation of linear momentum.
m1u1 + m2u2 = m1v1 + m2v2
50(0) + 80(0) = 50(v1) + 80(3)
0 = 50v1 + 240
50v1 = -240
v1 = -240/50
v1 = -4.8 m/s
Thus, the final velocity of the girl after the collision is determined as -4.8 m/s.
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