400N magnitude of the friction acting on the crate.
work done by gravity
[tex][w=mg sin \theta \cdotS],[w=mgh=],[w=800 \cdot2=w=1600][/tex]
Then was done by friction external work - wask done by gravity
[tex][f_S \cdot S=3200-1600],[f_S \cdot4=1600],[f_S=400 N][/tex]
Thus the crate is not moving with constant speed then we can say that the value of friction Force is less then 400 N
So Friction Force is not zero but less then the 400N
The resistance present at the contact surface at the point of contact when two or more objects move over one another can be referred to as friction force. The direction of friction force is always perpendicular to the object's motion.
The amount of friction is influenced by the surface's roughness and outside pressures. The force of friction works more strongly on a surface the rougher it is. The same is true of outside factors.
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A man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle . Describe how the force components change as the angle increases from 0° to 90° and use your graph to explain your answer. Give a detailed explanation of the forces at . Show a sample calculation at one angle for both components.
The 50 N force applied at an angle to the crate may be broken down into horizontal and vertical force components. As the angle created by the rope, e, increases from 0° to 90°, the horizontal component, Fx, drops and the vertical force component, Fy, increases.
What is a component of a force ?The components of a force are the force parts acting in perpendicular directions, horizontal and vertical, that combine to give the specified force.
The direction the crate is sliding = The horizontal, x-direction
The force exerted by the man = 50 N
The angle of the rope
The components of the force are therefore:
Horizontal component, Fx = 50 × cos(8)
Vertical component, F₁ = 50 x sin(0)
The value of cos(e) and sin(e) as the angle the rope makes with the horizontal,
e, increases from 0° to 90° are as follows:
Therefore, the horizontal component of the force exerted by the man, Fx has a maximum value at = 0, and decreases to 0, as increases from 0° to 90°.
The vertical component of the force exerted, Fy, has a minimum value of O at → = 0°, and the value of sin(e) and therefore Fy, increases to a maximum of (sin(90°) 1) 50 N as increases to 90°.
Please find attached the graph showing the components of the force, Fx, and Fy, exerted by the man as the angle formed by the rope increases from 0° to 90°
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9. A driver, driving a Bugatti Veyron, accelerates at 26.7 m/s² for 2.4 seconds. What change in
velocity did the driver experience?
The change in velocity experience by a driver, driving a Bugatti Veyron, accelerating at 26.7 m/s² for 2.4 seconds is 64.08 m/s.
What is chnage in velocity?Change in velocity is the difference between the final and the initial velocity of a body.
To calculate the change in velocity experienced by the driver, we use the formula below.
Formula:
Δv = at........... Equation 1Where:
Δv = Change in velocitya = Accelerationt = Time.From the question,
Given:
a = 26.7 m/s²t = 2.4 secondsSubstitute these values above into equation 1
Δv = 26.7×2.4Δv = 64.08 m/s.Hence, the change in velocity experienced by the driver is 64.08 m/s.
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A pack of dogs are pulling a wooden sled and rider of combined mass
of 238 kg across dry snow. How much force do the dogs need to apply
to cause the sled to begin to move?
Answer:
FN=-Fg -> Fg=mg -> Fg = 238 kg*9.8 m/s^2 ->
Fg = -2432.4 so FN = 2432.4 -> FF = μs*FN ->
FF = 0.22*2332.4 N -> FF = 513.128 ->
Fapplied > 513.128 N
Explanation:
...
Help! A car is traveling at 60 km/h. It accelerates to 85km/h in 5 seconds. What is the acceleration of the car?
A Car is travelling at a speed of 60 km/h and then accelerates to the velocity 85 km/h than acceleration in 5 sec is given by 18000 km/h² .
What is acceleration?Acceleration of body is defined as rate of change of the velocity with respect to the time. Acceleration is a vector quantity it have magnitude as well as direction.
Acceleration = (final velocity - initial velocity )/ time
Acceleration = change in velocity / change in time
Given that in the question that the velocity changes from 60 km/h to 85 km/h in 5 sec =( 0.00138 h ) then the acceleration of the car is given as,
Acceleration of the car = (60 - 85)/0.00138
Acceleration of the car = 18000 km/h²
Acceleration of the car travelling with the velocity 60 km/h to final the velocity 85 km/h in time 5 sec is given by 18000 km/h².
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NEED HELP URGENTLY FOR 10 POINTS
Answer:
Option 2
Explanation:
This is the definition of the plum-pudding model.
what's the answer to this question?
Answer:
Energy
Explanation:
Some of the suns energy is converted into wind and water waves
A trebuchet is a compound machine. What individual simple machines is it composed of ?
It uses one main simple machine, the lever, to propel a projectile, making it both a compound machine (a device that employs a number of simple machines) and a simple machine.
How Do Trebuchets Work?A trebuchet is a form of catapult, a weapon that can launch things considerably farther than a person can. The usage of trebuchets is first recorded in second-century China, however catapults were in use far before the Roman Empire. Trebuchets are most known for their use in medieval castle raids because they could be placed so far away from the fortress that archers couldn't touch them and could launch practically anything.
They are the most basic techniques that are now understood for using leverage (or mechanical advantage) to increase force. The wheel and axle, inclined plane, lever, wedge, pulley, and screw are examples of rudimentary machines.
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2. Your household electricity system is labeled as 127V/30A. If each electricheater consumes 1600W. How many such heaters can be running at the sametime safely?
We can calculated the maximum power as follows:
[tex]\begin{gathered} P_{Max}=VI \\ so: \\ P_{Max}=(127)(30) \\ P_{Max}=3810W \end{gathered}[/tex]Since the heater consumes 1600W, we can write the following inequality:
[tex]n1600<3810[/tex]Where n is the number of heaters, so:
[tex]\begin{gathered} n<\frac{3810}{1600} \\ n<2.38 \\ so: \\ n\approx2 \end{gathered}[/tex]Answer:
2 heaters
which color is bent the least by prism
The red light is the least refracted by the prism.
How light is refracted by a prism?Each beam of light with a particular wavelength is slowed differently by the glass. Since violet light has a shorter prism wavelength, it is brake more than the longer wavelengths of red light. accordingly, violet light is bent the most while red light is bent prism the least. Prism on dispersion, the light rays with longer wavelengths bend less than ones with shorter wavelengths. Since red has the longest wavelength, it bends the least. prism Among the 7 constituent colors of light, violet light has the least wavelength and hence it deviates the most, and red light having the largest wavelength deviates the least. Hence, prism the required order is violet, indigo, blue, green, yellow, orange, and red.
So we can conclude that in a prism, the red light is less refracted.
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a plane circular coil of radius 0.77 m lies in a horizontal plane. it carries a current of 4.38 a. the coil is in a uniform horizontal 1.157-t magnetic field. what is the magnitude of the magnetic torque on the coil? calculate the torque in the units of n.m. write your answer in decimal form with three digits to the right of the decimal point (e.g. 5.374); do not write any units.
The magnitude of the magnetic torque on the coil is 9.435 Nm.
A magnetic field exerts a torque that tries to align the normal vector of a loop of current with the magnetic subject. the size of the torque on a loop
The magnetic torque, τ, skilled by using a unmarried particle of quantity V and domain magnetization Md whose moment is oriented at attitude θ to carried out induction B is given by means of τ=mHsinθ where m=MdV is the magnetic second of the particle.
This is the torque on a modern-wearing loop in a uniform magnetic field. This equation can be proven to be valid for a loop of any form. The loop includes a modern I, has N turns, every of area A and the perpendicular to the loop makes an angle θ with the field B.
Calculation:-
τ = μ×B
= I A B sin90°
= 4.38 × 3.14×(0.77)²× 1.157
= 9.435 N m.
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we will explore more this equation. we need to solve this for all masses! you should recognize now that this system of linear equations can be written in a matrix form. we will define the variable
The coefficients of the variables in each equation can be arranged in a row to create the coefficient matrix. A constant term should always be written on the right in standard form for each equation.
A coefficient matrix, a variable matrix, and a constant matrix can all be used to describe a system of linear equations in matrix form.
Think about the system,
2x+3y=8
5x−y=−2
X and Y are the variables that we have. As a result, the variable matrix can be written as [xy].
The constant terms from the equations, 8 and 2, are on the right side of the equivalence. The first and second rows of the constant matrix are occupied by the two integers in that order since they are the ones that correspond to the first and second equations. The matrix then takes the form [82].
The system is now represented by the equation [2531] [xy] = [82].
Now, the system is denoted as [2531] [xy]=[82].
You can see that the matrix representation is identical to the system of equations using matrix multiplication.
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a ball of mass m collides completely inelastically in one dimension with another ball of mass 3m that is initially at rest (the balls stick together after the collision). what fraction of the initial kinetic energy is lost in the collision
Fraction of the initial kinetic energy is lost in the collision f = 3/4.
Two balls of masses M and 3M kinetic energy
Initially before collision:
Speed of ball of mass M = −V0 (Right direction is taken as negative)
Speed of ball of mass 3M = +V0
Finally after collision: Speed of ball of mass M = v
Speed of ball of mass 3M = V02
[tex]Finding the fraction(f) of initial kinetic energy lost in the collisionf=1−Final Kinetic EnergyInitial Kinetic Energyf=1−12×M×(v02)2+12×3M×(v02)212×M×(−v0)2+12×3M×(v0)2f=1−v024v02f=1−14=34[/tex]
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a conductor consists of an infinite number of adjacent wires, each infinitely long and carrying a current i (whose direction is out-ofthe-page), thus forming a conducting plane.
The important Physics chapter "Conductors and Dielectrics in an Electric Field" focuses on the electric field and its interactions with different kinds of materials, such as conductors and dielectrics.
The significance of its components in the electrical circuit is explained in Conductors and Dielectrics in an Electric Field. is a crucial resource component that all students require in order to succeed in the Class 12 Physics exams and admission exams. It is one of the greatest ways to prepare for physics exams and practice problems in order to get good marks. Here, the questions are primarily centered on electric field, current, speed, voltage, and other related concepts.
In-depth explanations are provided for the behavior of conductors and dielectrics. The issues help to strengthen the applicability of the theoretical ideas in daily life and activities.
For clear knowledge and a firm grasp of the syllabus and concept, students aiming for a good mark in a competitive examination must solve every issue provided.
Based on each and every formula, equation, and procedure, there are a variety of difficulties that can be accessed. Each problem's solution is broken down into logical steps and supported with relevant data, formulas, graphs, and equations. All questions based on conductors and dielectrics are readily available to students. This aids in conceptual clarity and full knowledge for kids.
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PLEASE HELP!!! WILL MARK BRAINLIEST
The environmental impact of the changes in the amount of energy resources is reduction in air pollution.
What are energy resources?Energy resources are the materials that can act as sources of energy which is grouped into two namely:
Renewable energy resources: These are energy resources that can easily be replaced by nature. A typical example is the solar energy.Non renewable energy resources: These are energy resources that cannot easily be replaced by nature. Examples include coal, nuclear and gas.From the given figures,
In 2014 renewable energy = 19%; while in 2015 it is = 25%
In 2014 non renewable energy when added = 79%; while in 2015 it is = 73%
This shows that there was reduction in the use of non renewable energy from 2014 to 2015 by 6%.
This would affect the environment positively as there would be reduction in air pollution caused by non renewable energy resources.
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A BALL Is released from a hight of 20m calculate the time it taken to fall. The velocity with it hits the ground
A ball is released from a certain height of 20m then the time taken by the ball to fall is 2 sec and the velocity is 20m/s
Here: s (height) = h =20
a=g=±10m/s
a=10m/s (since it is dropped)
[tex]v^{2} -u^{2} =2as\\v^{2} =2*10*10\\v^{2}= 200[/tex]
(u=0; it is dropped not thrown)
v=20m/s
for calculating time we know,
v=u+at
20= 0+ 10xt
t=20/10
t=2seconds
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With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in ____________ twitches per stimulus.
With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in identical twitches twitches per stimulus.
Alpha motor neurons are the motor neurons that innervate the fibers of the skeletal muscle. A number of branches, each innervating a different muscle fiber, are formed as the alpha motor neuron enters the muscle. A motor unit is made up of one alpha motor neuron and all of the muscle fibers it innervates. Small motor units with 3-5 muscle fibers per motor neuron are found in muscles that are involved in delicate, coordinated control. Our hand and eye muscles, as well as those that control eye movement, have very small motor units.
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imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? view available hint(s)for part a imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? 2 years it cannot be determined from the information given. 6 months 1 year
1year is the orbital period of this planet.
The orbital period is the quantity of time a given astronomical object takes to complete one orbit around every other object. In astronomy, it generally applies to planets or asteroids orbiting the solar, moons orbiting planets, exoplanets orbiting different stars, or binary stars.
Kepler's third law - indicates the relationship among the length of an items orbit and the common distance that it's far from the issue it orbits. this could be used for something clearly orbiting round another factor.
Entire revolution is known as the orbital duration. At 200 km that is approximately ninety minutes. The orbital duration will increase with altitude for two motives. First, as the altitude increases, Earth's gravity decreases, so the orbital speed had to stability it decreases.
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A medium-sized jet has a 3. 8-m-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to the cylindrical fuselage, and aerodynamic shaping gives it a drag coefficient of 0. 37.
To travel at 230 m/s at an altitude where the air density is 1.0 kg/m3, the jet's engines must deliver 111kN of thrust.
Air Density is defined as the mass of an object, including air, divided by its volume.
Scientists measure density in terms of kilogrammes per cubic metre when using the metric system.
The density of the air is influenced by its temperature, pressure, and water vapour content. We'll discuss dry air initially, so just temperature and pressure will be a concern.
In addition to a fundamental explanation of air density, we will go into how humans are affected by decreased air density, such as that experienced at high altitudes, how humidity influences air density in unexpected ways, and how air density affects things like aircraft, baseballs, and even racing automobiles.
The density of the air in a free environment drops as temperature increases.
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two ice skaters stand facing each other at rest on a frozen pond. they push off against one another and the 61 kg skater acquires a speed of 0.75 m/s. if the other skater acquires a speed of 0.89 m/s, what is her mass in kilograms?
The mass of the other skater who is pushed is 51.4 kilograms.
According to the law of conservation of momentum,
The total linear momentum is always conserved in a system if no external force is applied.
So. we can write,
Initial momentum = final momentum
Initial momentum is zero as both the skater are at rest.
So, Final momentum should be 0,
Final momentum = 0
M₁V₁ + M₂V₂ = 0
M₁ is the mass of first skater,
V₁ is the final speed of the first skater,
M₂ is the mass of the second skater,
V₂ is the final speed of the second skater, V₂ will taken as negative because the second skater is pushed into opposite direction,
Putting all the values,
61(0.75) = -M₂(-0.89)
M₂ = 51.4 Kg.
So, the mass of the skater is 51.4 kg.
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Write a properly formatted hypothesis statement to answer this question: how does the amount of dissolved salt affect the boiling point of water? specify how you plan to change the independent variable by using terms such as increase or decrease. also, specify how the dependent variable will change in response by using terms such as increase, decrease, or stays the same.
The theory is that:
H0: The amount of salt added to ice has no bearing on how quickly it melts.
H1: The amount of salt added to ice will have an impact on how quickly it melts.
By altering the rate at which salt is introduced to the equation, the independent variable can be modified.
The ice, which is the dependent variable, will alter or melt in response because it will get smaller as the rate at which salt is injected rises.
The boiling point of water, or the temperature at which it may erupt, rises when salt is added to it. For every 58 grams of dissolved salt per kilogram of water, the temperature required to reach boiling rises by around 0.5 C. This is an illustration of an elevated boiling point, which is not just a property of water.
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an electron of mass 9.11 3 10231 kg has an m initial speed of 3.00 3 105 m/s. it travels in a straight line, and its speed increases to 7.00 3 105 m/s in a dis- tance of 5.00 cm. assuming its acceleration is constant, (a) determine the magnitude of the force exerted on the electron and (b) c
a. The magnitude of the force exerted on the electron F = 3.64*10^-18N
b. The force F is 4.08*10^11 times the weight of the electron
a. In order to calculate the magnitude of the force exerted on the electron you first calculate the acceleration of the electron, by using the following formula:
v: final speed of the electron = 7.00*10^5 m/s
vo: initial speed of the electron = 3.00*10^5 m/s
a: acceleration of the electron = ?
x: distance traveled by the electron with certain speed= 5.0cm = 0.05m
you solve the equation (2) for a and replace the values of the parameters:
[tex]a=v^{2} - V^{2} /2x[/tex]
a=4×10^12 m/s²
to calculate the force we now use the second Newton law :
F=ma
m: mass of the electron = 9.11*10^-31kg
F=3.64*10^-18N
The magnitude of the force exerted on the electron is 3.64*10^-18N
b. given weight of electron is :
Fg=mg
Fg = 8.92*10^-30N
The Division between the force electron and the weight of the electron F is:
F/Fg=4.08*10^11
The force F is 4.08*10^11 times the weight of the electron
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A 750 resistor in a circuit has a current flowing through it of 2.0 A. What is
the power dissipated by the resistor? (Use P=OVI = /²R= VR)
OA. 300 W
B. 150 W
C. 38 W
D. 450 W
The power dissipated by the resistor is 3000W.
What is power?Electrical power, or (P), in a circuit is a unit of measurement for the rate at which energy is consumed or produced inside a circuit. The energy produced or delivered by an energy source, such as a voltage, is absorbed by the associated load.
In physics, power is referred to as the rate of energy conversion or transfer over time. The unit of power in the SI system, often known as the International System of Units, is the Watt (W). A single joule per second is one watt. Power was formerly referred to as activity in some research. A scalar quantity is power.
The resistor's power dissipation can be computed as P = I²R
here ,
I = 2 A
R = 750
Therefore P= 2² x 750 W
= 3000W
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A body weighs (i) 900N on the surface of earth how much will it weigh on the surface of
Mars whose mass is one ninth and radius is one half that of the earth take g on the surface
of earth to be 10 m/s2
The weight of the body on the surface of mars would be 333.9 Newtons.
What is Weight ?Weight is the force exerted by the earth on an object at the surface of the earth and this force is directed towards the center of the earth. Mathematically -
W = mg
where -
[m] is the mass of object
[g] is acceleration due to gravity
Given is a body that weighs 900N on the surface of earth. Mars is a planet whose mass is one ninth and radius is one half that of the earth. The same body is now placed on mars.
Since the weight of the body is 900 N on earth, we can write -
W = mg
900 = m x 10
m = 900/10
m = 90 Kg
Now, we know for a body of mass [m] on a planet of mass [M], the gravitational force exerted by planet on the body will be -
F = GMm/r²
but
F = W = mg
So, we can write -
mg = GMm/r²
g = GM/r²
For the planet of mars, we can write -
g = GM[mars]/r[mars]²
g = (6.6743 × 10⁻¹¹ x 0.65 x 10²⁴)/(3185.5 x 10³)
g = 3.71 m/s²
So, the weight of the body on mars will be -
W = mg = 90 x 3.71
W = 333.9 N
Therefore, the weight of the body on the surface of mars would be 333.9 Newtons.
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A charge of 15C has flowed past a point in the circuit with a current of 2A. How long has this charge been flowing through this circuit?
Round the answer to 2 decimal places.
The charge of 15 Chas been flowing through a circuit with current of 2 A for a time period of 7.5 s
Q = I t
Q = Electric charge
I = Electric Current
t = Time
Q = 15 C
I = 2 A
t = Q / I
t = 15 / 2
t = 7.5 s
Electric current is the rate of flow of charge. In a circuit the current always flows from the negative terminal to the positive terminal. Its unit is Ampere ( A ) which is C / s.
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18. How might the cycling of matter in Earth’s atmosphere be related to to the movement of dust from the Sahara desert to the Amazon?
This is Science
The cycling of matter in Earth’s atmosphere is related to the movement of dust from the Sahara desert to the Amazon because the biosphere is a major ecosystem that connects all ecosystems around the world.
What are ecosystems?The ecosystems are specific geographic regions in which biotic factors (life) and abiotic factors (e.g. dust) interrelate to shape the environmental condition of the area, while the term biosphere makes reference to a major ecosystem that connects all these region in the world.
Therefore, we can conclude that ecosystems are interconnected to shape the biosphere, thereby the phenomena that occur in Sahara desert are able to modify the conditions in a Forest like Amazon.
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Newton's First Law
A lantern of mass m is suspended by a string that is tied to two other strings, as shown
in the figure below. The free-body diagram shows the forces exerted by the three
strings on the knot.
F₂
Fy
0₂
¥
F₁
1. In terms of F₁, F2, and F3, what is the net force acting on the knot?
(Hint: The lantern is in equilibrium.)
2. Find the magnitudes of the x and y components for each force acting on the knot.
(Assume the positive directions are to the right and up.)
String 1 (F₁)
x component
y component
String 2 (F₂)
x component
y component
String 3 (F3)
x component
y component
3. In terms of F1, F2, and F3, what is the magnitude of the net force acting on the
knot in the x direction? in the y direction?
Fx net=
Fynet
=
. Assume that 8₁ = 30°, ₂ = 60°, and the mass of the lantern is 2.1 kg. Find,
F1, F2 and F3.
F₁=
F₂=
F3 =
Answer:
1. If the knot is in equilibrium - no net force acts on the knot.
2. F1x = 0 F1y = -F1
F2x = -F2 cos θ1 F2y = F2 sin θ1
F3x = F3 cos θ2 F3 = sin θ2
3. Fx net = 0
Fy net = 0 for equilibrium to occur
4. F2 cos θ1 = F3 cos θ2
F1 = M g = 2.1 * 9.8 = 20.6 N
F2 sin 30 + F3 sin 60 = 20.6 balancing forces in y-direction
or .5 F2 + .866 F3 = 20.6 (use this equation below ) (I)
F2 cos 30 = F3 cos 60 as stated above
.866 F2 = .5 F3 or F3 = 1.732 F2 substituting for θ
.5 F2 + .866 (1.732 F2) = 20.6 using (I) above
2.0 F2 = 20.6 and
F2 = 10.3 N
F3 = 1.732 * 10.3 = 17.8 N
Check:
10.3 * .866 = .5 * 17.8 using values above
8.92 = 8.9 forces balance
Also .5 * 10.3 + .866 (1.732 * 10.3) = 20.6
a human expedition lands on an exoplanet. one of the explorers is able to jump a maximum distance of 18.0 m with an initial speed of 2.60 m/s. find the gravitational acceleration on the surface of the exoplanet. assume the planet has a negligible atmosphere. (enter the magnitude in m/s2.)
The gravitational acceleration on the surface of the exoplanet is 0.188 m/s².
Gravitational acceleration has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration (gravitational acceleration), t is time and s is displacement.
From the question above, we know that
h = 18 m
vo = 2.6 m/s
In this case, the final velocity should be zero. Hence,
vt² = vo² + 2a . s
vt² = vo² - 2g . h
0² = 2.6² - 2.g . 18
36g = 6.76
g = 0.188 m/s²
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suppose that the resistance between the walls of a biological cell is 1.00 109 ω. (a) what is the current when the potential difference between the walls is 45 mv?
The current when the potential difference between the walls is 45 mv is 4.500×10⁻¹¹ A.
To find the current when the potential difference between the walls is 45 mv, we will Use Ohm's law.
V = IR ........................ Eqn 1
Where
V = Potential difference between the walls
I = current
R = Resistance between the walls
Make I the subject of the equation
I = V/R...................... Eqn 2
From the question, we are given that:
V = 45 mV = 0.045 V
R = 1.0×10⁹ Ω.
Substitute into Eqn 2
I = 0.045/(1.0×10⁹)
I = 4.500×10⁻¹¹ A.
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If a man pulls a box with a force of 90 N at an angle of 45
degrees, then what are the X and Y components of the force?
Answer:
See below
Explanation:
x component = 90 cos 45 = 63.6 N
y component = 90 sin 45 = 63.6 N
a plane is flying horizontally with speed 198 m/s at a height of 3210 m above the ground, when the package is dropped from a plane. The acceleration of gravity is 9.8 m/s^2.
a second package is thrown downward from the plane with a vertical speed v1=78m/s. what is the magnitude of the total velocity of the package at the moment it is thrown as seen by an observer on the ground? answer in units of m/s.
The magnitude of the total velocity of the package at the moment it is thrown as seen by an observer on the ground is D = 193m/s 15.2s = 2934 m.
What is velocity ?
velocity is the prime indicator of the position as well as the rapidity of the object
Sol-
1. 0.5gt^2 = 2010 m.
4.9t^2 = 2010.
t = 20.3 s. = Fall time.
D = Xot. = 193m/s 20.3s = 3909 m.
2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.
3. Vot + 0.5gt^2 = 2010 m.
58t + 4.9t^2 = 2010.
4.9t^2 + 58t - 2010 = 0.
Use the quadratic formula we are get
t = 15.2 s. = Fall time
D = 193m/s 15.2s = 2934 m.
D = 193m/s 15.2s = 2934 m.
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