Answer:
True
Explanation:
Markovnikov rule states that the negative part of the addendum is added to the carbon atom having the least number of hydrogen atoms.
This means that during acid-catalyzed addition of water to an alkene, the -OH is added to the more substituted carbon atom while the -H is added to the least substituted carbon atom in obedience to Markovnikov regiochemistry.
Answer:
a. True
Explanation:
Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H+ adds to the sp2 carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol.
Calculate the Standard Enthalpy of the reaction below:
NH3(g) + HCl (g) → NH4Cl(s)
Using the following Enthalpy of Reactions:
2HCl(g) → H2(g) + Cl2(g)
AH = +184.6 kJ
2H2(g) + 12 N2(g) + 2 Cl2(g) NH4Cl(s) AH = -314.4 kJ
N2(g) + 3 H2(g) → 2 NH3(g)
AH = +184.6 kJ
Answer:
(we use hess's law) it is so simple but the second reaction is not correct please right it
You and your science group have been handed five mineral samples to identity. First, you on the minerals by color None of the
minerals are white. You and your group know that you probably do not have
A) Calcite
B) gypsum
C) Calcite and Talc
D) feldspar and calcite
Answer: A
Explanation:
PLZ HELP ME ASAP!!!!(I WILL ALSO MARK BRAINLIEST!!!)
(True or False) A cold front often signals sunny warm weather.
how we can remove temporary hardness of water?and write the chemical reaction?
Answer:
it can be removed
1. by boiling
Ca(HCO3)2 > CaCO3 + H2O +CO2
2. by treating with calcium hydroxide
In the western U.S., ranchers aggressively killed wolves because they posed a threat to their cattle. As the wolf population declined, the deer population began increasing. As a result, the surrounding forest ecosystems experienced increasing damage. The large number of deer ravaged vegetation and destroyed young trees. The entire ecosystem became degraded until wolves became protected when they were determined to be an endangered species. Based on this information, what can you infer about the role of the wolves in this ecosystem? Please make it 3-5 sentences. Thank you so much
Answer:
Explanation:
You can make a couple of statements.
The wolves are preditors. They eat meat.The wolves hunt only 1 kind of food. They are not interested in young trees or grass (well not much anyway). If one species is allowed to get out of control, the entire ecosystem suffers because of it.This last statement only becomes true if man allows the hunted species that controlled the deer to regain good numbers. Man can be a blockhead sometimes; he learns slowly at times.Answer:
The wolves role in the ecosystem is to hunt/eat deer. In the question it states, "...ranchers aggressively killed wolves because they posed a threat to their cattle. As the wolf population declined, the deer population began increasing." It's clearly cause and affect, the wolves use to eat a lot of deer, then a large percentage of wolves died by the ranchers. The wolves role in the ecosystem is to hunt deer and help balance out animal to vegetation ratio.
Explanation:
Because i'm awesome lol
(Give me good ratings pleaseeeee.
Gelatinization happens with what type of Carbohydrate?
When 148. mg of a certain molecular compound X are dissolved in 75.g of cyclohexane (CH), the freezing point of the solution is measured to be 59 'C. Calculate the molar mass of X If you need any additional information on cyclohexane, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to l significant digit. XS ?
Answer: The molar mass of X is 61.3g/mol
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=(6.55^0C-5.9^0C)=0.65^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant = [tex]20.2^0C/mol[/tex]
m= molality = [tex]\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in Kg}}[/tex]
where,
Now put all the given values in this formula, we get
[tex]0.65^0C=20.2°C/m\times frac{0.148g}}{M\times 0.075kg}[/tex]
[tex]M=61.3g/mol[/tex]
Thus molar mass of X is 61.3g/mol
- Calculate the Standard Enthalpy of the reaction below:
NH3(g) + HCI (g) → NH4Cl(s)
Using the following Enthalpy of Reactions:
2HCI(g) → H2(g) + Cl2(g)
AH = +184.6 KJ
2H2(g) + 1/2 N2(g) + 1/2 Cl2(g) → NH4Cl(s) deltaH = -314.4 kJ
N2(g) + 3 H2(g) → 2 NH3(g)
deltaH = +184.6 kJ
Answer:
Explanation:
We have the three equations:
[tex]NH_{3(g)} + HCl_{(g)} => NH_4Cl_{(s)} ..... \Delta H = ? (1)\\2HCl_{(g)} => H_{2(g)} + Cl_{2(g)} .... \Delta H = +184.6 kJ (2)\\2H_{2(g)} + 1/2N_{2(g)} + 1/2Cl_{2(g)} => NH_4Cl_{(s)} ..... \Delta H = -314.2 kJ (3)\\ N_{2(g)} + 3H_{2(g)} => 2NH_{3(g)} .... \Delta H = +184.6kJ (4)[/tex]
(can you double check that it is 184.6kJ for both equations 2 and 4 because it seems unlikely). We need to solve for equation 1 by addition and changing equations 2, 3 and 4. After possibly some trial and error, we can find that if we flip equations 4, multiply equation 3 by 2, add the equations together, and then finally divide by 2, we can get equation 1. We will get the answer of -314.2 kJ. However, I am again skeptical about the delta H values for equation 2 and 4 so double check that. This method might be super confusing and it is really hard to explain. So what I would suggest you to watch videos on Hess' law.
Can you all go vote for Dacia Campbell for Brainly Educator of The Year!!!!!
It would mean a ton!!! Plus, I'll give your profile a big THANK YOU...I'll give Brainliest and you get 50 points! Please, please, please. Go vote for her!
Answer:
i voted her!!!!
Explanation:
How many moles of BaS would be used to make 1200 mL of a 10.OM solution?
How many grams of H2SO4 will react 650.0 grams of NaOH?
Answer:
H2SO4 + 2NAOH➡NA2SO4+2H2O
H2SO4 = 1*2 +32+16*3= 98g
NAOH = (11+16+1)=28
Explanation:
To calculate the number of Mole = Mole *Molar Mass
To calculate for gram = Mole/ Molar Mass
20.5g NaoH/1 * 1 mole NaOH/28g NaoH = 0.73M NaoH
0.73M NaoH /1 * 1 M H2SO4 /2M NaoH = 0.37M H2SO4
0.37 M H2SO4 /1 * 98g H2SO4 /1M H2SO4 = 0.00367g H2SO4
:- 0.00367g of Sulphuric Acid will be needed to complete the reaction.
What is the balanced net ionic reaction for the following -
CaCl2 + Na2S --> NaCl + CaS?
Answer:
CaCl2 + Na2S --> 2NaCl + CaS?
Explanation:
CaCl2 + Na2S --> 2NaCl + CaS?
A 1.4639-g sample of limestone is analyzed for Fe, Ca, and Mg. The iron is determined as Fe2O3 yielding 0.0357 g. Calcium is isolated as CaSO4, yielding a precipitate of 1.4058 g, and Mg is isolated as 0.0672 g of Mg2P2O7. Report the amount of Fe, Ca, and Mg in the limestone sample as %w/w Fe2O3, %w/w CaO, and %w/w MgO
Answer:
A) w/w % of Fe - 2.44%
B) w/w % of Mg - 4.590%
C) w/w % of Ca - 96%
Explanation:
A) w/w % of Fe in limestone as Fe2O3 = (Mass of Fe2O3 /Mass of limestone) x 100
0.0357/1.4639 X 100
= 2.438 =2.44
B) w/w % of Mg in limestone as Mg2P2O7 = (Mass of Mg2P2O7 /Mass of limestone) x 100
= 0.0672/1.4639 X 100
= 4.590
C) w/w % of Ca in limestone as CaSO4 = (Mass of CaSO4/Mass of limestone) x 100
= 1.4058/1.4639 X 100
= 96
Answer:Fe =1.71% Ma=0.99% Ca=28.24%
Explanation:
A 15.0 mL solution of 0.10 M Fe(NO3)3 reacts with K2C204 according to the reaction 2 Fe(NO3)3 + 3 K2C2O4 → Fe2 (C2O4)3 + 6 KNO3 . What volume of 0.30 M K2C2O4 is needed to react completely?
The volume of 0.30 M potassium chromate needed to react with 15 ml of 0.10 M ferric nitrate is 5 ml.
What is molarity?Molarity of a solution is the ratio of its number of moles of solute to the volume of solution in liter. It is the common term used to express the concentration of a solution.
Let V1 and M1 be the volume and molarity of solution 1 and V2 and M2 that of solution 2 which are reacting together.
Thus, V1 M1 = V2 M2.
The volume of 0.30 M potassium chromate is calculated as follows:
volume = (15 ml × 0.10 M) / 0.30 M = 5 ml.
Therefore, the volume of the potassium chromate solution is 5 mL.
To find more on molarity, refer here:
https://brainly.com/question/8732513
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Which phase change is exothermic?
Answer:
B. Solidification
Hope this helped! :)
Collisions app covalent bonding level 15
Answer: change the nitrogen with oxygen for the first part then have the nitrogens collided instead of oxygens in the last part - not sure if my terminology is correct but here is the pic to show!
Explanation:
The different unit cell types have a different packing efficiency. The simple cubic has the least efficient packing and the face-centered cubic has the most efficient packing (sometimes the face-centered cubic is called cubic closest packing). You can determine what percent of the unit cell is occupied by (1) determining the volume of the whole unit cell and (2) determining the volume of the occupied space by the atoms in the unit cell. Remember that the volume of a cube is V
Answer:
The answer is "52.8".
Explanation:
Please find the graph file in the attachment.
They have the atoms in 8 corners with one unit cell in an one so mesh (SCC).
Atoms throughout the corner contribute [tex]\frac{1}{8}[/tex]to both the cell unit
Atom number per SCC unit cell, [tex]Z = (8 \times \frac{1}{8}) = 1[/tex]
Let 'r' become the atom's radius. [tex]r = 3.43\times 10^{-8}\ \ cm[/tex]
We can see from the diagram that edge length [tex]AB = a = 2r[/tex]
[tex]Packing\ efficiency = \frac{(1 \ atom \ Volume \times Z)}{Volume \ of \ unit\ cell \times 100}\\\\[/tex]
[tex]= \frac{\frac{4}{3}\times \pi \times r^3 \times 1}{a^3 \times 100}\\\\=\frac{\frac{4}{3}\times \pi \times r^3 \times 1}{(2r)^3 \times 100} \\\\=\frac{\frac{4}{3}\times \pi \times( 3.43\times 10^{-8}cm)^3 \times 1}{(2\times 3.43\times 10^{-8}cm)^3 \times 100}\\\\= 52.8 \%[/tex]
For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the slower phase only) of 0.216 (in a cuvette with a pathlength of 1 cm) over the course of two minutes. Use the Beer-Lambert Law to calculate the concentration of product released over this time; the extinction coefficient of p-nitrophenol at 405 nm is 18,000 M-1 cm-1.
Answer:
1.2x10⁻⁵M = Concentration of the product released
Explanation:
Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:
A = E*b*C
Where A is the absotbance of the solution: 0.216
E is the extinction coefficient = 18000M⁻¹cm⁻¹
b is patelength = 1cm
C is concentration of the solution
Replacing:
0.216 = 18000M⁻¹cm⁻¹*1cm*C
1.2x10⁻⁵M = Concentration of the product releasedcalculate the percentage of CL in AL(CLO3)3
Answer:
38.4%
Explanation:
We'll begin by calculating the molar mass of Al(ClO₃)₃. This can be obtained as follow:
Molar mass of Al(ClO₃)₃
= 27 + 3[35.5 + (16×3)]
= 27 + 3[35.5 + 48]
= 27 + 3[83.5]
= 27 + 250.5
= 277.5 g/mol
Next, we shall determine the mass of Cl in Al(ClO₃)₃. This can be obtained as follow:
Mass of Cl in Al(ClO₃)₃ = 3 × Cl
= 3 × 35.5
= 106.5 g
Finally, we shall determine the percentage of Cl in Al(ClO₃)₃. This can be obtained as follow:
Mass of Cl in Al(ClO₃)₃ = 106.5 g
Mass of Al(ClO₃)₃ = 277.5 g
Percentage of Cl =?
Percentage of Cl = mass of Cl / mass of Al(ClO₃)₃ × 100
Percentage of Cl = 106.5 / 277.5 × 100
Percentage of Cl = 38.4%
Select the statement that is FLASE about this experiment. Group of answer choices Changing temperature will affect the redox potential. Changing concentration will affect the redox potential. Changing metal solution will affect the redox potential. To ensure stable reading, insert the conductivity meter in the solution for at least 60 seconds. To ensure consistent data, collect the redox potential values at least three times.
Answer:
To ensure stable reading, insert the conductivity meter in the solution for at least 60 seconds.
Explanation:
The False statement is ; To ensure stable reading, insert the conductivity meter in the solution for at least 60 seconds.
All other statement will affect the experiment's redox potential but inserting the conductivity meter in the solution for at least 60 seconds will not affect the Redox potential .
Redox potential is used to describe/measure a system's oxidizing capacity
lave
Use the drop-down menus to identify the parts of a
wave.
A
B:
C
D
Answer:
Use the drop-down menus to make your selections.
What is the difference between wave A and wave B?
✔ Wave A has higher amplitude than wave B.
What is the difference between wave C and wave D?
✔ Wave C has a lower frequency than wave D.
Explanation:
An isolated atom of a certain element emits light of wavelength 655 nm when the atom falls from its fifth excited state into its second excited state. The atom emits a photon of wavelength 435 nm when it drops from its sixth excited state into its second excited state. Find the wavelength of the light radiated when the atom makes a transition from its sixth to its fifth excited state.
Answer:
[tex]\frac{1}{\lambda_{6-5}} \approx 752nm[/tex]
Explanation:
From the question we are told that
Light wavelength [tex]\lambda_l=655nm[/tex]
Light wavelength atom fall [tex]x_L=5th-2nd[/tex]
Photon wavelength [tex]\lambda_p=435nm[/tex]
Photon wavelength atom fall [tex]x_P=^th-2nd[/tex]
Generally the equation for the reciprocal of wavelength of emitted photon is is mathematically given by
[tex]\frac{1}{\lambda}=R(\frac{1}{ \lambda _f^2}-\frac{1}{\lambda _i^2} )[/tex]
Therefore for initial drop of 5th to 2nd
[tex]\frac{1}{\lambda_{5-2}}=R(\frac{1}{2^2}-\frac{1}{5^2} )[/tex]
Therefore for initial drop of 6th to 2nd
[tex]\frac{1}{\lambda_{6-2}}=R(\frac{1}{2^2}-\frac{1}{6^2} )[/tex]
Generally we subtract (5th to 2nd) from (6th to 2nd)
[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=R(\frac{1}{2^2}-\frac{1}{5^2} )-\frac{1}R(\frac{1}{2^2}-\frac{1}{6^2} )[/tex]
[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=R(\frac{1}{5^2}-\frac{1}{6^2} )[/tex]
[tex]\frac{1}{\lambda_{5-2}}- \frac{1}{\lambda_{6-2}}=\frac{1}{\lambda_{5-6}}[/tex]
[tex]\frac{1}{\lambda_{5-6}}=\frac{1}{4350nm}-\frac{1}{655nm}[/tex]
[tex]\frac{1}{\lambda_{5-6}}=1.33*10^{-3}[/tex]
Therefore for 6th to 5th stage is mathematically given by
[tex]\frac{1}{\lambda_{6-5}}=(1.33*10^{-3})^{-1}[/tex]
[tex]\frac{1}{\lambda_{6-5}}=751.879nm[/tex]
[tex]\frac{1}{\lambda_{6-5}} \approx 752nm[/tex]
Calculate the pH when 64.0 mL of 0.150 M KOH is mixed with 20.0 mL of 0.300 M HBrO (Ka = 2.5 × 10⁻⁹)
Answer:
The answer is "12.06"
Explanation:
Given:
[tex]M(HBrO) = 0.3\ M\\\\V(HBrO) = 20 \ mL\\\\M(KOH) = 0.15 \ M\\\\V(KOH) = 64 \ mL[/tex]
[tex]\to mol(HBrO) = M(HBrO) \times V(HBrO) = 0.3 M \times 20 mL = 6 \ mmol\\\\\to mol(KOH) = M(KOH) \times V(KOH)= 0.15 M \times 64 mL = 9.6 mmol[/tex]
6 mmol of both will react
excess KOH remaining[tex]= 3.15 \ mmol[/tex]
Volume[tex]= 20 + 64 = 84 \ mL[/tex]
[tex][OH^{-}] = \frac{ 9.6 \ mmol}{84\ mL} = 0.01142\ M[/tex]
use:
[tex]pOH = -\log [OH^-][/tex]
[tex]= -\log (1.142\times 10^{-2})\\\\= 1.94[/tex]
use:
[tex]PH = 14 - pOH[/tex]
[tex]= 14 - 1.94\\\\= 12.06[/tex]
The pH of the resulting solution is 12.63.
The equation of the reaction is;
HBrO(aq) + KOH(aq) ------> KOBr(aq) + H2O(l)
Number of moles of KOH= 64/1000 × 0.150 M = 0.0096 moles
Number of moles of HBrO = 20/1000 × 0.300 M = 0.0060 moles
Number of moles of excess base = 0.0096 moles - 0.0060 moles = 0.0036 moles
Total volume of solution = 64.0 mL + 20.0 mL = 84 mL = 0.084 L
Molarity of excess base = 0.0036 moles/0.084 L = 0.043 M
pOH = -log[OH-]
pOH = -log[ 0.043 M]
pOH = 1.37
pH + pOH = 14
pH = 14 -pOH
pH = 14 - 1.37
pH = 12.63
Learn more: https://brainly.com/question/11897796
help asap please, What does Newton's law of gravitation state that two masses will do?
always fall
not have any affect on each other
attract each other
repel each other
Answer:
According to Newton's law of gravitation two objects attract each other
Answer: C. Attract each other!
Explanation:
What is the greatest concentration of pollution
Answer:
B
Explanation:The poisonous substances, present in the environment can easily get into the trophic level as living organism depends on each other and environment for food and nutrition. These poisonous substances may not be broken down in the body or excreted easily, efficiently and quickly. Instead, they accumulate in the tissues, and as the living organism eats more, the concentration of these substances increases and they pass from one trophic level to the next. The tertiary consumer being at the top of trophic levels receives the maximum pollutant. This phenomenon is known as biological magnification.
So, the correct answer is option B.
Draw curved arrows to show electron reorganization for the mechanism step below. (For a resonance-stabilized anion, draw a single resonance form with the negative charge on oxygen, not on carbon.) Make the ends of your arrows specify the origin and destination of reorganizing electrons.
Answer:
Explanation:
Dear student, this question appears to be incomplete but in the diagram attached below, I have carefully drawn out the required organic structure.
The aim of this question is to show the mechanism of the given structure and to point out the resonance structure.
The first diagram shows the complete part (i.e. the structure of the organic compound) and its major product(answer).
The second diagram shows the mechanism by which we arrived at the major product.
From the second diagram attached below, the -oxo substituent of the methanol attacks the hydrogen atom as shown below, leading to the formation of the enolate ion (a resonance stabilized anion).
However, this is because the alpha carbon attaches to the hydrogens readily leaves as H⁺ to yield an enolate ion as a result of -C- that is doubly bonded to oxygen (an Electron withdrawing group).
Kindly check out the images attached below to see the mechanism.
Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.
Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.
Complete question :
Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.
m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C
Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.
M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C
Answer:
Quantity of heat gained = 67401.6 Joules
Quantity of heat lost by hot water = 40854.25 Joules
Explanation:
The heat gained by cold liquid :
Q = m × c × ΔT
m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C
Q = 248.9 * 3.73 * 72.6
Q = 67401.6 Joules
Quantity of heat gained = 67401.6 Joules
Heat lost by hot water :
m × c × ΔT
M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C
Q = 237 * 41.2 * 4.184
Q = 40854.25 Joules
Quantity of heat lost by hot water = 40854.25 Joules
PLEASE HELP ITS DUE SOON AND I DONT UNDERSTAND
How many grams of KClO3 must be decomposed to produce 3.45 L of oxygen at STP with a 75.3% yield? 2 KClO3(s) à 2 KCl(s) + 3 O2(g)
3. Convert the word equations below to symbolic:
Sodium + chlorine sodium chloride
• Calcium + bromine ---- calcium bromide
• Potassium + water → potassium hydroxide + hydrogen
ot
Answer:
1)2Na + Cl2 ----> 2NaCl
2)Ca + Br2 ---->CaBr2
3)K + H2O -----> KOH + H2
heat would best be transferred by conduction between
A. a candle and the air
B. an oven and a glass dish
C. a stove and a copper pot
D. water and a wooden spoon
Answer:
C. or B.
Explanation:
The reason I chose c best, is when your cooking something with a pot with food in it max heat in about 5 minutes, the handle starts to get warmer every minute. This is conduction, where the heat transfers from the very bottom all the way to the very edge of something that is heated at a certain temperature.